If an apple pie recipe calls for 3 pounds of candy apples then how many cups of canned apples required

Answer:

The neighborhood the home is located in

The factors which does not affect the mortgage payment is the neighborhood the home is located in.

The correct option is D.

We are aware of this;

A mortgage is a loan when the borrower's property is used as security. The mortgage payment is determined by the cost of the property, the interest rate, the down payment, the length of the loan, taxes, and various insurances like homeowners insurance, among other factors.

Hence, It's not depend on ''The neighborhood the home is located in.''

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The correct statement is : M spans P2.

The set M = {[tex]x+1, x^2-2, 3x[/tex]} consists of three polynomials in the variable x.

To determine whether M spans P3 or P2, we need to consider the highest degree of the polynomials in M.

The highest degree of the polynomials in M is 2 (from [tex]x^2-2[/tex]), which means that M can span at most the space of polynomials of degree 2 or less, i.e., P2.

To check whether M spans P2 or not, we need to see if any polynomial of degree 2 or less can be expressed as a linear combination of the polynomials in M.

We can write any polynomial of degree 2 or less as [tex]ax^2 + bx + c[/tex], where a, b, and c are constants.

To express this polynomial as a linear combination of the polynomials in M, we need to solve the system of equations:

[tex]a(x^2-2) + b(x+1) + c(3x) = ax^2 + bx + c[/tex]

This can be written as:

[tex]ax^2 + (-2a+b+3c)x + (b+c) = ax^2 + bx + c[/tex]

Equating the coefficients of [tex]x^2, x,[/tex] and the constant term, we get:

[tex]a = a,\\-2a+b+3c = b,\\b+c = c.[/tex]

The first equation is always true, and the other two equations simplify to:

[tex]-2a+3c = 0,\\b = 0.[/tex]

Solving for a, b, and c, we get:

[tex]a = 3c/2,\\b = 0,\\c = c.[/tex]

Therefore, any polynomial of degree 2 or less can be expressed as a linear combination of the polynomials in M. This means that M spans P2.

However, M cannot span P3, because P3 includes polynomials of degree 3, which cannot be expressed as a linear combination of the polynomials in M (since the highest degree polynomial in M is [tex]x^2[/tex]).

Therefore, the correct statement is: M spans P2.

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Answer:

not a complete question..

Step-by-step explanation:

Answer: January 1, 2025

Step-by-step explanation:

The debt is due to be paid back in 10 years.

If the first payment was in 2016, the last payment should therefore be:

= 2016 + 9 years

= 2025

We used 9 years because 2016 was the first year of payment so the remaining years would be 9 years.

As the first payment was on January 1, 2016, the last payment would have to be on the same date in 2025 which is:

= January 1, 2025

To calculate[tex]2^2873686243768478237864767208[/tex] mod 101 using Fermat's little theorem, we can simplify the exponent by taking it modulo 100, since 100 is the Euler's totient function value of 101. Therefore,[tex]2^2873686243768478237864767208[/tex] mod 101 is equal to 57.

Fermat's little theorem states that if p is a prime number and a is any integer not divisible by p, then a^(p-1) ≡ 1 (mod p). In this case, p = 101, and we need to find[tex]2^2873686243768478237864767208[/tex]mod 101.

First, we simplify the exponent by taking it modulo 100, since 100 is the Euler's totient function value of 101. The exponent 2873686243768478237864767208 is congruent to 8 modulo 100. So, we need to calculate 2^8 mod 101. Applying Fermat's little theorem, we know that 2^(101-1) ≡ 1 (mod 101), since 101 is prime. Therefore, 2^100 ≡ 1 (mod 101).

We can express [tex]2^8[/tex] in terms of 2^100 as [tex](2^100)^0.08[/tex]. Simplifying this, we get [tex](2^100)^0.08 ≡ 1^0.08[/tex]≡ 1 (mod 101).

