For each of the following questions, draw the phase portrait as function of the control parameter μ. classify the bifurcations that occur as μ varies, and find all the bifurcation values of μ .
1. θ = μ sin θ - sin 2θ
2. θ = sin θ/ μ+cos θ
3. θ = sin θ / μ + sin θ
4. θ = μ + cos θ + cos 2 θ
5. θ = μ sin θ + cos 2θ
6. θ = sin 2θ/ 1 + μ sin θ

Answers

Answer 1

Phase portrait as a function of the control parameter μ and the classification of bifurcations that occur as μ varies in the following questions are:

1. θ = μ sin θ - sin 2θA) μ<0, stable equilibrium at θ = nπ, where n is an odd integerB) μ>0, stable equilibrium at θ = 0, unstable equilibrium at θ = nπ, where n is a non-zero even integer. Hence, we have homoclinic bifurcation at μ = 0.

2. θ = sin θ/ μ+cos θA) μ<1, stable equilibrium at θ = nπ, where n is an integerB) μ>1, stable equilibrium at θ = sin−1 (μ) + nπ, where n is an integer. Hence, we have a pitchfork bifurcation at μ = 1.

3. θ = sin θ / μ + sin θA) μ<−1, stable equilibrium at θ = nπ, where n is an integerB) μ>−1, stable equilibrium at θ = 0, unstable equilibrium at θ = nπ, where n is a non-zero integer. Hence, we have homoclinic bifurcation at μ = −1.

4. θ = μ + cos θ + cos 2θA) μ>−1, stable equilibrium at θ = nπ, where n is an even integerB) μ<−1, no equilibrium point exists. Hence, we have fold bifurcation at μ = −1.

5. θ = μ sin θ + cos 2θA) μ>0, stable equilibrium at θ = sin−1 (−μ) + 2nπ, where n is an integerB) μ<0, stable equilibrium at θ = sin−1 (−μ) + (2n+1)π, where n is an integer. Hence, we have pitchfork bifurcation at μ = 0.

6. θ = sin 2θ/ 1 + μ sin θA) μ<−1, unstable equilibrium at θ = nπ/2, where n is an odd integerB) μ>−1, unstable equilibrium at θ = 0, stable equilibrium at θ = π. Hence, we have pitchfork bifurcation at μ = −1.

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Related Questions

Lighthouse B is 9 miles west of lighthouse a a boat leaves a and sales 6 miles. At this time it is lighted from B. If the bearing of the boat from B is North 64° east how far from be is the boat?

Answers

Answer:

12.61 miles

Step-by-step explanation:

The distance of lighthouse B from lighthouse A, the distance from lighthouse A to the boat and the distance of lighthouse B from the boat all form a triangle. Since lighthouse B is west of lighthouse A, and at a distance of 9 miles form lighthouse A, light house A is at a bearing of North 90° East of lighthouse B. The distance from lighthouse A to the boat is 6 miles, and the bearing of the boat from lighthouse B is North 64° East.

So, the angle between the distance from lighthouse B to the boat and lighthouse B to lighthouse A is 90° - 64° = 26°

Since we have two sides and an angle, we use the sine rule

a/sinA = b/sinB where a = 6, A = 26°, b = 9, B = unknown

So, sinB = bsinA/a

= 9sin26/6

= 3(0.4384)/2

= 1.3151/2

= 0.6576

B = sin⁻¹(0.6576)

= 41.11°

≅ 41.1°

We now find the third angle in the triangle, C(the angle facing the distance from lighthouse B to the boat) from

26° + 41.1° + C = 180° (sum of angles in a triangle)

67.1° + C = 180°

C = 180° - 67.1° = 112.9°

Using the sine rule again to find the third side, c(the distance from lighthouse B to the boat), we have

a/sinA = c/sinC

c = asinC/sinA

= 6sin112.9°/sin26°

= 6(0.9212)/0.4384

= 5.5271/0.4384

= 12.61 miles

The estimated regression equation for a model involving two independent variables and 10 observations follows. Here SST = 6,724.125, SSE = 507.75, S_b_1 = 0.0813, and s_b_2 = 0.0567.

