Find the basis for the kernel and imagine of this transformation. Let T : P₂ → R where T(p(x)) = p(1). Find a or the kernel and image of this transformation.

Answer

use trigonometry to find both the answers.    

i have done the working out in the picture hope it helps...

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

[tex]3^{4m+4}+3^{4m}=246\\ (3^{4}+1)*3^{4m}=246\\82*3^{4m}=246\\3^{4m}=3\\m=\frac{1}{4}[/tex]

Answer:

(4x+5y=7

y=3x+9

4x+5(3x+9)=7

4x+15x+45=7

19x=7-45

19x= -38

19×/19=-38/19

x= -2

whlie y=3x+9

y=3(-2)+9

y= -6+9

y=3 end solution

x= -2,y= 3

Answer:

y = -4

Step-by-step explanation:

dy/dx gives you slope

(-4)-(-4)/5-3 = 0/2  ----> slope = 0

y = mx+b

m = 0

y = 0x+b

y = b

as it says F(3) and F(5) = -4 b must be -4

so you end up with y = -4

Answer: Use cylindrical coordinates. Evaluate z dv, where E is enclosed by ... A: Solution:Given∫c3y sinx dx+5xdyFormula:∫cPdx+Qdy=∬ ∂Q∂x-∂P∂y dA ... z) if the midpoint of the line segment joining the two points (x, y, z) and (-6, -5, -4). ... A: A cone is a 3-D shape with a circular base and tapers smoothly over to an

Step-by-step explanation:

Answer:

median = 5

range = 2

mean = 11

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

2x+9

Step-by-step explanation:

You have to combine like terms. 2x stays the same because there are no other like terms, but 5, 2, and 2 can be added together to make 9

Answer:

The answer is m=1 , the slope is 1

Step-by-step explanation:

Answer:

Step-by-step explanation:

m<1 = 50

m<2 = 22

m<3 = 108

m<4 = 50

m<5 = 65

m<6 = 50

m<7 = 43

m<8 = 65

m<9 = 75

m<10 = 18

m<11 = 25

m<12 = 40

m<13 = 115

m<14 = 65

m15 = 115

Answer:

One Chilly Night, Elijah Was Sleeping but Then Woke Up. He Realized It Was 45 Degrees According To the AC Monitor, So He Changed it To 70 Degrees But The Monitor Broke And Changed to -6 DEGREES!!

Step-by-step explanation:

A situation that can be represented by the integer - 6 was envisaged.

An integer is a whole number (not a fractional number) that can be positive, negative, or zero.

One day maths teacher decided to take a random test

There were 16 questions each of 4 marks and 1 mark deduction for each wrong answer, with no penalties for non-attempt.

David was so good at guessing. He guessed all the 16 answers out of which 2 were correct and 14 were incorrect.

So, the total marks that David got = 4(2)-1(14) = 8-14 =-6

Thus, a situation that can be represented by the integer - 6 was envisaged.

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Answer:

$244.00

Step-by-step explanation:

- gave bank $100

- +6% of $100 per month

- 6% of $100 = $6 (earns $6 per month)

- twelve months in a year, so 12 x $6 = $72 per year

- $100 + $72 + $72 = $244

If Lacey wants to utilize her money to purchase a new bicycle in two years, she will spend $244 on the bike.

Answer:

y = 2

Step-by-step explanation:

y = x

x = 2

Plug in the given value.

y = (2)

This is already simplified.

Therefore, when x = 2, y = 2.

Hope this helps!

Answer:

28

Step-by-step explanation:

We have proven that ΔWXY is similar to ΔWVZ using the ASA criterion.

We have,

To prove that ΔWXY is similar to ΔWVZ, we can use the ASA (Angle-Side-Angle) criterion.

Here are the steps of the proof:

Proof:

- Given: ΔWXY is isosceles with legs WX and WY; ΔWVZ is isosceles with legs WV and WZ.

Since ΔWXY is isosceles, we have WX ≅ WY. (Given)

Since ΔWVZ is isosceles, we have WV ≅ WZ. (Given)

We also know that ΔWXY and ΔWVZ share the common side segment WZ. (Common side)

Let's consider the angles: ∠WXY and ∠WVZ. Since ΔWXY is isosceles, we have ∠WXY ≅ ∠WYX. (Isosceles triangle property)

Similarly, since ΔWVZ is isosceles, we have ∠WVZ ≅ ∠WZV. (Isosceles triangle property)

Now, we have two pairs of congruent angles: ∠WXY ≅ ∠WYX and ∠WVZ ≅ ∠WZV.

