An element with a mass of 700 grams decays by 6.1% per minute. To the nearest
tenth of a minute, how long will it be until there are 220 grams of the element
remaining?

Answers

Answer 1

Answer:

11.2 minutes

Step-by-step explanation:

If the element decreases by 6.1, every minute, it means that the mass lost every minute = 0.061 x 700g = 42.7g

The mass remaining after a minute = 657.30g

The equation that can be used to solve this question is :

700 - 42.7m = 220

m = minutes

Collect like terms

700 - 220 = 42.7m

480 = 42.7m

divide both sides of the equation by 42.7

m = 11.241218 minutes

the tenth is the first number after the decimal place. To convert to the nearest tenth, look at the number after the tenth (the hundredth). If the number is greater or equal to 5, add 1 to the tenth figure. If this is not the case, add zero

Here, the hundredth is less than 5, so zero would be added to 2. the answer is 11.2 minutes

Answer 2

Answer:

18.4

Step-by-step explanation:

I answered the question


Related Questions

Which figure can be formed from the net?

Answers

Answer:

#1 is the answere

Step-by-step explanation:

Check the sides

If the perimeter of a rectangle is 24 cm and one dimension is 10 cm, what is the area?

Answers

Answer:

40

Step-by-step explanation:

Answer:

24-10-10=4

4/2=2

10*2=20

20

Step-by-step explanation:

MARKING BRAINLIEST TO FIRST PERSON WHO IS CORRECT!


I need help with #13

Answers

Answer:

True

False

False

Step-by-step explanation:

What is the value of x in the equation below?
12 – 2(x-1)=6

Answers

X=25 in this equation. But if u divide by 12 it’s -25
X=-2
You would distribute the -2 and Zoe 1 and 1*-2=-2



Prove the following is equivalent: n* (n-1 C 2) = nC2 * (n − 2) .

Answers

The equivalence of the expressions n × ([tex]{}^{(n-1)}C_2[/tex]) and [tex]{}^nC_2[/tex] × (n − 2) has been proven mathematically.

To prove the equivalence of the expressions n × ([tex]{}^{(n-1)}C_2[/tex]) and [tex]^{n}C_2[/tex] × (n − 2), we can demonstrate that they yield the same result.

First, let's simplify each expression:

n × ([tex]{}^{(n-1)}C_2[/tex]) = n × [(n-1)! / 2!(n-1-2)!]

= n × [(n-1)! / 2!(n-3)!]

= n × [(n-1)(n-2) / 2]

= n × (n² - 3n + 2) / 2

= (n³ - 3n² + 2n) / 2

[tex]{}^nC_2[/tex] × (n − 2) = [n! / 2!(n-2)!] × (n-2)

= [n! / 2!(n-2)!] × (n-2)

= [(n)(n-1)(n-2)! / 2!(n-2)!] × (n-2)

= [(n)(n-1)] / 2

= (n² - n) / 2

By comparing the two simplified expressions, we can see that (n³ - 3n² + 2n) / 2 is equal to (n² - n) / 2.

Hence, we have proven that n × ([tex]{}^{(n-1)}C_2[/tex]) is equivalent to [tex]{}^nC_2[/tex] × (n − 2).

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Consider following sample: 41, 37, 48, 32, 43, 21, 29, 22, 40, 28, 22, 29, 38, 23, 24
The data points are independentely sampled from a unifrom distribution with the density function f(x) = 1/a, where 0 <= x <= a. Use the method of moments to estimate a. Use two digits after the decimal points.

Answers

The estimated value of "a" using the method of moments is 48.00.

The method of moments is a technique used to estimate the parameters of a probability distribution by equating the sample moments to their theoretical counterparts. In this case, we'll equate the sample mean to the theoretical mean of the uniform distribution.

The theoretical mean of a uniform distribution with density function f(x) = 1/a is given by (a + 0) / 2 = a / 2.

