A chemist has three different acid solutions,
The first solution contains 20 % acid, the second contains 35 % acid, and the third contains 55%
acid.
She created 108 liters of a 40 % acid mixture, using all three solutions. The number of liters of
55 % solution used is 3 times the number of liters of 35 % solution used.
How many liters of each solution was used?
The chemist used
liters of 20% solution,
liters of 35 % solution, and
liters of 55 % solution.
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Answers

Answer 1

9514 1404 393

Answer:

36 liters of 20%18 liters of 35%54 liters of 55%

Step-by-step explanation:

Let a, b, c represent the quantities of 20%, 35%, and 55% solutions, respectively. Then for the given mix, we have ...

  a + b + c = 108 . . . . . total number of liters

  .20a +.35b +.55c = 0.40·108 . . . . . liters of acid

  0a - 3b + c = 0 . . . . . 55% solution was 3 times 35% solution

__

Solving these three equations by your favorite method gives ...

  (a, b, c) = (36, 18, 54)

The chemist used 36 liters of 20%, 18 liters of 35%, and 54 liters of 55%.

_____

Comment on alternate approach

Since the ratio of 55% to 35% is 3 : 1, that mix will have an acid content of ...

  (3(.55) +1(.35))/4 = 0.50 = 50%

So, the final mix is equivalent to some quantity of 50% mix being added to some quantity of 20% mix. The fraction that is 50% mix* will be (40-20)/(50-20) = 2/3 of the total, or (2/3)(108 L) = 72 L.

Now we know that (1/3)(108 L) = 36 L of 20% solution is needed and (1/4)(72 L) = 18 L of 35% solution is needed. 3 times that is 54 L of 55% solution.

__

* After you work a few mixture problems, you can see the pattern. If we start with an equation for x = fraction of 50% to use with 20% to make 40%, we get ...

  x(50%) +(1 -x)(20%) = 40%

  x(50% -20%) = 40% -20% . . . . . subtract 1(20%) and factor out x

  x = (40% -20%)/(50% -20%)

The key here is to see where the numbers 20%, 40%, and 50% show up in the fraction.


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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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 [tex]\bold{Hello!}\\\bold{Your~Answer~Is~Below!}[/tex]

______________________________

 [tex]\bold{Solution~Steps:}[/tex]

[tex]1.)~54+3(1-1):[/tex]

[tex]\bold{Subtract~1~from~1~to~get~0.}[/tex][tex]\bold{Multiply~3~and~0~to~get~0.}[/tex][tex]\bold{Add~54~and~0~to~get~54.}[/tex]

[tex]2.)~54+3(2-1):[/tex]

[tex]\bold{Subtract~1~from~2~to~get~1.}[/tex][tex]\bold{Multiply~3~and~1~to~get~3.}[/tex][tex]\bold{Add~54~and~3~to~get~57.}[/tex]

[tex]3.)~54+3(3-1):[/tex]

[tex]\bold{Subtract~1~from~3~to~get~2.}[/tex][tex]\bold{Multiply~3~and~2~to~get~6.}[/tex][tex]\bold{Add~54~and~6~to~get~60.}[/tex]

[tex]4.)~54+3(4-1):[/tex]

[tex]\bold{Subtract~1~from~4~to~get~3.}[/tex][tex]\bold{Multiply~3~and~3~to~get~9.}[/tex][tex]\bold{Add~54~and~9~to~get~63.}[/tex]

______________________________

 [tex]\bold{Answers:}[/tex]

[tex]\bold{Term~1=\boxed{54}}[/tex][tex]\bold{Term~2=\boxed{57}}[/tex][tex]\bold{Term~3=\boxed{60}}[/tex][tex]\bold{Term~4=\boxed{63}}[/tex]

______________________________

 [tex]\bold{Hope~this~helps,}\\\bold{And~best~of~luck!}\\\\\bold{~~~~~~~-TotallyNotTrillex}[/tex]

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

ln

(

6

x

)

=

ln

(

66

)

Expand

ln

(

6

x

)

by moving

x

outside the logarithm.

x

ln

(

6

)

=

ln

(

66

)

Divide each term by

ln

(

6

)

and simplify.

Tap for more steps...

x

=

ln

(

66

)

ln

(

6

)

The result can be shown in multiple forms.

Exact Form:

x

=

ln

(

66

)

ln

(

6

)

Decimal Form:

x

=

2.33829083

Answer:

X=19

Step-by-step explanation:

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