ŷ = 29.1270 +0.5906x_1 + 0.4980x_2

a. Interpret the regression coefficients in this estimated regression equation

A one-unit increase in x_1 will lead to a 0.5906 unit decrease in y, when x_2 is held constant. A one-unit increase in x_2 will lead to a 0.498 unit increase in y, when x_1 is held constant.

A one-unit increase in x_1 will lead to a 0.5906 unit increase in y, when x_2 is held constant. A one-unit increase in x_2 will lead to a 0.498 unit decrease in y, when x_1 is held constant.

A one-unit increase in x_1 will lead to a 0.5906 unit increase in y, when x_2 is held constant. A one-unit increase in x_2 will lead to a 0.498 unit increase in y, when x_1 is held constant.

A one-unit increase in x_1 will lead to a 0.5906 unit increase in y. A one-unit increase in x_2 will lead to a 0.498 unit increase in y.

Answers

Option C is correct: A one-unit increase in x1 will lead to a 0.5906 unit increase in y, when x2 is held constant. A one-unit increase in x2 will lead to a 0.498 unit increase in y, when x1 is held constant.

The estimated regression equation for a model involving two independent variables and 10 observations follows. Here SST = 6,724.125,

SSE = 507.75,

Sb1 = 0.0813, and

Sb2 = 0.0567.

ŷ = 29.1270 +0.5906x1 + 0.4980x2

Interpretation of Regression Coefficients:

Below are the explanations of the regression coefficients in the estimated regression equation:

1. The regression coefficient for x1 is 0.5906. A one-unit increase in x1 will lead to a 0.5906 unit increase in y, when x2 is held constant.

2. The regression coefficient for x2 is 0.4980. A one-unit increase in x2 will lead to a 0.498 unit increase in y, when x1 is held constant.

Therefore, Option C is correct: A one-unit increase in x1 will lead to a 0.5906 unit increase in y, when x2 is held constant. A one-unit increase in x2 will lead to a 0.498 unit increase in y, when x1 is held constant.

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This large cube sculpture at the University of Michigan is made of steel. Even though it is extremely heavy, students can walk by and spin the cube very easily. Each side of the cube measures 15 feet across.

If this cube was a perfect cube and filled with sand, how much sand would be needed to completely fill it?

Answers

We would need 337,500 pounds of sand to completely fill the cube with sides measuring 15 feet across if it were a perfect cube.

The volume of a cube is calculated by taking the length of one side and raising it to the power of 3. In this case, the cube has sides that measure 15 feet each, so the volume can be calculated as:

Volume of cube = (Length of one side)^3 = (15 feet)^3 = 3,375 cubic feet

To fill the cube with sand, we would need to add enough sand to completely fill this volume. The weight of the sand we need can be calculated using its density. The density of sand varies depending on the type of sand, but a common density for dry sand is around 100 pounds per cubic foot.

Therefore, the weight of sand needed to fill the cube would be:

Weight of sand = (Volume of cube) x (Density of sand) = 3,375 cubic feet x 100 pounds per cubic foot = 337,500 pounds

It is worth noting that the real cube sculpture at the University of Michigan is not a perfect cube and is not filled with sand.

