College admissions According to information from a college admissions office, 62% of the students there attended public high schools, 26% attended private high schools, 2% were home schooled, and the remaining students attended schools in other countries. Among this college's Honors Graduates last year there were 47 who came from public schools, 29 from private schools, 4 who had been home schooled, and 4 students from abroad. Is there any evidence that one type of high school might better equip students to attain high academic honors at this college? Test an appropriate hypothesis and state your conclusion.

Answers

Answer 1

To test whether one type of high school better equips students to attain high academic honors at a college, we can compare the observed proportions of Honors Graduates from different high school types to the expected proportions based on the overall distribution. Using a chi-squared test, the hypothesis test assesses whether the observed differences are statistically significant.

To test the hypothesis, we set up the null hypothesis (H0) that the type of high school attended does not affect the likelihood of attaining high academic honors. The alternative hypothesis (Ha) states that there is a significant association between high school type and academic honors.
Using the given information, we calculate the expected number of Honors Graduates for each high school type based on the overall distribution of high school attendance. Then, we compare the observed and expected frequencies using a chi-squared test. The test evaluates the difference between the observed and expected counts to determine if it is statistically significant.If the chi-squared test results in a p-value below a predetermined significance level (e.g., 0.05), we reject the null hypothesis, suggesting that there is evidence to support the alternative hypothesis.

This would indicate that one type of high school may better equip students to attain high academic honors at the college. Conversely, if the p-value is above the significance level, we fail to reject the null hypothesis, indicating that there is insufficient evidence to conclude a significant association between high school type and academic honors.
To draw a conclusion, we would need to perform the chi-squared test and compare the calculated p-value to the chosen significance level.

Learn more about chi-squared test here
https://brainly.com/question/30760432



#SPJ11


Related Questions

20 points for this!! thank you

Answers

Answer:

not a function becuz 2 repeats its self twice

Step-by-step explanation:

Answer:

You are welcome

Step-by-step explanation:

Find the value of the variable.
20
12

A. 10
В. 13
C. 16
D.18

Answers

Answer:

option c.

by Pythagoras theorem.

hypotenuse²=height ²+base²

20²=x²+12²

400=x²+144

400-144=x²

256=x²

256½=x

16=x

Bakery makes cupcakes and three different flavors chocolate, vanilla, and strawberry, with two choices of topics, butterscotch or pumpkin in two different sizes small or large how many different outcomes are there?

Answers

Answer:

24 or 12

Step-by-step explanation:

Multiplication

in counseling and psychotherapy groups, member-to-member contact outside of group often results in _____ and _____. group of answer choices

Answers

In counseling and psychotherapy groups, member-to-member contact outside of the group often results in subgroups and hidden agendas

According to various research studies on Personal relationships among specialty group members, such as counseling and psychotherapy groups, which was concluded that member-to-member contact outside of the group often results in SUBGROUP and HIDDEN AGENDAS.

However, Most of the time, which can lead to damaging situations.

Therefore it is considered a sensible strategy to prevent the formation of such subgroups.

Learn more about the subgroups

https://brainly.com/question/18994351

#SPJ1

Question is in picture

Answers

Step-by-step explanation:

you're multiple times a day po

the answer is c
hope it helps

Please answer correctly! I will mark you Brainliest!

Answers

Answer:

4.1 inches

I would appreciate Brainliest, but no worries.

Answer:

6

Step-by-step explanation:

the formula for the sphere's volume is [tex]\frac{4}{3} *\pi *r^3[/tex]

so when you set that equal to 288[tex]\pi[/tex], you get 6 as the radius

To go from Seattle, Washington, to Los Angeles, California, using the Interstate Train Company, one must travel through San Francisco, California, or Salt Lake City, Utah. Using the information given in the table, which route is shorter and by how much?

Answers

Answer:

The answer is BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB

To travel 1400miles from Seattle to Los Angeles it will take the train 35 hours

What is rate?

A rate is the ratio between two related quantities in different units. For example , the train travels 80 miles in 2hrs . the two quantities that are related here are distance and time

here, we have,

distance in miles and time in hours

the time to travel for 1 mile

= 2/80 = 1/40 miles

for the train to travel 1400 miles , it will take it

1/40× 1400

= 35 hours

learn more about rate from

brainly.com/question/25793394

#SPJ2

complete question:

There is a train that travels from Seattle, Washington, to Los Angeles, California. In its first 2 hours the train went about 80 miles including stops. At this rate, how longer will it take to travel the 1400 miles from Seattle to Los Angeles?








9. Consider the following permutation. 2 3 4 5 (₂2 24 5 1 6 a. Decompose into a product of cycles b. Decompose into the product of transposition. C. Decide if o is even or odd. 6 7 3 3)

Answers

a. The decomposition into cycles is (2 5 6 3 4).

b. The decomposition into transpositions is (2 5)(5 6)(6 3)(3 4).

c. The permutation is even.

We have,

To decompose the given permutation into cycles, we start with the first element and follow its path:

Starting with 2, we see that it goes to 5.

5 goes to 6.

6 goes to 3.

3 goes to 4.

Finally, 4 goes back to 2, completing the cycle.

The cycle can be represented as (2 5 6 3 4).

To decompose the permutation into transpositions, we consider each adjacent pair of elements and write them as separate transpositions:

(2 5)(5 6)(6 3)(3 4)

Now, we can observe that the permutation has a total of four transpositions.

To determine if the permutation is even or odd, we need to count the number of transpositions.

In this case, there are four transpositions, which means the permutation is even since the number of transpositions is even.

Therefore,

a. The decomposition into cycles is (2 5 6 3 4).

b. The decomposition into transpositions is (2 5)(5 6)(6 3)(3 4).

c. The permutation is even.

Learn more about permutations here:

https://brainly.com/question/32683496

#SPJ1

Find three numbers whose sum is 21 and whose sum of squares is a minimum. The three numbers are________ (Use a comma to separate answers as needed.)

Answers

the three numbers whose sum is 21 and whose sum of squares is a minimum are 7, 7, and 7.

To find three numbers whose sum is 21 and whose sum of squares is a minimum, we can use a mathematical technique called optimization. Let's denote the three numbers as x, y, and z.

We need to minimize the sum of squares, which can be expressed as the function f(x, y, z) = x² + y² + z²

Given the constraint that the sum of the three numbers is 21, we have the equation x + y + z = 21.

To find the minimum value of f(x, y, z), we can use the method of Lagrange multipliers, which involves solving a system of equations.

First, let's define a Lagrange multiplier, λ, and set up the following equations:

1. ∂f/∂x = 2x + λ = 0

2. ∂f/∂y = 2y + λ = 0

3. ∂f/∂z = 2z + λ = 0

4. Constraint equation: x + y + z = 21

Solving equations 1, 2, and 3 for x, y, and z, respectively, we get:

x = -λ/2

y = -λ/2

z = -λ/2

Substituting these values into the constraint equation, we have:

-λ/2 - λ/2 - λ/2 = 21

-3λ/2 = 21

λ = -14

Substituting λ = -14 back into the expressions for x, y, and z, we get:

x = 7

y = 7

z = 7

Therefore, the three numbers whose sum is 21 and whose sum of squares is a minimum are 7, 7, and 7.

Learn more about Sum here

https://brainly.com/question/2292486

#SPJ4

Plot the x-intercepts, the y-intercept, and the vertex of the graph (Must use Desmos!)

Answers

Answer:

x-intercept: (-1,0)

y-intercept: (0,3)

Vertex: (-2,-1)

Step-by-step explanation:

Please help me with this

Answers

Answer:

x = -2

Step-by-step explanation:

y = -4

2x -3y = 8

Substitute the first equation into the second equation

2x - 3(-4) = 8

2x +12 = 8

Subtract 12 from each side

2x+12-12 = 8-12

2x = -4

Divide by 2

2x/2 = -4/2

x = -2

what is 21x+1 in simple form

Answers

Answer:

( 21 x X ) + 1

Step-by-step explanation:

simplify the expression

Answers

Answer:

7m ^1÷2

Step-by-step explanation:

see attached joint

hope it helps

What are the first four marks on the x-axis for the following graph?
Y= 3/4sin3x/2

Answers

Answer:

uhh i don't know the answer sorry

Step-by-step explanation:

ummm i Don't know

If f(x) = (x + 7)2 and g(x) = x2 +9,
which statement is true?
A fo) B f(-4) > g(-3)
C f(1) = g(1)
D f(2) > g(2)

Answers

ANSWER : D

EXPLANATION : 81 > 13 is true

help me find the answer please​

Answers

Answer:

A x<1125

Step-by-step explanation:

What is the surface area of a cylinder with height 8 ft and radius 4 ft

Answers

The Surface area of the cylinder with a height of 8 ft and a radius of 4 ft is approximately 301.44 square feet.

The surface area of a cylinder, we need to consider the lateral surface area and the area of the two circular bases.

The lateral surface area of a cylinder can be determined by multiplying the height of the cylinder by the circumference of its base. The formula for the lateral surface area (A) of a cylinder is given by A = 2πrh, where r is the radius and h is the height of the cylinder.

In this case, the height of the cylinder is 8 ft and the radius is 4 ft. Therefore, the lateral surface area can be calculated as follows:

A = 2π(4 ft)(8 ft)

A = 64π ft²

The area of each circular base can be calculated using the formula for the area of a circle, which is A = πr². In this case, the radius is 4 ft. Therefore, the area of each circular base is:

A_base = π(4 ft)²

A_base = 16π ft²

Since a cylinder has two circular bases, the total area of the two bases is:

A_bases = 2(16π ft²)

A_bases = 32π ft²

the total surface area, we sum the lateral surface area and the area of the two bases:

Total surface area = Lateral surface area + Area of bases

Total surface area = 64π ft² + 32π ft²

Total surface area = 96π ft²

Now, let's calculate the numerical value of the surface area:

Total surface area ≈ 96(3.14) ft²

Total surface area ≈ 301.44 ft²

Therefore, the surface area of the given cylinder, with a height of 8 ft and a radius of 4 ft, is approximately 301.44 square feet.

In conclusion, the surface area of the cylinder with a height of 8 ft and a radius of 4 ft is approximately 301.44 square feet.

To know more about Surface area .

https://brainly.com/question/951562

#SPJ8

I wanted to find you a higher-order differential equation that had a real-life application. Here is what I found: a cylindrical shaft of length L is rotating with angular velocity w. Find a function y(x) that models the deformation of the cylinder. Of course this is a little bit more specialized to the field of dynamics than what we studied this semester, but what I learned was that this can be modeled: dºy dx4 - a4y = 0

Answers

The given differential equation d⁴y/dx⁴ - a⁴y = 0 models the deformation of a cylindrical shaft rotating with angular velocity ω. The function y(x) represents the deformation of the cylinder.

To solve the differential equation, we can assume a solution of the form y(x) = A*cos(ax) + B*sin(ax), where A and B are constants to be determined, and 'a' is a parameter related to the properties of the cylinder.

Taking the fourth derivative of y(x) and substituting it into the differential equation, we have:

d⁴y/dx⁴ = -a⁴(A*cos(ax) + B*sin(ax))

Substituting the fourth derivative and y(x) into the differential equation, we get:

-a⁴(A*cos(ax) + B*sin(ax)) - a⁴(A*cos(ax) + B*sin(ax)) = 0

Simplifying the equation, we have:

-2a⁴(A*cos(ax) + B*sin(ax)) = 0

Since the equation must hold for all x, the coefficient of each term (cos(ax) and sin(ax)) must be zero:

-2a⁴A = 0   (coefficient of cos(ax))

-2a⁴B = 0   (coefficient of sin(ax))

From these equations, we find that A = 0 and B = 0, which implies that the only solution is the trivial solution y(x) = 0.

Therefore, the solution to the differential equation d⁴y/dx⁴ - a⁴y = 0 is y(x) = 0.

To know more about higher-order differential equations , refer here:

https://brainly.com/question/30256978#

#SPJ11

Let X1 and X2 be independent random variables with mean μ and variance σ2. Suppose that we have two estimators of μ: Math and 1 = X1+X2/2 and math2=x1 + 3x2/4
(a) Are both estimators unbiased estimators of μ? (b) What is the variance of each estimator? Hint: Law of expected values

Answers

(a) Math2 is not an unbiased estimator of μ. (b)Math1 has a variance of

σ[tex]^{2}[/tex] and Math2 has a variance of  5σ[tex]^2[/tex]/8

(a) Neither of the estimators, Math1 or Math2, is an unbiased estimator of μ. An unbiased estimator should have an expected value equal to the parameter being estimated, in this case, μ.

For Math1,

the expected value is

E[Math1] = E[([tex]X_{1}[/tex] + [tex]X_{2}[/tex]) / 2]

= (E[[tex]X_{1}[/tex]] + E[[tex]X_{2}[/tex]]) / 2

= μ/2 + μ/2 = μ,

which means Math1 is an unbiased estimator of μ.

For Math2,

the expected value is

E[Math2] = E[([tex]X_{1}[/tex] + [tex]3X_{2}[/tex]) / 4]

= (E[[tex]X_{1}[/tex]] + 3E[[tex]X_{2}[/tex]]) / 4

= μ/4 + 3μ/4

= (μ + 3μ) / 4

= 4μ/4

= μ/2.

(b) To calculate the variances of the estimators, we'll use the property that the variance of a sum of independent random variables is the sum of their variances.

For Math1,

the variance is Var[Math1]

= Var[([tex]X_{1}[/tex] + [tex]X_{2}[/tex]) / 2]

= (Var[[tex]X_{1}[/tex]] + Var[[tex]X_{2}[/tex]]) / 4

= σ[tex]^2[/tex]/2 + σ[tex]^2[/tex]/2

= σ[tex]^2[/tex]

For Math2,

the variance is Var[Math2]

= Var[([tex]X_{1}[/tex] + [tex]3X_{2}[/tex]) / 4]

= (Var[[tex]X_{1}[/tex]] + 9Var[[tex]X_{1}[/tex]]) / 16

= σ[tex]^2[/tex]/4 + 9σ[tex]^2[/tex]/16

= 5σ[tex]^2[/tex]/8

Math1 has a variance of σ[tex]^2[/tex]

and Math2 has a variance of 5σ[tex]^2[/tex]/8

Learn more about parameter here:

https://brainly.com/question/31608396

#SPJ4

The number of pizzas consumed per month by university students is normally distributed with a mean of 12 and a standard deviation of 3. A. What proportion of students consume more than 13 pizzas per month? Probability = = B. What is the probability that in a random sample of size 10, a total of more than 110 pizzas are consumed? Probability = Note: You can earn partial credit on this problem.

Answers

The probability to consume more than 13 pizzas per month is 0.3707 and more than 110 pizzas in a random sample of size 10 is 0.9646.

The number of pizzas consumed per month by university students is normally distributed with a mean of 12 and a standard deviation of 3.

A. Probability that more than 13 pizzas consumed by students:

For finding the probability, we need to find the Z-score first.

z = (x - μ) / σz = (13 - 12) / 3z = 0.3333

Now, we have to use the z-table to find the probability associated with the z-score 0.3333.

The area under the normal distribution curve to the right of 0.3333 is 0.3707 (rounded off to 4 decimal places).

Thus, the probability that a student consumes more than 13 pizzas per month is 0.3707.

B. Probability that more than 110 pizzas consumed in a random sample of size 10:

Let x be the number of pizzas consumed in the random sample of size 10.

Then, the distribution of x is a normal distribution with the mean = 10 × 12 = 120 and standard deviation = √(10 × 3²) = 5.4772

We have to find the probability that the total number of pizzas consumed is greater than 110. i.e. P(x > 110).

For finding the probability, we need to find the Z-score first.z = (110 - 120) / 5.4772z = -1.8257

The area under the normal distribution curve to the right of -1.8257 is 0.9646 (rounded off to 4 decimal places).

Thus, the probability that more than 110 pizzas are consumed in a random sample of size 10 is 0.9646.

#SPJ11

Let us know more about probability: https://brainly.com/question/11034287.

The ratio of boys to girls at the play was 4 to 3. If there were 15 girls, how many boys were there?

Answers

Answer:

20 boys

Step-by-step explanation:

If there are 4 boys for every 3 girls, multiply both numbers by 5 (3*5 = 15) to find the number of boys.

Answer:

20

Step-by-step explanation:

4/3 = ?/15

multiply both sides by 15

15*4/3 = ?

? = 20

b. If each square has a side length of 61 cm, write an expression for the surface area and another for the volume of the figure

Answers

Answer:

6*(61^2) and 61^3

Step-by-step explanation:

If the squares have a side length of 61 (assuming this is a cube) our surface area is 6*(61^2) because each side is a square and there are six sides.

As for the volume, we have 61^3.

Hope this was helpful.

~cloud

we used the Optional Stopping Theorem to solve the Gambler's Ruin Problem. Specifically, we showed that if Sn So +?=1X; is a biased random walk starting at So = 1, where the steps X; are independent and equal to +1 with probability p1/2 and equal to - 1 with the remaining probability q=1 – p, then the probability of hitting N (jackpot") before 0 ("bust") is (g/p) - 1 PJ So = 1) = (g/p)N-1 Recall that the key to this was the martingale Mn = (g/p)Sn, which is only useful when pq. (a) For any pe [0, 1], argue that P(T<) = 1, where T = inf{n> 1: Sne {0,1}} is the first time that the walk visits 0 or N. Hint: One way is to consider each time that the walk visits 1 before time T, and then compare with a geometric random variable. Note: This is the one condition in the Optional Stopping Theorem that we did not verify during the lecture. (b) Find P(J|So = n) when instead So = n, for some 1

Answers

(a) To argue that P(T < ∞) = 1, where T is the first time the walk visits 0 or N, we can consider each time the walk visits 1 before time T.

Suppose the walk visits 1 for the first time at time k < T. At this point, the random walk is in a state where it can either hit 0 before N or hit N before 0.

Let's define a new random variable Y, which represents the number of steps needed for the walk to hit either 0 or N starting from state 1. Y follows a geometric distribution with parameter p since the steps are +1 with probability p and -1 with probability q = 1 - p.

Now, we can compare the random variable T and Y. If T < ∞, it means that the walk has hit either 0 or N before reaching time T. Since T is finite, it implies that the walk has hit 1 before time T. Therefore, we can say that T ≥ Y.

By the properties of the geometric distribution, we know that P(Y = ∞) = 0. This means that there is a non-zero probability of hitting either 0 or N starting from state 1. Therefore, P(T < ∞) = 1, as the walk is guaranteed to eventually hit either 0 or N.

(b) To find P(J|So = n), where So = n, we need to determine the probability of hitting N before hitting 0 starting from state n.

Recall that the probability of hitting N before 0 starting from state 1 is given by (g/p)^(N-1), as shown in the Optional Stopping Theorem formula. In our case, since the walk starts at state n, we need to adjust the formula accordingly.

The probability of hitting N before 0 starting from state n can be calculated as P(J|So = n) = (g/p)^(N-n).

This probability takes into account the number of steps required to reach N starting from state n. It represents the likelihood of hitting the jackpot (N) before going bust (0) when the walk starts at state n.

It's worth noting that this probability depends on the values of p, q, and N.

To know more about Optional Stopping Theorem refer here:

https://brainly.com/question/31828935#

#SPJ11

For f, g € L’[a,b], prove the Cauchy-Schwarz inequality |(f,g)| = ||$||||$||. = Hint: Define a function Q(t) = (f + tg, f + tg) for any real number t. Use the rules of inner product to expand this expression and obtain a quadratic polynomial in t; because Q(t) > 0 (why?), the quadratic polynomial can have at most one real root. Examine the discriminant of the polynomial.

Answers

Given that f, g ∈ L’[a, b], we need to prove the Cauchy-Schwarz inequality, |(f, g)| = ||$|| . ||$||.

The Cauchy-Schwarz inequality for inner product in L’[a, b] states that for all f, g ∈ L’[a, b],|(f, g)| ≤ ||$|| . ||$||Proof: Consider a function Q(t) = (f + tg, f + tg) for any real number t. Then, by using the rules of inner product, we can expand this expression and obtain a quadratic polynomial in t.$$Q(t) = (f + tg, f + tg) = (f, f) + t(f, g) + t(g, f) + t^2(g, g)$$$$ = (f, f) + 2t(f, g) + t^2(g, g)$$. Now, Q(t) > 0 because Q(t) is a sum of squares. So, Q(t) is a quadratic polynomial that can have at most one real root since Q(t) > 0 for all t ∈ R.

To find the discriminant of Q(t), we need to solve the equation Q(t) = 0.$$(f, f) + 2t(f, g) + t^2(g, g) = 0$$.

The discriminant of Q(t) is:$$D = (f, g)^2 - (f, f)(g, g)$$

Since Q(t) > 0 for all t ∈ R, the discriminant D ≤ 0.$$D = (f, g)^2 - (f, f)(g, g) ≤ 0$$$$\Right arrow (f, g)^2 ≤ (f, f)(g, g)$$$$\Right arrow |(f, g)| ≤ ||$|| . ||$||$$

Thus, |(f, g)| = ||$|| . ||$||, which proves the Cauchy-Schwarz inequality. Therefore, the given statement is true.

To know more about quadratic polynomial refer to:

https://brainly.com/question/26140455

#SPJ11

PLEASE HELPPPPPPPPPPPPPPPPPPPPPPPPPPP

Answers

Answer:

x = 5 ; z = 70

Step-by-step explanation:

Vertical angles have the same degree measure

(13x + 45) = 110

13x + 45 = 110

      -45     -45

13x = 65

/13     /13

x = 5

Complementary angles add up to 180°

110 + z = 180

-110         -110

z = 70

Answer:

X = 5º

Z = 70º

Step-by-step explanation:

So we know that vertical angles are congruent. So what we do to figure out x is set the equation equal to 110º because we are given that. And then we solve for x.

(13x + 45) = 110

13x + 45 = 110

      -45      -45

----------------------

13x = 65

÷13     ÷13

---------------

x = 5

Now, we plug x into the equation. (13x5 + 45) = 110 so we know that x = 5

Now, we also know that a straight line equals 180º so what we do is subtract 110 from 180.

180 - 110= 70º

z = 70º

A hiker is lost in the forest, but has his cell phone with a weak signal. Cell phones with GPS can give an approximate location through triangulation, which works by giving distances from two known points. Suppose the hiker is within distance of two cell phone towers that are 22.5 miles apart along a straight highway (running east to west, double-dashed line). Based on the signal delay, it can be determined that the signal from the hiker's phone is 14.2 miles from Tower A and 10.9 miles from Tower B. Assume the hiker is traveling a straight path south reach the highway quickly. How far must the hiker travel to reach the highway

Answers

Answer:

The distance the hiker must travel is approximately 5.5 miles

Step-by-step explanation:

The distance between the two cell phone towers = 22.5 miles

The distance between the hiker's phone and Tower A = 14.2 miles

The distance between the hiker's phone and Tower B = 10.9 miles

The direction of the highway along which the towers are located = East to west

The direction in which the hiker is travelling to reach the highway quickly = South

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(A)

Let 'a', 'b', and 'c', represent the sides of the triangle formed by the imaginary line between the two towers, the hiker's phone and Tower A, and the hiker's hone and tower B respectively, we have;

a = 22.5 miles

b = 14.2 miles

c = 10.9 miles

Therefore, we have;

22.5² = 14.2² + 10.9² - 2 × 14.2 × 10.9 × cos(A)

cos(A) = (22.5² - (14.2² + 10.9²))/( - 2 × 14.2 × 10.9) ≈ -0.6

∠A = arccos(-0.6) ≈ 126.9°

By sine rule, we have;

a/(sin(A)) = b/(sin(B)) = c/(sin(C))

∴ sin(B) = b × sin(A)/a

∴ sin(B) = 14.2×(sin(126.9°))/22.5

∠B = arcsine(14.2×(sin(126.9°))/22.5) ≈ 30.31°

∠C = 180° - (126.9° - 30.31°) = 22.79° See No Evil

The distance the hiker must travel, d = c × sin(B)

∴ d = 10.9 × sin(30.31°) ≈ 5.5

Therefore, the distance the hiker must travel, d ≈ 5.5 miles.

In the woods, a hunter is shooting at a hare. The probability of success for his first shot is 12. If he misses his first shot, the probability of success for his second shot is 1/4. If he misses his second shot, the probability of success for his third shot is 1/8. If he misses his third shot, the probability of success for his forth shot is 1/16. (1) The probability that he hits the hare within his first 2 shots is most nearly (a) 0.7 (b) 0.8 (c) 0.9 (d) 1 (2) The probability that he hits the hare within his first 3 shots is most nearly (a) 1 (b) 0.9 (c) 0.8 (d) 0.7 (3) The probability that he hits the hare within his first 4 shots is most nearly (a) 0.9 (b) 0.7 (c)1 (d) 0.8

Answers

The probability that he hits the hare within his first 4 shots is 0.8789.

