A placement exam has a measure of x=500 and a standard deviation of s=100. If a student obtained the standard value z= 1.8, then the exam grade is: a. 400 b. 640 c.320 d.680
deviation of the children's ages is: a. 1.27 b. 1.62 c. 2:25 a.m. 1.97 dad Frecuencia xf Jeg gon.no 7 12 10 8 5 42 84 80 72 50 252 588 640 648 500

Step-by-step explanation:

12. n^2+2n

if you insert 1 for k and then work up by inserting 2 for k and adding those together and stoping at n.

13. 8-2(2^n)

if you insert 3 for k and then work up by inserting 4 for k and adding those together and keep on going but stopping at n.

Hope that helps :)

Answer:

The angles are adjacent, and x=100

Step-by-step explanation:

The angles are adjacent because they share the same starting point. x=100 because x and the other angle are on a line, which has a measure of 180 degrees. We subtract 80 from 180 to get 100.

Hope this was helpful.

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The posterior probability mass function of X is given below:0.4 * 0.0183 = 0.00732.0.6 * 0.0513 = 0.03078. Posterior Probability Mass Function of X: ____0.00732 if A = 1.0.____0.03078 if A = 1.5.

Explanation: The probability mass function for Poisson distribution is given by: P(X = x) = (e^-λ * λ^x) / x!Where,λ is the mean. The given prior probability mass function of A is P (A = 1.0) = 0.4P(A = 1.5) = 0.6.

Thus, the mean is either A = 1.0 or A = 1.5.

Now, let X be the number of defects on a roll of tape. Using the law of total probability, the probability mass function of X is P (X = x) = P (X = x, A = 1.0) + P (X = x, A = 1.5)

Using Bayes' theorem, the posterior probability mass function is given by: P (A = 1.0 | X = 4) = P (X = 4 | A = 1.0) * P (A = 1.0) / P (X = 4) P (A = 1.5 | X = 4) = P (X = 4 | A = 1.5) * P (A = 1.5) / P (X = 4)

Now, we need to calculate P (X = 4 | A = 1.0) and P (X = 4 | A = 1.5) using the Poisson distribution.

P (X = 4 | A = 1.0) = (e^-1 * 1^4) / 4! = 0.0183.P(X = 4 | A = 1.5) = (e^-1.5 * 1.5^4) / 4! = 0.0513.

Now, we need to calculate the value of the denominator,

P (X = 4). P (X = 4) = P (X = 4, A = 1.0) + P (X = 4, A = 1.5) = P (X = 4 | A = 1.0) * P (A = 1.0) + P (X = 4 | A = 1.5) * P (A = 1.5)

Put the values: P (X = 4) = (0.0183 * 0.4) + (0.0513 * 0.6) = 0.0342.

Put the values in the above posterior probability mass function equations,

we get: P (A = 1.0 | X = 4) = 0.00732 and P (A = 1.5 | X = 4) = 0.03078.

Therefore, the posterior probability mass function of X is:0.00732 if A = 1.0.0.03078 if A = 1.5.

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Answer: √113 or 10.63

Step-by-step explanation: the exact answer is √113, or 10.63 if you're looking for the decimal form

Step-by-step explanation:

Let the distance between two points A = (-4,7) and B = (4,0).

Here, x1 = -4 , y1 = 7

x2 = 4 , y2 = 0

Use the distance formula to find out the distance between two points are:

AB = √[(x2-x1)²+(y2-y1)²]

= √[{4-(-4)}²+(0-7)²]

= √[(4+4)²+(-7)²]

= √[(8)² + (-7)²]

= √[(8*8)+(-7*-7)]

= √[64+49]

= √[113] ⇛10.630 units approximately.

Answer:

20

Step-by-step explanation:

Answer:

$5.41

Step-by-step explanation:

654 divided by 120.99=5.405... therefore the answer is $5.41

The projection matrix P is [1/√11 -1/√337].

To find the projection matrix that projects vectors in ℝ³ onto the subspace W spanned by the vectors [3 1 1] and [15 11 -1], we can follow these steps:

Let's start by normalizing the basis vectors of W. Normalizing means dividing each vector by its magnitude to obtain unit vectors.

First basis vector:

u₁ = [3 1 1]

Normalize: v₁ = u₁ / ||u₁||

Compute the magnitude: ||u₁|| = √(3² + 1² + 1²) = √11

Normalize: v₁ = [3/√11, 1/√11, 1/√11]

Second basis vector:

u₂ = [15 11 -1]

Normalize: v₂ = u₂ / ||u₂||

Compute the magnitude: ||u₂|| = √(15² + 11² + (-1)²) = √337

Normalize: v₂ = [15/√337, 11/√337, -1/√337]

Next, we construct a matrix P using the normalized basis vectors as columns.

P = [v₁ v₂]

P = [3/√11 15/√337]

[1/√11 11/√337]

[1/√11 -1/√337]

Therefore, the projection matrix P that projects vectors in ℝ³ onto the subspace W spanned by the vectors [3 1 1] and [15 11 -1] is:

P = [3/√11 15/√337]

[1/√11 11/√337]

[1/√11 -1/√337]

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Answer:

i think its c hope it helps

Step-by-step explanation:

Answer:

600 cm²

Step-by-step explanation:

The shaded area (A) is calculated as

A = area of square - ( area of 3 unshaded triangles )

area of square = 40 × 40 = 1600 cm²

area of lower right triangle = [tex]\frac{1}{2}[/tex] × 20 × 40 = 10 × 40 = 400 cm²

area of upper left triangle = [tex]\frac{1}{2}[/tex] × 40 × 20 = 20 × 20 = 400 cm²

area of lower left triangle = [tex]\frac{1}{2}[/tex] × 20 × 20 = 10 × 20 = 200 cm²

Then

A = 1600 - (400 + 400 + 200 ) = 1600 - 1000 = 600 cm²

Answer: D, i am a hight school teacher names miss smell my butt, and i know that i am right

Answer:

D) 2,4

Step-by-step explanation:

The only answer with positive numbers

Answer:

D) 2,4

Step-by-step explanation:

To test the given hypothesis, where the null hypothesis (H_ọ) states that the population mean (µ) is equal to 190, and the alternative hypothesis (H_A) states that µ is greater than 190, a one-tailed test should be performed.

Given that the sample mean (X) is 186, the sample standard deviation (s) is 22, and the sample size (n) is 14, we can use the t-test for a single sample to test the hypothesis.

Calculate the test statistic:

t = (X - µ) / (s / √n)

t = (186 - 190) / (22 / √14)

t ≈ -0.8182

Determine the critical value for the given significance level and degrees of freedom.

Since the alternative hypothesis is one-tailed (µ > 190), we need to find the critical value corresponding to the desired significance level (α). Let's assume a significance level of α = 0.05 and degrees of freedom (df) = n - 1 = 14 - 1 = 13. Using a t-distribution table or calculator, the critical value for a one-tailed test at α = 0.05 and df = 13 is approximately 1.771.

Compare the test statistic to the critical value:

If the test statistic is greater than the critical value, we reject the null hypothesis. Otherwise, we fail to reject the null hypothesis.

Since -0.8182 is less than 1.771, we fail to reject the null hypothesis.

Therefore, based on the given sample, assuming a normal population, and performing a one-tailed test at α = 0.05, we fail to reject the null hypothesis (H_ọ: µ = 190) in favor of the alternative hypothesis (H_A: μ > 190).

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the correct answer is X= -3

Answer:

26 per week

Step-by-step explanation:

Among the pairs of events A&B, A&C, A&D, B&C, B&D, and C&D, the pairs A&C and B&D satisfy the condition P(A∩B) = P(A) × P(B), indicating that they are independent events.

To determine if two events are independent, we compare the product of their individual probabilities to the probability of their intersection. If the product of the individual probabilities is equal to the probability of the intersection, then the events are independent.

Let's examine each pair of events:

A&B: Rolling a double and getting a sum of even scores are not independent events. The occurrence of one event does not guarantee the occurrence of the other.

A&C: Rolling a double and having the score on the blue die greater than the score on the red die are independent events. The probability of rolling a double is solely dependent on the outcome of the dice roll, while the probability of the blue die having a greater score than the red die is independent of the outcome of rolling a double.

A&D: Rolling a double and getting a 6 on the red die are not independent events. The occurrence of rolling a double does not affect the probability of getting a 6 on the red die.

B&C: Getting a sum of even scores and having the score on the blue die greater than the score on the red die are not independent events. The occurrence of one event does not guarantee the occurrence of the other.

B&D: Getting a sum of even scores and getting a 6 on the red die are independent events. The probability of getting a sum of even scores is solely dependent on the outcome of the dice roll, while the probability of getting a 6 on the red die is independent of the sum of the scores.

C&D: Having the score on the blue die greater than the score on the red die and getting a 6 on the red die are not independent events. The occurrence of one event does not guarantee the occurrence of the other.

In summary, the pairs of events A&C and B&D are the only pairs that satisfy the condition P(A∩B) = P(A) × P(B), indicating that they are independent events.

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Answer:

6.

m1 : 61

m2 : 61

m3 : 29

7.

m1 : 87

m2 : 45

m3 : 45

m4 : 52

The exponential distribution applies to the lifetimes of a certain component. Its failure rate is unknown. The probability that the component will survive the past 5 years assumes:

(a) lambda=.5

Pr= 0.082

(b) lambda=0.9

Pr= 0.082

(c) lambda=1.1

Pr= 0.036

In the exponential distribution, the failure rate is a degree of the way fast the factor is expected to fail. It is regularly denoted through the parameter lambda (λ).

The opportunity that a thing will continue to exist beyond a positive time may be calculated using the exponential survival function, which is given by:

[tex]Pr(X > t) = e^(-λt)[/tex]

where X represents the random variable denoting the life of the thing, t is the specific time, and e is the bottom of the herbal logarithm.

Now let's calculate the possibilities for each case:

(a) lambda = 0.5, t = 5

Pr(X > 5) = [tex]e^(-0.5 * 5)[/tex] ≈ 0.082

In this example, with a lambda of 0.5, the element has a notably low failure price. The opportunity of the thing surviving beyond 5 years is about 0.082, or 8.2%.

(b) lambda = 0.9, t =5

Pr(X > 5) = [tex]e^(-0.9 * 5)[/tex] ≈ 0.082

With a lambda of 0.9, the issue has a slightly higher failure rate as compared to the previous case. The probability of the aspect surviving beyond 5 years stays at about 0.082, or 8.2%.

(c) lambda = 1.1, t = 5

Pr(X > five) = [tex]e^(-1.1 * 5)[/tex]≈ 0.036

In this situation, with a lambda of one.1, the factor has a better failure fee. The possibility of the element surviving beyond 5 years decreases to approximately 0.036, or 3.6%.

In precis, the possibility of a component surviving the past five years in an exponential distribution relies upon the failure price parameter lambda.

A lower failure price ends in a higher chance of survival, at the same time as a higher failure price decreases the opportunity of survival. It is essential to don't forget these chances when assessing the reliability and toughness of additives in diverse packages.

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[tex]c_0 = 9, c_1 = 2(9^2), c_2 = 3(9^3), c_3 = 4(9^4)[/tex]and [tex]c_4 = 5(9^5)[/tex]. The radius of convergence R is infinity.

To find the coefficients of the power series representation of the function f(x) = 5/(1 - 9x)², we can expand the function using the geometric series formula. The formula states that for |x| < 1, we have:

1/(1 - 9x) = 1 + 9x + (9x)² + (9x)³ + ...

Now, let's differentiate both sides of the equation with respect to x:

d/dx [1/(1 - 9x)] = d/dx [1 + 9x + (9x)² + (9x)³ + ...]

To differentiate the left side, we can use the power rule:

d/dx [1/(1 - 9x)] = (1 - 9x)⁻²

To differentiate the right side, we differentiate each term individually. Since the derivative of x^n with respect to x is nxⁿ⁻¹, the terms with powers of x become:

d/dx [1 + 9x + (9x)² + (9x)³ + ...] = 0 + 9 + 2(9²)x + 3(9³)x² + ...

Equating the derivatives, we have:

(1 - 9x)⁻² = 9 + 2(9²)x + 3(9³)x² + ...

To obtain the coefficients of the power series representation, we compare the terms on both sides of the equation. Since the expression on the right side is already in the desired form, we can read off the coefficients as follows:

[tex]c_0 = 9\\c_1 = 2(9^2)\\c_2 = 3(9^3)\\c_3 = 4(9^4)\\c_4 = 5(9^5)[/tex]

Now, let's find the radius of convergence R of the series. The radius of convergence can be determined using the ratio test. The ratio test states that if the limit of |[tex]c_{n+1} / c_n[/tex]| as n approaches infinity is L, then the series converges if L < 1 and diverges if L > 1.

Applying the ratio test to our series, we have:

|[tex]c_{n+1} / c_n[/tex]| = |[(n+1)(9ⁿ⁺¹)] / [n(9ⁿ)]| = 9((n+1)/n)

Taking the limit as n approaches infinity, we get:

lim(n->∞) |[tex]c_{n+1}/ c_n[/tex]| = lim(n->∞) 9((n+1)/n) = 9

Since the limit is 9, which is less than 1, the series converges for all values of x within a radius of convergence R. Therefore, the radius of convergence R is infinity (R = ∞).

Therefore,[tex]c_0 = 9, c_1 = 2(9^2), c_2 = 3(9^3), c_3 = 4(9^4)[/tex]and [tex]c_4 = 5(9^5)[/tex]. The radius of convergence R is infinity.

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Answer:

90[tex]\pi[/tex]

Step-by-step explanation:

if you want explanation say in comments

Answer:

175 dollars

Step-by-step explanation:

from that word problem the equation that i was able to get out of it was

1225/ 7

^ the travel allowance and how much days they are going to be there

i dont know if you are allowed to use a calculator in your class but puting 1225/ 7 does give you a answer of a positive number of 175 dollars

meaning that they can only use 175 dollars a day so they dont go over the allowance

i hope this helps you! please stay safe and have a good day :)

Answer:

Um, the answer for that is 175.

Step-by-step explanation:

all you need to do is divide $1,225 by 7 which is 175.

Answer:  x = 10

Step-by-step explanation:

The sum of interior angles in a triangle is equal to 180°.

(2x + 3) + (5x + 17) + 90 = 180

2x + 3 + 5x + 17 + 90 = 180

7x + 110 = 180

7x = 70

x = 10

Answer:

x = - 8, y = 2

Step-by-step explanation:

[tex]x = - 4y......(1) \\ x + 5y = 2....(2) \\ plug \: x = - 4y \: in \: equation \: (2) \\ - 4y + 5y = 2 \\ y = 2 \\ plug \: y = 2 \: in \: equation \: (1) \\ x = - 4(2) \\ x = - 8\\[/tex]

Answer:

226.19 inches

Step-by-step explanation:

Answer:

the transfer of energy from one organism to another

Step-by-step explanation:

Answer:

235.5 cubic feet

Step-by-step explanation:

The volume v of a circular cylinder whose base radius is r and height h is given as

v = πr^2h

where π is 22/7 or 3.14

Given that the radius is five feet and the height  is three feet

the volume v = 3.14 *5^2 * 3

= 235.5 cubic feet

The volume of the oblique circular cylinder is 235.5 cubic feet

Answer:

7z

Step-by-step explanation:

Answer: 7z

Step-by-step explanation:

two negatives cancel into a positive, so -(-3z) is +3z. 4z + 3z = 7z