There are 20 electrons in the cyclobutadiene molecule shown in the image.
Cyclobutadiene is a molecule that contains 4 carbon atoms and 4 hydrogen atoms. The chemical formula for cyclobutadiene is C4H4. It is a highly reactive molecule and is unstable in its pure form. It has a square planar shape, and each carbon atom is bonded to two neighboring carbon atoms and one hydrogen atom.
Each carbon atom in cyclobutadiene has four valence electrons, and each hydrogen atom has one valence electron. Valence electrons are the outermost electrons in an atom and are involved in chemical bonding. The number of valence electrons in an atom is determined by the group number in the periodic table.
Carbon is in group 14, so it has 4 valence electrons. Hydrogen is in group 1, so it has 1 valence electron. The total number of valence electrons in cyclobutadiene is calculated by adding the valence electrons of all the atoms.
4 carbon atoms x 4 valence electrons per carbon atom = 16 valence electrons4 hydrogen atoms x 1 valence electron per hydrogen atom = 4 valence electrons Total number of valence electrons = 16 + 4 = 20Therefore, there are 20 electrons in the cyclobutadiene molecule shown in the image.
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What would be the mass, in grams, of 3.50 x 1025 molecules of chlorine?
Show your work
Answer:
2059.645g Cl
Explanation:
A mole of any element contains 6.022e23 molecules, so we will divide the given amount of molecules by 6.022e23.
3.5e25 / 6.022e23 = 5.81e1
5.81e1 = 58.1 mol Cl
Now that we have found the amount of moles of Chlorine, we will multiply the number of moles by the molar mass of Chlorine, which is 35.45g/mol.
35.45(58.1) = 2059.645g Cl
Calculate the solubility of Fe(OH)3 in buffer solutions having the following pHs: a) pH = 4.50; b) pH = 7.00; c) pH 9.50. The Ksp of Fe(OH)_3 is 2.8x10-3^9. a) 8.9x10-11 M; b) 2.8x10-18 M; c) 8.9x10-26 M
[tex]a) 8.9**10^-11 M; b) 2.8*10^-18 M; c) 8.9*10^-26 M[/tex] is the answer. Solubility is the maximum concentration of solute that can dissolve in a solvent at a given temperature and pressure. It is represented by Ksp.
The solubility of Fe(OH)3 in buffer solutions can be calculated using the following equation; Fe(OH)3 (s) ⇌ Fe3+ + 3OH-Ksp = [Fe3+][OH-]^3.
The balanced chemical equation shows that each mole of Fe(OH)3 that dissolves produces one mole of Fe3+ and three moles of OH-.
Step 1: Calculate the concentration of OH-.a) pH = 4.50.
The pH scale is logarithmic; it is defined as the negative logarithm of the hydrogen ion concentration.
To obtain the hydroxide ion concentration, we need to use the following equation;
pH + pOH
= [tex]14pOH[/tex]
= [tex]14- 4.5[/tex]
= [tex]9.50[OH-][/tex]
= [tex]1.00 * 10^-9.50[/tex]
= [tex]3.16 * 10^-10 M.[/tex]
Step 2: Calculate the solubility of Fe(OH)3.[Fe3+]
= solubility of Fe(OH)3Ksp
= [tex][Fe3+][OH-]^32.8 * 10^-39[/tex]
= [tex][Fe3+][3.16 * 10^-10 M]^3[Fe3+][/tex]
= [tex]8.94 * 10^-11 Mb) pH[/tex]
= [tex]7.00pOH[/tex]
= [tex]14 - 7.00[/tex]
= [tex]7.00[OH-][/tex]
= [tex]1.00 * 10^-7.00[/tex]
= [tex]1.00 * 10^-7 M[Fe3+][/tex]
= solubility of Fe(OH)3Ksp
= [tex][Fe3+][OH-]^32.8 * 10^-39[/tex]
= [tex][Fe3+][1.00 * 10^-7 M]^3[Fe3+][/tex]
= [tex]2.84 * 10^-18 Mc) pH 9.50pOH[/tex]
= [tex]14 - 9.50 = 4.50[OH-][/tex]
= [tex]1.00 * 10^-4.50[/tex]
= [tex]3.16 * 10^-5 M[Fe3+][/tex]
= solubility of Fe(OH)3Ksp
=[tex][Fe3+][OH-]^32.8 * 10^-39[/tex]
= [tex][Fe3+][3.16 x 10^-5 M]^3[Fe3+][/tex]
= [tex]8.94 * 10^-26 M[/tex]
Therefore, [tex]a) 8.9*10^-11 M; b) 2.8*10^-18 M; c) 8.9*10^-26 M[/tex]is the answer.
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Which of the following statements is true?
Volcanoes can form mountains and islands.
Most changes to the crust happen slowly over time.
Plateaus are large, flat areas of land more than two thousand feet tall.
all of the above
Kathy is trying to conduct an experiment she wants an element that is
very reactive, which of these should she use?
how do hydrogen fuel cells and fossil fuels produce energy?
Answer:
The hydrogen reacts with oxygen across an electrochemical cell
Explanation:
PLEASE HELP ILL GIVE BRAINLYIST
In which domain do organisms live deep in the Pacific Ocean where hot gases and molten rock spew from vents on the ocean floor?Immersive Reader
bacteria
eukarya
archaea
Answer:
bacteria
Explanation:
2.0 L of a gas is at STP. What is the new pressure in kPa if the volume changes to 10.5 L and the temperature and # of molecules remain constant?
Answer:
What is the new volume if the temperature is constant? V=2.50L. P = lookPa. P2=40k Pa. V2 = x. PV = P2 ... If a sample of gas occupies 6.8 L at 327°C
Predict the electron pair geometry and the molecular structure of each of the following molecules or ions: (a) ClNO (N is the central atom); Determine: electron-pair geometry ; molecular structure ; (b) CS2; Determine: electron-pair geometry ; molecular structure ; (c) Cl2CO (C is the central atom); Determine: electron-pair geometry ; molecular structure ; (d) Cl2SO (S is the central atom); Determine: electron-pair geometry ; molecular structure ; (e) SO2F2 (S is the central atom); Determine: electron-pair geometry ; molecular structure ; (f) XeO2F2 (Xe is the central atom); Determine: electron-pair geometry ; molecular structure ; (g) ClOF2 (Cl is the central atom); Determine: electron-pair geometry ; molecular structure ;
Answer:
See explanation
Explanation:
In ClNO , nitrogen is the central atom here. The central atom has a tetrahedral electron pair geometry and a lone pair on the nitrogen atom. Due to the lone pair, the electron pair geometry is now trigonal pyramidal.
The molecule CS2 has a linear molecular geometry. There are four electron groups around the central atom hence the electron pair geometry is tetrahedral but the molecular geometry results from the repulsion of the two double bonds.
The electron domain geometry for Cl2CO is tetrahedral since there are four electron pairs around the central atom. However, the molecular geometry is trigonal planar due to the sp2 hybridization of the central carbon atom.
The electron domain geometry of Cl2SO is tetrahedral due to the four electron pairs around the central atom. However, due to the lone pair on sulphur, the molecular geometry is triagonal pyramidal.
In SO2F2, sulphur the central atom is surrounded by four electron pairs which are all bonding groups hence both the molecular geometry and the electron pair geometry is tetrahedral.
In XeO2F2, the central atom is Xe. There are five electron pairs around the Xe central atom four of which are bonding groups. The electron domain geometry and molecular geometry is trigonal bipyramidal.
For ClOF2 , the central atom Cl is surrounded by four electron pairs hence the electron pair geometry is tetrahedral but it is an AX3E(three bonding groups and one lone pair are present in the structure) specie hence it is trigonal pyramidal.
A neutralization is a type of reaction. Identify the reactants & products in this type of reactions.
Answer:
please give me brainlist and follow
Explanation:
In this type of neutralization reaction, the acids and bases are the reactants, since they are the materials that will react to form a new solution. ... For instance, in the equation HCl + NaOH → NaCL + H2O, the HCl (hydrochloric acid, a strong acid) and NaOH (sodium hydroxide, a strong base) are the reactants.
Define Transportation plants:
Define Respiration Plants:
Answer:
Define Transportation in plants: Transportation in plants is when the plant transports water and other mineral throughout the whole plant from the roots to the stem and finally specific parts of a plant.
Define Respiration In Plants: Is when plants use photosynthesis to make their own food to make energy for the plant's growth
How do you make the shadows of objects appear bigger on the screen
Explanation:
Indoors, you can change the size of a shadow by moving your body or the object closer to or farther from the light.
Shadows grow bigger and fuzzier as the object moves closer to the light source, and smaller and sharper as the object moves farther away.
Use the reaction shown l to answer these questions.
2CO(g) + 2NO) → N2(g) + 2CO2(g)
If 42.7 g of CO is reacted completely at STP, what
volume of N2 gas will be produced?
To determine the volume of N_{2} gas produced when 42.7 g of CO is reacted completely at STP (Standard Temperature and Pressure), we need to use the concept of molar ratios and the ideal gas law. By calculating the number of moles of CO and using the balanced equation, we can find the number of moles of [tex]N_{2}[/tex]. Then, using the ideal gas law, we can convert the moles of N_{2} to volume at STP.
First, we need to determine the number of moles of CO using its molar mass. The molar mass of CO is approximately 28.01 g/mol. By dividing the given mass (42.7 g) by the molar mass, we can calculate the number of moles of CO. Next, using the balanced equation, we see that the stoichiometric ratio between CO and N2 is 2:1. This means that for every 2 moles of CO, 1 mole of N_{2}is produced. By applying the stoichiometric ratio, we can determine the number of moles of N_{2}produced.
Finally, to find the volume of N2 gas at STP, we can use the ideal gas law. At STP, the pressure is 1 atmosphere (atm) and the temperature is 273.15 K. The ideal gas law equation, PV = nRT, can be rearranged to V = (nRT)/P, where V is the volume, n is the number of moles, R is the ideal gas constant, T is the temperature in Kelvin, and P is the pressure. By substituting the calculated number of moles of N_{2}, the ideal gas constant, the temperature at STP, and the pressure at STP into the ideal gas law equation, we can determine the volume of N_{2} gas produced.
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Based on the reduction potential data, What is the standard cell potential for the following electrochemical cell reaction:
Zn(s) + Cu^2+(aq) Zn^2+(aq) + Cu(s)?
E red = -0.763 V for Zn^2+ (aq) + 2e^- Zn(s)
E red = +0.340 V for Cu^2+(aq) + 2e^- Cu(s)
a. -0.423 V
b. +1.10 V
c. +0.423 V
The standard cell potential (E° cell) for the given electrochemical cell reaction is +1.103 V. (B)
Based on the reduction potential data, the standard cell potential for the electrochemical cell reaction: Zn(s) + Cu⁺(aq) + Zn²⁺aq) + Cu(s) can be calculated as follows:
Reaction: Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)
The standard cell potential (E° cell) is calculated as follows:E° cell = E° red(cathode) - E° red(anode)
We have, E° red(Zn²⁺) = -0.763 VE° red(Cu²⁺) = +0.340 V
Therefore,E° cell = E° red(Cu²⁺) - E° red(Zn²⁺) = 0.340 V - (-0.763 V) = +1.103 V
The standard cell potential for the electrochemical cell reaction: Zn(s) + Cu⁺(aq) + Zn²⁺aq) + Cu(s) can be calculated using the reduction potentials for the cathode and anode.
The cathode has a reduction potential of +0.340 V for Cu²⁺(aq) + 2e⁻ Cu(s) and the anode has a reduction potential of -0.763 V for Zn²⁺ (aq) + 2e⁻Zn(s).
Using the formula,E° cell = E° red(cathode) - E° red(anode)we get,E° cell = E° red(Cu²⁺) - E° red(Zn²⁺) = 0.340 V - (-0.763 V) = +1.103 V.(B)
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what is the significance of the symbol and formula
Answer:
please give me brainlist and follow
Explanation:
Importance of symbols and Formulae :
Symbols and formulae of substance gives a lot of information like. Types of elements present in the compound. E.g. (H20 is made of two elements hydrogen and oxygen). Number of each kind of atoms in one molecule.
Things people think bad about them self
1. I'm to fat/skinny
2.I'm to ugly
3.I don't love myslef
4.why doesn't anyone like me
5. Im gonna hurt myslef
stay strong
1 2 3 4 5 and how the question ask
Normal values for chemistry tests on serous fluid are different from values obtained on serum.
a. True
b. False
a. True. Due to the differences in composition between serous fluid and serum, the normal values for chemistry tests can vary.
Serum refers to the liquid component of blood that remains after the blood has clotted and the clot has been removed.
On the other hand, serous fluid is a clear, watery fluid that is similar to serum and is found in body cavities such as the pleural, peritoneal, and pericardial cavities.
The composition of serous fluid can differ from serum due to various factors. When testing serous fluid, the values for chemistry tests such as electrolytes, proteins, enzymes, and other analytes may have different reference ranges compared to those obtained from serum testing. This is because the cellular and protein content of serous fluid is different from that of blood serum.
For example, the normal range for protein concentration in serum is generally higher compared to serous fluid due to the presence of fibrinogen and other proteins involved in clotting that are not present in serous fluid.
Due to the differences in composition between serous fluid and serum, the normal values for chemistry tests can vary. Therefore, it is important to use appropriate reference ranges specific to serous fluid when interpreting the results of chemistry tests on serous fluid samples.
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2HBr(g)+Cl2(g)⇌2HCl(g)+Br2(g) Calculate the value of the equilibrium constant. I already solved for delta G
The equilibrium constant expression for the given reaction is:
[tex]K = ([HCl]^2 * [Br_2]) / ([HBr]^2 * [Cl_2])[/tex]
To calculate the value of the equilibrium constant for the reaction [tex]2HBr(g) + Cl_2(g)[/tex] ⇌ [tex]2HCl(g) + Br_2(g),[/tex] you need the concentrations (or pressures) of the reactants and products at equilibrium.
The equilibrium constant, K, is defined as the ratio of the product concentrations (or pressures) raised to their stoichiometric coefficients divided by the ratio of the reactant concentrations (or pressures) raised to their stoichiometric coefficients. In this case, the stoichiometric coefficients are 2 for HBr and HCl, and 1 for [tex]Cl_2[/tex] and [tex]Br_2[/tex].
The equilibrium constant expression for the given reaction is:
[tex]K = ([HCl]^2 * [Br_2]) / ([HBr]^2 * [Cl_2])[/tex]
Here, [HCl], [[tex]Br_2[/tex]], [HBr], and [[tex]Cl_2[/tex]] represent the equilibrium concentrations (or pressures) of HCl, [tex]Br_2[/tex], HBr, and [tex]Cl_2[/tex], respectively.
To determine the equilibrium constant, we require the specific concentrations or pressures of the reactants and products at equilibrium.
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how to find rate of reaction experimentally of the reaction ? plz help
What is the oxidation state of copper in Cu(C2H3O2)2? +2 -1 -2 +4 +1
A 0. 821 gram sample of pure NH F was treated with 25. 0 mL of 1. 00 M NaOH
and heated to drive off the NH3. How many milliliters of 0. 500 M HCl are needed for the back titration?
To complete the back titration of NH4F, a quantity of 50.0 mL of 0.500 M HCl is required.
The given chemical equation for the reaction between NH4F and NaOH is as follows: NH4F + NaOH → NaF + NH3 + H2OThe reaction between NH3 and HCl can be written as follows:NH3 + HCl → NH4ClTherefore, the total reaction can be written as follows:NH4F + NaOH + HCl → NaCl + NH4Cl + H2O
The amount of NaOH needed to react with NH4F is calculated as follows:
n = C × Vn = 1.00 M × 0.0250 Ln = 0.025 mol
The amount of NH3 generated is equal to the amount of NH4F that reacted, assuming that NH3 is fully driven off. The amount of HCl that reacts with NH3 can be calculated using the following equation:
n = C × Vn
= 0.025 molC
= n / VC = 0.025 mol / 0.500 MC
= 0.0500 LTherefore, 50.0 mL of 0.500 M HCl is needed for the back titration
To complete the back titration of NH4F, a quantity of 50.0 mL of 0.500 M HCl is required.
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Atomic Size: Determine which of the following element pairs is the larger one
1. Carbon or Fluorine
2. Iodine or Fluorine
3. Krypton or Argon
4. Hydrogen or Potassium
Answer: I think the answer is 3.) Krypton or Argon.
Explanation:
How is it possible for scientists to know the composition of stars without traveling to the star?
Answer:
One of the most common methods used today to determine the composition of stars is spectroscopy.
Explanation:
Spectroscopy is the study of the interaction between matter and electromagnetic radiation as a function of the wavelength or frequency of the radiation.
Starting with a 7. 0 x 10-5 M. Allura Red stock solution you will need to calculate the volumes required to prepare 10.00 mL solutions of 3.5 x 10-5 M, 2.8 x 10-5 M, 2.1 x 10-5 M, 1.4 x 10-5 M, and 3.5 x 10-6 M before coming to lab. What volume of the stock solution will be required to prepare 10.00 mL of a 2.1 x 10-5 M solution of Allura Red?
Answer:
1) 5.0 mL, 4.0 mL, 3.0 mL and 2.0 mL respectively.
2) 3.0 mL
Explanation:
Hello there!
1) In this case, by considering that the equation we use for dilutions contain the initial and final concentrations and volumes:
[tex]C_1V_1=C_2V_2[/tex]
For the first four solutions, we compute the volume of the stock one (V1) as shown below:
[tex]V_1=\frac{C_2V_2}{C_1}[/tex]
Thus, we obtain:
[tex]V_1^1=\frac{3.5x10^{-5}M*10.00mL}{7.0x10^{-5}M} =5.0mL\\\\V_1^2=\frac{2.8x10^{-5}M*10.00mL}{7.0x10^{-5}M} =4.0mL\\\\V_1^3=\frac{2.1x10^{-5}M*10.00mL}{7.0x10^{-5}M} =3.0mL\\\\V_1^4=\frac{1.4x10^{-5}M*10.00mL}{7.0x10^{-5}M} =2.0mL[/tex]
2) In this case, for a final concentration of 2.1x10-5 M and a volume of 10.00 mL, the volume of the stock solution would be:
[tex]V_1=\frac{2.1x10^{-5}M*10.00mL}{7.0x10^{-5}M} =3.0mL[/tex]
Best regards!
1. A student wants to find how many calories are in a peanut. Describe in detailed complete sentences how they can test this using a can with
150g of water and a thermometer.
Answer: 65 cal
Explanation: they have to find the weight of the peanuts on a scale and per grams. Then put them in water . You should be able to get the calories
the standard heat of formation for NO2 is 33.2. kj/mol. how much energy is required to form 140.0g of NO2 from its respective elements in kj
Approximately 100.916 kJ of energy is required to form 140.0 g of NO2 from its respective elements.
The energy required to form 140.0 g of NO2 from its respective elements can be calculated using the standard heat of formation and stoichiometry. First, we need to determine the number of moles of NO2 in 140.0 g. The molar mass of NO2 is 46.01 g/mol, so the number of moles is calculated as:
moles of NO2 = mass of NO2 / molar mass of NO2 = 140.0 g / 46.01 g/mol ≈ 3.043 mol
Next, we multiply the number of moles by the standard heat of formation, which is given as 33.2 kJ/mol:
energy required = moles of NO2 × standard heat of formation
= 3.043 mol × 33.2 kJ/mol
≈ 100.916 kJ
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what is the specific heat of silver? express your answer with the appropriate units.
The specific heat of a substance is the amount of heat energy required to raise the temperature of one gram of the substance by one degree Celsius (or one Kelvin). The specific heat of silver is approximately 0.235 J/g·°C (joules per gram per degree Celsius).
This means that it takes 0.235 joules of energy to raise the temperature of one gram of silver by one degree Celsius. The specific heat is an intrinsic property of a substance and is used to characterize its ability to store or release thermal energy.
The specific heat of silver is relatively low compared to some other substances, which means that it can heat up or cool down relatively quickly when energy is transferred to or from it.
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Pls help if you can, Thx! Describe ozone creation and loss in the ozone layer. Does one occur more than the other?
Ozone was created millions of years ago from a natural process frozen in ice during the ice age, the gases that make up the ozone layer were formed naturally from oxygen atoms accompanied by a reaction of ultraviolet radiation and molecular oxygen which was frozen in the ice during the time of the ice age was released over years as the ice melted.
What is an atom?An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.
The protons are positively charged and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.
Atoms of the same element are similar as they have number of sub- atomic particles which on combination do not alter the chemical properties of the substances.
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. What is the total voltage of the circuit, if you install two D-cell batteries in a flashlight so that their positive ends are facing each other compared to If you installed the batteries with the positive and negative terminal facing each other
Answer:
0
Explanation:
A voltage makes the electric charges to move.
When we install a D - cell batteries in the flashlight with their positive ends facing each other, as compared to the batteries installed with their positive and negative terminals facing each other, the flashlight will not work as the total voltage across the two batteries will be zero.
The graph below shows how solubility changes with temperature.
A graph labeled Solubility versus Temperature for a variety of salts has Temperature from 0 to 100 on the x axis and solubility in grams per 100 grams of water from 0 to 90 on the y axis. 5 solutes are shown. All data are approximate. Upper N a Upper C l starts at (0, 35) and rises evenly across the graph to (100, 40). Upper N a Subscript 2 Baseline Upper H Upper A s Upper O Subscript 4 Baseline starts at (0, 8), and rises steadily through (30, 38) to (80, 85). Upper B a (Upper N Upper O Subscript 3) Subscript 2 Baseline starts at (0, 5) and rises steadily across the graph to (100, 33). Upper N a Subscript 2 Baseline Upper S Upper O Subscript 4 Baseline starts at (0, 5), curves up steeply to (30, 50), and declines slowly to (100, 43). Upper C e Subscript 2 Baseline (Upper S Upper O Subscript 4) Subscript 3 Baseline times 9 Upper H Subscript 2 Baseline Upper O starts at (0, 19), falls to (20, 10), and continues to decline to (100, 0).
What is the solubility of Na2HAsO4 at 60°C?
20 g/100 mL of water
46 g/100 mL of water
65 g/100 mL of water
70 g/100 mL of water
Answer:
C) Na2HAsO4 and Na2SO4
Explanation:
Got it right on Edg
Answer:
The answer is C 65 g/100 mL of water
Explanation:
- The pit of an aqueous solution of NaOH is 12.9. What is the molarity of the solution?
Answer: The molarity of solution is 0.08 M
Explanation:
pH is the negative logarithm of hydrogen ion concentration. It tells abpout the acidity or basicity of a solution.
[tex]pH=-log[H^+][/tex]
also pH+pOH=14
given : pH of NaOH = 12.9
Thus pOH = (14-12.9) = 1.1
Thus [tex][OH^-]=10^{-1.1}=0.08M[/tex]
As [tex]NaOH\rightarrow Na^++OH^-[/tex]
As 1 mole of [tex]OH^-[/tex] is produced by = 1 mole of NaOH
Thus 0.08 moles of [tex]OH^-[/tex] are produced by = [tex]\frac{1}{1}\times 0.08=0.08[/tex] moles of NaOH
The molarity of solution is 0.08 M