Considering the following precipitation reaction:
Pb(NO3)2(aq) + 2KI(aq) → PbI2(s) + 2KNO3(aq)
Which ion(s) would NOT be present in the net ionic equation?
A) Pb2+, NO3-
B) K+, NO3-
C) K+, Pb2+
D) K+, I-

Answers

Answer 1

The  ion(s) would NOT be present in the net ionic equation will be[tex]Pb^{2+[/tex], [tex]NO^{3-}[/tex]

Option (a) is correct.

To determine which ions would not be present in the net ionic equation, we need to identify the spectator ions. Spectator ions are the ions that do not participate in the chemical reaction and remain unchanged throughout the reaction.

The net ionic equation represents the chemical equation after removing the spectator ions. We can determine the spectator ions by comparing the initial and final compounds and identifying which ions remain the same on both sides of the reaction.

Let's analyze the given reaction:

[tex]Pb(NO_3)_2(aq) + 2KI(aq)[/tex] → [tex]PbI_2(s) + 2KNO_3(aq)[/tex]

The balanced equation shows that [tex]Pb^{2+[/tex] and [tex]2NO_3^-[/tex] ions combine with 2K+ and 2I- ions to form [tex]PbI_2(s)[/tex] and [tex]2KNO_3(aq)[/tex]. In the reaction, the [tex]NO_3^-[/tex]ions are part of both the starting compound [tex](Pb(NO_3)_2)[/tex]and the product compound [tex](KNO_3)[/tex]. Therefore, the [tex]NO_3^-[/tex] ions are spectator ions and would not be present in the net ionic equation.

Now, let's consider the answer choices:

A) [tex]Pb^{2+}, NO_3[/tex]-: [tex]NO_3^-[/tex] ions are spectator ions, so this option is correct.

B) [tex]K+, NO_3[/tex]-:[tex]NO_3^-[/tex] ions are spectator ions, so this option is correct.

C) [tex]K^+, Pb^{2+}[/tex]: Both [tex]K^+[/tex] and [tex]Pb^{2+}[/tex] ions participate in the reaction, so this option is incorrect.

D) [tex]K^+, I^-[/tex]: Both [tex]K^+[/tex] and[tex]I^-[/tex] ions participate in the reaction, so this option is incorrect.

Therefore, the correct answer is:

A) [tex]Pb^{2+}, NO_3^-[/tex]

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Related Questions

1 MLR3 → 1 MR + 1 LR2

If 23.5 grams of MLR3 react, how many moles of MR are produced?

Answers

2 sorry this isn’t an answer i just need points so i can ask a test question

Sarah and Jim investigated the effect of temperature on the solubility of copper sulphate. They dissolved copper sulphate crystals in the same volume of water until no more would dissolve. They measured the mass of copper using water at different temperatures.
One of the mass readings appears to be wrong ( anomalous ) which reading is anomalous? Use the graph to help you.

Answers

Answer:

Explanation:

H m sarav

Use the food web below to answer the following
question.
Frog
Red fox
Grasshopper
Weasel
Goldfinch
Great horned om
Clover
Deer mouse
Which group is not represerted in the food web?
A. producers
B. primary consumers
C. secondary consumers
D. decomposers

Answers

Answer:

uhm i believe its D hope i helped

Explanation:

Answer:

D. decomposers

How many grams of calcium carbonate, CaCO3, contain 48 grams of oxygen atoms?

A) 41
B) 50
C) 62
D) 88
E) 100

Answers

Answer:

(40 g O) / (15.99943 g O/mol) x (1 mol CaCO3 / 3 mol O) x (100.0875 g CaCO3/mol) =  

83 g CaCO3

So answer D), although three significant digits are not justified.

Your welcome! Please give me brainiest and have a Great day! <3

2. The density of helium is 1.78 X 104 g/cm. What is this
density in Dg/um??

Answers

Answer:

[tex]d=1.78\times 10^{-7}\ Dg/\mu m^3[/tex]

Explanation:

Given,

The density of Helium is [tex]1.78\times 10^4\ g/cm^3[/tex]

We need to find the density in Dg/μm

We know that,

1 g = 10 dg

1 cm³ = 10¹² μm³

So,

[tex]d=1.78 \times 10^4\ g/cm^3\\\\=1.78 \times 10^4\times \dfrac{10\ dg}{10^{12}\ \mu m^3}\\\\=1.78\times 10^{-7}\ Dg/\mu m^3[/tex]

So, the density of Helium is equal to [tex]1.78\times 10^{-7}\ Dg/\mu m^3[/tex].

calculate the temperature (in°c) at which pure water would boil at a pressure of 537.7 torr. hvap = 40.7 kj/mol

Answers

At a pressure of 537.7 torr, pure water would boil at approximately 95.8°C.

To calculate the boiling point of water at a given pressure, we can use the Clausius-Clapeyron equation:

ln(P2/P1) = (-ΔHvap/R) × (1/T2 - 1/T1)

where:

P1 and P2 are the initial and final pressures,

ΔHvap is the molar enthalpy of vaporization,

R is the ideal gas constant (8.314 J/(mol·K)),

T1 is the initial temperature,

T2 is the final temperature.

In this case, we want to find the boiling point (T2) of water at a pressure of 537.7 torr. The normal boiling point of water is 100°C (373.15 K) at atmospheric pressure (760 torr).

We can rearrange the equation to solve for T2:

T2 = (1/(((-ΔHvap/R) × (1/T1)) + (ln(P2/P1))))

Substituting the given values:

P1 = 760 torr

P2 = 537.7 torr

ΔHvap = 40.7 kJ/mol (convert to J/mol by multiplying by 1000)

R = 8.314 J/(mol·K)

T1 = 373.15 K

T2 = (1/(((-40.7 kJ/mol × 1000 J/kJ) / (8.314 J/(mol·K)) × (1/373.15 K)) + (ln(537.7 torr/760 torr))))

Calculating this expression gives us:

T2 ≈ 95.8°C

Therefore, at a pressure of 537.7 torr, pure water would boil at approximately 95.8°C.

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Which wavelength corresponds to photons with a greater energy?
a. 320 nm
b. 530 nm
c. they are equal in energy

Answers

The wavelength that corresponds to photons with greater energy is 320 nm. Hence, option a is correct.

The energy of a photon is inversely proportional to its wavelength according to the equation:

E = hc/λ

where E is the energy of the photon, h is Planck's constant (approximately 6.626 x 10^-34 J·s), c is the speed of light (approximately 3.00 x 10^8 m/s), and λ is the wavelength of the photon.

Since energy (E) is inversely proportional to wavelength (λ), shorter wavelengths correspond to photons with greater energy. Therefore, the photon with a wavelength of 320 nm has greater energy compared to the photon with a wavelength of 530 nm.

The wavelength that corresponds to photons with greater energy is 320 nm (option a).

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Hydrogen peroxide and water both contain the same two elements. Write their chemical formulas. Compare and contrast their properties. Explain the importance of writing correct chemical formulas

Answers

Hydrogen peroxide and water both contain the same two elements. The chemical formulas of hydrogen peroxide and water are respectively H2O2 and H2O. The two compounds have distinct physical and chemical properties. Here is a long answer to the question posed.



Water is a colorless, odorless, and tasteless liquid that is vital for life. Its melting point is 0 degrees Celsius, while its boiling point is 100 degrees Celsius. Water is the most prevalent chemical substance on Earth, with about 71% of the planet's surface covered by it.

Hydrogen peroxide is a pale blue liquid that is slightly more viscous than water. It has a bitter taste, and its odor is similar to that of bleach. The boiling point of hydrogen peroxide is 150.2°C, while the melting point is -0.43°C. Hydrogen peroxide is a powerful oxidizer that is commonly used as a bleaching agent, disinfectant, and antiseptic.


Chemical formulas are utilized in a variety of scientific applications, including chemical reactions and product descriptions. An incorrect chemical formula can have significant ramifications, potentially resulting in the formation of a hazardous substance.

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Se mezclan 20 gramos de agua (1cal/g°C) a 40 °C con 15 gramos de alcohol (0,58cal/g°C) a 30 °C. ¿Cuál ha sido la temperatura de equilibrio térmico?

Answers

Answer:

[tex]T_{EQ}=37\°C[/tex]

Explanation:

¡Hola!

En este caso, para los problemas de equilibrio térmico, consideramos que la energía liberada por la sustancia que inicialmente está caliente (agua), es absorbida por la sustancia que inicialmente está fría (alcohol); thus, we can write:

[tex]Q_{agua}=-Q_{alcohol}[/tex]

La cual puede ser escrita en términos de masa, calor specifico y temperaturas:

[tex]m_{agua}C_{agua}(T_{EQ}-T_{agua})=-m_{alcohol}C_{alcohol}(T_{EQ}-T_{alcohol})[/tex]

De este modo, al resolver para la temperature de equilibrio térmico, obtenemos la siguiente expresión:

[tex]T_{EQ}=\frac{m_{agua}C_{agua}T_{agua}+m_{alcohol}C_{alcohol}T_{alcohol}}{m_{agua}C_{agua}+m_{alcohol}C_{alcohol}}[/tex]

Así, al reemplazar los valores en esta, obtenemos:

[tex]T_{EQ}=\frac{(20g)(1cal/g\°C)(40\°C)+(15g)(0.58cal/g\°C)(30\°C)}{(20g)*(1cal/g\°C)+(15g)(0.58cal/g\°C)} \\\\T_{EQ}=37\°C[/tex]

¡Saludos!

using standard reduction potentials from the aleks data tab, calculate the standard reaction free energy ΔGD for the following redox reaction. round your answer to 3 significant digits.
I2 (s) + 6H20 (l) + 5Br2(l) --> 2IO3- (aq) + 12 H+ (aq) + 10 Br- (aq)

Answers

To calculate the standard reaction free energy (ΔG°) for the given redox reaction, we need to use the standard reduction potentials from the ALEKS data tab.

To calculate the standard reaction free energy (ΔG°) for the given redox reaction, we need to utilize the standard reduction potentials (E°) of the involved species. The ΔG° is related to the standard reduction potentials through the equation: ΔG° = -nFΔE°, where n represents the number of electrons transferred and F is the Faraday constant.

Let's analyze the reaction and identify the half-reactions to determine the number of electrons transferred.

Half-reaction 1: I2(s) + 2e- → 2I- (aq)

Half-reaction 2: Br2(l) + 2e- → 2Br- (aq)

Half-reaction 3: 6H2O (l) → 12H+ (aq) + 6e-

Half-reaction 4: 2IO3- (aq) + 12H+ (aq) + 10e- → I2 (s) + 6H2O (l)

By comparing the half-reactions, we can see that 5 electrons are transferred in the reaction.

For the oxidation reactions:

   2IO3- (aq) + 12H+ (aq) + 10Br- (aq) → I2 (s) + 6H2O (l) + 5Br2 (l): coefficient = 1

Now we can calculate ΔGᴰ:

ΔGᴰ = (1 * E°(I2/I-)) + (5 * E°(Br2/Br-)) + (3 * E°(H2O/O2)) - (1 * E°(IO3-/H2O/Br2))

Substituting the values:

ΔGᴰ = (1 * 0.536 V) + (5 * 1.087 V) + (3 * 1.229 V

ΔE° = E°(half-reaction 4) - [E°(half-reaction 1) + E°(half-reaction 2) + E°(half-reaction 3)]

After obtaining ΔE°, we can calculate the standard reaction free energy (ΔG°) using the equation ΔG° = -nFΔE°. Since we know n = 5 and F is a constant, we can substitute these values into the equation to calculate ΔG°.

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Describe reflection, refraction, and absorption.

Answers

Answer:

Refraction is the bending of a wave when it enters a medium where its speed is different, like going from the air (gas) to a glass of water (liquid). Absorption is when light energy penetrates an object. Typically this energy is then converted to heat.

A sample of 0.2140 g of an unknown monoprotic acid was dissolved in 25.0 mL of water and titrated with 0.0950 M NaOH. The acid required 27.4 mL of base to reach the equivalence point.
What is the molar mass of the acid?
After 15.0 mL of base had been added in the titration, the pH was found to be 6.50. What is the Ka for the unknown acid?

Answers

The molar mass of the acid is 82.0 g/mol. The Ka of the unknown acid is  1.69 × 10⁻⁶.

How to determine molar mass and Ka?

Molar mass of the acid:

The molar mass of the acid can be calculated using the following equation:

Molar mass = mass / moles

The mass of the acid is 0.2140 g and the moles of the acid can be calculated using the following equation:

moles = volume × concentration

The volume of NaOH used to reach the equivalence point is 27.4 mL and the concentration of NaOH is 0.0950 M.

moles of NaOH = 27.4 mL × 0.0950 M = 2.613 mmol

Since the acid and NaOH react in a 1:1 ratio, the moles of the acid is also 2.613 mmol.

Substituting these values into the first equation:

Molar mass = 0.2140 g / 2.613 mmol = 82.0 g/mol

Ka for the unknown acid:

The Ka for the unknown acid can be calculated using the following equation:

Ka = [H⁺][A⁻] / [HA]

where:

Ka is the acid dissociation constant

[H⁺] is the concentration of hydrogen ions

[A⁻] is the concentration of the conjugate base

[HA] is the concentration of the acid

The concentration of hydrogen ions can be calculated using the pH. The pH of the solution after 15.0 mL of base had been added is 6.50.

pH = -log[H⁺]

6.50 = -log[H⁺]

[H⁺] = 10^-6.50

[H⁺] = 3.162 × 10⁻⁷ M

The concentration of the conjugate base can be calculated using the following equation:

[A-] = moles of A- / volume of solution

The moles of A⁻ = the moles of NaOH added after 15.0 mL, which is 1.438 mmol. The volume of the solution is 25.0 mL + 15.0 mL = 40.0 mL.

[A⁻] = 1.438 mmol / 40.0 mL

[A⁻] = 3.595 × 10⁻³ M

The concentration of the acid can be calculated using the following equation:

[HA] = moles of HA / volume of solution

The moles of HA = the moles of acid, which is 2.613 mmol. The volume of the solution is 40.0 mL.

[HA] = 2.613 mmol / 40.0 mL

[HA] = 6.532 × 10⁻³ M

Substituting these values into the Ka equation:

Ka = (3.162 × 10⁻⁷ M)(3.595 × 10⁻³ M) / (6.532 × 10⁻³ M)

Ka = 1.69 × 10⁻⁶

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What is the Ka of a 0.0981 M
solution of hydrocyanic acid
(HCN) with a pH of 6.00?
Ka = [?] x 10!?)

Answers

Answer:

Attached picture

Ka = [?] x 10

1.02 x 10^-11 = [?] x 10

[?] = 1.02 (I'm assuming you're asking this)

(If not then divide the 10)

Answer:

The answer is 1.02x10^-11

Explanation:

Fill in the box 1.02 and then -11

Which of the following statement is not true?

Answers

Answer: 2

Explanation: Greenhouse gases are very important in keeping our planet just right. If we have too many Greenhouse gases it would be too hot, but we can't eliminate all of them or it will be too cold

What makes sound waves different from light waves?

Answers

Answer:

Light waves are electromagnetic waves while sound waves are mechanical waves. light waves are transverse while sound waves are longitudinal. sound waves require a material medium to travel, and hence, cannot travel in a vacuum. the speed of light in a medium is constant.

Explanation:

Hope this helped Mark BRAINLIEST!!

Uma peça de metal de formato irregular feita de uma liga particular foi galvanizada com zinco usando uma solução de Zn(NO₃)₂. Quando uma corrente de 2,70 A foi usada, levou exatamente 1 hora para depositar uma camada de 0,015 mm de zinco na peça. Qual é a área total de superfície da peça? A densidade do zinco é de 7,14 g /cm³. Suponha que a eficiência seja 100%. MM (Zn) = 65,4 g/mol; 1 mol e = 96500 C.

Answers

No co hao mi cho cu lo who

Which of the following balances has the least uncertainty? (PSS.1)
Group of answer choices

platform balance, +/- 0.1 g

analytical balance, +/- 0.0001 g

All balances have the same uncertainty

triple-beam balance, +/- 0.01 g

electronic balance, +/- 0.001 g

Answers

Answer:


Analytical balance


That should be the answer

The mixtures of sodium carbonate and calcium nitrate react to participate calcium carbonate and sodium nitrate. This reaction is shown by which balanced chemical equation?

Answers

Explanation:

Na2CO3+Ca(No3)2---> CaCO3+2NaNo3

Given that there are more possible combinations for amino acids than amino acids themselves, what does this imply about the number of codes for each amino acid?

Answers

The fact that there are more possible combinations for amino acids than the number of amino acids themselves implies that each amino acid can be encoded by multiple codons.

A codon is a sequence of three nucleotides in DNA or RNA that corresponds to a specific amino acid.

There are 20 standard amino acids used to build proteins in living organisms. However, there are 64 possible three-letter combinations of nucleotides (4³) that can be used to form codons. This means that on average, there are more than three codons that can encode each amino acid.

To calculate the number of codons per amino acid on average, we divide the total number of codons (64) by the number of amino acids (20). Therefore, the average number of codons per amino acid is 64/20 = 3.2.

This indicates that there is a degeneracy or redundancy in the genetic code, where multiple codons can specify the same amino acid.

For example, the amino acid leucine is encoded by six different codons (UUA, UUG, CUU, CUC, CUA, CUG), while methionine and tryptophan are each encoded by a single codon.

In conclusion, the existence of more possible combinations for amino acids than amino acids themselves means that the genetic code is degenerate, allowing for redundancy and flexibility in protein synthesis.

This redundancy helps to protect against errors in DNA replication and transcription and allows for evolution to occur through the accumulation of genetic variations.

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Calculate the mass in grams of 3.6 mol of iron(II) hydroxide. ​

Answers

Your answer is 323.494848

this is due in five mintues please help

Answers

Answer:

5

Explanation:

Na, N, O, O, O

acid-catalyzed addition of alcohols to alkenes proceeds in a mechanism analogous to the acid-catalyzed addition of water to yield ethers. true or false

Answers

We can see here that the acid-catalyzed addition of alcohols to alkenes proceeds in a mechanism analogous to the acid-catalyzed addition of water to yield ethers. True.

What is alcohol?

Alcohol is a broad term that refers to a class of organic compounds characterized by the presence of a hydroxyl (-OH) functional group attached to a carbon atom.

The acid-catalyzed addition of alcohols to alkenes is a useful reaction for the synthesis of ethers. It is also a relatively mild reaction, which makes it a good choice for the synthesis of ethers from sensitive compounds.

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How is activation energy represented on an energy diagram?
Energy
Reactants
Products
Reaction Progress
O A. Activation energy is the distance from the reactants to the top of
the "hill."
B. Activation energy is the distance from the top of the "hill to the
products.
O C. Activation energy is the final energy level of the product
molecules.
o
D. Activation energy is the starting energy level of the reactant
molecules.

Answers

In accordance with the diagram, activation energy is the distance from the reactants to the top of the "hill"

The activation energy represented on the energy diagram is as given as

"Activation energy is the distance from the reactant to the top of the hill"

So, the correct option is A.

What is activation energy?

The minimum amount of energy required by the reactant to do the reaction is called activation energy.

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What is the mass of sulfuric acid, H2SO4, that is contained in 2.0 L of a 5.85 M solution ?
A-1147.44 grams
B- 0.12 grams
C-11.7 grams
D-98.07 grams

Answers

D.-98.07 Grams this means that every mole of sulfuric acid has a mass of 98.0795g.

Rank the following fatty acids a coording to their melting point, from highest melting point to lowest melting point. Rank from highest melting point to lowest melting point. To rank items as equivalent, overlap them.

Answers

The ranking of the given fatty acids according to their melting point is Stearic acid > Palmitic acid > Lauric acid > Myristic acid > Oleic acid > Linoleic acid.

1. Stearic acid: Stearic acid has a long chain of 18 carbon atoms with no double bonds, resulting in a tightly packed structure. It has the highest melting point among the given fatty acids.

2. Palmitic acid: Palmitic acid also has a long chain of 16 carbon atoms with no double bonds. While it is slightly shorter than stearic acid, it still has a high melting point.

3. Lauric acid: Lauric acid contains 12 carbon atoms and no double bonds. It has a slightly lower melting point compared to palmitic acid and stearic acid.

4. Myristic acid: Myristic acid consists of 14 carbon atoms and no double bonds. It has a slightly lower melting point compared to lauric acid.

5. Oleic acid: Oleic acid is an unsaturated fatty acid with one double bond, located at the 9th carbon atom. It has a lower melting point compared to the saturated fatty acids listed above.

6. Linoleic acid: Linoleic acid is a polyunsaturated fatty acid with two double bonds, located at the 9th and 12th carbon atoms. It has the lowest melting point among the given fatty acids due to the presence of multiple double bonds, which disrupt the packing of the fatty acid chains.

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if you wish to observe features that are around the size of atoms, say 6.5 × 10-10 m, with electromagnetic radiation, the radiation must have a wavelength of about the size of the atom itself. (a) What is its frequency? (b) What type of electromagnetic radiation might this be?

Answers

(a) The frequency of electromagnetic radiation required to observe features around the size of atoms is approximately 4.6 × 10⁻¹⁹ Hz, (b) This type of electromagnetic radiation might be X-rays.

The relationship between the wavelength is (λ), frequency is (ν), and the speed of light is (c) is given by the equation c = λν. The atom size and the size of the wavelength should be same. Therefore, λ ≈ 6.5 × 10⁻¹⁰ m. Now, rearranging and solving,

ν = c/λ

ν = (3×10⁸m/s)/(6.5×10⁻¹⁰m)

ν ≈ 4.6 × 10¹⁹ Hz

Hence, the frequency of electromagnetic radiation required to observe features around the size of atoms is approximately 4.6 × 10¹⁹ Hz. This is X-rays.

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Hello Friends Can Yall Plz Help Me For Brainliest Don’t Comments No B.S Yu Will Get Cursed out show ya work

Answers

Answer:

it is b

Explanation:

mid ocean ridge diverges meaning it moving in two different direction horizontally - left to right

Help pls what is the (H+) of a solution with a pH of 4?
a. 1E-4 M
b. 0.602 M
c. 1E6 M
d. 1E4 M

Answers

Answer:

A

Explanation:

[H+] = 10^-pH

[H+] = 1 x 10^-4 M

The answer will be a I’m sure

Answer :A

Substances have a fixed arrangement of atoms. true or false (NO LINKS PLEASE)

Answers

Answer:

True

Explanation:

If HCl is a weaker acid than HI, why is ClCH2COOH a stronger acid than ICH2COOH?
a.)Because Cl is more electronegative than I.
b.)Because ICH2COO− is more stable than ClCH2COO−
c.)Because the size of Cl atom is greater than the size of I atom.
d.)Because I− is more stable than Cl−

Answers

The correct option is A. Because Cl is more b electronegative than I.

Both ICH2COOH and ClCH2COOH are members of the carboxylic acid family. The acidity of carboxylic acids is generated by their carboxyl group (-COOH). When it comes to acidity, there are numerous factors to consider. The acidity of a carboxylic acid is determined by its carboxyl group and the substituents on the carbon atom adjacent to the carboxyl group. In the case of carboxylic acids, the strength of the acid increases as the substituents on the carbon atom adjacent to the carboxyl group become increasingly electron-withdrawing or electronegative.

A carboxylic acid with a strong electron-withdrawing substituent on the adjacent carbon atom is more acidic than a carboxylic acid with a weak electron-withdrawing substituent on the adjacent carbon atom. When we look at the two molecules, ICH2COOH and ClCH2COOH, we see that they have the same chemical structure except for the halogen substituent. The electronegativity of Cl is more than that of I, which means that Cl is more electron-withdrawing than I. As a result, ClCH2COOH has a stronger electron-withdrawing group attached to it, making it a stronger acid than ICH2COOH. Therefore, the correct option is A. Because Cl is more electronegative than I.

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You are an analyst for a large company, the CFO provides details of NZD:USD in March 2020. Specifically he mentions that the New Zealand dollar changed from USD 0.6526 on the 6 March to USD 0.6332 on the 20 March. (1) What are the USD:NZD rates for these dates and did the NZ dollar appreciate or depreciate against USD over this period? (11) By how much (percent) did the NZ dollar change in value against the US dollar? Show your calculations ZA=6x-18HELP NOW!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!ZB=14x + 38BA Which is the most likely cause of the spike in cotton production in Mississippi in the mid-1800s A rocket sled moves along the horizontal plane under the presence of a friction force mg, where m is the mass of the sled at that moment and is the coefficient of kinetic friction. The rocket propels itself by ejecting mass at a constant rate dm/dt = R (R is a positive number, because the sleds mass is decreasing with time), and the fuel is ejected at a constant speed u relative to the sled. The sled starts from rest with initial mass M, and stops ejecting fuel when half the mass has been expended. A) How long does it take for the sled to finish ejecting i the complex set of interrelated activities comprising the social organization can be coordinated to a social map that is called . Consider the integral Jeliza |iz| + z dz (a) Compute the above integral when I is the circle 1-1 = 2, traversed once counterclockwise. (b) Give the value of the integral when I is the circle [2] = 2 traversed 6 times clockwise. Broussard Skateboard's sales are expected to increase by 25% from $8.2 million in 2019 to $10.25 million in 2020. Its assets totaled $4 million at the end of 2019.Broussard is already at full capacity, so its assets must grow at the same rate as projected sales. At the end of 2019, current liabilities were $1.4 million, consisting of $450,000 of accounts payable, $500,000 of notes payable, and $450,000 of accruals. The after-tax profit margin is forecasted to be 5%, and the forecasted payout ratio is 70%. Use the AFN equation to forecast Broussard's additional funds needed for the coming year. Enter your answer in dollars. For example, an answer of $1.2 million should be entered as $1,200,000. Do not round intermediate calculations. Round your answer to the nearest dollar. what does shabby mean a) innocent b) old c) worn d) dull ?Q6: Let 8 be an angle in standard position lying in QII. If cos 0 = -a, where a [0,1), find sin 0 in terms of a. 1 1 Q7: Simplify the expression + 1 cosx 1+cosx Q8: Find the possible value(s) of x Dymac Appliances uses the periodic inventory system. Details regarding the inventory of appliances at January 1, purchases invoices during the next 12 months, and the inventory count at December 31 are summarized as follows: fill in the blank so that the output is a count of how many negative values are in temperatures? Computing and Recording Cost and Depreciation of Assets (Straight-Line Depreciation) LOB- 2,8-3 [The following information applies to the questions displayed below) Shahia Company bought a building for $84,000 cash and the land on which it was located for $109,000 cash. The company paid transfer costs of $11,000 ($5,000 for the building and $6,000 for the land) Renovation costs on the building before it could be used were $24,000 Jaden (single) has a traditional IRA to which he has made only deductible contributions. At the end of 2022, Jaden is 74 years old. Jaden's required minimum distribution (RMD) from his IRA for 2022 is $5,200. Before considering the RMD, Jaden's AGI is $102,000. Jaden does not itemize deductions. a. What is Jaden's AGI if Jaden receives the RMD and donates the $5,200 distribution proceeds to a qualifying charity? b. What is Jaden's AGI if Jaden directs the IRA trustee to transfer the $5,200 distribution directly to a qualifying charity as a qualified charitable donation (QCD)? You may erase an element into an arbitrary position inside a vector using an iterator. Write a function, removeAll(vector, value) which erases all copies of value found in the vector, and returns the number of elements removed. Hint: i = v.erase(i) sets the iterator i the element following the erased item. vectors.cpp 1 #include 2 using namespace std; 3 _____________4 int removeAll(vector int>& v, int value) 5 { 6 int removed{0}; 7 ______________8 return removed; 9 } CodeCheck Reset a) On 1st November 2021, Katherine received a birthday gift of a limited-edition white T-shirt from her father. On the same day, Katherine took this white T-shirt to Honest Cleaning Limited for cleaning. Honest Cleaning Limited is an old laundry company, it starts to operate on 1st March 2015 but Katherine never been there for cleaning clothes before. Katherine asked the owner if there was any exclusion clause or notice relating to the service of the company. The owner said he did not know. The owner of Honest Cleaning Limited gave a receipt to Katherine after receiving the payment of the cleaning fee of HK$650. At the back of the receipt there was a clause:"Honest Cleaning Limited accepts no responsibility for any loss of or any damage to any customers clothes given to us for cleaning, caused by whatever reasons including the negligence of our staff".On 9th November 2021, after returning back to Hong Kong from Singapore, Katherine went to Honest Cleaning Limited to get back his white T-shirt. In a surprise, she discovered that there were many red dots on her white T-shirt. Advise Katherine her legal rights in relation to Contract law. (15 marks) two contribution format income statements, one showing present operations and one snowing now operations would appear in the new equipment is purchased. 2. Refer to the income statements in (1). For the present operations and the proposed new operations, compute (a) the degree of operating leverage, (b) the break-even point in dollar sales, and (c) the margin of safety in dollars and the margin of safety percentage. 3. Refer again to the data in (1). As a manager, what factor would be paramount in your mind in deciding whether to purchase the new equipment? (Assume that enough funds are available to make the purchase.) 4. Refer to the original data. Rather than purchase new equipment, the marketing manager argues that the company's marketing strategy should be changed. Rather than pay sales commissions, which are currently included in variable expenses, the company would pay salespersons fixed salaries and would invest heavily in advertising. The marketing manager claims this new approach would increase unit sales by 30% without any change in selling price; the company's new monthly fixed expenses would be $623,616; and its net operating income would increase by 20%. Compute the company's break-even point in dollar sales under the new marketing strategy. Answer is not complete. Complete this question by entering your answers in the tabs below. Required 1 Required 2 Refer to the original data. Rather than purchase new equipment, the marketing manager argues that the company's marketing strategy should be changed. Rather than pay sales commissions, which are currently included in variable expenses, the company would pay salespersons fixed salaries and would invest heavily in advertising. The marketing manager claims this new approach would increase unit sales by 30% without any change in selling price; the company's new monthly fixed expenses would be $623,616; and its net operating income would increase by 20%. Compute the company's break-even point in dollar sales under the new marketing strategy. (Hint: figure out the new variable cost per unit by preparing the new contribution format income statement.) (Do not round intermediate calculations. Round your answer to the nearest whole dollar amount.) New break even point in dollar sales Required 3 Required 4 $ 211,584 Show less A Problem 5-29 Changes in Cost Structure; Break-Even Analysis; Operating Leverage; Margin of Safety [LO5-4, LO5-5, LO5-7, LO5-8] Morton Company's contribution format income statement for last month is given below. Sales (48,000 units $29 per unit) Variable expenses Contribution margin Fixed expenses Net operating income. $ 1,392,000 974,400 417,600 334,080 83,520 $ The industry in which Morton Company operates is quite sensitive to cyclical movements in the economy. Thus, profits vary considerably from year to year according to general economic conditions. The company has a large amount of unused capacity and is studying ways of improving profits. Required: 1. New equipment has come onto the market that would allow Morton Company to automate a portion of its operations. Variable expenses would be reduced by $8.70 per unit. However, fixed expenses would increase to a total of $751,680 each month. Prepare two contribution format income statements, one showing present operations and one showing how operations would appear if the new equipment is purchased. 2. Refer to the income statements in (1). For the present operations and the proposed new operations, compute (a) the degree of operating leverage, (b) the break-even point in dollar sales, and (c) the margin of safety in dollars and the margin of safety percentage. 3. Refer again to the data in (1). As a manager, what factor would be paramount in your mind in deciding whether to purchase the new equipment? (Assume that enough funds are available to make the purchase.) 4. Refer to the original data. Rather than purchase new equipment, the marketing manager argues that the company's marketing strategy should be changed. Rather than pay sales commissions, which are currently included in variable expenses, the company would pay salespersons fixed salaries and would invest heavily in advertising. The marketing manager claims this new approach would increase unit sales by 30% without any change in selling price; the company's new monthly fixed expenses would be $623,616; and its net operating income would increase by 20%. Compute the company's break-even point in dollar sales under the new marketing strategy. which of the following statements most directly relates to the broad economic goal of freedom? (4 points 10. The figure below represents different possible values of the future price per share (P) of a company's stock. P P* p*, represents the current (today's) price per share. Assuming the vertical dista Let G be an abelian group and n a fixed positive integer. Prove that H = {a^n | a G} is a subgroup of G As of the end of June, the job cost sheets at Racing Wheels, Inc., show the following total costs accumulated on three custom jobs. Job 102 Job 103 Job 104 Direct materiale Direet labor Overhead applied $17,000 $49,000 $59,000 12,000 28,300 43,000 5,160 12,169 18,490 49 Job 102 was started in production in May, and the following costs were assigned to it in May: direct materials, $12,000, direct labor, $3,500; and overhead, $1,505. Jobs 103 and 104 were started in June. Overhead cost is applied with a predetermined rate based on direct labor cost. Jobs 102 and 103 were finished in June, and Job 104 is expected to be finished in July. No raw materials were used indirectly in June. Using this information, answer the following questions. (Assume this company's predetermined overhead rate did not change across these months) 182. Complete the table below to calculate the cost of the raw materials requisitioned and direct labor cost incurred during June for each of the three jobs? 3. Using the accumulated costs of the jobs, what predetermined overhead rate is used? 4. How much total cost is transferred to finished goods during June? Complete this question by entering your answers in the tabs below. Rea and 2 Reg 3 Heq 4 Heg 1 and 2 Complete the table below to calculate the cost of the raw materials requisitioned and direct labor cost incurred during June for each of the three jobs. Direct Materials Job May June Total 102 103 104 Total Direct Labor. Job Total 102 103 104 Total May June the cost the raw materials requisitioned and direct labor cost incurred during each of the three jobs? 3. Using the accumulated costs of the jobs, what predetermined overhead rate is used? 4. How much total cost is transferred to finished goods during June? Complete this question by entering your answers in the tabs below. Req 1 and 2 Req 3 Req 4 Using the accumulated costs of the jobs, what predetermined overhead rate is used? Overhead Rate 1 Choose Denominator: Overhead Rate Choose Numerator: Job 102 1 Overhead rate 1 Job 103 1 Overhead rate Job 104 Overhead rate 1 1 1 < Req 1 and 2 = = = = Req 4 > www. 4. How much total cost is transferred to finished goods during June? Complete this question by entering your answers in the tabs below. Req 1 and 2 Req 3 Req How much total cost is transferred to finished goods during June? Direct Job Direct Materials Applied Overhead Total Cost Cost Transferred to Finished Goods Labor 102 $ 17,000 $ 12,000 103 49,000 28,300 104 59,000 43,000 Total 83,300