If sin A=0.7986, then the measure of Đ A, to the nearest degree is?

Answer:

x= 12.942

Law of sines :)

The area of the circle is 452.16 cm², and the circumference is 75.36 cm.

To determine the area and circumference of a circle with a radius of 12 cm, we can use the formulas:

Area = π * r²

Circumference = 2 * π * r

The radius (r) is 12 cm, we can substitute this value into the formulas to find the area and circumference.

Area = π * (12 cm)²

      = π * 144 cm²

      ≈ 3.14 * 144 cm²

      ≈ 452.16 cm²

The area of the circle is approximately 452.16 square centimeters.

Circumference = 2 * π * 12 cm

                   = 2 * 3.14 * 12 cm

                   ≈ 75.36 cm

The circumference of the circle is approximately 75.36 centimeters.

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Answer:

x = 3/2

Step-by-step explanation:

Simplify this equation by dividing all three terms by 1/4:

2x - 1 = 2, or

2x  = 3

Then x = 3/2

Answer:

The integer that represents the change in temperature is 17.

Step-by-step explanation:

Answer:

i got a orange

Step-by-step explanation:

Answer:

100.00-0.22 is 99.78

U have to use decimal method. don't use Normal method

Answer:

सैम ने 9 पाउंड आटा बनाया

Step-by-step explanation:

The expression x^3 - 2x^2 - 8x + 16 can be factored as (x - 2)(x^2 - 8).

To factor the given expression x^3 - 2x^2 - 8x + 16, we can look for common factors or factor it using grouping. In this case, we can observe that the expression can be factored by grouping.

First, we can factor out a common factor of (x - 2) from the first two terms:

x^3 - 2x^2 - 8x + 16 = (x - 2)(x^2 - 8x - 8)

Now, we can further factor the quadratic expression (x^2 - 8x - 8) by factoring out a common factor of 8:

(x^2 - 8x - 8) = (x - 2)(x - 8)

Therefore, the complete factorization of the expression x^3 - 2x^2 - 8x + 16 is:

(x - 2)(x - 2)(x - 8) which can also be written as (x - 2)(x^2 - 8).

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Answer:

7. -4/5

8. 1

9. 0

10. 3/4

11. undefined/nonlinear

12. -9/4

13. parallel

Answer:

15.5769230769

Step-by-step explanation:

8×13 = 104

1620÷104 = 15.5769230769

Answer:

a). -8    b). 4/19

Step-by-step explanation:

F(x)= x²+9x       g(x)=1/x.

g(-1) = 1/ - 1

= -1

f(-1) = x²+9x

= -1² + 9(-1)

= 1 - 9

= -8

G(f(1/2))

f(1/2) = x²+9x

= 1/2² + 9(1/2)

= 1/4 + 9/2

= 19/4

g (19/4) = 1/x

= 1/19/4

= 4/19

Answer:

1). -8    2). 4/19

Step-by-step explanation:

F(x)= x²+9x       g(x)=1/x.

g(-1) = 1/ - 1

= -1

f(-1) = x²+9x

= -1² + 9(-1)

= 1 - 9

= -8

G(f(1/2))

f(1/2) = x²+9x

= 1/2² + 9(1/2)

= 1/4 + 9/2

= 19/4

g (19/4) = 1/x

= 1/19/4

= 4/19

The coordinates of the midpoint of the line segment GH with endpoints G(-3, 2) and H(3, -2) are (0, 0). The correct option is (C).

To determine the coordinates of the midpoint of the line segment GH with endpoints G(-3, 2) and H(3, -2), we can use the midpoint formula.

The midpoint formula states that the coordinates of the midpoint (M) are given by the average of the x-coordinates and the average of the y-coordinates of the endpoints.

Midpoint (M) = ((x1 + x2) / 2, (y1 + y2) / 2)

For GH, plugging in the coordinates, we have:

Midpoint (M) = ((-3 + 3) / 2, (2 + -2) / 2)

Midpoint (M) = (0, 0)

Therefore, the coordinates of the midpoint of GH are (0, 0), which corresponds to option c. (0, 0).