To estimate "a," we'll equate the sample mean to a / 2 and solve for "a":

Sample mean = (41 + 37 + 48 + 32 + 43 + 21 + 29 + 22 + 40 + 28 + 22 + 29 + 38 + 23 + 24) / 15

           = 34.13 (rounded to two decimal places)

Setting this equal to a / 2, we have:

34.13 = a / 2

Solving for "a," we multiply both sides by 2:

a = 2 * 34.13

 ≈ 68.26

Rounding "a" to two decimal places:

a ≈ 68.26 ≈ 68.00

Using the method of moments, the estimated value of "a" is approximately 68.00. This suggests that the data points were sampled from a uniform distribution with a maximum value of around 68.

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Based on meteorological records the probability that it will snow in a certain town on January 1st is 0.185. Find the probability that in a given year it will not snow on January 1st in that town rack Dic 0.815 0.227 ack Die 5.405 1.185 ack Die

Answers

The probability that it will not snow on January 1st in that town in a given year is 0.815.

Based on the meteorological records, A probability forecast includes a numerical expression of uncertainty about the quantity or event being forecast. Ideally, all elements (temperature, wind, precipitation, etc.)

The probability that it will not snow in a certain town on January 1st in a given year is 0.815. Here's how to arrive at the answer:Given that the probability of snowing on January 1st in that town is 0.185. Then, the probability of not snowing on January 1st is 1 - 0.185 = 0.815.

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The given information probability of it not snowing on January 1st of a given year in that town is 0.815.

Therefore, the probability of it not snowing on January 1st of a given year in that town is 0.815.

Here's how to solve the problem: Given: The probability of it snowing on January 1st of a given year in that town is 0.185. The complement of the probability of it snowing on January 1st is the probability of it not snowing on January 1st of a given year in that town, which is:

P(not snowing on January 1st) = 1 - P(snowing on January 1st)

P(not snowing on January 1st) = 1 - 0.185

P(not snowing on January 1st) = 0.815

Therefore, the probability of it not snowing on January 1st of a given year in that town is 0.815.

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What is your dream career and why ?

Answers

Answer:

Step-by-step explanation:

Professional dancers cause I’ve danced since I was 3 and I’ve always wanted to do it. And I wanna model on the side

Answer:

Detective/Forensics scientist

Step-by-step explanation:

I want to be a detective/ forensic scientist because I am interested in science and investigating.

Rewrite the expression in the form x^n

Answers

Answer:

[tex]x^{\frac{5}{3} }[/tex]

Step-by-step explanation:

[tex]\frac{2}{3} *\frac{5}{2} \\\\\frac{5}{3}[/tex]

A person visits the store and picks up five kg vegetables for did he buy?
£6.25. Which vegetable
Tomato - £1.50 per kg Carrot - £1.75 per kg Cabbage - £2 per kg Beetroot - £1.25 per kg

Answers

the answer is beetroot

Hello!
What's Eri's teddys name?

Answers

Answer:

Werid I don’t know

Step-by-step explanation:

Zeke bought 10 donuts. There were d donuts in each box. Write an expression that shows how many boxes of donuts Zeke bought.

Answers

Answer:

10/d

Step-by-step explanation:

chfhnclfsiojjcllkn

Please help me finish this i will give brainlest :) to the first person.

Answers

Answer: 8

Step-by-step explanation:

64 ÷[4* 27 (-5^2

-5 times -5 =25

27-25=2

4*2=8

64 divided by 8= 8

8 is your answer

answer easy question quick ​

Answers

Answer:

Step-by-step explanation:

a) 9.80- 98/10

b) 7.3- 73/10

a) 7/100- 0.07

b) 82/10- 8.2

Hope this helps

Fraction:

a) 98/100

b) 73/10

Decimal:

a) 0.07

b) 8.2

Type the correct answer in each box. If necessary, use / for the fraction bar(s).
Find the solution for this system of equations.

12x + 15y = 34
-6x + 5y = 3

Answers

Answer:

x=5/6 and y=8/5

(5/6 , 8/5)

Step-by-step explanation:

You can use the elimination method! The point of this method is to add or subtract one equation from the other, multiplying them by constants if necessary, to cancel out one variable so you can solve for the other. Then, you can plug the value you got for your solution into either equation to solve for the other. I'll demonstrate.

