Answer:
100 Nm
Step-by-step explanation:
Work is said to be done when a force moves a body through a distance. This may be expressed as
work done = Force * distance
where
work done is measured in joules or Newton-meter
Force is measured in newtons and distance in meters
Substituting the given values,
Workdone = 20 * 5
= 100 Nm
= 100J
Find the sum of the measures of the exterior angles of a convex 65-gon
Answer: 360
Step-by-step explanation: Sum of exterior angles of any convex polygon is always 360, think about it.
a local ice cream shop has a special deal on thursdays: buy a waffle cone for $3 and get each scoop of ice cream for $1.50. what would be the rate of change in this word problem?
In the given word problem, the rate of change is the change in the cost of the ice cream concerning the change in the number of scoops.
That is, the rate of change is the ratio of the change in the cost of ice cream and the change in the number of scoops. Let's first calculate the initial rate of change or slope of the given deal: When we buy a waffle cone, the cost is $3, and we can buy one scoop of ice cream for $1.50.So, for one scoop of ice cream, the total cost would be 3 + 1.50 = $4.50.
We can represent the cost of one scoop of ice cream with the help of a linear equation: y = mx + b. Here, the slope or the rate of change, m = Change in cost of ice cream/ Change in the number of scoops= 1.5/1= 1.5Therefore, the rate of change of the ice cream with respect to the number of scoops is $1.50/scoop.
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Find the mean, median, and mode of the data set.
{0,9, 3, 6, 10, 10, 7,1
MEAN:
MEDIAN:
MODE:
A blue circular target is tacked onto a square corkboard. The area of the target is 75 square units. What is the area of the corkboard that is not covered by the target?
An article in Technometrics ("Validation of Regression Models: Methods and Examples"presented the following data (which have been rounded to the nearest whole value) on the motor fuel octane ratings of several blends of gasoline:
89 99 90 92 93 88 88 91 95 88
90 83 88 93 88 90 84 90 92 91
93 94 88 92 90 91 91 88 94 97
89 90 89 91 89 89 90 84 92 92
90 92 88 93 91 93 89 92 88 94
87 87 89 90 90 91 8591 94 89
93 90 8790 91 91 93 93 92 93
89 100 90 89 87 90 96 91 88 92
a. Construct a frequency distribution for these data by filling in the table below. Use 8 bins. Lower limit Upper limit Midpoint Frequency Relative frequency
b. Use the frequency distribution on the previous page to construct a histogram for these data.
To analyze the motor fuel octane ratings data, we can start by constructing a frequency distribution and then use it to create a histogram.
The frequency distribution will provide information about the distribution of the data across different octane rating ranges, while the histogram visually represents the distribution graphically.
a. To construct a frequency distribution, we divide the data into bins and count the frequency of values falling within each bin. In this case, we will use 8 bins. We determine the lower and upper limits for each bin and calculate the midpoint by averaging the limits. Then, we count the number of values within each bin and calculate the relative frequency by dividing the frequency by the total number of values.
b. Once the frequency distribution is constructed, we can use it to create a histogram. The histogram represents the frequency or relative frequency of values within each bin as vertical bars. The bins are plotted along the x-axis, and the height of the bars represents the frequency or relative frequency on the y-axis. The histogram allows us to visualize the distribution pattern of the motor fuel octane ratings data, showing if it is skewed, symmetric, or has other characteristics.
By constructing a frequency distribution and creating a histogram, we can gain insights into the distribution of the motor fuel octane ratings data. The frequency distribution table provides a summarized view of how the data is spread across different octane rating ranges, while the histogram visually represents the same information in a graphical form. Both the frequency distribution and the histogram aid in understanding the distribution pattern, identifying potential outliers or gaps, and informing further analysis or decision-making related to the data.
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SOLVE THIS PLEASE I WILL GIVE BRAINLIEST AND 5 STAR RATING! AND GIVING 70 POINTS!!!!!
Answer:
[tex]L^{2} + W^{2} = d^{2}[/tex]
d = 31.6
Step-by-step explanation:
[tex]L^{2} + W^{2} = d^{2}[/tex]
[tex]30^{2} + 10^{2} = d^{2}[/tex]
[tex]d^{2}[/tex] = 900 + 100
= 1000
d = [tex]\sqrt{100}[/tex] = 31.6
5. How many mililiters of a 3.5 M iron (II) nitrite (Fe(NO2)2) solution are needed to provide a tot
of 0.13 kg of Fe(NO),?
need help plss
Answer:
try this link!
Step-by-step explanation:
https://www.wylieisd.net/cms/lib09/TX01918453/Centricity/Domain/783/Math%20Connections%20Key.pdf
Kai has 8 pints of buttermilk. He uses 4 ounces of buttermilk in
his receipe for a loaf of bread. How many loaves of bread can he make with the buttermilk that he has?
A. 2 loaves
B. 16 loaves
C. 24 loaves
D. 32 loaves
Verify that Rolle's Theorem can be applied to the function f(x) = 3 - 102 +31-30 on the interval [2, 5]. Then find all values of c in the interval such that f' (c) = 0.
Enter the exact answers in increasing order.
To enter √a, type sqrt(a).
c =
C=
Show your work and explain, in your own words, how you arrived at your answers.
Equation Editor A- A T I
BIUS X₂ x²
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Words: 0
The exact values of c in increasing order are: c = (10 - sqrt(7)) / 3, (10 + sqrt(7)) / 3
To verify that Rolle's Theorem can be applied to the function f(x) = x³ - 10x² + 31x - 30 on the interval [2, 5], we need to check if the following conditions are satisfied:
f(x) is continuous on [2, 5].f(x) is differentiable on (2, 5).f(2) = f(5).Let's check each condition:
f(x) = x³ - 10x² + 31x - 30 is a polynomial function and is continuous for all real values of x. So, it is continuous on [2, 5].
To check the differentiability, we need to find f'(x):
f'(x) = 3x² - 20x + 31.
The derivative f'(x) exists and is continuous for all real values of x. So, f(x) is differentiable on (2, 5).
Now, let's evaluate f(2) and f(5):
f(2) = (2)³ - 10(2)² + 31(2) - 30 = -10
f(5) = (5)³ - 10(5)² + 31(5) - 30 = 95
Since f(2) = -10 is not equal to f(5) = 95, we can conclude that Rolle's Theorem can be applied to the function f(x) = x³ - 10x² + 31x - 30 on the interval [2, 5] after differentiable.
To find the values of c in the interval (2, 5) such that f'(c) = 0, we need to solve the equation f'(c) = 3c² - 20c + 31 = 0.
Using quadratic formula:
c = (-(-20) ± sqrt((-20)² - 4(3)(31))) / (2(3))
c = (20 ± sqrt(400 - 372)) / 6
c = (20 ± sqrt(28)) / 6
c = (20 ± 2sqrt(7)) / 6
c = (10 ± sqrt(7)) / 3
The values of c in the interval (2, 5) such that f'(c) = 0 are:
c = (10 + sqrt(7)) / 3
c = (10 - sqrt(7)) / 3
Therefore, the exact values of c in increasing order are: c = (10 - sqrt(7)) / 3, (10 + sqrt(7)) / 3.
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Incomplete question:
Verify that Rolle's Theorem can be applied to the function f(x) = x³ - 10x² +31x-30 on the interval [2, 5]. Then find all values of c in the interval such that f' (c) = 0.
Enter the exact answers in increasing order.
To enter √a, type sqrt(a)
c = ?
A race was 993 meters. If 28 people ran in the marathon how many meters would they
have run total?
Answer:
27,804
Step-by-step explanation:
28x993= 27,804
Triangle ABC has a side length of 8 and is dilated to Triangle XYZ with a side length
of 4. Is this a reduction or enlargement, and what is the scale factor?
v
Enlargement; scale factor of 1/2
Reduction; scale factor of 2
Enlargement; scale factor of 2
Reduction; scale factor of 1/2
Someone please please help me on this problem
Answer:
81 Pesos
Step-by-step explanation:
Use a proportion.
$3 is to 2 Pesos as $121.10 is to x Pesos.
3/2 = 121.1/x
3x = 2 * 121.1
3x = 242.20
x = 80.7333...
Answer: 81 Pesos
whata 10 divided by 100
Answer:
it 10000
Step-by-step explanation:
79ib dlndokveik dinfl. kwbfb
Raffia went shopping for new furniture he bought a couch for $750 and a mattress for 950 dollars. When he came home he had $350 in his purse. How much money did he have when he left home. Please answer step by step will mark brainliest and thanks !!!!!!!!!!!
Answer:
$2050
Step-by-step explanation:
750+950+350
Use the Singapore Bar Method, including drawings, to solve the following problem. Identify the unit value when appropriate, including labels. The sides of the triangle are in the ratio 5:7:8 and the longest side is 36 cm longer than the shortest side. Find the perimeter of the triangle.
When the sides of the triangle are in the ratio 5:7:8 and the longest side is 36 cm longer than the shortest side, the perimeter is 240cm.
How to calculate the perimeterLet's assume the shortest side of the triangle has a length of x cm. According to the given ratio, the sides of the triangle are in the ratio 5:7:8. Therefore, the lengths of the sides can be expressed as:
Shortest side: 5x
Second side: 7x
Longest side: 8x
We are also given that the longest side is 36 cm longer than the shortest side. So we can set up the following equation:
8x = 5x + 36
Now, let's solve this equation to find the value of x:
8x - 5x = 36
3x = 36
x = 36 / 3
x = 12
Now we can substitute this value back into the expressions for the side lengths to find their actual lengths:
Shortest side: 5x = 5 * 12 = 60 cm
Second side: 7x = 7 * 12 = 84 cm
Longest side: 8x = 8 * 12 = 96 cm
Finally, we can calculate the perimeter of the triangle by adding the lengths of all three sides:
Perimeter = Shortest side + Second side + Longest side
= 60 cm + 84 cm + 96 cm
= 240 cm
Therefore, the perimeter of the triangle is 240 cm.
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One pump can fill a tank of water in 5 hours. A second tank can fill the same tank in 4 hours. If both pumps are used together, how long will it take to fill the tank?
4/5 hours
20/9 hours
9/20 hours
5/4 hours
Answer:
4/5 hours
Step-by-step explanation:
Answer:
20/9 hours
Step-by-step explanation:
I got it right on the quiz
A food safety guideline is that the mercury in fish should be below 1 part per million (ppm) Listed below are the amounts of mercury (ppm) found in tuna sushi sampled at different stores in a major city Construct a 10% confidence interval estate f too much marcury in una sush? 051 0.01 0.10 0.96 128 057 056 What is the confidence interval estimate of the population mean? pppp Round to three decimal places as needed) Does it appear that there is too much mercury in una sush? OA. Yes, because it is possible that the mean is greater than 1 ppm. Also, at least one of the sample values exceeds 1 ppm, so at least some of the fish have too much mercury 1. No, because it is possible that the mean is not greater than 1 ppm Also, at least one of the sample values is less than 1 ppm, so at least some of the fish sale OC. Yes because it is possible that the mean is not greater than 1 ppm. Also, at least one of the sample values exceeds 1 ppm, so at least some of the fish have too much mercury OD. No. because it is not possible that the mean is greater than 1 ppm Also at least one of the sample values is less than 1 ppm, so at least some of the fish are safe
The confidence interval estimate of the population mean is (0.37, 0.75). The correct option is B No. Based on the confidence interval, it is not possible to say that the mean mercury level in tuna sushi is greater than 1 ppm.
How to explain the informationThe confidence interval includes 1 ppm, so the true mean could be 1 ppm or less. Additionally, at least one of the sample values is less than 1 ppm, so at least some of the fish are safe.
The sample standard deviation is calculated by finding the square root of the sum of the squared deviations from the mean for each value in the sample. The sample size is the number of values in the sample.
Confidence interval = sample mean ± 1.645 * (sample standard deviation / ✓(sample size))
Confidence interval = 0.51 ± 1.645 * (0.24 / ✓(7))
= (0.37, 0.75)
As you can see, the confidence interval includes 1 ppm, so the true mean could be 1 ppm or less.
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9. (10%) Consider a linear block code whose generator matrix G is. 1 0 0 1 1 1 0 0 1 0 1 1 0 1 0 0 1 1 0 1 1 (a) (2%) Find the parity check matrix H. (b) (3%) What is the minimum distance of the code?
(a) The parity check matrix H is:
1 1 1 0 1
0 1 0 1 1
0 1 1 0 0
To find the parity check matrix H, we can use the fact that H is the transpose of the generator matrix G with an identity matrix on the right side.
Given the generator matrix G:
1 0 0 1
1 1 1 0
1 0 1 1
0 1 0 0
1 1 0 1
We can rewrite G as:
1 0 0 1 1 1 0 0
1 1 1 0 0 1 1 0
1 0 1 1 1 0 1 1
0 1 0 0 1 1 0 0
1 1 0 1 0 1 1 1
Now, we can obtain the parity check matrix H by taking the transpose of G and removing the rightmost identity matrix:
H = Transpose(G without the rightmost identity matrix)
H =
1 1 1 0 1
0 1 0 1 1
0 1 1 0 0
Therefore, the matrix H is:
1 1 1 0 1
0 1 0 1 1
0 1 1 0 0
(b) The minimum distance of a linear block code is the smallest number of bit positions in which any two codewords differ. It determines the error detection and correction capability of the code.
To find the minimum distance of the code, we can examine the columns of the parity check matrix H. The number of non-zero entries in the smallest column gives us the minimum distance.
Looking at the parity check matrix H, we see that the smallest column has two non-zero entries in positions 1 and 2. Therefore, the minimum distance of the code is 2.
In conclusion, the minimum distance of the code is 2.
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(3)(0.2)+9 help please
Answer:
9.6
Step-by-step explanation:
Answer:
[tex]9.6[/tex]
Step-by-step explanation:
1) Simplify 3 × 0.2 to 0.6.
[tex]0.6 + 9[/tex]
2) Simplify.
[tex]9.6[/tex]
Hence, the answer is 9.6
could someone help me solve 7h plus 3
2. A wooded area is in the shape of a a trapezoid whose bases measure 128 m and $2 m and its height is 40 m. A 4 m wide walkway is constructed which runs perpendicular from the two bases. Calculate the area of the wooded area after the addition of the watkway
Correction in the Question:
A wooded area is in the shape of a a trapezoid whose bases measure 128 m and 92 m and its height is 40 m. A 4 m wide walkway is constructed which runs perpendicular from the two bases. Calculate the area of the wooded area after the addition of the walkway.
Answer:
The wooded area after the addition of the walkway is 4240 [tex]m^2[/tex].
Step-by-step explanation:
we are given
length of the two bases = 128m and 92m
height of the trapezoid = 40m
the approximate figure of the given trapezoid is given as:
__ __ __ 92 __ __ _
/ | | | \
/ | 40 |4| \
/__ _| __ __ | |__ __ __ __ \
128
Area of a trapezoid = [(a + b)/2] * height, where a and b are representing the bases of the given trapezoid.
Area = [(92 + 128)/2] * 40
= [220/2] * 40
= 110 * 40
= 4400 [tex]m^2[/tex]
Now there is a 4m wide walkway is to be constructed in that trapezoid. The pathway will be a rectangle as it has 4m width and 40m height as it is perpendicular to both the bases.
Area of a rectangle = length * width
Area = 40 * 4
= 160
Since the walkway will reduce the area of the trapezoid as it is constructed upon it therefore the wooded area after the addition of the walkway is
4400 + (-160) = 4240 [tex]m^2[/tex].
Help me plzzz with rectangle
Answer:
26
Step-by-step explanation:
please help me with this i will give brainliest
Answer:
A and E, The first and the last
Need help as soon as possible pls help
1. The value of x is:
180° - 40° - 30° = 110°
2. The value of x is:
90°- 38° = 52°
Answer:
Step-by-step explanation:
180 = 40 + x + 30
110 = x
90 = 38 + x
52 = x
Find the radius of the button.
28 mm
radius:
mm
Answer:
14 mm
Step-by-step explanation:
Just write down the answer.
Answer:
28mm
Step-by-step explanation:
is the right answer
consider the polynomial function q(x)=-2x^8+5x^6-3x^5+50
What is the end behavior of the graph of q?
Choose 1 answer:
(Choice A) As x→∞, q(x)→∞, and as x→−∞, q(x)→∞
(Choice B) As x→∞, q(x)→-∞, and as x→−∞, q(x)→∞
(Choice C) As x→∞, q(x)→-∞, and as x→−∞, q(x)→-∞
(Choice D) As x→∞, q(x)→∞, and as x→−∞, q(x)→-∞
Answer:
C.
Step-by-step explanation:
Answer A and D are definitely incorrect. Hope this helps Zoey. #Zoeyiscute:)
Please help!!
A circle has a circumference of 1007 cm. What is the radius of the circle?
Answer:
3/2 I'm not sure I think it's that
Take the sample mean of this data series: 15, 26, 25, 23, 26, 28, 20, 20, 31, 45, 32, 41, 54, 23, 45, 24, 90, 19, 16, 75, 29 And the population mean of this data series: 15, 26, 25, 23, 26, 28, 20, 20, 31, 45, 32, 41, 54, 23, 45, 24, 90, 19, 100, 75, 29 Calculate the difference between the two quantities (round to two decimal places)
The sample mean of the given data series is 33.7 and the population mean is 35.86. The difference between the two quantities, rounded to two decimal places, is -2.16.
Sample mean and population mean are important terms in statistics. The sample mean is the average of a set of data taken from a larger population, while the population mean is the average of an entire population.
To find the sample mean of the given data series, we add up all the values and divide by the total number of values. Therefore,
Sample mean = (15+26+25+23+26+28+20+20+31+45+32+41+54+23+45+24+90+19+16+75+29) / 21
Sample mean = 33.7
To find the population mean, we use the same formula but with all the values of the population included. Therefore,
Population mean = (15+26+25+23+26+28+20+20+31+45+32+41+54+23+45+24+90+19+100+75+29) / 21
Population mean = 35.86
Finally, to find the difference between the two quantities, we subtract the sample mean from the population mean. Therefore,
Difference = Population mean - Sample mean
Difference = 35.86 - 33.7
Difference = -2.16 (rounded to two decimal places)
Therefore, the difference between the sample mean and population mean is -2.16.
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The distribution of white blood cell count per cubic millimeter of whole blood is approximately Normal with mean 7500 and standard deviation 1750 for healthy patients Include an appropriately labeled and shaded Normal curve for each part. There should be three separate curves. 4. What is the probability that a randomly selected person will have a white blood cell count of between 2000 and 10,000?
The probability that a randomly selected person will have a white blood cell count of between 2000 and 10,000 is 0.9223 approximately.
The given mean, standard deviation, and the range of values are as follows:
Mean = 7500
Standard deviation = 1750
Range of values = Between 2000 and 10000
We are required to calculate the probability of a random person having a white blood cell count between 2000 and 10000.
Let's find the Z values for 2000 and 10000.Z1 = (2000 - 7500) / 1750 = -3Z2 = (10000 - 7500) / 1750 = 1.43
The required probability is the sum of the probability of the given range of values.
The probability of the first value is:P(X < 2000) = P(Z < -3) = 0.00135
The probability of the second value is:P(X > 10000) = P(Z > 1.43) = 0.0764
To find the probability for the given range, we will subtract the probability of the second value from the probability of the first value.
P(2000 < X < 10000) = 1 - P(X < 2000) - P(X > 10000)P(2000 < X < 10000)
= 1 - 0.00135 - 0.0764P(2000 < X < 10000) = 0.9223
The probability that a randomly selected person will have a white blood cell count between 2000 and 10,000 is 0.9223, approximately.
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44/15 converted into a mixed number (convert a fraction into a decimal before converting it into a mixed number)
Answer:
2 14/15
Step-by-step explanation:
44/15= 2.9333333333333
2.9333333333333= 2 14/15