Find the area of the trapezoids

Answer:

3.14 * r * r = area of circle, 2 * 3.14 * r = circumference

Step-by-step explanation:

Remember these formulas, very important.

(a) The top of the ladder is sliding down the wall at a rate of 3/2 m/sec.

(b) The angle between the ladder and the ground is changing at a rate of 1/2 rad/sec.

To solve this problem, we can use related rates, considering the ladder as a right triangle formed by the ladder itself, the wall, and the ground.

Let's denote:

x: the distance from the base of the ladder to the house (in meters)

y: the height of the ladder on the wall (in meters)

θ: the angle between the ladder and the ground (in radians)

Given:

dx/dt = -2 m/sec (the rate at which the base of the ladder is moving away from the house)

Using the Pythagorean theorem, we have:

x^2 + y^2 = 5^2 (since the ladder has a length of 5 meters)

Taking the derivative of both sides with respect to time (t), we get:

2x(dx/dt) + 2y(dy/dt) = 0

(a) To find dy/dt:

We can solve the equation above for dy/dt:

2x(dx/dt) + 2y(dy/dt) = 0

2(3)(-2) + 2y(dy/dt) = 0 (substituting x = 3 and dx/dt = -2)

-12 + 2y(dy/dt) = 0

2y(dy/dt) = 12

dy/dt = 12/(2y)

dy/dt = 6/y

Now, we need to find y. Using the Pythagorean theorem again:

x^2 + y^2 = 5^2

3^2 + y^2 = 5^2

9 + y^2 = 25

y^2 = 25 - 9

y^2 = 16

y = 4 (taking the positive value as y represents a length)

Substituting y = 4 into dy/dt = 6/y:

dy/dt = 6/4

dy/dt = 3/2 m/sec

Therefore, the top of the ladder is sliding down the wall at a rate of 3/2 m/sec.

(b) To find dθ/dt:

We can use trigonometry to relate θ, x, and y:

tan(θ) = y/x

Differentiating both sides with respect to time (t), we get:

sec^2(θ)dθ/dt = (x(dy/dt) - y(dx/dt))/x^2

Substituting the given values:

sec^2(θ)dθ/dt = (3(3/2) - 4(-2))/3^2

sec^2(θ)dθ/dt = (9/2 + 8)/9

sec^2(θ)dθ/dt = (25/2)/9

sec^2(θ)dθ/dt = 25/18

Since sec^2(θ) is equal to 1 + tan^2(θ) and tan(θ) = y/x:

sec^2(θ) = 1 + (y/x)^2

sec^2(θ) = 1 + (4/3)^2

sec^2(θ) = 1 + 16/9

sec^2(θ) = (9 + 16)/9

sec^2(θ) = 25/9

Substituting sec^2(θ) = 25/9 into the equation:

(25/9)dθ/dt = 25/18

Simplifying and solving for dθ/dt:

dθ/dt = (25/18) * (9/25)

dθ/dt = 1/2 rad/sec

Therefore, (b) the angle between the ladder and the ground is changing at a rate of 1/2 rad/sec.

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Answer:

Answer:

3x-13+2x+4=116( the sum of two interior angle is epual to the sum of exterior angle )

5x =116-9

5x=107

x=21.4 degree

then

angle a= 3*21.4-13

a=51.2degree

angle b=2*21.4+2

b =44.8degree

Step-by-step explanation:

plz make me brainliest

Answer:

7,-7 are the solutions

Step-by-step explanation:

Not a perfect square so its

+-7

I would go with -7 since its the lowest amount

Answer:

-7

Step-by-step explanation:

Answer:

rap music

Step-by-step explanation:

^

Answer:

i’m not sure if these are right or not but

Step-by-step explanation:

the first one is no

i think the second one is no

i think the third one is yes

i think the fourth one is yes

i am not sure and i’m REALLY sorry if its wrong

Answer: the answer is 3/10

Step-by-step explanation: because its 3/10

Answer:

es

3/ 10

Step-by-st

:-):-):-):-):-)

Step-by-step explanation:

1) 40÷10

2) 40÷2

Answer:

72 degrees

Step-by-step explanation:

To determine the value of DBC, we first have to determine the value of q

Angle on a straight line = 180 degrees

7q - 46 + 3q + 6 = 180

10q - 40 = 180

collect like terms

10q = 180 + 40

10q = 220

q = 22

Substitute for q in angle dbc

3(22) + 6 = 72 degrees

Answer:

r = dx - de

Step-by-step explanation:

x = e + r/d

x - e = r/d

d (x - e) = r

dx- de = r

r = dx - de

Answer:

No such a triangle can not exist.  

Answer:

uhuhuhuhuhuhuhuhuhuhuh oh yeah

Step-by-step explanation:

Given, an equivalence relation ~ on a set S. Let a and b be two elements in the set S. Assuming that [a] and [b] are two equivalence classes under the equivalence relation ~. Now we need to prove that either [a] = [b] or [a] ∩ [b] = ∅ (disjoint).

Proof:If [a] and [b] are not equal, then there must be some element c in the intersection of the equivalence classes [a] and [b]. i.e, c belongs to [a] and c belongs to [b].Thus, [a] ∩ [b] is not empty.

Let x be an element in [a], then x~a, and a~c (since c belongs to [a]) and hence x~c. So, x belongs to [c] which implies that [a] is a subset of [c].Now, let y be an element in [b], then y~b, and b~c (since c belongs to [b]) and hence y~c. So, y belongs to [c] which implies that [b] is a subset of [c].Thus, both [a] and [b] are subsets of [c].

Therefore, if [a] and [b] are not equal, then [a] and [b] are both subsets of [c] and hence the intersection of [a] and [b] is not empty. Thus, [a] and [b] are not disjoint. Hence, the proof by contradiction.

Conversely, if [a] and [b] are disjoint, then [a] ∩ [b] = ∅. And thus, [a] is not equal to [b].Therefore, two equivalence classes under the equivalence relation ~ are either equal or disjoint.

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Answer:

Two solutions

Step-by-step explanation:

Given the functions Y = -x + 1 y = -x² + 4x − 2

Since they are both y values, we will equate them to have:

-x+1 = -x² + 4x − 2

Equate to zero

x²-x-4x+1+2=0

x²-5x+3 = 0

Since the resulting equation is quadratic (highest degree being 2), hence there will be two solutions to the equation

a. The area of the shaded region = (3x)(5x + 2y).

b. The area of shaded region = 2x(2xπ - 3x).

Given that,

We have to write an expression in factored form to represent the area of each shaded region.

We know that,

a. In the picture we can see that the shaded region.

The area of the shaded region is area of rectangle with vertical + area of rectangle Horizontal

The area of rectangle is length × width.

The area of the shaded region = (3x)(3x + y) + (2x + y)(3x)

The area of the shaded region = (3x)(3x + y + 2x + y)

The area of the shaded region = (3x)(5x + 2y)

Therefore, The area of the shaded region = (3x)(5x + 2y)

b. In the picture we can see that circle with shaded region,

The area of shaded region is area of the circle - area of the rectangle

The area of the circle is πr² and area of rectangle is length × width.

The area of shaded region = πr² - (l×w)

The area of shaded region = π(2x)² - (2x × 3x)

The area of shaded region = 4x²π - 6x²

The area of shaded region = 2x(2xπ - 3x)

Therefore, The area of shaded region = 2x(2xπ - 3x).

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Answer:

$97,894.33.

Step-by-step explanation

Answer:

4

Step-by-step explanation:

To find median, arrange the data set in ascending order. Then the middle term is the median

2 , 3 , 4 , 5 , 6

Median = 3rd term  = 4

Answer:

4 is the median

Step-by-step explanation:

From least to greatest:

2,3,4,5,6

Since the total values is odd, the middle number is the median

4 is the median

Answer:

7 people

Step-by-step explanation:

Chocolate: 350 / 100 = 3.5 x 2 = 7

Butter: 45 / 10 = 4.5 x 2 = 9

Eggs: 8 / 2 = 4 x 2 = 8

The amount of chocolate is the limiting factor as you have enough eggs for 8 people and enough butter for 9 people, but only enough chocolate for 7 people

The question is incomplete. The compete question is :

Saul decides to use the IQR to measure the spread of data. Saul calculates the IQR of the data set to be 27. Saul asks Jasmine to check his work. Saul copies the data in numerical order from least to greatest for Jasmine. 25, 30, 50, 50, 50, 50, 56, n, 250. What is the value of n that will make the IQR of the data set equal to 27?

Solution :

The inter quartile range is being measured as : 3rd quartile - 1st quartile

The 1st quartile = 25% mark

The 3rd quartile = 75% mark

The data set as given in the question is :

25, 30, 50, 50, 50, 50, 56, n, 250

Therefore, the total number of the sample = 9

And the median is = 50

The median separates the given data sets into two equal halves-- that is the upper half and the lower half.

Let the middle of a lower half is the 1st quartile be [tex]$Q_1$[/tex]

And the middle of a 2nd half is the 3rd quartile be [tex]$Q_3$[/tex]

∴ [tex]$Q_1=\frac{30+50}{2}$[/tex]

        [tex]$=40$[/tex]

  [tex]$Q_3=\frac{56+n}{2}$[/tex]

Now for the IQR of the data set to be equal to [tex]$27$[/tex],

[tex]$\frac{56+n}{2}-40=27$[/tex]

[tex]$\frac{56+n}{2}=27+40$[/tex]

[tex]$\frac{56+n}{2}=67$[/tex]

[tex]$56 +n=134$[/tex]

[tex]$n=134-56$[/tex]

[tex]$n=78$[/tex]

Answer:

2x^2-x-3

(2x)(-3)

(x)

(1)

Step-by-step explanation:

Distribute

(2x^2) (-3x)

(2x) (-3)

Answer:

answer is 65 in²

hope this helps

25

porque al multiplicar 25×25 nos da 625

Answer:

25

Step-by-step explanation:

25x25=625

The probability of getting four consecutive heads in four 2-sided coin tosses is 1/16 or 0.0625 or 6.25%.

The Probability is defined as a measure of the likelihood or chance that an event will occur, expressed as a value between 0 and 1, where 0 represents impossibility and 1 represents certainty.

To calculate the probability of getting four consecutive heads in a row, we multiply the probabilities of each individual toss.

The Probability of heads (H) is = 1/2,

So, The Probability of four consecutive heads (HHHH) is :

= (1/2) × (1/2) × (1/2) × (1/2) = (1/2)⁴ = 1/16,

Therefore, the required probability is 1/16 or 6.25%.

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Answer:

Rate of change is 1

Step-by-step explanation:

Well rate of change in a function is basically slope

theres 1 rise and.1 run

1/1=1

So rate of change is 1

The derivatives of the vector function are r'(t) = (18 · t, 1, 0), r''(t) = (18, 0, 0) and r'''(t) = (0, 0, 0).

In this question we find the definition of a vector function in terms of time, whose first, second and third derivatives must be found. This can be done by using derivative rules several times. First, define the vector function:

r(t) = (9 · t² + 6, t + 5, 6)

Second, find the first derivative:

r'(t) = (18 · t, 1, 0)

Third, find the second derivative:

r''(t) = (18, 0, 0)

Fourth, find the third derivative:

r'''(t) = (0, 0, 0)

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