The mean difference between Process A and Process B is 3.0 (rounded to 1 decimal place).
To calculate the mean difference between two processes, we subtract the average of Process B from the average of Process A.
Mean difference = Average of Process A - Average of Process B
Mean difference = 277 - 274 = 3.0
Therefore, the mean difference between Process A and Process B is 3.0.
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HELP ME PLZZ
A cone has a volume of 686 cubic centimeters. If the cone is 14cm high, what is its diameter?
Answer:
3.9mm
Step-by-step explanation:
Help with number one only,no bad answers or links please.
Answer: 180 ft^3
Step-by-step explanation:
Answer: 180 ft is the answer
Step-by-step explanation:
15% of $9.00 is $
I need help!!
Answer:
$ 1.35
Step-by-step explanation:
9 times 0.15 is 1.35
6 1⁄6 - 3 5⁄12 =
plz help me with it
Answer:
33/12 or 2.75
Step-by-step explanation:
6 1⁄6 - 3 5⁄12
37/6 - 41/12
74/12 - 41/12
33/12 or 2.75
(a) Find ged(18675, 20112340) (b) Factor both numbers from (b) above. (c) Find the lem of the two numbers from (b) above.
The lem of 18675 and 20112340 is 2^2 * 3^2 * 5^2 * 7 * 83 * 143659.
(a) To find the greatest common divisor (GCD) of 18675 and 20112340, we can use the Euclidean algorithm. The algorithm involves repeatedly dividing the larger number by the smaller number until the remainder becomes zero.
Using the Euclidean algorithm:
20112340 = 1074 * 18675 + 12590
18675 = 1 * 12590 + 6095
12590 = 2 * 6095 + 4000
6095 = 1 * 4000 + 2095
4000 = 1 * 2095 + 1905
2095 = 1 * 1905 + 190
1905 = 10 * 190 + 15
190 = 12 * 15 + 10
15 = 1 * 10 + 5
10 = 2 * 5 + 0
Since the remainder is now zero, the GCD is the last non-zero remainder, which is 5.
Therefore, ged(18675, 20112340) = 5.
(b) To factor the numbers 18675 and 20112340, we can find their prime factorizations.
Prime factorization of 18675:
18675 = 3^2 * 5^2 * 83
Prime factorization of 20112340:
20112340 = 2^2 * 5 * 7 * 143659
(c) To find the least common multiple (LCM) of 18675 and 20112340, we can use the prime factorizations obtained in the previous step.
The LCM is the product of the highest powers of all the prime factors involved.
Prime factors in the LCM:
2^2 * 3^2 * 5^2 * 7 * 83 * 143659
Therefore, the lem of 18675 and 20112340 is 2^2 * 3^2 * 5^2 * 7 * 83 * 143659.
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A dartboard has 20 equally divided wedges, and you are awarded the number of points in the section your dart lands in. If you are equally likely to land in any wedge, what is the probability you will score 10, 11, or 12 points?
Answer: 10 points
Step-by-step explanation:
Joe, Josie and Bob has $35 when they put their money together. Joe has half as much as Josie. Bob has four times as much money as Joe. How much money does Josie have?
Answer: $10
Step-by-step explanation:
Let Josie's money be x
Since Joe has half as much as Josie. Joe's money will be: x/2 = 0.5x
Bob has four times as much money as Joe. Bob's money will be = (4 × 0.5x) = 2x
Therefore, we add all the amount together and equate to $35. This will be:
x + 0.5x + 2x = 35
3.5x = 35
x = 35/3.5
x = 10
Josie has $10
Part b: The length of the hypotenuse is?
Answer:
B
Step-by-step explanation:
cus thats the formula
put this is y-intercept form 5x + 4y = -4
Answer:
slope-intercept form: y= -5/4x-1
Step-by-step explanation:
Answer:
17
Step-by-step explanation:
Find the total surface area of this triangular prism.
Answer:
28 i think
Step-by-step explanation:
Given the following data: 46, 47, 110, 56, 71, 109, 63,91, 111,93, 125,78,85, 108,73, 118,70,89,99, 45,73.
Compute the five-number summary and draw the boxplot.
The five-number summary for the given data is as follows: Minimum = 45, First Quartile (Q1) = 71, Median (Q2) = 89, Third Quartile (Q3) = 108, Maximum = 125.
The five-number summary provides key descriptive statistics that summarize the distribution of the data. It consists of the minimum value, the first quartile (Q1), which represents the lower 25% of the data, the median (Q2), which represents the middle value or the 50th percentile, the third quartile (Q3), which represents the upper 25% of the data, and the maximum value.
To draw a boxplot based on this five-number summary, a box is drawn from Q1 to Q3, with a line indicating the median (Q2). Whiskers extend from the box to the minimum and maximum values. Outliers, if present, are represented as individual data points beyond the whiskers.
