According to the given problem,
(i) It is given that,
The cost price of 1000 packets of peanuts = Rs. 50
We need to find the cost price of 1 packet of peanut = [tex]\frac{50}{1000}[/tex] = Rs. 0.05
(ii) Selling price at which Sipho continues to sell 1 packet = Rs. 1
Then Selling price of 1000 packets = 1000 x 1 = Rs. 1000
Then Profit made by sipho = Selling Price - Cost Price
= 1000 - 50
= Rs.950
Profit percentage gained by Sipho = [tex]\frac{Profit}{Cost Price}[/tex] x 1000
= [tex]\frac{950}{50}[/tex] x 1000
= 1900 %
(iii) The profit earned by sipho remains same, we nee to find the cost price at which Sipho should sell 100gm of her peanuts is Rs. 1
(iv) I would advice Sipho to sell peanuts at a selling price more than the cost price in order to gain profit
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Which point is a solution to the system of linear equations?
y = −x + 3
2x − y = 6
(3, 0)
(3, −1)
(0, 3)
(−1, 3)
The ordered pair which is a solution to the system of linear equations is: A. (3, 0).
How to determine the solution?In order to determine a solution to the system of linear equations, we would have to test the given ordered pairs by substituting their values into the linear equations as follows;
For ordered pair (3, 0), we have:
y = −x + 3
0 = -3 + 3
0 = 0 (True).
2x − y = 6
2(3) - 0 = 6
6 - 0 = 6
6 = 6 (True).
For ordered pair (3, -1), we have:
y = −x + 3
-1 = -3 + 3
-1 = 0 (False).
For ordered pair (0, 3), we have:
y = −x + 3
3 = 0 + 3
3 = 3 (True).
2x − y = 6
2(0) - 3 = 6
0 - 3 = 6
-3 = 6 (False).
For ordered pair (-1, 3), we have:
y = −x + 3
3 = -1 + 3
3 = 2 (False).
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A $40 phone case is taxed with
an 8% sales tax. How much tax will be
paid?
Answer: $3.20 is the sales tax
Step-by-step explanation:
[tex]\frac{8x40}{100} =3.2[/tex] (8 times 40 divided by 100)
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If f(x) = –2x+4 Evaluate the function when x= -3. f(-3) = ?
Answer:
f(-3)=10
Explanation:
Given the function:
[tex]f\mleft(x\mright)=-2x+4[/tex]When x = -3
[tex]\begin{gathered} f(-3)=-2(-3)+4 \\ =6+4 \\ =10 \end{gathered}[/tex]Write the relation as a set of ordered pairs. a. ordered pairs: {(–1, 1), (2, 0), (3, 1)} b. ordered pairs: {(–1, 1), (0, 2), (1, 3)} c. ordered pairs: {(1, –1), (0, 2), (1, 3)} d. ordered pairs: {(1, –1), (2, 0), (3, 1)} Please select the best answer from the choices provided A B C D
Answer:
a) (in order) {-1, 0, 1, 2, 3}
b) {-1, 0, 1, 2, 3}
Step-by-step explanation:
Pot the points (4, 4), (8, 4), (3, 1), and (7, 1) on the coordinate plane.Use the points to draw two parallel, horizontal segments. Label theendpoints of one segment A and B. Label the endpoints of the othersegment C and D What is the distance between points A and B?What is the distance between points C and D
Solution
The diagram below shows what is needed
As shown above
distance between points A and B is
[tex]4[/tex]distance between points C and D is
[tex]4[/tex]Which expressions are equivalent to ✓-27?
3i√3
91√√/3
O √27i
O i√27
3√/91²
The expression for [tex]\sqrt{-27}[/tex] is 3i[tex]\sqrt{3}[/tex]
What is an expression?
Expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.
given [tex]\sqrt{-27}[/tex] we know that
3 multiplied by 9 gives 27 and the square root of 9 is 3
we can write
[tex]\sqrt{-3(3)(3)}[/tex]
or [tex]3\sqrt{-3}[/tex]
square root of minus gives iota
we get,
[tex]3i\sqrt{3}[/tex]
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Simplify m^9 m^−3.
A. -m^12
B. 1 / m^27
C. 1 / m^6
D. m^6
I will use the law of exponent below
⇒if you re multiplying powers of them same base, keep one base and add the exponents mathematically we say:
[tex]x^{n} *x^{n} \\=x^{n+n}[/tex]
[tex]=m^{9+(-3)} \\=m^{9-3} \\=m^{6}[/tex]
OPTION D is the solution
y=x+2 find the coordinates of the x and y intercept
All the points are P1=(0, 2), P2= (1,3), P3(2,4), P4(3,5 ), and P5(4,6).
y=x+2 is obtained function through the equation y-x=2.
Consider the value of X=0 for P1.
Y= 0+2
Y=2
If X=0, then Y=2.
∴ (0, 2)
Consider the value of X=1 for P2.
Y=1+2
Y=3
If X=1, then Y=3
∴ (1,3)
Consider the value of X=2for P3.
Y=2+2
Y=4
If X=2, then Y=4
∴ (2,4)
Consider the value of X=3for P4.
Y=3+2
Y=5
If X=3, then Y=5.
∴ (3,5 )
Consider the value of X=4 for P5.
Y=4+2
Y=6
If X=4, then Y=6.
∴ (4,6)
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uppose p ( t ) p(t) represents the population of a certain mosquito colony, where t t is measured in days. the current population of the colony is known to be 578 578 mosquitos; that is, p ( 0 )
The size of the population of mosquito follows an exponential model.
the size of the population in 10 days is 1370
The size of the population in 10 days is 1370
The given parameters are:
p(0) = 574
p'(0)= 50
An exponential function is represented as:
p(t) =p(0) * e^ rt
So, we have:
p(t)=574*e^rt
Differentiate
p'(t)=574*r*e^rt
Substitute 0 for t
50=574 r
Divide both sides by 574
r=0.087
The function becomes
p(t)= 574*e^rt
= 574*e^0.087 t
In 10 days, t = 10.
So, we have:
p(10)=574*e^0.87
Solve
p(0)=1370
Hence, the size of the population in 10 days is 1370
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Translate this sentence into an equation.
The difference of Janelle's height and 9 is 65
Use the variable j to represent Janelle's height.
Step-by-step explanation:
Translate this sentence into an equation. The difference of Janelle's height and 9 is 65. Use the variable j to represent Janelle's height.
j - 9 = 65
to solve:
j - 9 = 65
add 9 to both sides:
j - 9 + 9 = 65 + 9
j = 74
Please helppp <3
The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over times, x measured in seconds. During what interval(s) of the domain is the water balloon's height staying the same?
A. 0 ≤ x ≤ 2
B. 2 ≤ x ≤ 5
C. 5 ≤ x ≤ 6
D. 6 ≤ x ≤ 8
Answer:
B
Step-by-step explanation:
it shows that it doesn't go anywhere in the interval of 2 and 5, other ones would be wrong bcs it's either go up or down
It took Elsa 18 minutes to make 3 bookmarks.
Which of the following pairs of equivalent fractions could be used to determine how many bookmarks she can make in 90 minutes?
Create three probability application problems of your own. Solve your problems. Explain your answers.
The required problems on probability application are detailed below.
Probability is the study of chance represented as a proper fraction between 0 and 1 .
The manufacturing process of a particular rugby ball consists of two parts, a leather covering and a rubber bladder. The probabilities of defect in the leather covering is 5% and the probability of the rubber bladder is 15% respectively. What is the probability that the assembled Rugby ball will not have any defect.
Let A and B denote the event that a rugby ball is defective due to defects in the leather covering and the rubber bladder respectively.
Then we can say that P(A) = 5 / 100 = 1 / 20 and
P(B) = 15 / 100 = 3 / 20
Therefore P(A') = 1 - 1/20 = 19/20 and P(B') = 1 - 3 / 20 = 17 / 20.
P(A') and P(B') gives us the probabilities that the rugby ball will not have defective parts respectively.
Therefore the probability that the assembled product will not have any defect is:
P(A') × P(B')
[tex]=\frac{19}{20} \times \frac{17}{20}\\\\=\frac{323}{400} \\\\=0.8075[/tex]
Therefore the probability that the rugby ball will not have any defect is 80.75% .
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HELP PLEASE!!A(5,1), B(7,1), C(7,6), D(5,6) What is the perimeter of rectangle ABCD?
Which sequence exhibits the similarity between rectangles ABCD which A’B’C’D’ shown in the coordinates plane below
The sequence of transformation that exhibits the similarity between the rectangles ABCD and rectangle A'B'C'D' is the option C.
C. Rectangle ABCD is reflected across the y-axis and then dilated by a scale factor of 2 with the center of dilation at the origin to obtain rectangle A'B'C'D'
What is a reflection transformation in geometry?A reflection transformation of an object gives or produces the mirror image of the object about a specified line.
The coordinates of the points of the rectangle ABCD obtained from the graph are; A(-4, -4), B(-4, 4), C(2, 4), and D(2, -4).
The coordinates of the image of the rectangle ABCD (rectangle (A'B'C'D') are; A'(8, -8), B'(8, 8), C'(-4, 8) and D'(-4, -8)
The coordinates of the reflection of the point (x, y), following a reflection across the y-axis is the point (-x, y)
The vertices of the image of rectangle ABCD formed following a reflection across the x-axis are therefore;
A(-4, -4) [tex]\underrightarrow{R_{x-axis}}[/tex] A''(4, -4)
B(-4, 4) [tex]\underrightarrow{R_{x-axis}}[/tex] B''(4, 4)
C(2, 4) [tex]\underrightarrow{R_{x-axis}}[/tex] C''(-2, 4)
D(2, -4) [tex]\underrightarrow{R_{x-axis}}[/tex] D''(-2, -4)
The coordinates of the point (x, y) following a dilation by a scale factor of k, with the center of dilation at the origin is (k·x, k·y)
The dilation of the image of the rectangle ABCD by a scale factor of 2 gives;
A''(4, -4) [tex]\underrightarrow{D_{2}}[/tex] (2×4, 2×(-4)) = A'(8, -8)
B''(4, 4) [tex]\underrightarrow{D_{2}}[/tex] (2×4, 2×(4)) = B'(8, 8)
C''(-2, 4) [tex]\underrightarrow{D_{2}}[/tex] (2×(-2), 2×(4)) = C'(-4, 8)
D''(-2, -4) [tex]\underrightarrow{D_{2}}[/tex] (2×(-2), 2×(-4)) = D'(-4, -8)
The points of the image of rectangle ABCD following a a reflection and a dilation are A'(8, -8), B'(8, 8), C'(-4, 8) and D'(-4, -8), which are the same as the coordinates of the points of the given rectangle A'B'C'D'
The correct option is therefore option C;
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The function h
(
t
)
=
−
0. 25
t
2
+
1. 9
t
+
17
, where h
(
t
)
is height in feet, models the height of an "angry bird" shot into the sky as a function of time (seconds). Use this function to answer the following questions. Round all answers to two decimal places
The height of an "angry bird" shot into the sky as a function of time (seconds) is h = 8.65 ft.
The height of the bird is given by the following equation
h(t)= -0.25t2 + 1.9t + 17
t= 1
= -0.25 + 1.9 + 17
= -8.35 + 17
h = 8.65 ft.
The following are the three equations:
-First equation of motion: v = u + at
-Second equation of motion: s = u t + 1/2 at2
Third equation of motion: v2 = u2 + 2as
t is the time, in seconds.
h(t) is the height, in feet, which is dependent of the time.
h(t) is height in feet and t is time in seconds
then h = 8.65 ft.
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DOES ANYONE KNOW THE ANSWERSSSS
65 pt
Answer:
3.75 cups of flour
2.5 cups of sugar
1.25 cups of butter
Step-by-step explanation:
Hello!
Let the amount of sugar used be x:
Flour = 1.5xButter = 0.5xThe total sum of ingredients should be 7.5 cups, so we can add x, 1.5x, and 0.5x and set it to 7.5.
Solve for xx + 0.5x + 1.5x = 7.53x = 7.5x = 2.5Clifford needs 2.5 cups of sugar.
The amount of flour can be found by multiplying 2.5 by 1.5: 3.75 cups
The amount of butter can be found by multiplying 2.5 by 0.5: 1.25
Clifford needs 3.75 cups of flour, 2.5 cups of sugar, and 1.25 cups of butter.
The listed price of the pair of pants was $38, but the price with tax came to $39.14. Find the percent sales tax.
well, the difference is 39.14 - 38 = 1.14, so that's the tax.
if we take 38 to be the 100%, just the listed price alone, what is 1.14 off of it in percentage?
[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} 38 & 100\\ 1.14& x \end{array} \implies \cfrac{38}{1.14}~~=~~\cfrac{100}{x} \implies 38x=114\implies x=\cfrac{114}{38}\implies x=3[/tex]
HELP ASAP WILL GIVE 20 POINTS AND BRAINLIEST TO WHOEVER SOLVES THIS
The length of a bacterial cell is about 4 x 10−6 m, and the length of an amoeba cell is about 2.5 x 10−4 m. How many times smaller is the bacterial cell than the amoeba cell? Write the final answer in scientific notation with the correct number of significant digits. A 6.25 x 10^2
B 2 x 10^2
C 6 x 10^1
D 16 x 10^1
The bacterial cell is 6.25 x 10 times smaller than the amoeba cell.
The length of the Bacterial cell is 4 x 10⁻⁶ meters.
The length of the Amoeba cell is 2.5 x 10⁻⁴ meters.
The length L of the bacterial cell can be written as,
L = 0.000004 meters.
Also, the length L' of the amoeba cell can be written as,
L' = 0.00025 meters.
Let us say that the bacterial cell is N times smaller than the amoeba cell.
So. we can write,
Length of bacterial cell x N = length of amoeba cell.
LN = L'
0.000004(N) = 0.00025
N = 0.00025/0.000004
N = 62.5
So, now we can say that the length of the bacterial cell is 62.5 times smaller than he amoeba cell.
As we have to state our answer in scientific notation,
We can write 62.5 as 6.25 x 10.
Now the number of significant figure is has are three.
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Write an equation that passes through the given points and is perpendicular to the line , (-3,1); y=-5x+2, write it in slope-intercept form pls.
The equation of the line that passes through point (-3,1) and perpendicular to y=-5x+2 is y = (1/5)x + 8/5.
What is the equation of line that passes through the given points and is perpendicular to the given line?Given the data in the question;
Equation of line: y = -5x + 2Point: (-3,1)First we determine the slope of the initial line using the slope intercept-form. y = mx + b
y = -5x + 2
Compared with the slope intercept form,
Slope m = -5
Now, for the equation of line perpendicular to the initial line, its slope must be a negative reciprocal of the initial slope.
Hence, slope of the perpendicular line is;
Slope m = -1/(-5) = 1/5
To find the equation of the perpendicular line, we use the point slope formula.
y - y₁ = m( x - x₁ )
Plug in the slope m ( 1/5) and point (-3,1).
y - 1 = (1/5)( x - (-3) )
y - 1 = (1/5)( x + 3 )
Convert to slope-intercept form.
y - 1 = (1/5)( x + 3 )
y - 1 = x/5 + 3/5
y = x/5 + 3/5 + 1
y = x/5 + 3/5 + 1
y = x/5 + 8/5
y = (1/5)x + 8/5
Therefore, the equation of the perpendicular line is y = (1/5)x + 8/5.
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Question 22 of 27
Question 22
On Sunday, Jax biked 25.91 miles. This is 3.3 fewer miles than the number of miles he biked on Saturday. Let b represent the number of miles
Jax biked on Saturday.
Write a subtraction equation that could be used to find the number of miles Jax biked on Saturday.
18.75 = u/3 solve for u please
Answer: 56.25 = u
Step-by-step explanation:
1) Multiply 3 on both sides to leave u by itself
18.75 = u/3
18.75*3 = u
56.25 = u
Evaluate. Write your answer as a whole number or as a simplified fraction.
Answer:
121
Step-by-step explanation:
11^6/11^4
= 11^(6-4)
= 11^2
= 121
HELP PLEASE <3: quadratic functions, (image contains question)
not too hard I'm just bad at math-
THANK YOU :)
Answer:
f(x)=(x-4)^2-4
The parent function (x^2) is shifted to the right 4 times (x-4) and down 4 times (-4).
a gardener has 760 feet of fencing to fence in a rectangular garden. one side of the garden is bordered by a river and so it does not need any fencing.
The dimensions that would guarantee that the garden has the greatest possible area is 190 feet on the shorter side and 380 feet on the longer side to produce an area of 72,200 square feet.
A dimensions of a rectangle is the length of each side.
Let x = length of the shorter side
y = length of the longer side
If one side of the garden is bordered by a river and so it does not need any fencing, and assume that the longer side is this side, then the perimeter that only needs to be fenced by 760 feet of fencing materials is
2x + y = 760
y = 760 - 2x
The area of the rectangular garden is the product of the shorter side and the longer side of the garden. Hence,
A = xy
A = x(760 - 2x)
A = 760x - 2x²
To obtain the largest area possible, the first derivative of the area should be equal to zero.
A(x) = 760x - 2x²
A'(x) = 0
760 - 4x = 0
Solve for x.
760 - 4x = 0
4x = 760
x = 190
length of the shorter side = 190 feet
y = 760 - 2x
y = 760 - 2(190)
y = 380
length of the longer side = 380 feet
Solve for the greatest possible area.
A = xy
A = 190 feet(380 feet)
A = 72,200 square feet
" A gardener has 760 feet of fencing to fence in a rectangular garden. One side of the garden is bordered by a river and so it does not need any fencing. What dimensions would guarantee that the garden has the greatest possible area? "
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45. Maury bought concert tickets at the Ticket Outlet. He paid $12 for each
ticket, plus a $5 service charge for the whole set of tickets. The total cost
was $77. How many tickets did he buy? 3-11
Using mathematical operations, Maury bought 6 tickets at the Ticket Outlet if he paid $77 at $12 each.
What are the mathematical operations?The basic mathematical operations are addition, subtraction, multiplication, and division.
These basic operations are used to manipulate numbers and variables in mathematical expressions to produce mathematical results.
The first mathematical operation used here is the subtraction operation.
After subtracting the fixed cost from the total cost, the difference is the total variable cost.
This difference is then divided by the unit variable cost to get the number of tickets.
The unit cost of the ticket = $12
The service charge (fixed cost) = $5
The total cost = $77
The number of tickets bought = 6 ($77 - $5)/$12
Thus, using mathematical operations, Maury did buy 6 tickets for $77.
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I need help please. Find the distance between Points U and Q.
Answer:
1 unit
Step-by-step explanation:
- 1 1/2 - (- 2 1/2)
= 1 unit
trucks in a delivery fleet travel a mean of 80 miles per day with a standard deviation of 26 miles per day. the mileage per day is distributed normally. find the probability that a truck drives at least 113 miles in a day. round your answer to four decimal places.
Answer:
0.1037
Step-by-step explanation:
9th grade math helppp
Answer:
b
Step-by-step explanation:
Find the points on the graph of[tex]x^{2/3}[/tex] + [tex]y^{2/3}[/tex] = 1 where the tangent line has slope 1
Any point satisfying the relation y = -[1 - (∛x²)]²(1/(∛x)) will be points on the graph where the tangent line has slope 1.
What is the slope of a given line?
A line's slope in mathematics is defined as the ratio of the change in the y coordinate to the change in the x coordinate. Both the net change in the y-coordinate and the net change in the x-coordinate are denoted by y and x, respectively.
Consequently, the formula for the change in y-coordinate with respect to the change in x-coordinate is the slope of a line is represented by the expression m = change in y/change in x =Δy/Δx.
Additionally, the slope of the line can be shown as tan θ = Δy/Δx
So, the slope of a line is tan θ.
The given equation is: (∛x²) + (∛y²) = 1
Therefore, (∛y²) = 1 - (∛x²) ⇒ y² = [1 - (∛x²)]³
Differentiating the equation formed with respect to x, we get
2y(dy/dx) = 3[1 - (∛x²)]²(-2/3)(1/(∛x)) ⇒ dy/dx = (-1/y)[1 - (∛x²)]²(1/(∛x)) -(i)
Given, the slope of the tangent line is = 1 -(ii)
Thus, equating (i) and (ii), we get,
(-1/y)[1 - (∛x²)]²(1/(∛x)) = 1 ⇒ y = -[1 - (∛x²)]²(1/(∛x))
Therefore any point satisfying the relation y = -[1 - (∛x²)]²(1/(∛x)) will be points on the graph where the tangent line has slope 1.
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