Thus, we conclude that[tex]2^8[/tex] ≡ 1 (mod 101), and therefore 2^2873686243768478237864767208 ≡ [tex]2^8[/tex] (mod 101).

Finally, evaluating [tex]2^8[/tex] mod 101, we find that [tex]2^8[/tex] ≡ 57 (mod 101).

Therefore,[tex]2^2873686243768478237864767208[/tex] mod 101 is equal to 57.

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Answer:

267/500

Step-by-step explanation:

0.534 = 534 / 1000

Simplify to 267/500

Step-by-step explanation:

537/1000

this is the correct answer

Answer:

Yay fun day :DDDDDD

Step-by-step explanation:

Answer:

The experimental probability of rolling anumber less than 3 is 3/20

Step-by-step explanation:

16+14=30

30/200

=3/20

Answer:

7/50

Step-by-step explanation:

[tex]\frac{-3 - (-4)}{1 - (-5)}[/tex]

= [tex]\frac{-3 + 4}{1 + 5}[/tex]

= 1/6

Answer:

41.7feet

Step-by-step explanation:

From the question we are given the following

angle of depression = 50°

Distance of the pole from the base of the feet = 35feet (Adjacent)

Required

height of the school (opposite)

Using the SOH CAH TOA identity

Tan theta = opp/adj

Tan 50 = H/35

H = 35tan 50

H = 35(1.1918)

H = 41.7feet

Hence the height of the school is 41.7feet

Answer:The diagram that models the ratio in the story is:

Mermaid book: Princess book = 3:2

To find out how many times Nolan has read the mermaid book, we can set up the following proportion:

3/2 = x/20

Cross-multiplying, we get:

2x = 3 * 20

2x = 60

Dividing both sides by 2, we find:

x = 60/2

x = 30

Therefore, Nolan has read the mermaid book 30 times this month.

Answer:

models

Step-by-step explanation:

Answer: B.) Models

Edge

Answer:

B = 48.7°

C = 61.3°

b = 12

Step-by-step explanation:

Given:

A = 70°

a = 15

c = 14

Required:

B, C, and b

Solution:

✔️Using the law of sines, let's find C:

Sin C/c = Sin A/a

Plug in the values

Sin C/14 = Sin 70/15

Cross multiply

Sin C × 15 = Sin 70 × 14

Divide both sides by 15

Sin C = (Sin 70 × 14)/15

Sin C = 0.8770

C = Sin^{-1}(0.8770)

C = 61.282566° = 61.3° (nearest tenth)

✔️Find B:

B = 180 - (70 + 61.3) (sum of triangle)

B = 48.7°

✔️Find b using the law of sines:

b/sinB = a/sinA

Plug in the values

b/sin 48.7 = 15/sin 70

Cross multiply

b*sin 70 = 15*sin 48.7

Divide both sides by sin 48.7

b = (15*sin 48.7)/sin 70

b = 11.9921789

b = 12.0 (nearest tenth)

Given that a hockey tournament consists of 16 teams. In the first round, every team is randomly assigned to one of 8 games (2 teams per game). We are supposed to find the probability that all three Alberta teams are randomly assigned to different games. Let A be the event of assigning all three Alberta teams to different games.

Then the number of ways to select 3 teams from 16 teams is $\ dbinom {16}{3}$, the number of ways to assign 3 teams to different games is $8\times7\times6$, and the number of ways to assign the remaining 13 teams to games is $(13!) / (2^6\times6!)$.The probability of event A is given by;$$

P(A) = \frac{\text{number of ways to assign 3 teams from Alberta to different games}}{\text{number of ways to assign all teams to games}} = \frac{8\times7\times6 \times (13!) / (2^6\times6!)}{\dbinom{16}{3} \times (14!) / (2^7\times7!)}
$$Simplifying the above expression,$$
P(A) = \frac{8\times7\times6 \times 13! \times 2}{\dbinom{16}{3} \times 14!} = \frac{8\times7\times6 \times 2}{\dbinom {16}{3}} = \frac{336}{560} = \frac{3}{5}

Therefore, the probability that all three Alberta teams are randomly assigned to different games is $\frac{3}{5}$.

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Answer:

12.6

Step-by-step explanation:

divide the length value by 3

Answer:

x axis

Step-by-step explanation:

Answer:

1/2 x 1/2 = 1/4

Step-by-step explanation:

P(H,H) = 1/2 x 1/2 = 1/4

P(T,T) = 1/2 x 1/2 = 1/4

P(H,T) = 1/2 x 1/2 = 1/4

P(T,H) = 1/2 x 1/2 = 1/4

Answer:

38

Step-by-step explanation:

(10*2)+(9*2)

Answer:

(X+6)(x-5) + (X-5)(X+6)

Answer:

[tex]2x ^{2} - 22x + 60[/tex]

Answer:

-10x+30

Step-by-step explanation:

just got it right on edg 2021 :)

None of these are correct

(a) If there are 4 candidate,  the smallest number of votes that a plurality candidate could have is 33.

(b) If there are 8 candidate,  the smallest number of votes that a plurality candidate could have is 17.

The smallest number of votes that a plurality candidate could have is calculated as follows;

(a) If there are 4 candidate, the number of votes for each candidate;

= 129 / 4

= 32.25

The least number of votes for the plurality candidate = 33

(b) If there are 8 candidate, the number of votes for each candidate;

= 129 / 8

= 16.125

The least number of votes for the plurality candidate = 17

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Answer:

60 mins

Step-by-step explanation:

15+45=60

The time needed to make 138 pancakes if both Mark and Charlotte work together is 227.142 minutes.

A fraction is a way to describe a part of a whole. such as the fraction 1/4 can be described as 0.25.

As it is given that Mark can make 9 pancakes in 15 minutes, therefore, the number of pancakes that Mark can make in one minute,

[tex]\text{Number of Pancake in one minute} = \dfrac{9}{15}[/tex]

Now, for Charlotte, it is given that he makes 42 pancakes in 45 minutes, therefore, the number of pancakes that Charlotte can make in one minute,

[tex]\text{Number of Pancake in one minute} = \dfrac{42}{45} = \dfrac{12}{15}[/tex]

Further, the total pancakes that can be made in one minute,

[tex]\text{Total Number of Pancake in one minute} = \dfrac{9}{15} +\dfrac{12}{15} = \dfrac{21}{15}[/tex]

As they both need to make 138 pancakes together, therefore, the time they need is,

[tex]\rm Time\ Needed = \dfrac{\text{Total number of pancakes}}{\text{Total number of pancakes in one minute}}[/tex]

[tex]\rm Time\ Needed = \dfrac{138}{\frac{21}{15}} = \dfrac{138\times 15}{21} = 227.142[/tex]

Hence, the time needed to make 138 pancakes if both Mark and Charlotte work together is 227.142 minutes.

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[tex]\Large\boxed{\tt Answer:~A:~y=-3x+5}[/tex]

All we have to do in order to find the equation that is equivalent to 6x + 2y = 10 is to solve for y.

Step 1: Keep y on one side of the equation and move the rest to the other.

[tex]\tt 6x + 2y = 10\\2y = -6x + 10[/tex]

Step 2: Divide all terms by 2 to isolate y.

[tex]\tt 2y \div 2=y\\-6x \div 2 = -3x\\10 \div 2 =5\\\\y=-3x+5[/tex]

Answer:

5 batches

Step-by-step explanation:

1/6 oatmeal  can make 1 batch, so 5/6 makes 5 batches

The types of transformation in this problem is given as follows:

Vertical and horizontal translation.

The four translation rules are defined as follows:

The translations for this problem are given as follows:

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Answer:

131.95yd squared

Step-by-step explanation:

A=2πrh+ 2 r(2)=2*π*3*4+2*π*3(2)~131.94689yd(2)

Mathematical induction can be used to prove that for every non-negative odd integer n, the expression [tex]24 / (2^{(3n+1)}+1+1) * (n^2+1)[/tex] holds true.

To prove the statement using mathematical induction, we need to follow two steps: the base case and the induction step.

First, we verify if the statement holds true for the base case, which is typically the smallest value of n. In this case, let's consider n = 0. Plugging in n = 0 into the expression, we get [tex]24 / (2^{(3*0+1)}+1+1) * (0^2+1)[/tex]. Simplifying, we have 24 / (2+1+1) * 1, which equals 24 / 4 * 1, resulting in 6. Therefore, the statement holds true for n = 0.

Next, we assume that the statement is true for some arbitrary odd integer k, and we will prove that it holds true for k+2. Assume that [tex]24 / (2^{(3k+1)}+1+1) * (k^2+1)[/tex] holds true.

Now, we substitute k+2 into the expression and aim to show that it holds true for k+2 as well. We have [tex]24 / (2^{(3(k+2)+1)}+1+1) * ((k+2)^2+1)[/tex]. Simplifying the expression, we get [tex]24 / (2^{(3k+7)}+1+1) * (k^2 + 4k + 5)[/tex].

We can manipulate the equation further to demonstrate that it is equal to the assumed expression for k. By performing algebraic manipulations and simplifications, we can equate the expressions and conclude that the statement holds true for k+2.

Since we have verified the base case and shown that the statement holds true for k+2 when it holds true for k, we can conclude that the statement is true for every non-negative odd integer n.

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Shape a = 6 x 4 x 3 = 72

Shape b = 4 x 4 x 4 = 64

72 + 64 = 136

A

Answer:

A

Step-by-step explanation:

The following can cause OLS estimators to be biased: Omitting an important independent variable.

Multicollinearity. Heteroskedasticity, Including an irrelevant variable.

The following does not cause the usual OLS t statistics to be invalid (that is, to have t distributions under H0): The error term non-normally distributed

OLS (ordinary least squares) estimates are typically unbiased when calculated.

However, the following problems may cause OLS estimates to be biased:

Omitting an important independent variable: When an important independent variable is omitted from the regression equation, the OLS estimate of the effect of one variable on the dependent variable is biased.

In particular, the estimate of the effect of the variable that is omitted is influenced by the remaining variables' presence in the equation.

Multicollinearity: When the independent variables in a multiple regression model are strongly related, multicollinearity exists.

When there is multicollinearity in a model, the estimated slope coefficients are frequently biased, making them difficult to interpret.

In this scenario, small changes in the data may cause substantial changes in the estimated coefficients.

As a result, the usual tests of hypothesis may fail to produce reliable inferences.

Heteroskedasticity: In the population, heteroskedasticity exists when the variance of the error term is not constant across observations.

Heteroskedasticity can induce OLS estimates' variance to be biased, even if the estimates are unbiased themselves.

When there is heteroskedasticity, the OLS estimates are no longer BLUE (best linear unbiased estimator).

Including irrelevant variable: When an irrelevant variable is included in a regression equation, the OLS estimates of the other variables' effects are biased, and the estimates' standard errors are larger than necessary.

The error term non-normally distributed: When the error term in a regression equation is non-normally distributed, the distribution of the OLS estimates is also non-normal.

However, this does not affect the distribution of the t statistics under H0.

The reason for this is that, even if the error term is non-normally distributed, the sample mean converges to the population mean, according to the central limit theorem.

Furthermore, the standard error of the mean is unaffected by the distribution of the error term, as long as the sample size is large enough.

As a result, the t statistics can be trusted to be asymptotically normally distributed under H0.

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Answer:

42cm3

Step-by-step explanation:

v = 0.5× b × h × l

= 0.5 × 4 × 3 × 7

= 42cm3