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4. (Newton's Method). Consider the problem of finding the root of the function f(x)=x+el.812r in [-1,0]. (i) Find the formula of the iteration function g(x) = x- f(x) f'(x) for Newton's method, and then work as instructed in Problem 3, that is, plot the graphs of g(x) and g'(x) on [-1,0] with the use of Wa to show convergence of Newton's method on [-1,0] as a Fixed-Point. Iteration technique. (ii) Apply Newton's method to find an approximation py of the root of the equation x+el.812x = 0 in [-1,0] satisfying RE(PNPN-1 < 10-5) by taking po = -1 as the initial approximation. All calculations are to be carried out in the FPA7. Present the results of your calculations in a standard output table for the method of the form TL Pn-1 Pn RE(pn pn-1) ⠀ B : (As for Problem 3, your answers to the problem should consist of two graphs, a conclusion on convergence of Newton's method, a standard output table, and a conclusion regarding an approximation PN.) As was discussed during the last lecture, applications of some cruder root-finding methods can, and often do, precede application of Newton's method (and the Bisection method is one that is used most commonly for this purpose). 4. (Newton's Method). Consider the problem of finding the root of the function f(x)=x+²-812 in 1-1,0). (1) Find the formula of the iteration function f(x) g(x) = P(x) for Newton's method, and then work as instructed in Problem 3, that is, plot the graphs of g(x) and g'(z) on [-1.0 with the use of Who to show convergence of Newton's method on [-1.0] as a Fixed-Point Iteration technique. (ii) Apply Newton's method to find an approximation py of the root of the equation z+el-813x = 0 in (-1,0 satisfying RE(PNPN-1 <10-5) by taking po = -1 as the initial approximation. All calculations are to be carried out in the FPA7. Present the results of your calculations in a standard output table for the method of the form P-1 PRE(PP-1) (As for Problem 3, your answers to the problem should consist of two graphs, a conclusion on convergence of Newton's method, a standard output table, and a conclusion regarding an approximation px-) As was discussed during the last lecture, applications of some cruder root-finding methods can, and often do, precede application of Newton's method (and the Bisection method is one that is used most commonly for this purpose).

Answers

The formula of the iteration function for Newton's method is given by g(x) = x - f(x) / f'(x).

The graph of g(x) and g'(x) shows convergence of Newton's method on [-1, 0] as a Fixed-Point Iteration technique. Applying Newton's method to find an approximation of the root of the equation x + e^(-0.812x) = 0 in [-1, 0], with an initial approximation of p0 = -1, gives an approximation of p_n = -0.567143. The standard output table for this method is: TLP_nP_n-1RE(P_nP_n-1) 0-1.00000000000.1559875219 1-0.4801700174-1.00000000000.4801700174 2-0.5889524214-0.4801700174 0.1087824049 3-0.5671941668-0.5889524214 0.0217582546 4-0.5671432850-0.5671941668 0.0000508818. The conclusion is that the Newton's method converges to a root of the equation x + e^(-0.812x) = 0 in [-1, 0] with a tolerance of 10^-5.

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Ms. Keating’s class wants to compare the use of social media between the seventh-grade students and eighth-grade students at Valleydale School.The MAD (the average distance between each data value and the mean) for both data sets is approximately 14. What can you infer about the two sets of data?

Answers

Answer:

Need to add picture

Step-by-step explanation:

HEY LOL PLEASE ANSWER THESE. PLEASE IM BEGGING YOU. HELP ME

Answers

Answer:

a. ∆ABC ~ ∆A'B'C'

b. Enlargement

c. Scale factor = 4

Step-by-step explanation:

a. <A corresponds to <A'

<B corresponds to <B'

<C corresponds to <C',

Therefore, the similarity statement would be: ∆ABC ~ ∆A'B'C'

b. The image of the dilation is an enlargement of the original figure because the side lengths of ∆A'B'C are larger than the corresponding side lengths of ∆ABC.

c. Scale factor = the ratio of the corresponding sides

Thus:

Scale factor = A'B'/AB = B'C'/BC = A'C'/AC

Scale factor = 24/6 = 48/12 = 60/15 = 4

Scale factor = 4

Margarita was buying soil for her spring garden. What would be the most reasonable amount of soil she would need to buy for a garden?
A. 5 grams
B. 50 liters
C. 50 kilograms
D. 5,000 kilograms

Answers

Answer:

C

Step-by-step explanation:

No soil bag weighs A or B and D is too much unless she has many acres.

Answer  The guy Above  is right

Compute the following by using ancient Egyptian multiplication: (a) 74 X 64 (b) 129 X 413 (c) 58 X 692 (d) 4968 X 1234

Answers

Using Ancient Egyptian multiplication, the values are obtained as: (a)  74 × 64 = 2724: (b)  129 × 413 = 35405: (c)  58 × 692 = 30456: (d)  4968 × 1234 = 6148172.

Ancient Egyptian multiplication, also known as Egyptian multiplication or the method of multiplication through doubling and halving, is a method used by ancient Egyptians to multiply two numbers.

It involves breaking down one of the numbers into a sum of powers of two and then adding the corresponding multiples of the other number. Here's how you can compute the given multiplications using ancient Egyptian multiplication:

(a) 74 × 64:

We start with the number 1 and keep doubling it until we reach a number greater than or equal to 74. We then create a column for each power of 2 that was used, and write the corresponding multiple of 64 in each column. Finally, we add the numbers in the columns corresponding to the powers of 2 that make up 74.

1  ×  64 =  64

2  ×  64 = 128

4  ×  64 = 256

8  ×  64 = 512

16 ×  64 = 1024

32 ×  64 = 2048

Adding the numbers corresponding to powers of 2 that make up 74:

64 + 0 + 0 + 512 + 0 + 2048 = 2724

Therefore, 74 × 64 = 2724.

(b) 129 × 413:

1  ×  413 =  413

2  ×  413 =  826

4  ×  413 = 1652

8  ×  413 = 3304

16 ×  413 = 6608

32 ×  413 = 13216

64 ×  413 = 26432

Adding the numbers corresponding to powers of 2 that make up 129:

413 + 0 + 1652 + 0 + 6608 + 0 + 26432 = 35405

Therefore, 129 × 413 = 35405.

(c) 58 × 692:

1  ×  692 =  692

2  ×  692 = 1384

4  ×  692 = 2768

8  ×  692 = 5536

16 ×  692 = 11072

32 ×  692 = 22144

Adding the numbers corresponding to powers of 2 that make up 58:

692 + 1384 + 0 + 5536 + 0 + 22144 = 30456

Therefore, 58 × 692 = 30456.

(d) 4968 × 1234:

1   ×  1234 =   1234

2   ×  1234 =   2468

4   ×  1234 =   4936

8   ×  1234 =   9868

16  ×  1234 =  19668

32  ×  1234 =  39468

64  ×  1234 =  78936

128 ×  1234 = 157872

256 ×  1234 = 315744

512 ×  1234 = 631488

1024 × 1234 = 1262976

Adding the numbers corresponding to powers of 2 that make up 4968:

1234 + 2468 + 4936 + 0 + 19668 + 39468 + 78936 + 157872 + 315744 + 0 + 1262976 = 6148172

Therefore, 4968 × 1234 = 6148172.

Using the ancient Egyptian multiplication method, we have computed the products for the given multiplications.

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A particular type of mouse's weights are normally distributed, with a mean of 409 grams and a standard deviation of 24 grams. If you pick one mouse at random, find the following: (round all probabilities to four decimal places) a) What is the probability that the mouse weighs less than 332 grams? b) What is the probability that the mouse weighs more than 480 grams? c) What is the probability that the mouse weighs between 332 and 480 grams? d) Is it unlikely that a randomly chosen mouse would weigh less than 332 grams? No, the likelihood exceeds 5% Yes, the likelihood is less than 50% Yes, the likelihood is less than 5% No, the likelihood exceeds 50% e) What is the cutoff for the heaviest 6% of this type of mouse? grams (round to the nearest whole gram).

Answers

a) To find the probability that the mouse weighs less than 332 grams is calculated using the z-score formula which is: z= (x-μ)/σ where, x=332μ=409σ=24z= (332−409)/24z=−3.21

Hence, P (x < 332) = P (z < -3.21)

The probability that the mouse weighs less than 332 grams is approximately equal to 0.0007. Therefore, the answer is 0.0007 (rounded to four decimal places).

b) To find the probability that the mouse weighs more than 480 grams is calculated using the z-score formula which is: z= (x-μ)/σwhere,x=480μ=409σ=24z= (480−409)/24z=2.96

Hence, P (x > 480) = P (z > 2.96)

The probability that the mouse weighs more than 480 grams is approximately equal to 0.0015. Therefore, the answer is 0.0015 (rounded to four decimal places).

c) To find the probability that the mouse weighs between 332 and 480 grams is calculated using the z-score formula which is: P (332 < x < 480) = P (-3.21 < z < 2.96)

Hence, the probability that the mouse weighs between 332 and 480 grams is approximately equal to 0.9980. Therefore, the answer is 0.9980 (rounded to four decimal places).

d) The probability of a randomly chosen mouse weighing less than 332 grams is found to be P (x < 332) = 0.0007 which is less than 5%. Therefore, it is unlikely that a randomly chosen mouse would weigh less than 332 grams. Hence, the answer is "Yes, the likelihood is less than 5%".

e) To find the cutoff for the heaviest 6% of this type of mouse can be done by using the Z-table, that gives the z-score for any given probability. For the heaviest 6%, we need to find the z-score corresponding to a probability of 0.94 (100% - 6%). Hence, the Z-score for 0.94 probability is 1.55. Cutoff weight = μ + Z-score * σ= 409 + 1.55 * 24 = 447.2 ≈ 447 (rounded to the nearest whole gram). Therefore, the answer is 447 (rounded to the nearest whole gram).

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A machine press has 51 yards of steel for making 4-inch nails. How many nails can be pressed from the steel?

Answers

459 nails is your answer

51 yards of steel x 3 feet/yard = 153 feet of steel
153 feet x 12 inches/foot = 1836 inches of steel.

1836/4 inches per nail = 459 nails

You arrive at the airport at 1:50 pm and your flight leaves at 5:20 pm. How many MINUTES will you need to wait?

Answers

Answer:

you will need to wait 3 hours and 30 mins

Step-by-step explanation:

Answer:

Hello There!!

Step-by-step explanation:

It is 3 hours and 30 minutes which is 210 minutes altogether.

hope this helps,have a great day!!

~Pinky~

the polynomial x^2+bx+15 has a factor of x-3. what is the value of b ?

Answers

Answer:

b = -8

Step-by-step explanation:

Attachment.....added.

Hope it helps :)

If a translation of the figure above is plotted 7 units to the right and 2 units up, where will point A' be located on the new figure?
A. (7,2)
B. (-12,3)
C. (12,3)
D. (2,7)

Answers

d. because you just count 7 units to the right and then 2 units up.

If a translation of the figure above is plotted 7 units to the right and 2 units up, the (12,3) point A' will be located on the new figure.

What is translation?

The process of changing the location of the image on the coordinate system will be known as the translation. Here the image is translated as;

The given coordinate of the point is:- (7, 2)

Then it is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s range(involving values of y) or in it’s domain(involving values of x  because we  just count 7 units to the right and then 2 units up.

Hence If a translation of the figure above is plotted 7 units to the right and 2 units up, the (12,3) point A' will be located on the new figure.

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below there was a daily rental cost for ski equipment at benton mountin ski resort radall rents one set of skis two set of poles and two pairs of boots the sales tax for the rental was 7.69 and he paid with a 100 bill how much chang should randall recive frome the 100 dollar bill

Answers

Answer:

hi

Step-by-step explanation:

USA Today reported that the population mean life span of people who live in Hawaii is 77 years. A random sample of 20 obituary notices gave a sample mean life span of x= 71.4 years and a sample standard deviation s = 20.65 years. Assuming that the life span of people in Hawaii is normally distributed, does this indicate that the population mean life span is less than 77 years? Use a 5% level of significance. a.) What is a? State the null and alternate hypotheses. Will you use a left-tailed, right-tailed, or two tailed test?
α = ____
H_0: µ = _____
H_1: µ = _____
The test is a _______ test.

Answers

Yes, there is evidence to suggest that the population mean life span in Hawaii is less than 77 years.

How to find that is there statistical evidence that the mean life span in Hawaii is less than 77 years?

The hypothesis test in question aims to determine if there is sufficient evidence to support the claim that the population mean life span in Hawaii is less than 77 years.

The null hypothesis (H₀) assumes that the mean life span is equal to 77 years, while the alternative hypothesis (H₁) suggests that the mean life span is less than 77 years.

To conduct the hypothesis test, a significance level (α) of 5% is chosen, which corresponds to a 95% confidence level.

Since the question asks whether the population mean is less than 77 years, this is a left-tailed test.

Using the given sample information, the test statistic can be calculated using the formula:

t = (x - µ) / (s / √n), where x is the sample mean (71.4), µ is the population mean (77), s is the sample standard deviation (20.65), and n is the sample size (20).

By plugging in the values, the test statistic is calculated to be t = (71.4 - 77) / (20.65 / √20) ≈ -1.64.

To determine whether the test statistic falls in the critical region, the critical value for a left-tailed test at α = 0.05 is obtained from the t-distribution table or calculator.

With 19 degrees of freedom, the critical value is approximately -1.73.

Since the test statistic (-1.64) is not less than the critical value (-1.73), we fail to reject the null hypothesis.

This means that there is insufficient evidence to conclude that the population mean life span in Hawaii is less than 77 years at a 5% level of significance.

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Shade 3/4 on the grid

Answers

What grid????? There’s no grid
shade 3 spots and leave one open

give an estimated simple linear regression equation of = 46.2 589.2x with a coefficient of determination r2 of 0.7523, interpret the coefficient of determination for this equation.

Answers

The estimated simple linear regression equation is y = 46.2 + 589.2x, with a coefficient of determination (r^2) of 0.7523.

The coefficient of determination (r^2) measures the proportion of the total variation in the dependent variable (y) that can be explained by the independent variable (x) in a linear regression model. In this case, the coefficient of determination is 0.7523, indicating that approximately 75.23% of the variation in the dependent variable (y) can be explained by the independent variable (x) using the given regression equation. This means that the linear relationship between x and y accounts for 75.23% of the variability observed in y. The remaining 24.77% of the variation is attributed to other factors not included in the model. A higher value of r^2 indicates a stronger relationship between the variables.

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Solve for X if 8X = 40​

Answers

Step-by-step explanation:

X=40/8

X=5 Answer

hope it helps

Answer:

X= 5

Step-by-step explanation:

NOTE: DIVIDE 8 IN BOTH SIDE

8X/8 = X

40/8 = 5

SO X = 5

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help☝️☝️☝️☝️‍☝️☝️‍☝️‍‍☝️☝️‍☝️☝️

Answers

Answer:

40 + 25 = 65

49 + 63 = 112

63 + 15 = 78

7×16 =112

26 × 3 =78

5×13=65

so the answer is

40 + 25 -------- 5 × 13

49 + 63 -------- 7 × 16

63 + 15 --------- 26 × 3

i hope this help you

5.The employees of Xitrex, Inc., are paid each Friday. The company’s fiscal year-end is June 30, which falls on a Wednesday for the current year. Salaries and wages are earned evenly throughout the five-day work week, and $13,000 will be paid on Friday, July 2.
Required:
1. Prepare an adjusting entry to record the accrued salaries and wages as of June 30, a reversing entry on July 1, and an entry to record the payment of salaries and wages on July 2.
2. Prepare journal entries to record the accrued salaries and wages as of June 30 and the payment of salaries and wages on July 2 assuming a reversing entry is not recorded.

Answers

The entry to record the payment of salaries and wages on July 2 is a debit to Salaries and Wages Payable and a credit to Cash.

1. The adjusting entry on June 30 is necessary to recognize the expense for salaries and wages earned but not yet paid. It increases the Salaries and Wages Expense account and creates a liability in the Salaries and Wages Payable account.

The reversing entry on July 1 is made to simplify the subsequent accounting process and ensure accurate financial reporting. On July 2, when the payment is made, the Salaries and Wages Payable account is reduced, and Cash is decreased by the same amount.

2. Without a reversing entry, the journal entry on June 30 still recognizes the expense for salaries and wages earned but unpaid. The Salaries and Wages Expense account is debited, reflecting the expense, and the Salaries and Wages Payable account is credited, indicating the liability.

On July 2, when the payment is made, the Salaries and Wages Payable account is reduced, and Cash is decreased by the same amount. The absence of a reversing entry means that the Salaries and Wages Expense account will continue to reflect the total expense accrued throughout the fiscal year, rather than resetting to zero at the beginning of the new period.

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The price of an mp3 player is reduced by 60%. The expression c – 0.6c represents the sale price. Which represents an equivalent expression to determine the sale price?

Answers

Answer:

0.4c

Step-by-step explanation:

Given that :

Price of mp3 is reduced by 60%

Let initial price of mp3 = c

Discount on price = 60% = 0.6

Discounted price = initial price - discount on price

Discounted price = c - 0.6c

Discounted price = 0.4c

80% of grade 8 students, that is, 60 students want a new ice-cream shop in the
cafeteria. The total number of grade 8 students are?

Answers

Answer:

48

Step-by-step explanation:

60 students X 80%=48

20% is 12 students

40% is 24 students

60% is 36 students

so on and so forth.

Answer:

48.

Step-by-step explanation:

.80 x 60 = 48








18. In the photograph of a father and his daughter, the daughter's height is 2 cm and the father's height is 5 cm. If the father's height is actually 185 cm, how tall is the daughter?

Answers

Answer:

114cm

Step-by-step explanation:

When you're in a situation like this, you use ratios!

If the father's height is 5cm, and actually 185cm, the ratio of photo height and actual height is 1:57.

When we use this, the father is 57 times taller than him inside the photo, so since the daughter (in photo) is 2 cm, her height should be 2*57 cm.

2*57 = 114, which concludes to 114 cm.

:)

A rectangle has a length of 3 units and a width of
y units. Write an expression for the area of this
rectangle.

Answers

Answer:

An expression for this would be 3y as length * breadth is the area of a rectangle.

What divided by 76 equals 127

Easy one please answer ASAP

Answers

Answer is : 9692

cxcvbnm

School administrators in Boston want to assess the efficacy of a new reading program they wish to put in place. Therefore, they randomly assign some schools in the city to institute the new reading program and other schools to remain on the traditional reading program. When performing the analysis to determine whether students using the new reading program perform better, the educators control for socioeconomic status, a variable known to be related to educational outcomes. What kind of analysis have the educators performed

Answers

Answer:

The selection of the schools is done by random sampling, the remaining schools are considered as the control and stratified sampling for the selection of students for analysis is considered

Step-by-step explanation:

Based on the scenario, the following key highlights are presented:

The sampling for selection is carried out randomly.The control group is maintained.The selection of students for analysis is considered with a specific socio-economic status.

This indicates that the selection of the schools is done by random sampling, the remaining schools are considered as the control and stratified sampling for the selection of students for analysis is considered.

find the 9th term in 3, -11, -25, -39

Answers

Answer:

-53

Step-by-step explanation:

The length of title a is about 2.23607 inches which mark on the tape measure is closest to 2,23607 inches ?

Answers

2 and 1/4 inches.

Decimal equals 2.25 inches

Kendra ordered a set of blue and brown pins. She received 100 pins, and 30% of them were blue. How many blue pins did Kendra receive?

Answers

Answer:

30 blue pins

Step-by-step explanation:

30% is the same as 30 out of 100, so this can be written in this fraction: [tex]\frac{30}{100}[/tex]

now, you should multiply this fraction by the total number of pins she ordered:

100 x [tex]\frac{30}{100}[/tex]

to solve this, you can simplify by dividing 100 by 100, this equals 1

30 times 1 is 30

there are 30 blue pins

Answer:

30 hair pins were blue

Step-by-step explanation:

100 x 0.3 =  30

In figure find the value of x triangle PQR

Answers

Answer:

x = 35

m<PQR = 70

Step-by-step explanation:

This is an isoceles triangle so the base angles are the same and they all add up to 180 so:

2x + 2x + 40 = 180

4x + 40 = 180

4x = 140

x = 35

m<PQR:

2x

2(35)

70

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