I NEED HELP I WILL GIVE BRANLIEST REAL ANSWERS ONLY PLZZZ!!!!!I NEED HELP I WILL GIVE BRANLIEST REAL ANSWERS ONLY PLZZZ!!!!!I NEED HELP I WILL GIVE BRANLIEST REAL ANSWERS ONLY PLZZZ!!!!!I NEED HELP I WILL GIVE BRANLIEST REAL ANSWERS ONLY PLZZZ!!!!!I NEED HELP I WILL GIVE BRANLIEST REAL ANSWERS ONLY PLZZZ!!!!!I NEED HELP I WILL GIVE BRANLIEST REAL ANSWERS ONLY PLZZZ!!!!!I NEED HELP I WILL GIVE BRANLIEST REAL ANSWERS ONLY PLZZZ!!!!!

Answer:

-3

Step-by-step explanation:

got it right on edg

The sequence of transformations that produces R'ST' from RST is reflection over the x axis and translation 2 units right.

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, translation and dilation. Rotation, translation and reflection produce congruent images.

Triangle RST has vertices at R(0, 0), S(-2, 3) and T(-3, 1).

Triangle RST is reflected over the x axis to give R*(0, 0), S*(-2, -3) and T*(-3, -1). It is then translated 2 units right to get R'(2, 0), S'(0, -3) and T*(-1, -1).

The sequence of transformations that produces R'ST' from RST is reflection over the x axis and translation 2 units right.

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Answer:

should be 612

Step-by-step explanation:

Answer:

(10-4)²(12+10/2)=

(6)²(12+5)=

(36) (17) = 612

Step-by-step explanation:

radius = 1 inches

π = 3.14

volume of SPHERE = 4/3 × π × radius³

= 4/3 × 3.14 × 1³

= 4.19 inches³

a. The value of the integral ∬R xsin(θ) dA over the rectangle R = [0,3] x [0,1/2) is (9/4) sin(θ).

b. The value of the integral ∬D y^2 dA over the region bounded by the y-axis, y = 0, and y = 4 is 64.

a. To evaluate the integral ∬R xsin(θ) dA over the rectangle R = [0,3] x [0,1/2), we can use Cartesian coordinates. The integral becomes:

∬R xsin(θ) dA = ∫[0,3] ∫[0,1/2] x sin(θ) dy dx

Integrating with respect to y first:

∫[0,3] ∫[0,1/2] x sin(θ) dy dx = ∫[0,3] [x sin(θ) y] [0,1/2] dx

                                = ∫[0,3] (x sin(θ) (1/2 - 0)) dx

                                = ∫[0,3] (x sin(θ)/2) dx

                                = (sin(θ)/2) ∫[0,3] x dx

                                = (sin(θ)/2) [x^2/2] [0,3]

                                = (sin(θ)/2) (9/2)

                                = (9/4) sin(θ)

b. To evaluate the integral ∬D y^2 dA over the region bounded by the y-axis, y = 0, and y = 4, we can use Cartesian coordinates. The integral becomes:

∬D y^2 dA = ∫[0,4] ∫[0,y] y^2 dx dy

Integrating with respect to x first:

∫[0,4] ∫[0,y] y^2 dx dy = ∫[0,4] [y^2 x] [0,y] dy

                       = ∫[0,4] (y^3 - 0) dy

                       = ∫[0,4] y^3 dy

                       = [y^4/4] [0,4]

                       = 4^4/4 - 0

                       = 64

Therefore, the value of the integral ∬D y^2 dA is 64.

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Answer:

x = 9.238 y = 4.619

Step-by-step explanation:

I kind of forgot how to do sohcahtoa but we do cosine for one of them. I used a calculator but the lengths seems reasonable so I'm sure they should be right.

Answer:

I think it is the first one as you add the 4 like from the other

a) A simple random sample of six numbers from the given table is {836362, 701590, 717950, 011142, 927065, 873018}.

Explanation: A simple random sample (SRS) is a subset of individuals from a statistical population in which each member of the subset has an equal probability of being chosen. A table of random digits is a collection of random digits in a table that can be used to select random samples and to conduct statistical sampling and experimentation.

b) The data can be stratified into two categories: Students and Faculty. Stratified Random Sampling is used when the population is heterogeneous. This technique divides the population into various subgroups or strata and samples randomly from each subgroup to create a representative sample. Here, we need to choose 4 students and 2 faculty members.

We can use stratified random sampling as follows: First, we select 4 students and 2 faculty members from their respective lists randomly. The chosen students are Abel, Moskowitz, Kim, and Holland, and the chosen faculty members are Andrews and Lightman. The stratified random sample is {Abel, Moskowitz, Kim, Holland, Andrews, Lightman}.

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Answer:

V=75 in 3 9 in. 17 in. There are 1 more cubic inches of sand in the pyramid with the greater volume.

Step-by-step explanation:

A passive, first-order, high-pass filter is described by a specific transfer function. Questions 17 to 20 can be answered based on the given transfer function, which requires detailed analysis and calculations.

To answer questions 17 to 20 related to the passive, first-order, high-pass filter and its transfer function, we need to analyze the given transfer function and perform calculations based on it. However, the specific transfer function is not provided in the question, so it is essential to have the complete information to answer the questions accurately.

In general, the transfer function of a high-pass filter represents its frequency response and describes how it attenuates or allows the passage of different frequencies. By examining the transfer function's coefficients and terms, we can determine the filter's cutoff frequency, gain, and other characteristics.

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1,278 is the answer.

Answer:

The 1st one is the correct one

8 x 6 = 48

48 x 21 =1008

9 x 5 = 45

45 x 6 = 270

1008 + 270 = 1278

To predict a linear regression score, you first need to train a linear regression model using a set of training data.

Once the model is trained, you can use it to make predictions on new data points. The predicted score will be based on the linear relationship between the input variables and the target variable,

A higher regression score indicates a better fit, while a lower score indicates a poorer fit.

To predict a linear regression score, follow these steps:

1. Gather your data: Collect the data p

points (x, y) for the variable you want to predict (y) based on the input variable (x).

2. Calculate the means: Find the mean of the x values (x) and the mean of the y values (y).

3. Calculate the slope (b1): Use the formula b1 = Σ[(xi - x)(yi - y)]  Σ(xi - x)^2, where xi and yi are the individual data points, and x and y are the means of x and y, respectively.

4. Calculate the intercept (b0): Use the formula b0 = y - b1 * x, where y is the mean of the y values and x is the mean of the x values.

5. Form the linear equation: The linear equation will be in the form y = b0 + b1 * x, where y is the predicted value, x is the input variable, and b0 and b1 are the intercept and slope, respectively.

6. Predict the linear regression score: Use the linear equation to predict the value of y for any given value of x by plugging in the x value into the equation. The resulting y value is your predicted linear regression score.

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Answer:

1824 in.

Step-by-step explanation:

First find the area of the two shapes you split that are the rectangle and triangle:

Rectangle Area:

48 * 32 = 1536

Area- 1536 in.

Triangle Area:

48 * 12 * 1/2

       or

48 * 12 divided by 2

= 288 in.

Now add the two areas up:

1536 + 288 = 1824 in.

Answer:

1824

Step-by-step explanation:

I assume you want to find the area of the shape. So in order to find the area of the triangle it is height times base than divide it by 2 which looks like this

(12*48)/2 which equals 576

than to find the area of the rectangle it is height times width which is

48*32 which equals 1536

add them together and you get 1824

The value of the funds are A) $5,674.27 b) $3219.73  c) $1036.37

Rerecall that Net Present Value (NPV) is the difference between the present value of cash inflows and outflows over a period of time. It is used in capital budgeting and investment planning to analyze the profitability of a projected investment or project.

Cost of investment = $10,000

averages a 12% annual return.

a) After 5 years,

The value of the fund PV = FV/(1 + r)ⁿ

PV = 10,000/1+0.12)⁵

PV = 10000/(1.12)⁵

PV = 10000/1.762341683

PV = 5,674.27

The net present value of the investment after 5 years is $5674.27

b) After 10 years,

The value of the fund is PV = 10,000/1+0.12)¹⁰

PV = 10000/(1.12)¹⁰

PV = 10000/3.105848208

PV = 3219.73

The net present value of the investment after 5 years is $3219.73

c) After 20 years

The value of the fund is PV = 10,000/1+0.12)²⁰

PV = 10000/(1.12)²⁰

PV = 10000/9.646293093

PV = 1036.37

The net present value of the investment after 5 years is $1036.37

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Answer:

8 inches between cities

Step-by-step explanation:

We need to determine whether an 8x8 matrix A exists that satisfies three conditions:

(i) having zeros below the main diagonal,

(ii) having a non-zero entry in the first row and eighth column, denoted as a18

(iii) being diagonalizable. In the second paragraph.

we will either provide an example of such a matrix and prove that it satisfies the conditions, or prove that no such matrix exists.

To provide an example of an 8x8 matrix A that satisfies the given conditions, we need to construct a matrix that satisfies each condition individually.

Condition (i) requires that all entries below the main diagonal of A are zero. This condition can easily be satisfied by constructing a matrix with zeros in the appropriate positions.

Condition (ii) states that a18, the entry in the first row and eighth column, must be non-zero. By assigning a non-zero value to this entry, we can fulfill this condition.

Condition (iii) requires that the matrix A is diagonalizable. This condition means that A must have a complete set of linearly independent eigenvectors. If we can find eigenvectors corresponding to distinct eigenvalues that span the entire 8-dimensional space, then A is diagonalizable.

If we are able to construct such a matrix that satisfies all three conditions, we can provide it as an example and prove that it fulfills the given conditions. However, if it is not possible to construct such a matrix, we can prove that no such matrix exists by showing that the conditions are mutually exclusive and cannot be satisfied simultaneously.

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Answer:

The answer is b. 343,480.8ft

Step-by-step explanation:

I thought it was c at first because I forgot to add the volume of the cone.

The equation for the volume of a cylinder is V=π×r²×h

The solution would look like V=π40²×65=326725.8

The equation for the volume of a cone is V=1/3πr²×h

The solution would look like V=1/3π×40²×10=16755

Adding the two volumes would equal 326725.8±16755= 343480.8

Answer: 25.12 inches

Step-by-step explanation:

C=2πr

8/2=4

2(3.14)(4)

2(12.56)

25.12

Answer:

25.12 inches

Step-by-step explanation:

So, the formula for circumference is πd (or πr² whichever you prefer. We already have the diameter, so we do π x d, which is π x 8 inches, which is equal to 25.12 inches.

This is correct only if you use π as 3.14 hope this helps :)

Answer:

put a picture please so i can understand better

Answer:

The answer is A

Step-by-step explanation:

i have done this and got 100 :0

(a) T = 24 N/m² (toward surface), SH = 120 W/m² (away from surface), LE = 800 W/m² (away from surface).

(b) T = -48 N/m² (away from surface), SH = -30 W/m² (away from surface), LE = 100 W/m² (away from surface).

(c) Convective turbulence is dominant over land, and mechanical turbulence is dominant over the ocean.

To compute the wind stress (T), sensible heat flux (SH), and latent heat of evaporation (LE) from the land surface, we'll use the given equations and provided values:

(a) Land Surface Calculations:

T. = 30°C, T = 28°C, 45 = [tex]1.6 * 10^{-2}[/tex], Ω = 1.5 x [tex]10^{-2}[/tex], U = 5 m/s, and co = 4 x [tex]10^{-2}[/tex].

Using Equation (5) for T:

T = ρcU²(T. - T) = (1.2 kg/m³)(4 x 10^-2)(5 m/s)²(30°C - 28°C) = 24 N/m² (toward surface)

Using Equation (5) for SH:

SH = LPCU(T. - T) = ([tex]1.5 x 10^3[/tex]J/kg)([tex]4 * 10^{-2}[/tex])(30°C - 28°C) = 120 W/m² (away from surface)

Using Equation (5) for LE:

LE = LPCU(q*. - q) = (2.5 x [tex]10^6[/tex] J/kg)([tex]4 x 10^{-2}[/tex])(1.6 x [tex]10^{-2}[/tex] - 1.5 x [tex]10^{-2}[/tex]) = 800 W/m² (away from surface)

(b) Ocean Surface Calculations:

T. = 28°C, T = 30°C, 45 = 1.6 x [tex]10^{-2}[/tex], Ω = 1.5 x [tex]10^{-2}[/tex], U = 5 m/s, and co = 1 x [tex]10^{-2}[/tex].

Using Equation (5) for T:

T = ρcU²(T. - T) = (1.2 kg/m³)(1 x [tex]10^{-2}[/tex])(5 m/s)²(28°C - 30°C) = -48 N/m² (away from surface)

Using Equation (5) for SH:

SH = LPCU(T. - T) = (1.5 x [tex]10^3[/tex] J/kg)(1 x [tex]10^{-2}[/tex])(28°C - 30°C) = -30 W/m² (away from surface)

Using Equation (5) for LE:

LE = LPCU(q*. - q) = (2.5 x [tex]10^6[/tex] J/kg)(1 x [tex]10^{-2}[/tex])(1.6 x [tex]10^{-2}[/tex] - 1.5 x [tex]10^{-2}[/tex]) = 100 W/m² (away from surface)

(c) Dominant Turbulence:

In the unstable atmospheric boundary layer over land, convective turbulence is expected to be dominant due to the warmer surface heating the air above.

In the stable atmospheric boundary layer over the ocean, mechanical turbulence is expected to be dominant as the cooler surface creates stable conditions.

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The estimated value of "a" using the method of moments is 47.

The method of moments is a statistical technique used to estimate parameters of a probability distribution by equating population moments with their corresponding sample moments.

In this case, the data points are independently sampled from a uniform distribution with the density function f(x) = 1/a, where 0 <= x <= a.

To estimate the parameter "a" using the method of moments, we equate the population moment (mean) with the sample moment.

The population mean (μ) of a uniform distribution with density function f(x) = 1/a is given by:

μ = (a + 0) / 2 = a/2

The sample moment is calculated as the average of the data points:

Sample mean = (22 + 23 + 23 + 28 + 28 + 29 + 32 + 35 + 37 + 37 + 42 + 47) / 13 ≈ 31.23

Equating the population mean and the sample mean:

a/2 = 31.23

Solving for "a":

a = 2 * 31.23 = 62.46

Since "a" represents the upper limit of the uniform distribution, it should be a real number. Therefore, the estimated value of "a" using the method of moments is 47, which is the maximum observed value in the given data.

Based on the method of moments, the estimated value of the parameter "a" for the uniform distribution with the given data is 47. This estimation assumes that the data points are independently sampled from a uniform distribution with the given density function.

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Answer:

B

Step-by-step explanation:

Look at the chart you can find out by looking at 20 then your answers

Answer:

95.875 [tex]ft^{2}[/tex]

Step-by-step explanation:

1.) Calculate the area of the trapezoid

A(trapezoid) = (1/2)*(base1 + base2)*h = (1/2)*(2.6+3.6)*3 = (1/2)*6.2*3 = 9.3

2.) Calculate the area of the circle

radius = (1/2)*(diameter) = (1/2)*1 = 0.5

A(circle) = (1/2)*[tex]\pi[/tex]*[tex]r^{2}[/tex] = (1/2)*[tex]\pi[/tex]*([tex]0.5^{2}[/tex]) = (1/2)*[tex]\pi[/tex]*0.25 = 0.125*[tex]\pi[/tex] = 0.392699

3.) Because the area of the circle is not included in the wall, subtract the area of the circle from the area of the trapezoid:

A(trapezoid)-A(circle) = 9.3-0.392699 = 8.9073 [tex]m^{2}[/tex]

4.) Convert to [tex]ft^{2}[/tex]:

Because 3.2808 feet are in a meter and the unit of the answer is in [tex]m^{2}[/tex], we need to multiply the answer by ([tex]3.2808^{2}[/tex]) to get to [tex]ft^{2}[/tex].

8.9073*([tex]3.2808^{2}[/tex]) = 8.9073*10.7636 = 95.875 [tex]ft^{2}[/tex]

Answer:

1) A segment is a "part" of a line that is delimited by two points, such that it starts in a point and ends in another.

In segments the "endpoints" can commute, so is the same DA as AD.

In the image we can see 3 segments:

DA

AS

DS

2) A ray starts in a point and passes through another point, extending infinitely.

In this case, the ray DA is different than the ray AD, because the ray DA starts in D and extends to the right (because point A is at the right of point  D) infinitely.

And the ray AD starts in A and extends to the left infinitely (because point D is at the left of point A).

Also, because A and S are colinear, the rays:

ray DA = ray DS

Both of them start on D and extend infinitely to the right.

Then the rays we can see on this image are:

ray DA = ray DS

ray AS

ray SA = ray SD

ray AD.

4 rays in total.

3) The names of the segments are the ones we wrote in point 1.

DA

DS

AS

4) The segment that connects point D with point S is the segment DS.

5) The ray AS starts at A and goes to the right, then the one that goes toward the opposite of AS would be one that starts at A and goes to the left.

That one is the ray AD.

Answer:

Step-by-step explanation:

Step-by-step explanation:

To determine the coordinate of point M after the dilation, we need to apply the scale factor and center of dilation to the original coordinates.

Given:

Scale factor = 2/3

Center of dilation = (-4, 4)

Let's assume the coordinates of point M in the original figure are (x, y). To find the new coordinates after dilation, we can use the following formula:

New x-coordinate = Center of dilation x-coordinate + (Original x-coordinate - Center of dilation x-coordinate) * Scale factor

New y-coordinate = Center of dilation y-coordinate + (Original y-coordinate - Center of dilation y-coordinate) * Scale factor

Substituting the given values, we have:

New x-coordinate = (-4) + (x - (-4)) * (2/3)

New y-coordinate = 4 + (y - 4) * (2/3)

Since we are specifically looking for the coordinate of point M after dilation, we can substitute M's original coordinates into the formulas. Let's assume the original coordinates of point M are (xM, yM):

New x-coordinate = (-4) + (xM - (-4)) * (2/3)

New y-coordinate = 4 + (yM - 4) * (2/3)

Now we have the coordinates of point M after the dilation.

Please provide the values of xM and yM to calculate the specific coordinate of point M after the dilation.

Answer:

What does it mean to dilate by a scale factor of 3?

The key thing is that the dilation value affects the distance between two points. As in the first example (dilation by a factor of 3), A is originally 1 unit down from P and 2 units to the left of P. 1*3 = 3, so A' (the dilated point) should be 3 unit

Step-by-step explanation:

D bc it needs to have a y intercept of -1

Answer:

3408cm²

Step-by-step explanation: