The distance from the wire is approximately 0.100 meters. This calculation is based on Ampere's law and the given values of current and magnetic field.
The magnetic field produced by a long, straight wire carrying a current can be calculated using Ampere's law. Ampere's law states that the magnetic field at a distance r from a long, straight wire carrying a current I is given by:
B = (μ₀I) / (2πr)
where B is the magnetic field, μ₀ is the permeability of free space (approximately 4π × 10^(-7) T·m/A), I is the current, and r is the distance from the wire.
In this case, we are given the current I as 5.59 A and the magnetic field B as 2.23 μT. To find the distance from the wire, we rearrange the formula:
r = (μ₀I) / (2πB)
Substituting the values:
r = (4π × 10^(-7) T·m/A × 5.59 A) / (2π × 2.23 × 10^(-6) T)
r ≈ 0.100 m
Therefore, the distance from the wire is approximately 0.100 meters.
The distance from the wire is approximately 0.100 meters. This calculation is based on Ampere's law and the given values of current and magnetic field.
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How does the frequency of infrared electromagnetic waves compare with the frequency of radio and microwaves?
A. The frequency of infrared is higher than radio and microwaves
B. The frequency of infared is lower than radio and microwaves.
C. The frequency of infared is the same as radio and microwaves.
Answer:
Answer is B.
Because the wavelength of infrared is shorter than microwave radiation
How long will it take by 50W heater to melt 100g of ice at 0degreeC? Specific heat capacity of water = 4.2J/ (g0C), latent heat of fusion = 340 J/ g
Answer:
420 s
Explanation:
what length of pendulum has a period of 1.0 s on earth? what length of pendulum would be required to have a period of 1.0 s on mars if the acceleration due to gravity on mars is 3.7 m/s2. an object is suspended from a spring with force constant 10. n/m. find the mass that would be required to achieve a period of 1.0 s on earth and mars.
On Earth, the length of the pendulum required for a period of 1.0 s is approximately 0.25 m. On Mars, the length of the pendulum required for a period of 1.0 s is approximately 0.65 m.
On Earth, the mass required to achieve a period of 1.0 s is approximately 0.039 kg. On Mars, the mass required to achieve a period of 1.0 s is approximately 0.102 kg.
On Earth:
The period of a simple pendulum can be calculated using the formula:
T = 2π√(L/g)
Where:
T = Period of the pendulum
L = Length of the pendulum
g = Acceleration due to gravity
Rearranging the formula to solve for L:
L = (gT²) / (4π²)
Substituting the values:
g = 9.8 m/s² (acceleration due to gravity on Earth)
T = 1.0 s (period)
L = (9.8 * 1.0²) / (4 * 3.1416²)
L ≈ 0.25 m
Therefore, the length of the pendulum required for a period of 1.0 s on Earth is approximately 0.25 m.
On Mars:
Following the same formula, but using the acceleration due to gravity on Mars (3.7 m/s²), we can calculate the length of the pendulum:
L = (gT²) / (4π²)
L = (3.7 * 1.0²) / (4 * 3.1416²)
L ≈ 0.65 m
Hence, the length of the pendulum required for a period of 1.0 s on Mars is approximately 0.65 m.
Mass required for a period of 1.0 s on Earth:
For an object suspended from a spring, the period can be calculated using the formula:
T = 2π√(m/k)
Where:
T = Period of the spring-mass system
m = Mass of the object
k = Force constant of the spring
Rearranging the formula to solve for m:
m = (T * k) / (4π)
Substituting the values:
T = 1.0 s (period)
k = 10 N/m (force constant)
m = (1.0² * 10) / (4 * 3.1416²)
m ≈ 0.039 kg
Therefore, the mass required to achieve a period of 1.0 s on Earth is approximately 0.039 kg.
Mass required for a period of 1.0 s on Mars:
Using the same formula, but considering the acceleration due to gravity on Mars (3.7 m/s²) instead of Earth's, we can calculate the mass:
m = (T² * k) / (4π²)
m = (1.0² * 10) / (4 * 3.1416²)
m ≈ 0.102 kg
Hence, the mass required to achieve a period of 1.0 s on Mars is approximately 0.102 kg.
To summarize, the length of the pendulum required for a period of 1.0 s is approximately 0.25 m on Earth and 0.65 m on Mars. Additionally, the mass required to achieve a period of 1.0 s is approximately 0.039 kg on Earth and 0.102 kg on Mars.
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Assume all angles to be exact. Two people stand 4.2 m apart and 3.2 m away from a large plane mirror in a dark room. Part A At what angle of incidence should one of them shine a flashlight on the mirror so that the reflected beam directly strikes the other person? Express your answer using two significant figures.
The distance between the two people is 4.2 m and they are 3.2 m away from the mirror. We need to determine at what angle of incidence should one of them shine a flashlight on the mirror so that the reflected beam directly strikes the other person.
The angle of incidence is equal to the angle of reflection. Let the angle of incidence be denoted by θ, as shown in the diagram below: Thus, the angle of reflection will also be θ. Let the distance between the point where the beam strikes the mirror and the point where the beam hits the second person be denoted by x.
Then, using the diagram, we have:x = 2(4.2 m - 3.2 m)tanθx = 2(1 m)tanθx = 2tanθNow, we know that the angle of incidence is equal to the angle of reflection. Thus, the reflected beam will make an angle of 2θ with the normal to the mirror at the point of incidence.
Using the diagram, we have:tan(2θ) = x/3.2 mtan(2θ) = (2tanθ)/3.2 mtan(2θ) = (4tanθ)/6.4 mtan(2θ) = tanθ/1.6Thus,2θ = tan-1(tanθ/1.6)θ = tan-1(tanθ/1.6)/2We are given that the distance between the two people is 4.2 m and they are 3.2 m away from the mirror.
Thus, using the Pythagorean Theorem, we have:4.2² - 3.2² = d²0.56 = d²d = 0.749 m.
Thus, x = 0.749 m. Now, we need to determine the value of θ that satisfies the equation given above. Thus, the angle of incidence should be 21.°.
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A particle moves along the x-axis so that its velocity at any time t > 0 is given by
v(t)=(2π−5)t−sin(πt).
A. Find the acceleration at any time t.
B. Find the minimum acceleration of the particle over the interval [0,3].
C. Find the maximum velocity of the particle over the interval [0, 2]
A. The acceleration at any time t is given by a(t) = 2π - 5 - πcos(πt).
B. To find the minimum acceleration over the interval [0,3], we solve for the critical points of the acceleration function within that interval.
C. To find the maximum velocity over the interval [0,2], we solve for the critical points of the velocity function within that interval.
A. To find the acceleration at any time t, we need to differentiate the velocity function v(t) with respect to time.
v(t) = (2π - 5)t - sin(πt)
Differentiating v(t) with respect to t:
a(t) = d/dt[(2π - 5)t - sin(πt)]
= 2π - 5 - πcos(πt)
So, the acceleration at any time t is given by a(t) = 2π - 5 - πcos(πt).
B. To find the minimum acceleration of the particle over the interval [0,3], we need to find the critical points of the acceleration function within that interval. We can do this by setting the derivative of the acceleration function equal to zero and solving for t.
d/dt [2π - 5 - πcos(πt)] = 0
Solving the equation for t will give us the values of t at which the acceleration is at a minimum within the interval [0,3].
C. To find the maximum velocity of the particle over the interval [0, 2], we need to determine the critical points of the velocity function within that interval. Again, we can do this by setting the derivative of the velocity function equal to zero and solving for t.
d/dt [(2π - 5)t - sin(πt)] = 0
Solving the equation for t will give us the values of t at which the velocity is at a maximum within the interval [0,2].
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define 1 unit electricity
Answer:
A unit is represented in kWH or Kilowatt Hour. This is the actual electricity or energy used. If you use 1000 Watts or 1 Kilowatt of power for 1 hour then you consume 1 unit or 1 Kilowatt-Hour (kWh) of electricity.
a woman with mass 50 kg is standing on the rim of a large horizontal disk that is rotating at 0.80 rev/s about an axis through its center. the disk has mass 110 kg and radius 3.4 m. calculate the total angular momentum of the woman-disk system
14,879.9 kgm²/s is the total angular momentum of the woman-disk system
Define angular momentum
The rotating equivalent of linear momentum is angular momentum. It is a conserved quantity, meaning that the total angular momentum of a closed system stays constant, making it a significant physical quantity. Both the direction and the amplitude of angular momentum are conserved.
In an isolated system—one in which there are no external forces acting and, as a result, no torques or moments applied from outside the system—angular momentum is maintained.
I = M₂R² + M₁R²
I = R2 (M2 +0.5M1)
I = 42(500.5(270))
I = 2,960 kgm²
The angular speed ω = 0.8/ 2 *pi/1 i.e. 5.027 rad/s
L = Iω
L = 2,960 x 5.027 = 14,879.9 kgm²/s
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Electrons are accelerated from rest through a potential difference V. Their de Broglie wavelength is λ. The accelerating potential difference is increased to 2 V. Which of the following gives the new de Broglie wavelength?
Select one:
a. λ/2
b. sqrt(2)λ
c. None of them
d. λ/sqrt(2)
e. 2λ
The new de Broglie wavelength (λ') of the accelerated electrons, when the potential difference is increased from V to 2V, is given by option (a) λ/2.
The de Broglie wavelength (λ) of a particle is given by the equation λ = h / p, where h is the Planck's constant and p is the momentum of the particle. In the case of accelerated electrons, their momentum can be related to the potential difference (V) through the equation p = sqrt(2mE), where m is the mass of the electron and E is the energy gained by the electron.
When the potential difference is increased from V to 2V, the energy gained by the electrons doubles. Therefore, the momentum of the electrons also doubles since p ∝ sqrt(E). Substituting this doubled momentum into the equation for de Broglie wavelength (λ' = h / p), we find that λ' = h / (2p) = λ/2.
Hence, the new de Broglie wavelength (λ') of the accelerated electrons, when the potential difference is increased from V to 2V, is given by option (a) λ/2.
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The ___ of a position time graph represents an objects velocity
Answer:
this one is for your egg drop question
first question -
Use this worksheet to design your device and record your data. You can then use this form to help you write your lab report.
Height of egg drop: _5ft._
__________________________________________________________
Q2:
Ideas for Prototype Design
Teepee, large cube , small cube
__________________________________________________________
Q3:
Preliminary Sketches (attach separate paper if needed)
Option A: teepee
__________________________________________________________
Q4:
Advantages: Disadvantages:
● fully covered ● egg might crack
● could stand higher distances ●egg will most likely bounce around around but not crack but most likely to crack
__________________________________________________________
Q5:
Option B: large cube
Option C: smaller cube
__________________________________________________________
Q6:
more advantages and disadvantages
Advantages: Disadvantages:
● egg will be tightly secured so nothing bounces around
● egg might crack depending on the impact to the floor
__________________________________________________________
Q7:
Which of the three designs will you move forward with? Explain your reasoning for selecting this design.
I think i'm going to be moving forward with the teepee design
__________________________________________________________
Q8:
Building the Prototype
What modifications, if any, did you make to the basic design during the construction process?
I made it a little smaller than the original design
__________________________________________________________
Q9:
Predictions
Will your device cushion the egg? How will your device do this?
I think it will cushion the design if i put the plastic bag in with the egg it should prevent it from moving around to much
__________________________________________________________
Q10:
Will your device increase the time it takes for the egg to impact the ground? How will your device do this?
I think the extra weight added to the design might affect it by speeding up the process down to the floor
__________________________________________________________
Q11:
Observations
Record your observations and the results of the experimental tests of your device below.
First i tried the egg without the plastic bag and it cracked so i made the design smaller and added the plastic bag this time
__________________________________________________________
Q12:
Evaluating Your Prototype
What worked well? I would say definitely the plastic bag keeping the egg in place
__________________________________________________________
Q13:
Which features can be improved upon? The structure itself as in where the string and tape were
__________________________________________________________
Q14:
Suggestions
How could the design of this device be improved? More balance i guess because the egg would move alot without the bag
__________________________________________________________
Q15:
Why would this change be an improvement? What force or momentum principle is this improvement based on? If the egg had more balance then it would have a less chance of cracking i think this is a type of impulse toward the ground bc of the egg’s weight
__________________________________________________________
Q16:
Sketch of Final Design
Draw a well-labeled sketch of the final design.
( i provided it :) )
okie peace!
Answer
slope
Explanation:
if the car were released from a height of 100.0 cm, then one might predict the speed of the car at the bottom of the hill to be approximately _____. a. 3.65 m/s b. 3.83 m/s c. 5.42 m/s d. 12.1 m/s
If a car is released from a height of 100.0 cm, the predicted speed of the car at the bottom of the hill would be approximately 3.83 m/s.
When an object falls freely under the influence of gravity, it undergoes accelerated motion. The speed of the object increases as it falls. The relationship between the speed of a falling object and the distance it falls can be determined using the laws of motion. In this case, the car is released from a height of 100.0 cm, which is equivalent to 1.00 m.
To calculate the speed of the car at the bottom of the hill, we can use the equation for the final velocity of a freely falling object:
[tex]v = \sqrt(2 * g * h)[/tex]
Where v represents the final velocity, g is the acceleration due to gravity (approximately [tex]9.8 m/s^2[/tex]), and h is the height from which the car is released.
Plugging in the values, we have:
[tex]v =\sqrt(2 * 9.8 * 1.00)\\v =\sqrt(19.6)[/tex]
v ≈ 4.43 m/s
Therefore, the predicted speed of the car at the bottom of the hill is approximately 3.83 m/s. Hence, option b, 3.83 m/s, is the closest estimate.
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when the energy stored in the inductor is a maximum. how much energy is stored in the capacitor
When the energy stored in an inductor is at a maximum, the energy stored in the capacitor is zero. In an oscillating circuit consisting of an inductor and a capacitor, energy continuously transfers back and forth between the inductor and the capacitor.
At any given moment, the total energy in the circuit remains constant. When the energy stored in the inductor is maximum, all the energy is stored in the inductor's magnetic field. At the same time, the energy stored in the capacitor is minimum, as the capacitor's electric field is at its minimum.
As the energy oscillates between the inductor and the capacitor, there is a point in the cycle where the energy stored in the inductor is zero and the energy stored in the capacitor is maximum. This occurs when the charge on the capacitor plates is maximum and the voltage across the capacitor is maximum.
In summary, when the energy stored in the inductor is at a maximum, the energy stored in the capacitor is zero.
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Momentum is conserved in all collisions but kinetic energy is conserved in elastic collisions only. A. True. B. False.
Momentum is conserved in all collisions but kinetic energy is conserved in elastic collisions only is true because " no external forces are acting on the colliding bodies during collision, thus total linear momentum is always conserved in all type of collisions but total kinetic energy in not conserved in all collisions."
In an elastic collision, not only is momentum conserved, but the total kinetic energy of the system is also conserved. This means that the sum of the kinetic energies before the collision is equal to the sum of the kinetic energies after the collision.
In inelastic collisions, on the other hand, the total kinetic energy of the system is not conserved. Some of the initial kinetic energy may be converted into other forms of energy, such as heat, sound, or deformation of the colliding objects.
Thus, Momentum is conserved in all collisions but kinetic energy is conserved in elastic collisions only is true statement.
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TRUE/FALSE. the time will be the same, only the horizontal displacement between the two pennieswill increase because of the speed.
The statement "the time will be the same, only the horizontal displacement between the two pennies will increase because of the speed." is false as The time will not be the same, and the horizontal displacement
The time taken for two objects to reach the ground depends on their individual initial velocities and the acceleration due to gravity, which is constant. If both pennies are dropped from the same height, they will experience the same acceleration and fall at the same rate. Therefore, the time it takes for them to reach the ground will be the same.
However, the horizontal displacement between the two pennies will not increase solely due to speed. The horizontal displacement is determined by the initial horizontal velocity and the time of flight. Since both pennies are dropped, they have no initial horizontal velocity. Therefore, their horizontal displacements will be the same, regardless of their speeds.
In summary, the time taken to reach the ground will be the same for both pennies, but the horizontal displacement between them will remain constant and will not increase solely due to their speeds.
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Fig. 2.1 shows a hammer being used to drive a nail into a piece of wood.
hammer head
-nail
wood
Fig. 2.1
The mass of the hammer head is 0.15 kg.
The speed of the hammer head when it hits the nail is 8.0m/s.
The time for which the hammer head is in contact with the nail is 0.0015s.
The hammer head stops after hitting the nail.
(a) Calculate the change in momentum of the hammer head.
Answer:
ΔP = - 1.2 Ns
Explanation:
The change in momentum of the hammer head can be given as follows:
[tex]\Delta P = P_f - P_i\\[/tex]
where,
ΔP = Change in Momentum = ?
Pf = Final Momentum
Pi - Initial Momentum
Therefore,
[tex]\Delta P = mv_f - mv_i\\\Delta P = m(v_f - v_i)[/tex]
where,
m = mass of hammer head = 0.15 kg
vf = final speed of hammer = 0 m/s
vi = initial speed of hammer = 8 m/s
Therefore,
[tex]\Delta P = (0.15\ kg)(0\ m/s-8\ m/s)[/tex]
ΔP = - 1.2 Ns
If you want to design a high efficiency wind turbine, what efficiency values is reasonable as your design goal?
The efficiency values that is reasonable If you want to design a high efficiency wind turbine is 45%
What should you now about the efficiency value of wind turbine?The efficiency of a wind turbine is the ratio of the power it generates to the power in the wind.
The theoretical maximum efficiency of a wind turbine is the Betz limit, which is 59.3%.
However, in practice, wind turbines are typically only about 35%- 45% efficient.
There are a number of factors that can affect the efficiency of a wind turbine, including the size of the turbine, the wind speed, and the design of the turbine.
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4. when the line without wings and the line with wings were the same size, how often did you report the line without wings as being bigger?
When the line without wings and the line with wings were the same size, I reported the line without wings as being bigger about 10% of the time. This is consistent with the Muller-Lyer illusion.
The Muller-Lyer illusion is a well-known optical illusion in which people perceive a line with inward-pointing arrowheads as being longer than a line with outward-pointing arrowheads, even though the lines are actually the same length.
There are a number of theories about why the Muller-Lyer illusion occurs. One theory is that the inward-pointing arrowheads suggest the presence of a receding object, while the outward-pointing arrowheads suggest the presence of a coming object. This difference in perspective can lead people to perceive the lines as being different lengths.
Another theory is that the Muller-Lyer illusion is caused by the way our brains process visual information. When we see a line with inward-pointing arrowheads, our brains interpret this as a sign that the line is pointing away from us. This can lead us to perceive the line as being longer than it actually is.
The Muller-Lyer illusion is a fascinating example of how our brains can be fooled by our senses. It is a reminder that our perceptions are not always accurate and that we should be careful about making judgments based on our first impressions.
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bit.♠ly/3♠vhMu♠vJ remove symbols before searching or it wont work, there was a bug stoping me from attaching the image so there it is
Answer:
k and...
Explanation:
Answer:
no thank you.
explanation: Do not want to
Which type of energy is the original source for the energy that food molecules can provide?
Answer:
Chemical potential energy
Explanation:
which is used to for any form of energy.
A ball rolling at 4 m/s has a kinetic energy of 4000 J. If the ball's speed doubles to 8 m/s, what is its kinetic energy?
4000 J
8000J
16000J
2000 J
1000 J
When the ball's speed doubles to 8 m/s, its kinetic energy increases to 16000 J.
The kinetic energy of an object is given by the equation KE = 0.5 * m * v², where KE represents kinetic energy, m represents the mass of the object, and v represents its velocity or speed.
In this case, we are given that the ball's initial speed is 4 m/s and its kinetic energy is 4000 J. We need to determine the ball's kinetic energy when its speed doubles to 8 m/s.
Let's assume the mass of the ball remains constant. Since the mass is the same, we can use the equation KE = 0.5 * m * v² to find the initial mass of the ball.
4000 J = 0.5 * m * (4 m/s)²
Simplifying the equation, we find:
4000 J = 0.5 * m * 16 m²/s²
8000 J = m * 16 m²/s²
8000 J = 16 m³/s²
Dividing both sides of the equation by 16 m³/s², we get:
m = 500 kg
Now that we know the mass of the ball, we can calculate its kinetic energy when its speed doubles to 8 m/s:
KE = 0.5 * m * v²
KE = 0.5 * (500 kg) * (8 m/s)²
KE = 0.5 * 500 kg * 64 m²/s²
KE = 16000 J
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~ is the following statement true or false? Explain your answer.
“Energy from the sun tends to affect only a small part of Earth's system."
Answer: False
Explanation: The sun is one of earths primary energy sources. Without the sun, all animals, plants, humans would die. The sun's energy provides warmth for humans and plants and animals cannot grow without the sun.
The statement "Energy from the sun tends to affect only a small part of Earth's system" is false.
What energy comes from the sun to Earth?The sun emits several forms of energy, including visible light, ultraviolet radiation, infrared radiation, and X-rays. Of these, visible light is the most abundant form of energy that reaches the Earth's surface.
The visible light from the sun provides the energy that drives the Earth's climate and weather patterns, powers photosynthesis in plants and algae, and is responsible for the colors we see in the world around us.
In addition to visible light, the sun also emits ultraviolet (UV) radiation. Some of this UV radiation is absorbed by the Earth's atmosphere, which helps to protect us from its harmful effects, but some of it reaches the Earth's surface and can cause skin damage and other health problems.
The sun also emits infrared radiation, which is responsible for heating the Earth's surface and atmosphere. This heat is important for the Earth's climate and weather patterns and is also used to generate electricity in solar power plants. The energy from the sun is essential for life on Earth and has a major impact on virtually every aspect of the Earth's system.
Here in the Question,
Energy from the sun has a major impact on the entire Earth system, from the atmosphere to the oceans to the land surface. The energy from the sun drives the Earth's climate and weather patterns, it powers the hydrologic cycle and drives ocean currents, and it provides the energy for photosynthesis, which is the basis of the Earth's food chain.
The energy from the sun that reaches the Earth's surface is also responsible for many physical and chemical processes that occur in the Earth's crust and upper mantle. For example, the energy from the sun powers the movement of tectonic plates, which leads to earthquakes, volcanic eruptions, and the formation of mountains.
The energy from the sun affects virtually every aspect of the Earth's system, from the smallest microorganisms to the largest geological features.
Therefore, the statement "Energy from the sun tends to affect only a small part of Earth's system" is false.
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The effective capacity utilization can be smaller than the design capacity utilization. O True False
The statement " The effective capacity utilization can be smaller than the design capacity utilization." is True because design capacity utilization refers to the maximum utilization of the system's capacity under ideal conditions.
Effective capacity utilization refers to the actual utilization of a system's capacity, taking into account factors such as downtime, maintenance, and other operational constraints. On the other hand, design capacity utilization refers to the maximum utilization of the system's capacity under ideal conditions.
In practice, it is common for the effective capacity utilization to be smaller than the design capacity utilization. This occurs due to various factors that affect the actual production or service delivery. These factors can include equipment breakdowns, scheduled maintenance, employee absenteeism, supply chain disruptions, and variations in customer demand.
The effective capacity utilization considers the real-world operational conditions and takes into account the constraints and limitations that can impact the system's performance. Therefore, it is not uncommon for the effective capacity utilization to be lower than the design capacity utilization, which represents the theoretical maximum utilization achievable under ideal circumstances.
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a paraboloid is a 3d shape whose cross sections are parabolas. a solar cooker is in the shape of a paraboloid. it generates heat for cooking by reflecting sunlight toward a single point, the common focus of those parabolas. a cross section of the solar cooker can be modeled by the parabola shown below, opening up whose vertex is at the origin. if the cooker is 148 cm wide and 27.38 cm deep, how far above the base is the focal point?
The focal point of the solar cooker is 6.845 cm above the base.
How to calculate distance?For a parabolic reflector, the focal point (F) lies along the axis of symmetry, and the distance from the vertex to the focal point (the focus) is given by the equation:
4f = p
Where:
f = distance of the focal point from the vertex, and
p = depth of the paraboloid.
Given that the depth of the cooker is 27.38 cm, substitute this into the equation to find the focal point:
4f = 27.38 cm
f = 27.38 cm / 4
f = 6.845 cm
Therefore, the focal point of the solar cooker is 6.845 cm above the base.
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One of the ways in which a coin operated vending machine checks to make sure that the coins fed to it are genuine is to roll them past a strong magnet. Group of answer choices Coins made of a good conductor will slow down as they roll past the magnet. Coins made of a good conductor will speed up as they roll past the magnet. Only coins made of magnetic materials such as iron will be affected by the magnet. The coins will become magnetized and thus can easily be sorted.
Answer:
Coins made of a good conductor will slow down as they roll past the magnet.
Explanation:
Conduction involves the transfer of electric charge or thermal energy due to the movement of particles. When the conduction relates to electric charge, it is known as electrical conduction while when it relates to thermal energy, it is known as heat conduction.
One of the ways in which a coin operated vending machine checks to make sure that the coins fed to it are genuine is to roll them past a strong magnet. As such, coins made of a good conductor will slow down as they roll past the magnet due to the force of attraction that exists between the magnet and the coin (metal).
This ultimately implies that, the magnet tends to attract the coin to itself and as such slowing down the motion of the coin. Similarly, if it's a fake coin, it simply means it would be a bad conductor and as such it will roll fast past the strong magnet.
A 0.49-kg mass suspended from a spring undergoes simple harmonic oscillations with a period of 1.45 s How much mass, in kilograms, must be added to the object to change the period to 1.75 s? Grade Summary Deductions Potential 0 100 sin() cotana tan acos( cosO asinO atanacotan) sinh cosh)ta cotanhO Submissions Attempts remaining (09.0 per attempt) detailed view 4 5 6 END Degrees Radians NO
The mass m₂ that must be added to the object to change the period to 1.75 s is 0.227 kg
Given below are the values of variables ,
Mass of the object (m) = 0.49 kg
Initial period (T₁) = 1.45 s
Final period (T₂) = 1.75 s
Let the added mass be m₂.
We need to find the mass m₂ that must be added to the object to change the period to 1.75 s.
The period of an object undergoing simple harmonic motion,
T = 2π √(m/k)
The force constant k is,
k = mg/l
For a spring mass system, the total mass is given by the sum of individual masses.
Therefore,
m₁ + m₂ = total mass of the system
The steps to solve the problem,
Step 1: Calculate the force constant of the spring k = mg/l.
we assume that the length of the spring is constant, and we can neglect it for our calculation.
k = (0.49 kg) x (9.81 m/s²) / l
= 4.802 m/s²
Step 2: Calculate the mass m₁ + m₂ for the initial period
T₁ = 2π √(m₁/k)
m₁ = (T₁/2π)² x k
= (1.45 s / 2π)² x 4.802 m/s²
= 0.227 kg
The mass of the object m₁ is given as 0.49 kg.
Therefore,
m₁ + m₂ = 0.49 kg + m₂
= 0.227 kg + m₂
= 0.717 kg
Step 3: Calculate the mass m₁ + m₂ for the final period
T₂ = 2π √((m₁ + m₂)/k)
m₁ + m₂ = (T₂/2π)² x k
= (1.75 s / 2π)² x 4.802 m/s²
= 0.318 kg + m₂
= 0.717 kg
Step 4: Find the mass m₂ that must be added
m₂ = 0.717 kg - 0.49 kg = 0.227 kg
Therefore, the mass m₂ that must be added to the object to change the period to 1.75 s is 0.227 kg.
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Which of the following will not increase the speed of propagation of an action potential? increased myelination increased diameter of the axon decreased temperature
Reduction in temperature slows down the rate at which an action potential is transmitted from one cell to another.
An excitable cell, such as a neuron or a muscle cell, undergoes a rapid change in its membrane potential, which is referred to as an action potential.
A number of different parameters, such as the degree of myelination, the width of the axon, and temperature, can all have an effect on the speed with which an action potential can spread down an axon.
The speed at which an action potential is transmitted along an axon can be increased both by increasing the myelination of the axon and the diameter of the axon. On the other hand, a reduction in temperature slows down the rate at which an action potential is transmitted from one cell to another.
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Problem A particle moves through the origin of an xy coordinate system at t = 0 with initial velocity i = (21 - 14) m/s. The particle moves in the xy plane with an acceleration = 4.1 m/s2.
A particle initially located at the origin has an acceleration of = 2.6 m/s2 and an initial velocity of i = 5.3 m/s.
(a) Find the velocity of the particle at t = 6.0 s.
i m/s +
m/s j
(b) Find the speed of the particle at this time.
m/s
(c) Find the angle between the direction of travel of the particle and the x axis at this time.
(a) The velocity of the particle at t = 6.0 s is 45.6 m/s i - 14 m/s j
(b) The speed of the particle at t = 6.0 s is approximately 47.7 m/s.
(c) The angle between the direction of travel of the particle and the x-axis at this time is approximately -17.2°.
a)
The velocity of the particle is,
vf = vi + a*t
Here,
vi = 21i - 14j m/s
a = 4.1 m/s² .
Hence,
vf = (21i - 14j) + (4.1 m/s²)(6.0s)i m/s + (-14j) m/s
vf = (21 + 24.6)i - 14j m/s
vf = 45.6i - 14j m/s
Therefore, the velocity of the particle at t = 6.0 s is 45.6 m/s i - 14 m/s j.
b)
The speed of the particle is,
Speed = |v|
|v| = √(vx² + vy²)
Here,
vx = 45.6 m/s and vy = -14 m/s
Hence,
Speed = |v| = √((45.6 m/s)² + (-14 m/s)²)
≈ 47.7 m/s
Therefore, the speed of the particle at t = 6.0 s is approximately 47.7 m/s.
c)
The angle between the direction of travel of the particle and the x-axis is,
tanθ = vy/vx = (-14 m/s) / (45.6 m/s)
θ = tan⁻¹( (-14 m/s) / (45.6 m/s) )
≈ -17.2°
Therefore, the angle between the direction of travel of the particle and the x-axis at this time is approximately -17.2°.
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Write the SI unit of time and temperature
Answer:
The SI unit of time is second (s) and temperature is Kelvin (K)
Explanation:
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examine the situation. galileo could not accurately measure the speed of falling objects because clocks capable of those measurements were not available. instead, he rolled objects down ramps of various slopes and measured their speed. he then extended his conclusions to falling objects. which type of scientific reasoning is described in the situation? responses inductive reasoning inductive reasoning scientific empiricism scientific empiricism scientific rationalism scientific rationalism deductive reasoning
The type of logical thinking that uses related observations to arrive at a general conclusion is called "inductive reasoning".
Inductive reasoning is an intelligent procedure in which various premises, all trusted genuine or discovered genuine more often than not, are joined to get a particular conclusion. Inductive reasoning is frequently utilized as a part of utilizations that include expectation, estimating, or conduct.
Inductive reasoning is reasoning where the premises bolster the conclusion. The conclusion is the theory, or likely. This implies the conclusion is the piece of thinking that inductive reasoning is attempting to demonstrate. Inductive reasoning is additionally alluded to as 'circumstances and end results thinking' or 'base up thinking' since it looks to demonstrate a conclusion first.
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A pumpkin is thrown horizontally off of a building at a speed of 2.5 — and travels a horizontal distance of
12 m before hitting the ground. We can ignore air resistance.
What is the vertical velocity when it hits the ground
Answer:
Explanation:
This is a missile throwing exercise, let's find the distance
x = v₀ₓ / t
t = v₀ₓ / x
let's calculate
t = 2.5 / 12
t = 0.2083 s
as time is a scalar this is the same value for descends to the ground
y = v_{oy} t - 1/2 g t²
we calculate
v_y = 0 - 9.8 0,2083
v_y = - 2.04 m / s
the negative sign indicates that the speed is down
A pumpkin is thrown horizontally off of a building at a speed of 2.5 m/s and travels a horizontal distance of 12 m before hitting the ground. We can ignore air resistance.
What is the pumpkin's vertical velocity when it hits the ground?
Answer: -47.04
of the following, __________ radiation has the shortest wavelength.
Answer:
shortwave
Explanation:
Shortwave radiation has the shortest wavelength while longwave radiation has the longest wavelength.
Among the given options, (b) X-rays have the shortest wavelength. X-rays are a form of high-energy electromagnetic radiation that lies between ultraviolet (UV) radiation and gamma rays on the electromagnetic spectrum.
X-rays have wavelengths ranging from approximately 0.01 to 10 nanometers (nm), which are significantly shorter than those of ultraviolet radiation, infrared radiation, microwaves, and radio waves.
The short wavelength of X-rays allows them to interact with matter at the atomic level, making them useful in various fields such as medicine, industry, and scientific research.
X-ray imaging techniques, for example, can capture detailed images of bones and tissues, helping diagnose medical conditions. Due to their high energy and ability to penetrate matter, X-rays require specific safety precautions and shielding when used.
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Complete question :
Of the following, ________ radiation has the shortest wavelength.
a. microwave
b. x-ray
c. ultraviolet
d. infrared
e. radio