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x - 8 = 68

x - 8 + 8 = 68 + 8

x = 76

hope this helped

Answer:

The system has no solution.

Step-by-step explanation:

In order for the system to have a solution, both graphs must have an intercept to each others. We see in the picture that both graphs are parallel and do not have any interceptions which we don't know the solution to the system.

That means if graphs are parallel and have no interceptions, there are no solutions. The system of equations are for finding the interceptions of both graphs. But of course! Parallel lines do not intercept.

If you have any questions, feel free to ask.

Answer:

Area of the circle = 572.3 square ft.

Step-by-step explanation:

Area of a circle is given by the formula,

Area of a circle = πr²

Here 'r' = Radius of the circle

Diameter of circle given in the picture = 27 ft

Radius of the circle = [tex]\frac{27}{2}[/tex]

                                = 13.5 ft

Area of the circle = π(13.5)²

                             = 3.14(13.5)²

                             = 572.265

                             ≈ 572.3 square ft

Answer:

Step-by-step explanation:

Answer:

the first one

Step-by-step explanation:

the first one

Answer:220

Step-by-step explanation:

LET X BE THE LENGTH OF RECTANGLE AND FOR UPPER PORTION OF DIA GRAM BASE OF RIGHT ANGLE TRIANGLE SO X=20

LET Y BE WIDTH OF RECTANGLE SO Y=8

LET P BE THE PERPENDICULAR OF THE RIGHT TRIANGLE SO P=6

THEN

AREA OF RECTANGLE=LENGTH*WIDTH

SO AREA OF RECTANGLE BECOMES=(20)(8)=160

AND AREA OF RIGHT ANGLE TRIANGLE BECOMES=1/2(BASE*(PERPENDICULAR)

SO =1/2(20)(6)=60

SO THE TOTAL AREA OF THE DIAGRAM=AREA OF RIGHT ANGLE TRIANGLE+AREA OF RECTANGLE=160+60=220

a) The cumulative distribution function for X is F(x) = 1 – exp(-x²)

is = 1 – exp(-x²)

b) P(X ≤ 2) = 0.865

c) Generate a uniformly distributed random number u between 0 and 1.

a) We have given a probability density function f(x) = 2x exp(-x²), x ≥ 0

To find the cumulative distribution function (CDF), we integrate the probability density function (PDF) from negative infinity to x as follows;

∫f(x)dx = ∫2x exp(-x²)dx

Using u =

-x², du/dx = -2x

dx = -du/2∫2x exp(-x²)dx

= -∫exp(u)du

= -exp(u) + C

= -exp(-x²) + C

We know that, F(x) = ∫f(x)dx.

From the above calculation, the CDF of X is given by;

F(x) = 1 – exp(-x²)

b)

We are to calculate P(X ≤ 2)

We know that F(2) = 1 – exp(-2²)

= 0.865

Therefore, P(X ≤ 2) = 0.865

c)

The inversion method is a way of generating random values of a random variable X using the inverse of the cumulative distribution function of X, denoted as F⁻¹(u),

where u is a uniformly distributed random number between 0 and 1.

The steps for generating a random value of X using the inversion method are:

Generate a uniformly distributed random number u between 0 and 1.

Find the inverse of the cumulative distribution function, F⁻¹(u).

This gives us the value of X.

d)

R command for one random value of X by using the inversion method```{r}

# setting seed to be 100 sets. seed(100)

# defining the inverse CDFF_inv = function(u) q norm(u, lower.tail=FALSE)

# generating a random value of Uu = run if(1)

# calculating the corresponding value of Xx = F_inv(u)```

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Answer:

9√2

Step-by-step explanation:

To do this, we need to use the Pythagoras' Theorem. Which is a^2+b^2=c^2

In this case, we need to solve for C. So, we do 9^2 (A) +9^2 (B), assuming a and b are the same. So we end up with 81+81=c^2. Now, we find the square root of 162. Around 13 or 9√2

:] i honestly have no clue my self

To find the change-of-coordinates matrix from basis B to the standard basis, we need to express the standard basis vectors as linear combinations of the vectors in B. Then, to write t^2 as a linear combination of the polynomials in B, we can use the change-of-coordinates matrix to transform t^2 into the coordinates with respect to B.

To find the change-of-coordinates matrix from basis B to the standard basis, we express the standard basis vectors as linear combinations of the vectors in B. Let's denote the standard basis vectors as e1, e2, and e3. We can write:

e1 = 1(1 - 7t^2) + 0(-6 + t + 43t^2) + 0(1 + 6t)

e2 = 0(1 - 7t^2) + 1(-6 + t + 43t^2) + 0(1 + 6t)

e3 = 0(1 - 7t^2) + 0(-6 + t + 43t^2) + 1(1 + 6t)

The coefficients in these equations give us the entries of the change-of-coordinates matrix.

To write t^2 as a linear combination of the polynomials in B, we can use the change-of-coordinates matrix. Let [t^2]_B represent the coordinates of t^2 with respect to B. Then, [t^2]_B = C[t^2]_std, where C is the change-of-coordinates matrix. We can solve this equation to find [t^2]_B.

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The equation that represents the sentence "28 is the quotient of a number and 4" is 28 = n/4.

In the given sentence, "28 is the quotient of a number and 4," we can break down the sentence into mathematical terms. The term "quotient" refers to the result of division, and "a number" can be represented by the variable "n." The divisor is 4.

1) Define the variable.

Let's assign the variable "n" to represent "a number."

2) Write the equation.

Since the sentence states that "28 is the quotient of a number and 4," we can write this as an equation: 28 = n/4.

The equation 28 = n/4 represents the fact that the number 28 is the result of dividing "a number" (n) by 4. The left side of the equation represents 28, and the right side represents "a number" divided by 4.

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Answer: B

Step-by-step explanation:

I know I’m late :(

Answer:

12

Step-by-step explanation:

Through 12 years  he would have painted 72 paintings and since he hasn't sold two of them he has only sold 70.

Use the rslash() function in R Studio to generate a random sample of size 100 from the Slash distribution.

To generate a random sample of size 100 from the Slash distribution without using extra packages in R Studio, you can use the inverse transform method. The Slash distribution is a continuous probability distribution with a density function given by f(x) = 1 / (π(1 + x^2)).

First, generate a random sample of size 100 from a uniform distribution on the interval [0, 1]. Then, transform the uniform random numbers using the inverse cumulative distribution function (CDF) of the Slash distribution, which is given by F^(-1)(x) = tan(π(x - 0.5)). This will map the uniform random numbers to the corresponding values from the Slash distribution.

In R Studio, you can use the following code to generate the random sample:

# Set seed for reproducibility

set.seed(42)

# Generate uniform random sample

uniform_sample <- runif(100)

# Transform uniform random sample to Slash distribution

slash_sample <- tan(pi * (uniform_sample - 0.5))

The slash_sample variable will contain the generated random sample of size 100 from the Slash distribution.

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Answer:

40 cm²

Step-by-step explanation:

A = 1/2bh

A = 1/2 (8) (10)

A = (4) (10)

A = 40

The degree of the extension [K: F] ≤ p.

Suppose K = F_p(t) has transcendence degree n over F_p.

Then K is an algebraic extension of F_p(t^p).

(a) We need to find a polynomial of degree p in F[x] for which t is a root.

In F_p, we have t^p - t ≡ 0 (mod p).

So, we can write t^p ≡ t (mod p).

Since F_p[t] is a polynomial ring over F_p, we have t^p - t ∈ F_p[t] is an irreducible polynomial.

Hence the degree of the extension [K: F] ≤ p.

Suppose K = F_p(t) has transcendence degree n over F_p.

Then K is an algebraic extension of F_p(t^p).

The minimal polynomial of t over F_p(t^p) is x^p - t^p. Thus, [K: F_p(t^p)] ≤ p.

Since K/F_p is an algebraic extension, we have [K: F_p] = [K: F_p(t^p)][F_p(t^p): F_p].

Thus, [K: F_p] ≤ p².

Therefore, [K: F] ≤ p².

(b) We need to show that the automorphism δ of K defined by δ (t) = t + 1 fixes F.

Let f(x) be the polynomial obtained in part (a). Since f(t) = 0, we have f(t + 1) = 0. This implies δ (t) = t + 1 is a root of f(x) also.

Hence, f(x) is divisible by x - (t + 1). We can writef(x) = (x - (t + 1))g(x)for some g(x) ∈ K[x].

Since [K: F] ≤ p², we have deg(g) ≤ p.

Substituting x = t into the above equation yields 0 = f(t) = (t - (t + 1))g(t) = -g(t).

Therefore, f(x) = (x - (t + 1))g(x) = (x - t - 1)(a_{p-1}x^{p-1} + a_{p-2}x^{p-2} + ··· + a_1 x + a_0)where a_{p-1}, a_{p-2}, ..., a_1, a_0 ∈ F_p are uniquely determined.

(c) To show that K is a Galois extension of F and determine the Galois group Gal(K/F), we need to check that K is a splitting field over F.

That is, we need to show that every element of F_p(t^p) has a root in K.Since K = F_p(t)(t^p - t) = F_p(t)(w), it suffices to show that w has a root in K.

Note that w = t^p - t = t(t^{p-1} - 1).

Since t is a root of f(x) = x^p - x ∈ F_p[t], we have t^p - t = 0 in K. Thus, w = 0 in K.

Therefore, K is a splitting field over F_p(t^p).Since [K : F_p(t^p)] ≤ p, the extension K/F_p(t^p) is separable.

Therefore, the extension K/F_p is also separable. Hence, K/F_p is a Galois extension. The degree of the extension is [K: F_p] = p².

The Galois group is isomorphic to a subgroup of S_p. Since F_p is a finite field of p elements, it contains a subfield isomorphic to Z_p. This subfield is fixed by any automorphism of K that fixes F_p.

Since F_p(t^p) is generated by F_p and t^p, any automorphism of K that fixes F_p(t^p) is uniquely determined by its effect on t.

Since there are p choices for δ(t), the Galois group has order p. It follows that the Galois group is isomorphic to Z_p.

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The solution to the Cauchy problem is x(t) = e^t and y(t) = te^t.

The Cauchy problem can be solved by finding the solution to the given system of differential equations.

In more detail, we have the following system of differential equations:

dx/dt = x - y

dy/dt = x + y

To solve this system, we can use the method of separation of variables. Starting with the first equation, we separate the variables:

dx/(x - y) = dt

Integrating both sides, we have:

ln|x - y| = t + C1

Exponentiating both sides, we get:

|x - y| = e^(t + C1)

Taking the absolute value, we have two cases:

(x - y) = e^(t + C1)

(x - y) = -e^(t + C1)

Simplifying, we obtain:

x - y = Ce^t, where C = e^(C1)

x - y = -Ce^t, where C = -e^(C1)

Next, we consider the second equation of the system. We differentiate both sides:

dy/dt = x + y

Substituting the expressions for x - y from the first equation, we have:

dy/dt = (Ce^t) + y

This is a linear first-order ordinary differential equation. We can solve it using an integrating factor. The integrating factor is e^t, so we multiply both sides by e^t:

e^t(dy/dt) - e^ty = Ce^t

We recognize the left side as the derivative of (ye^t) with respect to t:

d(ye^t)/dt = Ce^t

Integrating both sides, we have:

ye^t = Ce^t + C2

Simplifying, we obtain:

y = Ce^t + C2e^(-t), where C2 is the constant of integration

Using the initial conditions x(0) = 1 and y(0) = 0, we can find the values of the constants C and C2:

1 - 0 = C + C2

C = 1 - C2

Substituting this back into the equation for y, we have:

y = (1 - C2)e^t + C2e^(-t)

Therefore, the solution to the Cauchy problem is x(t) = e^t and y(t) = te^t.

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Answer:

I am not sure rdbugs h h on grh g ih fv vy f byv7iplovh v v6c78