9514 1404 393
Answer:
0.2 m/s
Explanation:
The average velocity is the change in position divided by the change in time:
(8 m -4 m)/(20 s) = (4/20) m/s = 1/5 m/s = 0.2 m/s
The boy's average velocity is 0.2 m/s.
What is the acceleration of the object if a 300-N force acting on a 25 kg object
Given parameters:
Force on the object = 300N
Mass of object = 25kg
Unknown:
Acceleration = ?
Solution:
According to Newton's second law of motion, force is a product of mass and acceleration.
Force = mass x acceleration
Input the parameters and solve for the acceleration;
300 = 25 x acceleration
Acceleration = 12m/s²
The acceleration is 12m/s²
What is the rate of acceleration of a hammer whose head goes from moving -2 m/s (downward) to +0.5 m/s (upward) when it hits and bounces off a hard rock ? The actual bounce takes 0.025 seconds
Answer:
[tex]a=100\ m/s^2[/tex]
Explanation:
Given that,
Initial velocity, u = -2 m/s
Final velocity, v = =.5 m/s
Time, t = 0.025 s
We need to find the rate of acceleration of a hammer. Acceleration is equal to the change in velocity divided by the time taken.
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{0.5-(-2)}{0.025}\\\\a=100\ m/s^2[/tex]
So, the acceleration of the jet is [tex]100\ m/s^2[/tex].
Imagine that you throw a rock into the air. When you release the rock, it is moving at 19.4 m/s. The rock flies straight up into the air and returns back to your hand. For how long was the rock in the air? Note: acceleration due to gravity is -9.81 m/s/s.
Answer:
4 s
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 19.4 m/s.
Acceleration due to gravity (g) = –9.81 m/s²
Total time (T) =.?
Next, we shall determine the time take by the rock to get to the maximum height. This can be obtained as follow:
NOTE: At maximum height, the final velocity is zero.
Initial velocity (u) = 19.4 m/s.
Acceleration due to gravity (g) = –9.81 m/s²
Final velocity (v) = 0 m/s
Time taken to reach the maximum height (t) =.?
v = u + gt
0 = 19.4 + (–9.81 × t)
0 = 19.4 – 9.81t
Collect like terms
0 – 19.4 = –9.81t
–19.4 = –9.81t
Divide both side by –9.81
t = –19.4 / –9.81
t ≈ 2 s
Thus, it took approximately 2 s for the rock to reach its maximum height.
Finally, we shall determine the total time spent by the rock in the air as follow:
Time taken to reach the maximum height (t) = 2 s
Total time spent in air (T) =?
The total time (T) spent by the rock in the air will be two times the time taken (t) to reach the maximum height i.e
T = 2t
t = 2 s
T = 2 × 2
T = 4 s
Therefore, the rock spent approximately 4 s in the air.
A ball is thrown horizontally from a 12 m
building with a speed of 2.0 m/s.
-high
How far from the base of the building does the ball hit the ground ?
Answer:
24
Explanation:
you multiply 2.0x12
2.What is the weight of an object that has a mass of 5 kg?
Answer:
5 kg
or 11 lbs
Explanation:
When does a scatter plot show a correlation?
Answer:
Mark brainliest please
Explanation:
If the data points make a straight line going from the origin out to high x- and y-values, then the variables are said to have a positive correlation .When there is no clear relationship between the two variables, we say there is no correlation between the two variables.
why a dam is thicker at the bottom than it's top
Answer: Due to water pressure.
Explanation:
As depth increases so does the pressure.
As part of their research on cell reproduction, Ms. Kelly's biology class designed various experiments to determine the best conditions for budding, or asexual reproduction, in common yeast cells. The students added sucrose as a source of food for the yeast and each group added water of a different temperature to the yeast-sugar mix. They used a light microscope to observe and count the yeast cells.
Based on the recorded data, what observation did the students make regarding the growth of yeast cells?
A) Once the temperature reached 50oC, the yeast died.
B) The size of individual yeast cells increased with an increase in temperature.
C) Increased temperature played no role in increasing the number of yeast cells.
D) The number of yeast cells increased as the temperature of the water increased.
Your are part of a team to help design the atrium of a new building.Your boss, the manager of the project, wants to suspend a 6.2 kg sculpture high over the room by hanging it from the ceiling using thin, clear fishing line (string) so that it will be difficult to see how the sculpture is held up. The only place to fasten the fishing line is to a wooden beam which runs around the edge of the room at the ceiling.The fishing line that she wants to use will hold 10 kg so she suggests attaching two lines to the sculpture to be safe. Each line would come from the opposite side of the ceiling to attach to the hanging sculpture. Her initial design has the first line making an angle of 12.67∘with the ceiling and the second line making an angle of 16.15∘ with the ceiling. She knows you took physics, so she asks you if her design can work.
How much force would the first line exert on the beam holding it up?
Assume that g=9.8 m/s−2.
Answer:
The answer is below
Explanation:
Given that the mass of the sculpture (m) = 6.2 kg, [tex]\theta_1=12.67^o,\theta_2=16.15^o[/tex]
[tex]Sum\ of\ horizontal\ force\ is\ zero\ hence:\\\\T_1cos(\theta_1)=T_2cos(\theta_2)\\\\T_1=\frac{T_2cos(\theta_2)}{cos(\theta_1)}\\ \\Sum\ of\ vertical\ force\ is\ zero:\\\\T_1sin(\theta_1)+T_2sin(\theta_2)=mg\\\\\frac{T_2cos(\theta_2)}{cos(\theta_1)}sin(\theta_1)+T_2sin(\theta_2)=mg\\\\T_2=\frac{mg}{\frac{cos(\theta_2)}{cos(\theta_1)}sin(\theta_1)+sin\theta_2} \\\\T_2=\frac{6.2*9.81}{\frac{cos(16.15)}{cos(12.67)}sin(12.67)+sin16.15} =123.1\ N\\\\[/tex]
[tex]T_1=\frac{T_2cos(\theta_2)}{cos(\theta_1)}=121.2\ N[/tex]
A helpful association method like remembering the Allies during World War II as BAR
(Britain, America, and Russia) is called
O an acronym
O the DAP flashcard method
O a visual image
O a mind map
Answer:
an acronym because it is shorted to remember like mvemjsun it's the planet
A boy and a girl are pulling a heavy crate at the same time with 7 units of firce each. What is the net force acts on the ibject? Is the object balanced or unbalanced?
Answer:
Net force= 14 units
The object is unbalanced
Explanation:
The net force refers to the sum of all forces applied to an object. However, the direction of force applied determine the net force. In this question, a boy and girl is pulling a heavy crate at the same time.
This means that the force is in the same direction, hence, the net force will be:
F(N) = 7 + 7 = 14 unit
However, since the pull is occuring at the same direction. This means that the object has a net force, therefore, will move in a particular direction. This means that the OBJECT IS UNBALANCED
How can you predict the number of swings an 80 cm pendulum will make in 15 seconds?
Compact fluorescent bulbs are much more efficient at producing light than are ordinary incandescent bulbs. They initially cost much more, but last far longer and use much less electricity. According to one study of these bulbs, a compact bulb that produces as much light as a 100 W incandescent bulb uses only 23.0 W of power. The compact bulb lasts 10000 hours, on the average, and costs $ 12.00, whereas the incandescent bulb costs only $ 0.76, but lasts just 750 hours. The study assumed that electricity cost $ 0.090 per kilowatt-hour and that the bulbs were on for 4.0 h per day.
Required:
a. What is the total cost (including the price of the bulbs) to run each bulb for 3.0 years?
b. How much do you save over 3.0 years if you use a compact fluorescent bulb instead of an incandescent bulb?
c. What is the resistance of a "100-W" fluorescent bulb?
Answer:
a
[tex]The \ price \ for \ Compact\ fluorescent\ bulbs \ is \ C_T = \$ 21.067\\The \ price \ for \ incandescent\ bulb \ is \ C_t = \$ 43.98[/tex]
b
[tex]The \ amount \ saved \ is \ C_S = \$ 22.913[/tex]
c
[tex]The \ resistance \ is \ R = 626.1 \Omega[/tex]
Explanation:
From the question we are told that
The power used by incandescent bulb [tex]P_r = 23.0 W[/tex]
The power used by Compact fluorescent bulb [tex]P_p = 100W[/tex]
The life span of Compact fluorescent bulb is [tex]t = 1000 \ hours[/tex]
The prices of Compact fluorescent bulb is [tex]C_c = \$ 12 [/tex]
The prices of incandescent bulb is [tex]C_i = \$ 0.76 [/tex]
The life span of incandescent bulb is [tex]t_k = 750 \ hours[/tex]
The cost of electricity is [tex]C_e = \$ 0.090/ kilowatt-hour = \frac{0.090}{1000} = \$0.00009 / W / h[/tex]
The duration of daily bulb usage is [tex]t_d = 4 \ hours[/tex]
Generally 3 years of bulb usage in hours is mathematically evaluated as
[tex]t_3 = 3 * 365 * t_d[/tex]
=> [tex]t_3 = 3 * 365 * 4[/tex]
=> [tex]t_3 = 4380 \ h [/tex]
Generally the cost to power a 23W bulb for the above duration is mathematically represented as
[tex]Z = 23 * t_3 * C_e[/tex]
=> [tex]Z = 23 * 4380 * 0.00009[/tex]
=> [tex]Z = \$ 9.0667[/tex]
The number of Compact fluorescent bulbs required to achieve this about of time is mathematically represented as
[tex]N = \frac{t_3}{ t}[/tex]
=> [tex]N = \frac{4380}{1000}[/tex]
=> [tex]N = 0.438 [/tex]
=> [tex]N \approx 1 [/tex]
The total cost of usage for the Compact fluorescent bulb is mathematically represented as
[tex]C_T = Z +C_c[/tex]
=> [tex]C_T = 9.0667 +12[/tex]
=> [tex]C_T = \$ 21.067 [/tex]
The number of incandescent bulbs required to achieve this about of time is mathematically represented as
[tex]M = \frac{t_3}{ t_k}[/tex]
=> [tex]M = \frac{4380}{750}[/tex]
=> [tex]M = 6 [/tex]
Generally the cost to power a 100W bulb for the above duration is mathematically represented as
[tex]Z = 100 * t_3 * C_e[/tex]
=> [tex]Z = 100 * 4380 * 0.00009[/tex]
=> [tex]Z = \$ 39.42[/tex]
The total cost of usage for the incandescent bulbs is mathematically represented as
[tex]C_t = C_e + [6 *C_i][/tex]
=> [tex]C_t = 39.42 + [0.76 * 6][/tex]
=> [tex]C_t = \$ 43.98[/tex]
Generally the total amount saved is mathematically represented as
[tex]C_S = C_t - C_T[/tex]
=> [tex]C_S = 43.98 - 21.067[/tex]
=> [tex]C_S = \$ 22.913[/tex]
Generally the resistance of the Compact fluorescent bulb is
[tex]R = \frac{V^2}{P}[/tex]
[tex]R = \frac{120^2}{23}[/tex]
[tex]R = 626.1 \Omega[/tex]
Which function has a graph that intersects the y-axis at the point (0-4)?
Plz help por favor
Answer:
I believe B. The picture is not completely clear
Explanation:
2 physical properties for manganese
A hammer drives a nail into a piece of wood. Which of the following correctly
identifies the pair of equal and opposite forces involved.
A. The hammer exerts a force on the nail: the nail exerts a force on the wood
B. The hammer exerts a force on the nail: the wood exerts a force on the nail.
C. The nail exerts a force on the hammer: the hammer exerts a force on the wood.
D. The hammer exerts a force on the nail: the nail exerts a force on the hammer.
Answer:
D
Explanation:
The statement which correctly describes the pair of equal and opposite forces involved is that the hammer exerts a force on the nail: the nail exerts a force on the hammer. Thus, the correct option for this question is D.
What is Force?Force may be defined as the process that significantly involves the pulling and pushing of an object with mass which stimulates itself to change its velocity accordingly. It is a type of vector quantity because it has both magnitude and direction.
According to Newton's third law of motion, if object A exerts a force on object B, then object B must significantly exert a force of equal magnitude and opposite direction on object A. Here, object A is a hammer, and object B is a nail.
Therefore, the hammer exerts a force on the nail: the nail exerts a force on the hammer is the statement that correctly describes the pair of equal and opposite forces. Thus, the correct option for this question is D.
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1)
You travel east at 50 km/hr and then north at 75 km/hr. What is your Resultant Velocity in km/h?
(Remember the angle) (5pts)
Answer:
15
Explanation:
Type of tissue that helps with movement.Immersive Reader
a. Epithelial
b.Muscle
c.Connective
d.Nervous
Please help me if you know physics
Answer:
19. down
20. True
Explanation:
The examples I saw were projectiles launched at different angles and speeds. In each case, the only acceleration was ...
19: down
20: due to gravity (true)
An unbalanced force of 23 N is applied to a 13 kg mass. What is the acceleration of the
mass?
Answer:
1.77 m/s^2
Explanation:
since it is unbalanced there must be net force(resultant force)
[tex]net \: force \: = accleration \: \times mass[/tex]
net force = 23N
mass = 13kg
a = x
x = 23/13
= 1.769...
approximately = 1.77 m/s^2
The particle model shows the image of the moving object.
TRUE OR FALSE
ANSWER AND I WILL GIVE YOU BRAINILIEST
Answer:
it does show the objects position
In which scenario will the two objects have the greatest gravitational force
between them?
A. Mass of object 1 = 22 kg
Mass of object 2 = 14 kg
Distance between objects = 28 m
B. Mass of object 1 = 22 kg
Mass of object 2 = 16 kg
Distance between objects = 48 m
C. Mass of object 1 = 22 kg
Mass of object 2 = 14 kg
Distance between objects = 48 m
D. Mass of object 1 = 22 kg
Mass of object 2 = 16 kg
Distance between objects = 28 m
Answer: The answer is D
Explanation:
The greater the mass and the less the distance
The two objects that will have the greatest gravitational force between them is:
D. Mass of object 1 = 22 kg
Mass of object 2 = 16 kg
Distance between objects = 28 m
What is Gravitational force?It is an appealing power that exists between all items with mass; an article with mass draws in one more particle with mass; the size of the power is straightforwardly corresponding to the majority of the two articles and contrarily relative to the square of the distance between the two particles.
It is given by:
[tex]F=G*\frac{m_1*m_2}{r^2}[/tex]
So, for the highest value of gravitational force there must be greater mass and lesser distance. So the option that holds good is option D.
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If I kick a ball off the top of a mountain cliff, will it take longer to hit the ground than if I just drop it? Explain your answer. Your answer:
Answer:
they will drop at the same time
Explanation:
projectile motion consists of two components, horizontal and vertical, which are independent of one another. That means that if you drop a ball and kick another one straight out, they will both hit the ground at the same time so long as they have the same initial drop height .
If a pair of shoes weighs 0.3 N on Pluto what is the strength of gravity on Pluto
Answer:
0.6 m/s 2
Explanation:
List 20 examples vector quantities
Answer:
That's all I got.
Explanation:
acceleration
velocity
momentum
force
increase
and decrease in temperature
weight
I need helpppppppppppppppppp!
Answer:
i think its B
Explanation:
but check it before do it
Answer:
A
Explanation:
Hope it helps I tried looking for think I found it hit the heart pls
How is a responding variable different from a manipulated variable?
A. When a responding variable changes, it causes the manipulated
variable to change.
B. A responding variable changes as a result of changes made to the
manipulated variable.
C. When a responding variable stays the same, the manipulated
variable changes.
O D. A responding variable changes, but a manipulated variable stays
the same.
Answer:
B. A responding variable changes as a result of changes made to the
manipulated variable.
Explanation:
A responding variable is different from a manipulated variable because a responding variable keeps on changing, but a manipulated variable stays the same. Thus, the correct option is D.
What are responding variable and manipulated variable?A variable is any characteristic, number, or quantity which can be measured or counted easily. A variable may also be called as an item. Age, sex, business income and expenses, country of birth, capital expenditure, class grades, eye color and vehicle type all are the example of variables.
Manipulated Variable are those variables which is changed by the scientist and are called as the controlled variable. Responding Variable is the variable that might change on its own because of what the scientist changes in the experimental study.
Therefore, the correct option is D.
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When the force applied to an object increases, the motion of the object
Answer:
Semen is the most important thing in the life cycle of life
4. A 65 kg woman is inside an elevator. Calculate her apparent weight (Normal Force) for the following cases:
a. The elevator moves at constant speed of 10 m/s downward (2 pts)
b. The elevator accelerates upward at a constant rate of 2.4 m/s2 (2 pts)
c. If the scale read 450 N. Find the magnitude and direction of the elevator’s acceleration. (3 pts)
Answer:
Explanation:
a ) Let her apparent weight be W₁
Net force on her = W₁ - mg
acceleration a = 0
W₁ - mg = 0
W₁ = mg = 65 x 9.8 = 637 N
b )
a = 2.4 m /s²
W₁ - mg = ma
W₁ = m(g + a )
= 65 x ( 9.8 + 2.4 )
= 793 N
c )
W₁ = 450 N
a = ?
W₁ - mg = ma
450 - 65 x 9.8 = 65 x a
65 a = - 187
a = - 2.87 m /s²
acceleration is negative therefore , it must be downwards .
The elevator was accelerating downward at a constant rate of -3.1 m/s²
Let the acceleration due to gravity (g) = 10 m/s²
a) When moving at constant speed of 10 m/s downward:
Net force = mass * g = 65 kg * 10 m/s² = 650N
b) Net force = Mass * g + mass * acceleration
Net force = (65 * 10) + (65 * 2.4) = 806 N
c) Net force = Mass * g + mass * acceleration
450 = 65 * 10 + (65*a)
65a = -200
a = -3.1 m/s²
The elevator was accelerating downward at a constant rate of -3.1 m/s²
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A mountain biker is climbing a steep 20° slope at a constant speed. The cyclist and bike have a combined weight of 800 N. What can you say about the magnitude of the normal force of the ground on the bike?
Answer:
Normal force = 751.75 N
Explanation:
It is given that,
The combined weight of the cyclist and the bike is 800 N
We need to find the magnitude of the normal force of the ground on the bike. It can be given by the formula as follows :
[tex]N=mg\cos\theta[/tex]
mg = W, combined weight of cyclist and bike
[tex]N=W\cos\theta\\\\N=800\times \cos(20)\\\\N=751.75\ N[/tex]
So, the magnitude of the normal force of the ground on the bike is 751.75 N.
The magnitude of the normal force of the ground on the bike is 751.752 N
The formula for that will be used to calculate the normal force of the ground on the bike is expressed as:
[tex]N= Fcos \theta[/tex]
F is the combined weight
[tex]\theta[/tex] is the angle of inclination
Given the following paramters
F = 800 N
[tex]\theta[/tex] = 20 degrees
Substitute the given parameters into the formula:
[tex]N=800 \times cos20^0\\N=800 \times 0.9397\\N=751.752N[/tex]
Hence the magnitude of the normal force of the ground on the bike is 751.752 N
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