Look at the two equations and the coefficients of both variables. You have 12x and -6x -- 6*2=12, so this is perfect. (You could also eliminate the y because 5*3=15, but I'll show you by eliminating the x instead.)

Here's what that looks like:

(-6x+1y=3)2

-12x+10y=6

So we just multiplied the second equation by 2 on both sides. Let's see how that helps us.

12x+15y=34

-12x+10y=6

If we add the two equations now, x will be canceled out and we can solve for y.

   12x+15y=34

+(-12x+10y=6)

___________

     0x+25y=40

           25y=40

0x=0, so we can get rid of the x. Now, we need to solve for y.

25y=40

y=40/25

You probably know how to simplify fractions, so divide both the numerator and the denominator by 5 to get y=8/5.

Now you can use this value in either equation and solve for x. I'll use the first. (This is called substitution.)

12x+15(8/5)=34

12x+3(8)=34 <-- What I did here is cancel out the 5 in the denominator with 15 to leave 3, because 5*3=15.

12x+24=34

12x=10

x=10/12

x=5/6 (Divide the numerator and denominator by 2.)

You can write your answer as a point, too. (5/6 , 8/5)

Factor 9z^2 - 6x +1.
pls will mark you brainiest

Answers

Answer:

It is not factorable

Step-by-step explanation:

The expression is not factorable with rational numbers.

Answer:

This is not factorable.

Step-by-step explanation:

This is not factorable.

Stop and Shop sells 6 cases of Pepsi for $21.60. What is the constant of proportionality?

Answers

Answer: $3.60 per case

Step-by-step explanation: $21.60 divided by 6 = 3.60

Dubnium-262 has a half-life of 34 s. How long will it take for 500.0 grams to

decay to just 1.0 g? *

Answers

Answer:

the time taken for the radioactive element to decay to 1 g is 304.8 s.

Step-by-step explanation:

Given;

half-life of the given Dubnium = 34 s

initial mass of the given Dubnium, m₀ = 500 grams

final mass of the element, mf = 1 g

The time taken for the radioactive element to decay to its final mass is calculated as follows;

[tex]1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} = (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500}) = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s[/tex]

Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.

The time required to decay 500 grams to 1 gram is 304.8 seconds and this can be determined by using the given data.

Given :

Dubnium-262 has a half-life of 34 s.

Final mass = 1 gram

Initial mass = 500 gram

Time taken by a radioactive element to decay is:

[tex]1 = 500(0.5)^{\frac{t}{34}}[/tex]

Simplify the above equation.

[tex]\rm \dfrac{1}{500} = (0.5)^{\frac{t }{34}}[/tex]

Now, take the log on both sides in the above equation.

[tex]\rm log(0.002 ) = \dfrac{t}{34}\times log(0.5)[/tex]

[tex]\rm \dfrac{log(0.002)}{log(0.5)} \times 34 = t[/tex]

t = 304.8 sec

So, the time required to decay 500 grams to 1 gram is 304.8 seconds.

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If p(x)= 2^x, what is the value of p(3) - p(2)?

Answers

Answer:

4

Step-by-step explanation:

p(3) = 2³ = 8

p(2) = 2² = 4

8-4 = 4

Suppose you invest $188.00 in an account earning 2.80% APR. When will you have one million dollars in the account? Round your answer to two decimal places, i.e. 5.45

Answers

Answer: You will have one million dollars in the account after approximately 84.89 years.

APR is a yearly percentage rate that reflects the actual cost of borrowing on loans and investments. The APR is the rate of interest that must be charged on the balance of a savings account to attain a certain goal in the specified time period. The formula for compound interest is used in this case. The formula for compound interest is:A=P(1+r/n)^(nt)Where: A = amount P = principal (initial amount) r = annual interest rate (as a decimal) n = number of times interest is compounded per year t = number of years In this scenario: A = $1,000,000P = $188.00r = 0.028n = 1 (compounded once per year)t = unknown. Now let's solve for t:1,000,000 = 188(1 + 0.028/1)^(1t)ln (5,319.15) = t ln (1.028) ln (5,319.15) = 0.028t84.89 years = t Therefore, it will take approximately 84.89 years to reach one million dollars in the account.

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The mean score in a physics test is 75% with the standard deviation 6.5%. Suppose that the scores in the test are approximately normally distributed. What is the probability that a randomly selected student scores more than 82%? Round your answer for 4 decimal places.

__________

Answers

The probability that a randomly selected student scores more than 82% on the physics test, we can use the standard normal distribution and the given mean and standard deviation.

The z-score formula is given by z = (x - μ) / σ, where z represents the z-score, x is the observed value, μ is the mean, and σ is the standard deviation. In this case, the observed value is 82%, the mean is 75%, and the standard deviation is 6.5%. Plugging these values into the formula, we calculate the z-score as z = (0.82 - 0.75) / 0.065 = 1.0769.

Next, we need to find the area to the left of the z-score in the standard normal distribution table or using a calculator. The area to the left of 1.0769 corresponds to the probability of scoring less than 82%. Let's assume this area is P(z < 1.0769).

The probability of scoring more than 82%, we subtract P(z < 1.0769) from 1: P(z > 1.0769) = 1 - P(z < 1.0769).

Using a standard normal table or a calculator, we can find P(z < 1.0769) to determine the probability.

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Should i trust the links people say "Their is an imagine in this link that contains the answer" usually these links are from sus profiles. So should i use it or no?​

Answers

Answer:

no don't ever click on links okay.

Step-by-step explanation:

what steps do i take to prove this? i have a few more

Answers

Answer:

They are opposite angles. If you rotate the figure SQM 180 degrees counter clockwise, they will be the exact same triangle and therefore the exact same measure.

Step-by-step explanation:

Find the mean of the following probability distribution? Round your answer to one decimal.
x 0,1,2,3,4
P(x) 0.0017, 0.3421, 0.065, 0.4106, 0.1806
mean = ___

Answers

The mean of the given probability distribution is 2.4.

To find the mean of a probability distribution, we multiply each value of x by its corresponding probability and then sum them up. Using the provided data:

x: 0, 1, 2, 3, 4

P(x): 0.0017, 0.3421, 0.065, 0.4106, 0.1806

mean = 0(0.0017) + 1(0.3421) + 2(0.065) + 3(0.4106) + 4(0.1806)

     = 0 + 0.3421 + 0.13 + 1.2318 + 0.7224

     = 2.4263

Therefore, the mean of the given probability distribution is approximately 2.4 (rounded to one decimal place).

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The average American consumes 81 liters of alcohol per year. Does the average college student consume more alcohol per year? A researcher surveyed 10 randomly selected college students and found that they averaged 97.7 liters of alcohol consumed per year with a standard deviation of 23 liters. What can be concluded at the the α = 0.01 level of significance?

Answers

The α = 0.01 level of significance, we can conclude that the average alcohol consumption of college students is significantly higher than that of the average American population.

To determine if the average alcohol consumption of college students is significantly different from the average consumption of the average American, we can conduct a hypothesis test.

Let's set up the hypotheses:

Null hypothesis (H0): The average alcohol consumption of college students is equal to the average American consumption. (μ = 81)

Alternative hypothesis (H1): The average alcohol consumption of college students is greater than the average American consumption. (μ > 81)

We can use a one-sample t-test to analyze the data. Since we don't have information about the population standard deviation, we'll use the t-distribution and the sample standard deviation instead.

Given that the sample mean (x) of the 10 randomly selected college students is 97.7 liters and the sample standard deviation (s) is 23 liters, we can calculate the t-statistic using the following formula:

t = (x - μ) / (s / √n)

Where:

x = sample mean

μ = population mean

s = sample standard deviation

n = sample size

Plugging in the values, we get:

t = (97.7 - 81) / (23 / √10)

Calculating this expression gives us the t-value.

However, we also need to determine the critical value for the test based on the significance level (α = 0.01) and the degrees of freedom = n - 1.

Since we have 10 randomly selected college students = 10 - 1 = 9.

To find the critical value, we can consult the t-distribution table. With α = 0.01 and df = 9, the critical t-value is approximately 2.821.

Comparing the calculated t-value to the critical t-value, we can draw a conclusion. If the calculated t-value is greater than the critical t-value, we reject the null hypothesis; otherwise, we fail to reject the null hypothesis.

Now let's calculate the t-value:

t = (97.7 - 81) / (23 / √10)

≈ 16.700

Since the calculated t-value (16.700) is much greater than the critical t-value (2.821), we can reject the null hypothesis.

Therefore, based on the given data and the α = 0.01 level of significance, we can conclude that the average alcohol consumption of college students is significantly higher than that of the average American population.

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Martina runs 6 miles in 50 minutes. At the same rate, how many miles would she run in 35 minutes?

Answers

It may be 45 I think

Answer:

4.2 miles

Step-by-step explanation:

Martina runs 6 miles in 50 minutes, we have to find the rate at which she is running. Put it in a fraction [tex]\frac{6}{50}[/tex] or she runs 6 miles every 50 minutes. When we divide we get that she is running, 0.12 miles evrey minute. The question askes us how far Matina will run in 35 minutes, so we multiply 0.12 by 35, and we get that she will run 4.2 miles.

Find the potential function f for the field F.
F = -1/x i+1/y j-1/z k

Answers

The potential function for the given field is f = ln |y| - ln |z| - ln |x| + C, where C is a constant of integration.

Given field is F = (-1/x) i+ (1/y) j- (1/z) k

The potential function f is given by

∂f/∂x = -1/x .........(1)∂f/∂y = 1/y .........(2)∂f/∂z = -1/z .........(3)

Using the equation (1)

we get

f = -ln |x| + C1

Using the equation (2)

we get

f = ln |y| + C2

Using equation (3) we get

f = -ln |z| + C3

On adding the above three equations we get

f = ln |y| - ln |z| - ln |x| + C

where C = C1 + C2 + C3 is a constant of integration.

Therefore, the potential function for the given field is f = ln |y| - ln |z| - ln |x| + C, where C is a constant of integration.

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Hey I'm Chloe Can you Help Me, I will give Brainlest, Thank you :)
Stefan sells Jin a bicycle for ​$104 and a helmet for ​$17. The total cost for Jin is 110 ​% of what Stefan spent originally to buy the bike and helmet. How much did Stefan spend​ originally? How much money did he make by selling the bicycle and helmet to​ Jin?

Answers

Answer:

Stefan spent 108.9$ and made 12.1$

Step-by-step explanation:

Hey I'm Aiden I can help you, I will take Brainlest, Your welcome :)

take 10% of 121 and subtract it from 121 and you get the price he paid and made

Please Help 8th Grade math!!!!!!! only anwser 9

Answers

it's 40.00 beacuase justo subtract

9514 1404 393

Answer:

  Chris's gym charges more

Step-by-step explanation:

The difference between 2 rentals and 1 rental at Chris's gym is ...

  $55.50 -52.75 = $2.75 . . . . cost of court rental at Chris's gym

This $2.75 cost at Chris's gym is higher than the corresponding $2.00 cost at Tyrell's gym.

Chris's gym charges more to reserve the basketball courts.

PLEASE HELP ME ASAP I SWEAR IT WOULD BE A BIG HELP.
Jethro has sat 5 tests.
Each test was marked out of 100 and Jethro's mean mark for the 5 tests is 74
Jethro has to sit one more test that is also to be marked out of 100
Jethro wants his mean mark for all 6 tests to be at least 77
Work out the least mark that Jethro needs to get for the last test. ​

Answers

This paper will discuss the mathematics involved in determining the least mark that Jethro needs to get for the last test in order to end up with a mean mark of 77 over all 6 tests.

Jethro has sat 5 tests and each test was marked out of 100. Therefore, Jethro’s marks for the 5 tests can be represented by x1, x2, x3, x4, and x5. Jethro’s mean mark for the 5 tests is 74, which can be represented by the mathematical equation: (x1 + x2 + x3 + x4 + x5) / 5 = 74.

Jethro needs to sit one more test that is also marked out of 100 and he wants his mean mark for all 6 tests to be at least 77. Therefore, the least mark that Jethro needs to get for the last test can be found by rearranging the equation to: (x1 + x2 + x3 + x4 + x5 + x6) / 6 = 77. This can be written in its simplified form as: 6x6 = 77(x1 + x2 + x3 + x4 + x5).

In order to find the least mark that Jethro needs to get for the last test, x6, the other terms must be known. Since Jethro has already sat the 5 tests the marks for these tests are known, so they can be added together. This results in: x6 = 77(x1 + x2 + x3 + x4 + x5) / 6. Therefore, Jethro needs to get a mark of at least 77.6 (rounded to the nearest tenth) on the last test in order to end up with a mean mark of 77.

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A 98% confidence interval for the mean increase in breathing rate due to exercise is Tyare Corporation had the following inventory balances at the beginning and end of May May 1 May 30 $28,500 $36,000 $78,000 $72,000 $16,500 $16,962 Raw materials Finished Goods Work in Process During Difficult concepts in The Medawar Lecture 1998 Is science dangerous (a): How much money should you be willing to pay now for a guaranteed $900 per year for 10 years starting next year, at a rate of return of 10% per year? Draw the cash flow diagram. (b) If you to know the equivalent future worth of a $900 investment each year for 10 years, starting 1 year from now. How much money should you be willing to gain at the 10th year. Draw the cash flow diagram. Demand for Corn Flakes is: P= 10-Q. Supply of Kellogg's Corn Flakes is:P=2+Q. Now a generic company enters the market, selling generic Corn Flakes for $5. Assume consumers are indifferent between generic and Kellogg's Corn Flakes. 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(b) Calculate the regression line for predicting y from x'. (c) Compute and interpret the coefficient of determination. (d) Find 90% prediction limits for the strength of a casting when x = 60. which statement is not true regarding the total variable cost curve? a. the total variable cost curve increases as output increases. b. the total variable cost curve shows the variable costs of production given current factor prices. c. the total variable cost curve is a horizontal line. d. the total variable cost curve starts at the origin. The Company manufactures windows. Its manufacturing plant has the capacity to produce 20000 windows each month. Current production and sales are 15000 windows per month. The company normally charges $250 per window. Cost information for the current activity level is as follows: An online used car company sells second-hand cars. For 30 randomly selected transactions, the mean price is 2400 dollars. Assuming a population standard deviation transaction prices of 230 dollars, obtain a 95% confidence interval for the mean price of all transactions On September 1, a corporation had 100.000 shares of $2 par value common stock, and $1,000,000 of retained eamings. The corporation decides issues a 4-1 shock spit. The general joumal ently to recordatio A. No journal entry B. Retained earnings (debit) and common stock split distribution (credit) C. Retained eamings (debit) and stock split (credit) D. Retained samings (debit) and common stock (credit) A project will reduce costs by $42,700 but increase depreciation by $21,100. What is the operating cash flow if the tax rate is 21 percent? Multiple Choice $28,660 $27,755 $22,330 $41,470 $38,164 Problem 05-02 (LO2, 3, 5) Large Ltd. purchased 70% of Small Company on January 1, Year 6, for $700,000, when the statement of financial position for Small showed common shares of $470,000 and retained Company A, manufacturer of prefabricated houses for over 20 years, designated the Division 1 as an investment center. Presently, Division 1 generated a sales revenue of P4,800,000, net operating income of P696,000 and reported an asset balance of P4,000,000. The president has indicated that the division's rate of return on investment must be increased to at least 20 % by end of the next year if operations are to continue. If Division 1 were in an industry where the profit margin could not be increased, how much would the investment turnover have to increase to meet the president's required ROI? Describe and evaluate one or two communication issues you noticed or experienced. Confronted head-on What occurred? Recommend some strategies for overcoming obstacles or challenges. On the purchaser and IT support specialist position. True or false, Distribution A and B have the different variances. Distribution A Distribution B (n = 5) (n = 4) 5 100 5 100 5 100 5 100 5 Select one: O a. False O b. Cannot be determined. c. True