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A recent national report states the marital status distribution of the male population age 18 or older is as follows: Never Married (32.7%), Married (52.7%), Widowed (2.7%), Divorced (11.9%). The table below shows the results of a random sample of 1704 adult men from California. Test the claim that the distribution from California is as expected at the a-0.01 significance level. a. Complete the table by filling in the expected frequencies. Round to the nearest whole number: Frequencies of Marital Status Outcome Frequency Expected Frequency Never Married 545 Married 892 Widowed 27 Divorced 240 b. What is the correct statistical test to use? Select an answer c. What are the null and alternative hypotheses? c. What are the null and alternative hypotheses? H: Marital status and residency are dependent. The distribution of marital status in California is the same as it is nationally. The distribution of marital status in California is not the same as it is nationally. Marital status and residency are independent. H: The distribution of marital status in California is the same as it is nationally, The distribution of marital status in California is not the same as it is nationally. O Marital status and residency are independent. O Marital status and residency are dependent. d. The degrees of freedom e. The test-statistic for this data - (Please show your answer to three decimal places.) f. The p-value for this sample - (Please show your answer to four decimal places.) g. The p-value is Select an answer a h. Based on this, we should Select an answer 1. Thus, the final conclusion is... h. Based on this, we should Select an answer 1. Thus, the final conclusion is... There is insufficient evidence to conclude that the distribution of marital status in California is not the same as it is nationally. There is sufficient evidence to conclude that the distribution of marital status in California is the same as it is nationally. There is sufficient evidence to conclude that marital status and residency are dependent. There is sufficient evidence to conclude that the distribution of marital status in California is not the same as it is nationally. There is insufficient evidence to conclude that marital status and residency are dependent.
The chi-square test is used to test the claim of independence between marital status distribution in California and the expected distribution.
To test the claim that the distribution of marital status in California is as expected, the appropriate statistical test to use is the chi-square test for independence. The null hypothesis (H0) states that marital status and residency are independent, meaning the distribution of marital status in California is the same as it is nationally. The alternative hypothesis (Ha) suggests that the distribution of marital status in California is not the same as it is nationally.
The degrees of freedom for this test is calculated as (r - 1) * (c - 1), where r is the number of rows (4) and c is the number of columns (2). In this case, the degree of freedom is 3.
Using the observed frequencies and the expected frequencies, the chi-square test statistic is calculated. The p-value is then determined based on the test statistic and the degrees of freedom. The final conclusion is made by comparing the p-value to the significance level.
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Use the given prompt to answer question # to question #. The Angels baseball team contracted researcher Melanie to summarize information regarding pitcher Shohei Ohtani's batting average. Her goal is to compare the number of times he was at bat to the number of times he actually hit the ball in 2018 versus 2019. She specifically samples the Angels home games from each of those years and summarizes the information in the chart below. 2018 2019 Total 103 54 49 Ohtani hit the ball Ohtani didn't hit the ball 141 130 271 Total times at bat 195 179 Has Ohtani's proportion of hitting the ball (his batting average) decreased from 2018 to 2019? Use a 1% significance level, and assume the Central Limit Theorem conditions hold. Note/in case you wanted more information: A baseball player's batting average is the proportion of times the player hits the ball compared to the number of times they were at bat (Example, if a player was at bat 10 times but only hit the ball 2 times, their batting average is § = 0.2).
The proportion of Shohei Ohtani's hitting the ball (batting average) decreased from 2018 to 2019. In 2018, Ohtani hit the ball 103 times out of 195 at-bats, resulting in a batting average of approximately 0.528.
In 2019, he hit the ball 54 times out of 179 at-bats, yielding a batting average of approximately 0.302. To determine whether Ohtani's batting average decreased from 2018 to 2019, we compare the proportions of hitting the ball in each year. Using a 1% significance level and assuming the Central Limit Theorem conditions hold, we can conduct a hypothesis test. The null hypothesis (H0) states that there is no difference in Ohtani's batting average between 2018 and 2019, while the alternative hypothesis (Ha) suggests a decrease in batting average.
To test the hypotheses, we can use a two-sample z-test for proportions. We calculate the sample proportions for hitting the ball in each year: p1 = 103/195 ≈ 0.528 in 2018 and p2 = 54/179 ≈ 0.302 in 2019. The standard error for the difference in proportions is given by the formula sqrt((p1(1-p1)/n1) + (p2(1-p2)/n2)), where n1 and n2 are the sample sizes.
Next, we calculate the test statistic z using the formula z = (p1 - p2) / sqrt((p1(1-p1)/n1) + (p2(1-p2)/n2)). The calculated z-value can be compared to the critical z-value at the 1% significance level (zα/2) to determine if we reject or fail to reject the null hypothesis.
In this case, the z-value is negative, indicating that the proportion of hitting the ball decreased from 2018 to 2019. By comparing the calculated z-value to the critical z-value, we can conclude that the decrease in Ohtani's batting average is statistically significant.
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Approximately what percentage of hardcover books sold were nonfiction?
Answer:
B
Step-by-step explanation:
There are a total of 105 students in a drama club and a yearbook club. The drama club has 15 more students than the yearbook club. How many students are in the drama club? the yearbook club?
Which is the cosine ratio of ∠A?
ACB is right angle triangle. The length of AC is 28, the length of CB is 195, and the length of AB is 197.
A. 195197
B. 28197
C. 28195
D. 19528
Answer:
d . 19528
Step-by-step explanation:
maaf jika salah
By looking at your graph, how can you tell that () = 2
has an inverse (function)?
A. 5 cartoons/toy
B. 12 toys/ cartoon
C. 5 toys/ cartoon
Answer:
c
Step-by-step explanation:
Paul uses a coordinate plane to design his model town layout. Paul moves the market 2 units left and 3 units down. He says the ordered pair for the new location of the market is (0, 6). Explain Paul's mistake and write the correct ordered pair for the new location of the market.
Answer:
(1,5) because, before it was at (3,8) and
3 – 2 = 1
8 – 3 = 5
For further explanation:
(3,8) / (2,3) = (1,5)
2 for 2 units left and 3 for 3 units down
12!!! POINTS “what is the mode” question!
Answer:
The mode is 23
Step-by-step explanation:
PLS HELP IM STRUGGLING!!!!!!
Answer:
i think ist D correct me if im wrong
Step-by-step explanation:
Answer:
22.7
Step-by-step explanation:
if ∡M is 90° then you can do:
sin 65 = h/25
h = 25(sin 65°)
h = 22.65
A university department installed a spam filter on its computer system. During a 21-day period, 6693 messages were tagged as spam. How much spam you get depends on what your online habits are. Here are the counts for some students and faculty in this department (with log-in IDs changed, of course): ID Count ID Count ID Count ID Count AA 1818 BB 1358 CC 442 DD 416 EE 399 FF 389 GG 304 HH 251 || 251 JJ 178 KK 158 LL 103 All other department members received fewer than 100 spam messages. How many did the others receive in total? Make a graph and comment on what you learn from these data. .
The number of people who received fewer than 100 spam messages in the university department is calculated below:
Total number of messages tagged as spam = 6693
Total number of people = 12
Total number of people who received more than 100 spam messages = 11
Number of people who received fewer than 100 spam messages = 1
The number of people who received fewer than 100 spam messages can be calculated by subtracting the total number of people who received more than 100 spam messages from the total number of people in the department.
Thus, the other 1 person received a total of: 6693 - (1818 + 1358 + 442 + 416 + 399 + 389 + 304 + 251 + 251 + 178 + 158 + 103) = 474
Graph illustrating the data collected from students and faculty in the department. it is clear that the majority of students and faculty members in the department received more than 100 spam messages. One person received fewer than 100 spam messages. The number of spam messages received seems to decrease with time, which may indicate that the spam filter is effective.
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find the value of each variable 13-17
Answer:
Step-by-step explanation:
Question 13.
By applying cosine rule,
cos(45°) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]
[tex]\frac{1}{\sqrt{2} }=\frac{10}{y}[/tex]
y = 10√2
By applying sine rule,
sin(45°) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
[tex]\frac{1}{\sqrt{2} }=\frac{x}{y}[/tex]
[tex]\frac{1}{\sqrt{2} }=\frac{x}{10\sqrt{2} }[/tex]
x = 10
Question 15.
By applying sine rule,
sin(60°) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
[tex]\frac{\sqrt{3} }{2}=\frac{y}{32}[/tex]
y = 16√3
By applying cosine rule,
cos(60°) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]
[tex]\frac{1}{2}=\frac{x}{32}[/tex]
x = 16
Question 17.
By applying sine rule,
sin(60°) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
[tex]\frac{\sqrt{3} }{2}=\frac{11\sqrt{3} }{y}[/tex]
y = 22
By applying cosine rule,
cos(60°) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]
[tex]\frac{1}{2}=\frac{x}{y}[/tex]
[tex]\frac{1}{2}=\frac{x}{22}[/tex]
x = 11
Help help help! This is 40% of my grade and i am stuck.
FIND THE MEASURES OF THE INTERIOR ANGLES
Answer:
Angle A=68
Step-by-step explanation:
68+x+(x-24)=180
68+x+x-24=180
2x+44=180
2x=136
x=68
does anyone know the answer
Answer:
I think it is A.
Step-by-step explanation:
I hope this helps.
Can the following angle measures be the interior angles of a triangle: 29°, 29°, and 29° ? Justify your answer.
Answer:
No
Step-by-step explanation:
Angle measures of a triangle must add up to 180 and this only adds up to 87
Can someone help me with this. Will Mark brainliest.
Answer:
B ( -1, -8)
Step-by-step explanation:
A ( -7, -6)
midpt (-4, -7)
Equation:
(x + 3, y - 1)
Solve for B:
(-4, -7)
(x + 3, y - 1)
( -1, -8)
help ASAP please! ill mark brainliest!
Answer:
8!
Step-by-step explanation:
Answer) 8!
Explanation) i dont have one :')
8
p varies directly as the square root of q.
p = 8 when q = 25.
Find p when q = 100.
Answer:
16
Step-by-step explanation:
p=k√q
8=k√25
8=k5
k=8/5
p when q=100
p=8/5*√100
p=8/5*10
p=16
HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
Answer:
A is the answer.
Step-by-step explanation: It would go up about 2.2 i hope i helped! <3
Answer: A is your answer
Step-by-step explanation: