I just need help finding the last part which is the % of composition of unknown Ni compound

500 ie2 (kj/mol) would be expected for an element.

The value of IE2 (second ionization energy) is 16 times more than IE1(first ionization energy). So, the elements easily release outer most one electron as the IE1 value is low. But, it is very reluctant to release second electron which reflected in the IE2 value. Therefore, the element will form 1+ ion.

What is ionization energy?

Ionization energy may be defined simply as a measurement of how difficult it is to remove an electron from an atom or ion or of an atom's or ion's propensity to give up an electron. Usually, when a chemical species is in its ground state, an electron is lost.

As an alternative, we might say that ionization or ionization energy is a measurement of the intensity of the attractive forces that hold an electron in a certain location.

Therefore, 500 ie2 (kj/mol) is the answer.

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Question a

Step 1

The average atomic mass of the element is calculated as:

--------------------

Step 2

Information provided:

Isotope 1:

10.0 % abundant and 23.8 amu.

Isotope 2:

40.0 % abundant and 24.6 amu.

Isotope 3:

25.8 amu, the % abundant = 100 % - 10.0 % - 40.0 % = 50.0 %

-----------------------

Step 3

Procedure:

Average atom mass = (10.0% x 23.8 amu + 40.0% x 24.6 amu + 50.0 % x 25.8 amu)/100 = 25.12 amu

Answer: 25.12 amu

Cellular respiration and photosynthesis similar is both processes break down glucose

Photosynthesis converts carbon dioxide and water into oxygen and glucose and glucose is used as food by the plant and oxygen in a byproduct whereas cellular respiration converts oxygen and glucose into water and carbon dioxide and both processes break down glucose and both are processes within the cell which make chemical energy available for life

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Assume that the given alloy nichrome is pure of nickel and chromium then, if 100 g of nichrome contains 20 g of chromium , remaining is nickel thus, it contains 80 g of nickel.

Bronze hardly rust because the iron content in this alloy is very less. The reaction iron + copper sulphate gives iron sulphate + copper.

An alloy is a metallic substance made of two or more metals. For example nichrome is a combination of nickel and chromium and brass is a combination of copper and zinc.

If the 100 g of nichrome with 20 g of chromium purely contains nickel and chromium then, it contains 100-20= 80 g of nickel.

Bronze is an alloy of copper and tin. Rust is iron oxide and since bronze contains only traces of iron hence, it hardly undergo corrosion and form rust.

Iron and copper sulphate reacts to form iron sulphate and metallic copper: iron + copper sulphate [tex]\rightarrow[/tex] iron sulphate+ Cu.

Hence, the mass of 100 g of nichrome with 20g chromium is 80 g. Bronze does not rust because of the small iron content and iron and copper sulphate reacts to give iron sulphate and Cu.

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when 35.0kg of sio2 react with 25.3kg of c, 14.4kg of si are recovered.

The percent yield for the reaction is 8.8012%

sio2 + 2c = si + co

moles of sio2 = 35*[tex]10^{3}[/tex] / 600.02   = 582.503mol

moles of c = 25*[tex]10^{3}[/tex] / 12 = 2.1083 kcal

yield = moles of si produced / mole of sio2 used

        = 512.72/582.36  * 100

        = 8.8012%

chemical reaction is a process in which one or more substances the reactants—are changed into one or more additional substances the products. Chemical elements and compounds are both substances. To produce various compounds as products, a chemical reaction rearranges the atoms that make up the reactants.

Technology, culture, and life itself are all influenced by chemical interactions. Numerous activities that involve chemical reactions have been known and used for thousands of years, including burning fuels, smelting iron, creating glass and pottery, brewing beer, and producing wine and cheese. Numerous intricate processes that take place in all living systems, as well as the Earth's geology, atmosphere, and oceans, include chemical interactions.

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The ending or suffix of the hydrocarbon name tells the bonds found between carbon atoms in the molecule. Therefore, option (B) is correct.

Hydrocarbons are entirely made up of only two kinds of atoms which are carbon and hydrogen. Hydrocarbons are typically colorless gases and weak odors. Hydrocarbons can be relatively complex structures and can be classified into four subcategories, alkanes, alkenes, alkynes, and aromatic hydrocarbons.

Hydrocarbons such as propane and butane are used for commercial fuel purposes in the form of LPG and the molecular formula for the compounds is CxHy.

In the nomenclature of hydrocarbons, the suffix of the name indicates what type of bond is present between the atoms. If all carbon atoms have a single covalent bonds then the suffix is "ane". If one or more carbon-carbon double bonds are present then the suffix is "ene". If the triple bond is present then the suffix in the name of the hydrocarbon is "yne".

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Calculate the mass, in amu, of 278 atoms of Li.

1) We need to find Li (Lithium) in the periodic table.

1) The atomic mass of Lithium is 6.94 u.

2) We can cancel some units and rearrange the equation.

3) Multiply the equation above by the number of atoms

The mass of 278 atoms of Lithium is 3.20*10^-21 u

Because of these properties, cadmium (Cd) could also be identified as a transition metal.

Cadmium (Cd) is a solid at room temperature, forms an ion that has a +1 or +2 charge, is a less reactive metal, and forms more than one unique compound with a given nonmetal.

Transition metal, any of various chemical factors which have valence electrons i.e., electrons that can participate inside the formation of chemical bonds in two shells as opposed to simplest one.

Transition metals are determined within the periodic desk among the s-block and p-block elements. Hence, they are known as d-block elements. Transition metals are unstable metals that display transitional conduct between s and p block elements, therefore their name.

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Answer:

Explanation:

Here, we want to write the net ionic equation

We start by writing the complete equation of reaction:

Now, we write out the ions as follows:

The Chromium and Nitrate ions are spectator ions

Thus, we have:

Answer: 80000 micrometers

hope i helped

The time (in years) taken for the star's light to reach the earth, given it is 6.78 light years away is 6.78 years

From the definition 6.78 light years speed, we can obtain a formula to calculate time. This is illustrated below:

Speed = distance / time

Cross multiply

Speed × time = distance

Divide both side speed

Time = distance / speed

With the above formula, we can determine the time.

The following data were obtained from the question give above:

Time = distance / speedTime = distance / speed

Time = 6.78 / 1

Time = 6.78 years

Thus, we can conclude that the time required is 6.78 years

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The molarity of hydrobromic acid is 0.2909 M and molarity of barium hydroxide is 0.1517 M.

The balanced chemical reaction of hydrobromic acid(HBr) and barium hydroxide(Ba(OH)2) is :2HBr(aq) + Ba(OH)2(aq)     BaBr2(aq) + 2H2O(l)

So for every 2 moles of hydrobromic acid (acid) 1 mole of barium hydroxide(base) is used for neutralisation.

It is given that 22.0ml of 0.162M solution of barium hydroxide is used for complete neutralisation So no of millimoles of base used =22*0.162=3.564

Number of millimoles of acid required=2*3.564=7.128

Let x be the molarity of acid.then x multiplied by volume(in ml) would give the number of millimoles as molarity=moles/volume7.128=x*24.5x=0.2909

So molarity of hydrobromic acid is 0.2909 M

The balanced chemical reaction of hydroiodic acid (HCl) and barium hydroxide(Ba(OH)2) is :2HI (aq) + Ba(OH)2 (aq)    Bal2(aq) +2H2O(l)

So for every 2 moles of hydroiodic acid (acid) 1 mole of barium hydroxide(base) is used for neutralisation.

It is given that 18.8 ml of 0.197M solution of hydroiodic acid is used for complete neutralisation

So no of millimoles of acid used = 18.8*0.197=3.7036Number of millimoles of base required=3.7036/2=1.8518

Let x be the molarity of base.then x multiplied by volume(in ml) would give the number of millimoles as molarity=moles/volume1.8518=x*12.2x=0.1517So molarity of barium hydroxide is 0.1517 M

Therefore, molarity of hydrobromic acid is 0.2909 M and molarity of barium hydroxide is 0.1517 M.

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Answer:

For part A : Length = 3

Width = 3

Height = 4

For part B : on multiplying 3 × 4 × 3 = 36

For part C : Answer = 36

The percent yield of this reaction when based on the amounts of starting materials used, a chemist calculates a possible yield of 213.4 g in a reaction and isolating her purified product, she finds that she has only 198.5g of products is 93%

The percent yield is the experimental yield upon theoretical yield divided by 100

The experimental yield is 198.5 g

The theoretical yield is 213.4 g

The percent yield is as follows;

% yield= 198.5 g/213.4= 0.93x100

%yield=93%

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Answer: Calcium carbide (CaC2) reacts with water to produce acetylene (C₂H₂):. CaC2 (s) + 2H2O (g) → Ca(OH)2 (s) + C₂H₂ (g).

The correct option is option d 1.24

What is dipole moment?

A dipole moment forms in any system where the charges are dispersed. A dipole moment could be created by both covalent and ionic bonding. The development of the dipole moments is caused by the difference in electronegativity. Electronegativity describes the chemical bonding between these two atoms.

A bond dipole moment measures the polarity between two atoms in a molecule. Bond dipole and the concept of electric dipole moment are connected. It evaluates how effectively a system separates positive and negative charges. The bond dipole moment has magnitude and direction because it is a vector quantity.

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Yes, the given statement is true that an orbital is described by combining the n quantum number with the l quantum number, for example, 1s and 3p are descriptions of orbitals.

Quantum numbers are those numbers that are used to identify and describe the distribution and position of an electron in an atom.

In general, quantum numbers are classified as principal (n), angular (l) and magnetic (m) and consist of integers starting from 0, 1, 2, 3 and so on.

The estimated values for the principal quantum i.e. 'n' are 1, 2, 3, 4, and so on.

Similarly, for angular quantum numbers i.e. 'l' the values range between 0 and n - 1.

Orbitals are found in sub-shells and are made up of these quantum numbers i.e. n and l.

A two-digit code is assigned to an orbital e.g. 2p or 4f. Here 'n' is the shell whose value is 2 and 4 and 'p' and 'f' are subshells.

If we combine the abovementioned quantum numbers then we see that for shell n= 3 there will be three subshells 3s, 3p, and 3d orbitals.

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The conversion of NO to N2 is the reaction that takes place in the catalytic converter of an automobile.

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The ABS plastic is a polymer which has styrene 28.5% by mass.

A polymer is a substance or material made up of macromolecules, which are very big molecules made up of several repeating subunits.

Styrene and acrylonitrile are polymerized with polybutadiene to create ABS, a terpolymer. Since ABS plastic is amorphous, it lacks a proper melting point.

A polymer called a terpolymer is created when three distinct monomers are copolymerized.

Let the mass of sample ABS plastic = 100 g

Given, mass of Nitrogen (N) in ABS plastic = 11.9 g

Moles of Nitrogen (N) in ABS plastic = 11.9 / 14 = 0.85 mol

1 mole of N is present in 1 mole of acrylonitrile

0.85 mol of N is present in acrylonitrile = 0.85 mol

Moles of acrylonitrile = 0.85 mol

Mass of acrylonitrile = 0.85 mol X 53 g/mol = 45.05 g

Moles of [tex]Br_2[/tex] reacted = 1.56 g / 159.8 g/mol = 0.0098 mol

As given, [tex]Br_2[/tex] and butadiene react in 1:1 by moles

So, moles of butadiene = 0.0098 mol

Mass of butadiene in 2g ABS sample = 0.0098 mol X 54 g/mol = 0.529 g

Mass of butadiene in 100g ABS sample= 0.529 / 2 x 100 g = 26.45 g

Mass of styrene in 100g ABS Sample = mass of sample - mass of butadiene - mass of acrylonitrile

Mass of styrene = 100 – 26.45 – 45.05 = 28.5g

% Mass of styrene = 28.5%

Result:

28.5% of styrene is present in 100g ABS plastic, which is a polymer.

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Answer:

salt

Explanation:

cause salt is a solid item

We can use different properties and changes to identify a chemical substance through the following below:

This is referred to as a type of substance which has a definite composition and properties and it is based on different factors.

Pure substances have their own unique properties and a mixture can be separated by using the right techniques through this which is why all is the correct choice.

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Answer: The elements with properties intermediate between those of metals and nonmetals are called semimetals (or metalloids).

Electron configurations, the atomic number of the above element is 2+2+6+2+3=15. The atomic number of the element below the given element is 15+18=33.

Titanium, Nitrogen (N), Phosphorus, Sulfur (S)

The arrangement of an atom's or molecule's electrons in atomic or molecular orbitals is known as the electron configuration in atomic physics and quantum chemistry.

Electron configurations written down. The energy level (the period) should come first when writing an electron configuration, followed by the subshell that needs to be filled and the superscript, which indicates how many electrons are in that subshell. The atomic number Z represents the total number of electrons.

In other words, we adhere to the Aufbau Principle, Pauli-exclusion Principle, and Hund's Rule, which are the three key rules.

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Given Data:

Frequency of radiation = 6.00 x [tex]10^{15}[/tex] Hz

The relationship between frequency and wavelength is expressed by the formula , c = λν, where λ is the wavelength of the radiation,

ν is the frequency of the radiation, c is the velocity of light in free space.

c =3 x  [tex]10^{8}[/tex] m/s , ν = 6.00 x [tex]10^{15}[/tex] Hz

Then , wavelength of the radiation is , λ = [tex]\frac{c}{v}[/tex] =   [tex]\frac{3X10^{8} }{6X10^{15} }[/tex]  = 0.5 x [tex]10^{-7}[/tex] m

                                                                                        = 50 nm.

Hence, the radiation with a frequency will have a wavelength  of 50 x [tex]10^{-9}[/tex]  m = 50 nm.

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During the production of paper, use a mild base such as calcium or magnesium bicarbonate to neutralize the natural acids occurring in wood pulp, and prevent the formation of additional acids.

Acid-free paper is paper if soaked in water, gives a neutral or basic pH. The production of such paper can be done from any cellulose fiber as long as the active acid pulp is removed during processing. Acid-free paper is a solution to the problem of preserving documents and preserving artwork for long periods.

The wood pulp paper becomes to be acidic from alum-rosin sizing which,  generates sulfuric acid in the presence of moisture. Acids also are formed in a paper by the absorption of pollutants such as mainly sulfur and nitrogen oxides.

The addition of bicarbonate is in excess, to provide the paper with an alkaline reserve to offer protection from further attack by acids remaining in the paper.

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The net ionic reaction equation for the change that happens when strong base is added to this buffer looks like this:

CH₃COOH(aq) + OH⁻(aq) → CH₃COO⁻(aq) + H₂O(l)

To solve this problem, we need to consider what will happen when a strong base is added to a buffer solution made from acetic acid and sodium acetate. All buffers have a basic and an acidic component. In this one the acidic component is, obviously, acetic acid, a weak acid.

When making a buffer based on a weak acid, the basic component is usually a salt of that acid, in this case, sodium acetate.

When a strong base is added to the buffer, it will dissociate to yield the metal cation and the OH⁻ anion. The basic OH⁻ anion will interact with the acidic component, neutralizing it and forming the acetate ion and water.

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2.83 lamda is the wavelength of a wave with a frequency of 105.7 x10^6 Hz in here.

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The distance the ant would have covered crawling from 6 cm to 2 cm on ruler scale would be 4 cm and the speed would be 2 cm/s.

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