Probability of success for the first shot = P1 = 12 Probability of missing the first shot = 1 – P1 = 1 – 12 = 12  Probability of

success for the second shot, given that the first shot missed = P2 = 14Hence, the probability that he hits the hare within

his first 2 shots is:P1 + (1 – P1)P2= 12+(12)×(14)= 12+16= 38(2) The probability that he hits the hare within his first 3 shots is

most nearly (a) 1 (b) 0.9 (c) 0.8 (d) 0.7We have to find the probability of hitting the hare within his first 3 shots. Probability

of success for the first shot = P1 = 12Probability of missing the first shot = 1 – P1 = 1 – 12 = 12Probability of success for the

second shot, given that the first shot missed = P2 = 14Probability of success for the third shot, given that the first two

shots missed = P3 = 18Hence, the probability that he hits the hare within his first 3 shots is:P1 + (1 – P1)P2 + (1 – P1)(1 –

P2)P3= 12+(12)×(14)+(12)×(34)×(18)= 12+16+18×(12)= 1316= 0.8125(3) The probability that he hits the hare within his first 4

shots is most nearly (a) 0.9 (b) 0.7 (c)1 (d) 0.8We have to find the probability of hitting the hare within his first 4

shots. Probability of success for the first shot = P1 = 12Probability of missing the first shot = 1 – P1 = 1 – 12 = 12Probability

of success for the second shot, given that the first shot missed = P2 = 14Probability of success for the third shot, given

that the first two shots missed = P3 = 18 Probability of success for the fourth shot, given that the first three shots missed

= P4 = 116Hence, the probability that he hits the hare within his first 4 shots is:P1 + (1 – P1)P2 + (1 – P1)(1 – P2)P3 + (1 – P1)

(1 – P2)(1 – P3)P4= 12+(12)×(14)+(12)×(34)×(18)+(12)×(34)×(78)×(116)= 12+16+18×(12)+18×(78)×(116)= 7892= 0.8789

Therefore, the answer is (d) 0.8.

Learn more about probability:https://brainly.com/question/13604758

#SPJ11

Nicole has a bag filed win 8 red marbles 6 blue marbles and 9 green marbles. What is the probability of her choosing a red marble, then a blue marble without replacing them​

Answers

Answer:

34.78

Step-by-step explanation:

8/23

2/5+3/6 GETS BRAINLIEST​

Answers

Answer:

27/30

Step-by-step explanation:

yepyffghhhhgghjj

Answer:

9/10 or 0.9

Step-by-step explanation:

When adding fractions, you look at each of them as an equal number, or a whole.

25+36

91

So, now all we have to do is convert it to it's closest form. (In tenths, since we are adding tenths.)

90

And it would be 9/10, or 0.9

Hope this helps!

The cost of a banquet at Nick's Catering is $215 plus $27.50 per person. If
the total cost of a banquet was $2827.50, how many people were invited?​

Answers

Answer:

x = 95

Step-by-step explanation:

Given that,

The cost of a banquet at Nick's Catering is $215 plus $27.50 per person

The total cost of a banquet was $2827.50

We need to find the number of people invited. Let there are x people. So,

215+27.5x = 2827.50

27.5x = 2827.50 -215

27.5x = 2612.5

x = 95

So, there are 95 people that were invited.

Other Questions
which of the following is an advantage of aquaculture expansion? i.highly efficient ii.uses less water iii.uses less fuel iv.Prevents diseasea.i only ii only b.i and ii only , c.i, ii, and iiid.Hi, iii, iv Your portfolio is comprised of 40% of Stock A, 15% of Stock B, and 45% of Stock C. Stock A has a beta of 1.16, Stock B has a beta of 1.47, and Stock C has a beta of 1.72. What is the beta of your portfolio? O 1.05 O 1.87 O 1.46 O 1.23 O 1.37 Calculate the end areas for depths of fill from 0 to 20 ft using increments of 2 ft for level sections, a 58-ft-wide level roadbed with side slopes of 1:1. complete at least one practical activity related to business ,and fill in the practice report.The practice report includes threeparts: Practice process record, Practice acquisition and feeling,and Find the potential function f for the field F.F =1/z i-5j-x/z^2 k Identify the graph and describe the solution set of this system of inequalities.y < -3x - 2y > -3x + 8a. Linear graph; solution set is a line segment.b. Parabolic graph; solution set is a parabola.c. Hyperbolic graph; solution set is a hyperbola.d. Circular graph; solution set is a circle. Financial projections for a Poultry Egg Farming with the given details belowexplain key assumptions and features of the financial modelinclude detailed income and expenditure and cash flow forecastsdetail the level of working capital required to run the businessidentify the nature of potential returns Exercise 9.2 Packets of nuts Quantity Marginal Utility Quantity Marginal Utility 1 50 1 30 40 2 25 3 30 3 15 4 25 4 In the table above, if Avu maximizes his utility by consuming 2 packets of nuts and 4 cans of juice, then the ratio of the price of nuts to the price of juice must be: A. 3/1 B. 2/1 C. 1/4 D. 1/3 E. 4/1 2 The average number of miles (in thousands) that a car's tire will function before needing replacement is 64 and the standard deviation is 12. Suppose that 14 randomly selected tires are tested. Round all answers to 4 decimal places where possible and assume a normal distribution. A. If a randomly selected individual tire is tested, find the probability that the number of miles (in thousands) before it will need replacement is between 60.6 and 65. B. For the 14 tires tested, find the probability that the average miles (in thousands) before need of replacement is between 60.6 and 65. You are the portfolio manager at Financial Trust Ltd, an investment firm that is restructuring a variable income portfolio to meet the objectives of a client. The client plans to retire in 10 years and wants to diversify his portfolio to reduce his risk. You look at a group of securities on the JSE. Based on five years of monthly data, you derive the following information for four companies listed on the JSE which are given in the following table:Firm Std deviation i Correlation rim GK 12.10%, 0.72 LASCO 14.60%, 0.33 GLX 7.60%, 0.55 CARR 10.20 0.60 JSE Index 5.50 1.00 Required:A. Determine the beta coefficient for each stock. (6 m arks)B. Assuming a risk-free rate of 8 percent and an expected return for the market portfolio of 15 percent, compute the expected (required) return for all the stocks. (8 marks) Financial Analysts estimated returns for the next year are as follows: i. GK 20 percent ii. LASCO 15 percent iii. GLX 19 percent iv. CARR 10 percentC. Advise the client as to which stocks to hold and which ones to sell. answer should be in paragraphthank you for your helpall the updates now? Drive Safely J5 Jungle Scout 21 of 176 > Aa How would you act in the following situations? Why? How is your personal value system reflected in your choice? 1. You buy a candy bar What direction do you predict the addition of a base to the solution containing bromophenol blue will drive the equilibrium? Explain your prediction in terms of le chatelier principle nuclear fusion occurs in stars. please select the best answer from the choices provided true or false how the artist choses to position the audience in relation to artworks subject effects what? 1. There are several reasons why management may present biased information in the financial statements. Briefly identify any two such motivations.2. Explain the difference between principles-based and rules-based accounting standards. Are IFRS and ASPE considered more principles-based or rules based? Briefly explain.3. Accounting standards for Private Enterprises (ASPE) are geared towards fewer users who have access to additional information about the company. Although IFRS is not required for private enterprises, give a reason why a private company might choose to voluntarily adopt IFRS. The trial balance of Mendez Company at the end of its fiscal year, August 31, 2021, includes these accounts: Beginning Inventory $18,700, Purchases $154,000, Sales Revenue $190,000, Freight-In $8,000, Sales Returns and Allowances $3,000, Freight-Out $1,000, and Purchase Returns and Allowances $5,000. The ending inventory is $21,000. Instructions: Prepare a cost of goods sold section (periodic system) for the year ending August 31, 2021. t/f trophic structure refers to the pattern of food consumption in an ecosystem.\ Consider the following balanced equation: 2N2H4(g) + N2O4(g) + 3N2(g) + 4H2O(g) Complete the following table showing the appropriate numbers of moles of reactants and products. If the number of moles of a reactant is provided, fill in the required amount of the other reactant, as well as the moles of each product formed. If the number of moles of a product is provided, fill in the required amount of each reactant to make that amount of product, as well as the amount of the other product that forms. An article in the journal Applied Nutritional Investigation reported the results of a comparison of two different weight-loss programs (Liao, 2007). In the study, obese participants were randomly assigned to one of two groups and the percent of body fat loss was recorded. The soy group, a low-calorie group that ate only soy-based proteins (M= 2.95, s=0.6), while the traditional group, a low-calorie group that received 2/3 of their protein from animal products and 1/3 from plant products (M= 1.92, $=0.51). If S_M1-M2 = 0.25, s^2_pooled = 0.3, n_1 =9, n_2 = 11 is there a difference between the two diets. Use alpha of .05 and a two-tailed test to complete the 4 steps of hypothesis testing case manager in a rehabilitation facility is discussing discharge plans with a client who has a pressure injury and requires a special bed at home. Which of the following statements should the nurse make first? a. "Apply moisture barrier ointment three times a day." b. "Eat a balanced diet with high-protein snacks." c. "A social worker can help you with the cost of supplies." d. "Describe the place where you are currently living."