We already know that WX ≅ WY and WV ≅ WZ.

By the ASA criterion, if two pairs of corresponding angles and the included side are congruent, then the triangles are similar.

Applying the ASA criterion, we conclude that ΔWXY ~ ΔWVZ. (Angle-Side-Angle)

Therefore,

We have proven that ΔWXY is similar to ΔWVZ using the ASA criterion.

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Answer:

[tex]\frac{n}{5} - 6[/tex]

Step-by-step explanation:

Quotient of a number and 5 means n/5

6 less than n/5 means n/5 - 6

Answer:

the product of a triple a number and 19

Step-by-step explanation:

but i'm not 100% sure so don't quote me

The constant c that produces a solution satisfying the initial condition y(6) = 4 is c = 24.

To find the constant c that satisfies the given equation and the initial condition, we need to substitute the function y = x² + (c/x²) into the differential equation and solve for c. The given equation is xy' * 2y = 4x².

First, we differentiate y with respect to x to find y',

y = x² + (c/x²)

y' = 2x - (2c/x³)

Now we substitute y and y' into the differential equation,

xy' * 2y = 4x²

x(2x - (2c/x³)) * 2(x² + (c/x²)) = 4x²

Simplifying,

2x³ - 2cx + 4c = 4x²

Rearranging,

2x³ - 4x² - 2cx + 4c = 0

Now we substitute x = 6 and y = 4 (from the initial condition y(6) = 4) into the equation,

2(6)³ - 4(6)² - 2(6)c + 4c = 0

432 - 144 - 12c + 4c = 0

288 - 8c = 0

8c = 288

c = 36

Therefore, the constant c that produces a solution satisfying the initial condition y(6) = 4 is c = 36.

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The roots of the auxiliary equation for a homogeneous fourth-order linear differential equation with constant coefficients, given that the solution is y = 2 - x + x^2 + 8e^x, are -1, -1, -2, and -2.

For a homogeneous linear differential equation with constant coefficients, the auxiliary equation is obtained by replacing the derivatives of y with powers of the variable. In this case, since the given solution is y = 2 - x + x^2 + 8e^x, we differentiate y with respect to x to obtain the derivatives.

The fourth-order linear differential equation corresponds to the fourth power of the variable, which is x. Therefore, the auxiliary equation is a polynomial equation of degree four. To find the roots of the auxiliary equation, we set the polynomial equal to zero and solve for x.

The roots of the auxiliary equation for this particular solution, after solving the polynomial equation, are -1, -1, -2, and -2. These values represent the roots of the characteristic equation and are crucial in determining the form of the general solution of the differential equation.

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Answer:

The answer is A. 116 square cm

Step-by-step explanation:

The argument (arg) of the complex number z = (a + ai)(b + b/3i), where a and b are positive real numbers, is π/6 radians or 30 degrees.

To determine the argument (arg) of the complex number z = (a + ai)(b + b/3i), where a and b are positive real numbers, we can simplify the expression and find the argument without using a calculator.

First, expand the product (a + ai)(b + b/3i):

z = (a + ai)(b + b/3i)

 = ab + ab/3i + abi - ab/3

Combining like terms, we get:

z = (ab - ab/3) + (ab/3 + ab)i

 = (2ab/3) + (ab/3)i

Now, we have the complex number z in the form z = x + yi, where x = 2ab/3 and y = ab/3.

To compute the argument (arg) of z, we can use the definition of the argument as the angle θ between the positive real axis and the line connecting the origin to the complex number z in the complex plane.

Since a and b are positive real numbers, both x and y are positive.

The argument (arg) of z can be determined as:

arg z = arctan(y/x)

      = arctan((ab/3) / (2ab/3))

      = arctan(1/2)

      = π/6

Therefore, without using a calculator, the argument (arg) of the complex number z = (a + ai)(b + b/3i) is π/6 radians or 30 degrees.

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Answer:

Your answer would be A

Step-by-step explanation:

Answer:

Step-by-step explanation:

Dani has only 1/2 of a cup of baking mix. She needs 3/4 of a cup for one batch of muffins. Which solution method shows how much of a batch of muffins Dani can make?

