HELP PLEASE AND ASAP!! look at screenshot (10 pts)

HELP PLEASE AND ASAP!! Look At Screenshot (10 Pts)

Answers

Answer 1

Answer:

C

Step-by-step explanation:

Add like terms to get

4.5a + 4b + 3.5c


Related Questions

Ben opened a savings
account with $75,
Every week he added
$20 more. Write on
equation to model this
situation.

Answers

Answer:

The equation would be y = 75 + 20x

Find the value of x.

Answers

Answer:

14

Step-by-step explanation:

kswkekddkkekekekeke

jskekekkeenenen

nnwkekekenr

wnwnene

snsn

wm

w

Select all the equations that are true when xis -4.
A)-8 = 2x
B) -12 = x.-3
C) -12 = x+x+x
D = -1
Ex+4 = -8
F = -16

Answers

Answer:

A,C and D are the correct options.

Find the value of x ​

Answers

Answer:

dkeekek

Step-by-step explanation:

kddeejwkwnqnnwwnwwnwnwnwwnw

Answer:

use pythagoras theorem for solving this

value of x is 12 cm

What angle of rotation maps p onto P'?

Answers

Alms Alan’s Alanaj am so

HELP Me PLEASE I'M BEGGING. I GOT TO SEND IT TONIGHT

Answers

Answer:

1. -34

Step-by-step explanation:

10 x 10 = ? for easy points

Answers

100! Thanks for the easy points

Answer:

[tex]\huge\mathfrak{Heya\:Mate}[/tex]

[tex]\huge{\boxed{\bold{ANSWER}}}[/tex]

[tex]10 \times 10 \\ = 10^{2} \\ = 100[/tex]

⁺˚*・༓☾✧.* ☽༓・*˚⁺‧

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Mr. Herman's class is selling candy for a school fundraiser. The class has a goal of raising $500 by selling C
boxes of candy. For every box they sell, they make $2.75.
Write an equation that the students could solve to figure out how many boxes of candy they need to sell.

Answers

Answer:

2.75 x (c) = 500

Step-by-step explanation:

i think this is it

Help please will give brainlist!!!

MODELING REAL LIFE The equation y=2x + 3 represents the cost y(in dollars) of mailing a package that weighs x pounds.
a. Use a graph to estimate how much costs to mail the package.
b. Use the equation to find exactly how much it costs to mail the package.
It costs $ to mail the package.

Answers

Answer:

I can't read the weight of the package due to the image quality, could you type it out please.

The effectiveness of a blood-pressure drug is being investigated. An experimenter finds that, on average, the reduction in systolic blood pressure is 35.5 for a sample of size 767 and standard deviation 15.2. Estimate how much the drug will lower a typical patients systolic blood pressure (using a 90% confidence leve). Enter your answer as a tri-linear inequality accurate to one decimal place (because the sample statistics are reported accurate to one decimal place).

_____<µ<______

Answers

The tri-linear inequality that estimates how much the drug will lower a typical patient's systolic blood pressure using a 90% confidence level is 34.5 < µ < 36.5.

Given that the sample mean of a blood-pressure drug is 35.5 for a sample size of 767 and standard deviation 15.2, to estimate how much the drug will lower a typical patient's systolic blood pressure, we use the following formula of a confidence interval:

Confidence interval = sample mean ± margin of error,

where the margin of error = z(α/2) * (σ/√n),

σ = 15.2, the standard deviation

n = 767, sample size

α = 0.10, level of significance

z(α/2) = 1.645 (from a standard normal distribution table)

Plugging in the values,

Margin of error = 1.645 * (15.2 / √767)≈ 1.02

Confidence interval = 35.5 ± 1.02≈ 34.5 < µ < 36.5

Therefore, the blood-pressure drug will lower a typical patient's systolic blood pressure within the range of 34.5 and 36.5.

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Which expression is equivalent to
[tex](3 {u}^{3} {v}^{4}) ^{2} [/tex]
A.
[tex]3 {u}^{5} {v}^{6} [/tex]
B.
[tex]3 {u}^{6} {v}^{8} [/tex]
C.
[tex]9 {u}^{6} {v}^{8} [/tex]
D.
[tex]9 {u}^{5} {v}^{6} [/tex]

Answers

Answer:

C

Step-by-step explanation:

When 3 is squared, it becomes 9. That means that both A and B are incorrect.

The powers on u and v are doubled not added to become u^6 and v^8 so that makes C the only possible answer.

Why didn't some materials Sink in water and some others didn't?​

Answers

Items that are denser than water sink and items that are less dense than water float

Answer: Materials sink in water depending on how  heavy they are. It is about how heavy something is compared to the same amount (volume) of water. This ratio of an object’s mass to its volume is known as density. Density is what really determines whether something will sink or float.

there are 12 socks in flora drawer 9 are red and 2 are blue and 1 is green she take out one sock without looking at the color. What is the numerical probability of flora picking out a blue sock?

Answers

The numerical probability of Flora picking out a blue sock is 1 out of 6, or approximately 0.1667, or 16.67%.

To calculate the numerical probability of Flora picking out a blue sock, we need to consider the total number of socks and the number of blue socks in the drawer.

Given:

Total number of socks = 12

Number of red socks = 9

Number of blue socks = 2

Number of green socks = 1

The probability of Flora picking a blue sock can be calculated as the ratio of the number of blue socks to the total number of socks:

Probability of picking a blue sock = Number of blue socks / Total number of socks

Probability of picking a blue sock = 2 / 12

Simplifying the fraction, we get:

Probability of picking a blue sock = 1 / 6

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The depth of a river changes after a heavy rainstorm, Its depth, in feet, is modeled as a function of time, in hours. Consider this graph of the function. Enter the average rate of change for the depth of the river, measured as feet per hour, between hour 9 and hour 18. Round your answer to the nearest tenth

Answers

Answer:

The average rate of change for the depth of the river measured as feet per hour is approximately 0.3 feet/hour

Step-by-step explanation:

The depth of the river in feet with time is given by the function with the attached

From the graph, we have;

The depth of the river at hour t = 9 is f(9) = 18 feet

The depth of the river at hour t = 18 is f(18) = 21 feet

The average rate of change, A(x), for the depth of the river measured as feet per hour is given as follows;

[tex]A(X) = \dfrac{f(b) - f(a)}{b - a}[/tex]

Therefore, for the river, we have;

[tex]A(X) = \dfrac{f(18) - f(9)}{18 - 9} = \dfrac{21 - 18}{18 -9} = \dfrac{3}{9} =\dfrac{1}{3}[/tex]

The average rate of change for the depth of the river measured as feet per hour A(X) = 1/3 feet/hour

By rounding the answer to the nearest tenth, we have;

A(X) = 0.3 feet/hour.

Find the common difference of the arithmetic sequence 13, 10, 7

Answers

-3,
13-3=10
10-3=7
then you just know the common difference is 3

Answer: -3

Step-by-step explanation: DeltaMath

Find the area of the shape shown below. Please help :(

Answers

Answer:

the area is 42 square units

Step-by-step explanation:

lets break it down

12 x 1 = 12

12 x 5 = 60

60 / 2 = 30

12 + 30 = 42

Calculate the relative error of approximation On methods. y(t) = 8e²-8 (t+1) y (1) for all of three

Answers

The relative error is found by approximating y(1) relative to the exact value 8e²-16.

The relative error of approximation for the given method can be calculated using the formula:

Relative error = |(approximated value - exact value) / exact value| * 100%

In this case, we have the function y(t) = 8e²-8 (t+1) and need to approximate the value of y(1) using three different methods. To calculate the relative error for each method, we substitute t = 1 into the function and compare the approximated value with the exact value.

In the first paragraph,

To calculate the relative error of approximation for the given methods in estimating y(t), we substitute t = 1 into the function y(t) = 8e²-8 (t+1). By comparing the approximated values with the exact value, we can determine the relative error for each method.

In the second paragraph:

Let's evaluate the function at t = 1:

y(1) = 8e²-8 (1+1) = 8e²-8(2) = 8e²-16

Now, let's consider the three methods for approximating y(1) and calculate their respective relative errors:

Method 1: Approximated value = 8e²-8 (1+1) = 8e²-16

Relative error = |(8e²-16 - 8e²-16) / 8e²-16| * 100% = 0%

Method 2: Approximated value = 8e²-8 (1+1) - 8 = 8e²-24

Relative error = |(8e²-24 - 8e²-16) / 8e²-16| * 100% = |8e²-24 - 8e²-16| / |8e²-16| * 100%

Method 3: Approximated value = 8e²-8 (1+1) + 8 = 8e²-8

Relative error = |(8e²-8 - 8e²-16) / 8e²-16| * 100% = |8e²-8 - 8e²-16| / |8e²-16| * 100%

By calculating the relative error using the above formulas, we can determine the accuracy of each method in approximating y(1) relative to the exact value 8e²-16.

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Rosie bought a ring in the USA she paid 345 US dollars work out in pounds the amount rosie paid for the ring

Answers

1 Us dollar equals to 0.72 Pound sterling so to convert 345 US dollars to British sterling we’ll need to multiply the amount of dollars by 0.72, so
345 x 0.72 = 248.4
345 us dollars = 248.4 British pounds
Rosie paid 248.4 British pounds for the ring. Hope this helped

Answer:

Step-by-step explanation:

Consider the initial value problem y" + 16 = 48t, y(0) = 5, y'(0) = 2. a. Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t) by Y(S). Do not move any terms from one side of the equation to the other (until you get to part (b) below). 48/s^2 help (formulas) b. Solve your equation for Y(s). Y(s) = L{y(t)} = (58^3+2s^2+48)/(s^2(s^2+16)) c. Take the inverse Laplace transform of both sides of the previous equation to solve for y(t).

Answers

a. To solve the initial value problem using Laplace transforms, we start by taking the Laplace transform of both sides of the given differential equation. The Laplace transform of y(t) is denoted as Y(s). The Laplace transform of the second derivative y"(t) can be expressed as s²Y(s) - sy(0) - y'(0), where y(0) and y'(0) are the initial conditions. The Laplace transform of 48t is simply 48/s².

Applying the Laplace transform to the given differential equation, we get:

s²Y(s) - sy(0) - y'(0) + 16Y(s) = 48/s²

Substituting the initial conditions y(0) = 5 and y'(0) = 2, we have:

s²Y(s) - s(5) - 2 + 16Y(s) = 48/s²

Simplifying this equation gives the corresponding algebraic equation in terms of Y(s).

b. Now, we solve the equation obtained in part (a) for Y(s). Rearranging the terms, we have:

(s² + 16)Y(s) = 48/s² + s(5) + 2

Combining like terms, we get:

(s² + 16)Y(s) = (48 + 5s² + 2s) / s²

Dividing both sides by (s² + 16), we obtain:

Y(s) = (48 + 5s² + 2s) / (s²(s² + 16))

So, Y(s) is equal to the Laplace transform of y(t).

c. To find y(t), we take the inverse Laplace transform of Y(s) obtained in part (b). We can use partial fraction decomposition and the properties of Laplace transforms to simplify the expression and find the inverse Laplace transform.

Taking the inverse Laplace transform of Y(s), we find:

y(t) = L^(-1){Y(s)} = L^(-1){(48 + 5s² + 2s) / (s²(s² + 16))}

The inverse Laplace transform can be calculated using tables or software, and it yields the solution y(t) to the initial value problem.

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If a population of 10,000 increases by 5% every year, how large will the population be in 5 years?

______________________________​

Answers

Answer:

10.500

Step-by-step explanation:

step by step explenation

A random sample of n1 = 201 people who live in a city were selected and 73 identified as a "dog person." A random sample of n2 = 91 people who live in a rural area were selected and 56 identified as a "dog person." Find the 99% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person."

Answers

The 99% confidence interval for the difference in approximately (-0.409123, -0.095277).

Calculating the 99% confidence interval

To obtain the confidence interval for the difference in the proportions, we use the formula:

Confidence Interval = (p₁ - p₂) ± Z × √((p₁ × (1 - p₁) / n₁) + (p₂ × (1 - p₂) / n₂))

Where:

p₁ and p₂ are the proportionsn₁ and n₂ are the sample sizes of the city and rural areas respectively.Z = Z-score level (99% confidence level means Z = 2.576).

Given the parameters:

p₁ = 73 / 201 = 0.3632

p₂ = 56 / 91 = 0.6154

n₁ = 201

n₂ = 91

Z = 2.576

Plugging in the values:

Confidence Interval = (0.3632 - 0.6154) ± 2.576 × √((0.3632 × (1 - 0.3632) / 201) + (0.6154 × (1 - 0.6154) / 91))

Confidence Interval = -0.2522 ± 2.576 × √((0.3632 × 0.6368 / 201) + (0.6154 × 0.3846 / 91))

Confidence Interval = -0.2522 ± 2.576 × √(0.003712)

Confidence Interval = -0.2522 ± 2.576 × 0.060851

Confidence Interval = -0.2522 ± 0.156923

Confidence Interval = (-0.409123, -0.095277)

Therefore, the 99% confidence interval is approximately (-0.409123, -0.095277).

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Duncan has cups of sand. He divides the sand equally into 4 containers. He uses all the sand in 1 container to make pieces of sand art. It takes cups of sand to complete each piece of sand art. How many pieces of sand art does Duncan make? A. 1 2/3 B. 2 C. 4 D. 5 5/9

Answers

Answer:

4

Step-by-step explanation:

From the above question:

1/4 cup of sand = 1 sand art

1 cup of sand = x

Cross Multiply

x × 1/4 cup of sand = 1 cup of sand × 1 sand art

x = 1 cup of sand × 1 sand art/1/4 cup of sand

x = 1 ÷ 1/4

x = 1 × 4

x = 4 pieces sand art

Therefore, Duncan can make 4 pieces of sand art.

Twelve identical computers are to be distributed to an elementary, middle, high school and community college. How many ways are there to distribute the 12 computers to the four schools, if we assume that some schools might end up with none, but all 12 must be given out

Answers

There are 91 ways to distribute the 12 identical computers among the elementary, middle, high school, and community college, ensuring that all 12 computers are given out.

To find the number of ways to distribute 12 identical computers among four schools (elementary, middle, high school, and community college) while ensuring that all 12 computers are given out, we can use the concept of stars and bars or the balls and urns method.

Let's represent the distribution using stars and bars. We have 12 identical stars (representing the computers) and 3 identical bars (representing the separators between the four schools). The bars divide the stars into four groups, each representing the number of computers given to each school.

We need to determine the number of ways to arrange the 12 stars and 3 bars. This can be calculated using the formula:

Number of ways = (n + k - 1) choose (k - 1) where n is the number of stars (12) and k is the number of bars (3).

Using this formula, the number of ways to distribute the 12 computers among the four schools is:

Number of ways = (12 + 3 - 1) choose (3 - 1)

            = 14Choosee 2

            = 91

Therefore, there are 91 ways to distribute the 12 identical computers among the elementary, middle, high school, and community colleges, ensuring that all 12 computers are given out.

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PLZ HELPPPPPPP AND EXPLAIN BC I HAVE NO CLUE HOW TO DO THIS

A.) 500
B.) 490
C.) 21
D.) 390

Answers

i had this but your numbers aren't the same i thought i could help you..

HELP ME!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

H

Step-by-step explanation:

If they are similar that means that they are racially the same so just divide 60 by 84 to find the rate and then multiply the rate by 210 to get your answer

Find the area of the circle. Round your answer to the nearest hundredth. Use 3.14 or 22/7 for π (pi)

Answers

Answer:

3.14

Step-by-step explanation:

1x1xpi

1x3.14=3.14

In general, how many variables are there in an experiment? O a. Many including independent and dependent variables n O b. One independent variable and one dependent variable O c. None because experiments are controlled for the best results O d. Moisture and temperature are the only variables

Answers

In an experiment, there are many variables including independent and dependent variables. Therefore, the correct option is a.

Many including independent and dependent variables.

Variables are any feature, amount, or state that can be quantified or measured in any way. In a study, the term variable refers to any feature that can be changed or manipulated.

Variables in an Experiment. In an experiment, an independent variable is a variable that is changed or manipulated by the experimenter, and a dependent variable is a variable that is measured in response to the independent variable.

An independent variable is a variable that is changed or manipulated in an experiment by the researcher. The independent variable is the one that the researcher controls in order to examine its effect on the dependent variable.

The dependent variable is the variable that is measured in response to changes in the independent variable. This is the variable that the experimenter is interested in studying and is affected by the independent variable.

An experiment is a scientific study in which the researcher manipulates one or more independent variables in order to observe the effect on the dependent variable.

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what is the area of a trapezoid​

Answers

Answer:

28 in² = 28

Step-by-step explanation:

[tex]a = \frac{a + b}{2}h[/tex]

[tex]a = 6[/tex]

[tex]b = 8[/tex]

[tex]h = 4[/tex]

[tex]a = \frac{6 + 8}{2}4[/tex]

[tex] \frac{14}{2} 4[/tex]

[tex]7 \times 4[/tex]

[tex] = 28[/tex]

Answer = 28 _

What is the quotient of 905.8 and 0.2?​

Answers

Answer: 4529

Step-by-step explanation:

Hope it helps Have a good Day

Just divide it

HURRY PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

Answers

Answer:

Option 3 Or number 5

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

Eight people are at least 169.5 cm tall because the frequency of people that height is five. The frequency of people taller than 169.5 (because it said 'at least') is three. 5 + 3 = 8

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