We need to determine whether the test is for the population proportion, mean, or standard deviation, and what distribution should be applied for the critical value.

a) This test is for the population mean since we are comparing the sample mean to a hypothesized population mean. To find the critical value, we apply the t-distribution since the population standard deviation is un known, and we are working with a sample.

b) The test statistic for comparing means is calculated using the formula:

t = (sample mean - hypothesized mean) / (sample standard deviation / √sample size).

Substituting the given values, we have:

t = (750 - 745) / (30 / √225) = 5 / 2 = 2.5.

c) To find the p-value, we compare the absolute value of the test statistic to the critical value associated with the significance level. Since the significance level α is not specified, we cannot directly calculate the p-value without knowing the critical value or α.

d) Without the critical value or the specific significance level, we cannot determine the conclusion of the test. The conclusion is drawn by comparing the p-value to the significance level α. If the p-value is less than α, we reject the null hypothesis, and if the p-value is greater than α, we fail to reject the null hypothesis.

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All the graph of equations are shown in figure.

We have to given that,

All the quadratic equations are,

1) y = 1 - 2x + x²

2) y = 1 + 2x + x²

3) y = 1 + x²

4) y = 1 - x²

5) y = 1 + 3x²

We can see that,

All the equation form a quadratic equation.

Hence, Each graph shows a parabola.

Therefore, All the graph of equations,

1) y = 1 - 2x + x²

2) y = 1 + 2x + x²

3) y = 1 + x²

4) y = 1 - x²

5) y = 1 + 3x²

are shown in figure.

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Answer:

2/3

Step-by-step explanation:

Answer:

Slope = -6

Step-by-step explanation:

Answer:

g) [tex]u^{4}\cdot v^{-1}\cdot z^{3}[/tex], h) [tex]\frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}[/tex]

Step-by-step explanation:

We proceed to solve each equation by algebraic means:

g) [tex]\frac{u^{5}\cdot v}{z}\div \frac{u\cdot v^{2}}{z^{4}}[/tex]

1) [tex]\frac{u^{5}\cdot v}{z}\div \frac{u\cdot v^{2}}{z^{4}}[/tex] Given

2) [tex]\frac{\frac{u^{5}\cdot v}{z} }{\frac{u\cdot v^{2}}{z^{4}} }[/tex] Definition of division

3) [tex]\frac{u^{5}\cdot v\cdot z^{4}}{u\cdot v^{2}\cdot z}[/tex]   [tex]\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}[/tex]

4) [tex]\left(\frac{u^{5}}{u} \right)\cdot \left(\frac{v}{v^{2}} \right)\cdot \left(\frac{z^{4}}{z} \right)[/tex]  Associative property

5) [tex]u^{4}\cdot v^{-1}\cdot z^{3}[/tex]   [tex]\frac{a^{m}}{a^{n}} = a^{m-n}[/tex]/Result

h) [tex]\frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}[/tex]

1) [tex]\frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}[/tex] Given

2) [tex]\frac{\frac{x^{2}-16}{x^{2}-10\cdot x+25} }{\frac{3\cdot x - 12}{x^{2}-3\cdot x - 10} }[/tex] Definition of division

3) [tex]\frac{(x^{2}-16)\cdot (x^{2}-3\cdot x -10)}{(x^{2}-10\cdot x + 25)\cdot (3\cdot x - 12)}[/tex]  [tex]\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}[/tex]

4) [tex]\frac{(x+4)\cdot (x-4)\cdot (x-5)\cdot (x+2)}{3\cdot (x-5)^{2}\cdot (x-4) }[/tex] Factorization/Distributive property

5) [tex]\left(\frac{1}{3} \right)\cdot (x+4)\cdot (x+2)\cdot \left(\frac{x-4}{x-4} \right)\cdot \left[\frac{x-5}{(x-5)^{2}} \right][/tex] Modulative and commutative properties/Associative property

6) [tex]\frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}[/tex]  [tex]\frac{a^{m}}{a^{n}} = a^{m-n}[/tex]/[tex]\frac{a}{b}\times \frac{c}{d} = \frac{a\cdot c}{b\cdot d}[/tex]/Definition of division/Result