I'm stuck. plz help I dont know how​

Data analysts use one-sample hypothesis tests to manage random sampling error. The correct answer is (b).

Data analysts use one-sample hypothesis tests to manage random sampling error. Random sampling error refers to the variability or differences that can occur between a sample and the population it represents.

By conducting hypothesis tests, analysts can determine if the observed data from a sample is statistically significant and can be generalized to the larger population.

Hypothesis tests help analysts assess whether an observed effect or relationship in the sample is likely to be a true effect or relationship in the population or if it is simply due to random chance.

By testing a hypothesis and comparing the sample data to a null hypothesis, analysts can evaluate the validity of their findings and make informed decisions based on the results.

The purpose of hypothesis tests is not to frustrate students, justify their jobs, or make bad decisions. Instead, they serve as a statistical tool to manage random sampling error and provide reliable and valid conclusions based on data analysis.

The correct answer is (b)

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Answer:

"false" I believe if wrong srry

The length of the string is 5 and the alphabet is {0, 1, 2}.Therefore, the number of strings of length 5 that can be formed over the given alphabet is:$$3^5 = 243$$ Therefore, there are 243 strings of length 5 over the alphabet {0, 1, 2}.

To calculate the number of strings of length 5 over the alphabet {0, 1, 2}, we need to determine the number of choices for each position in the string. Since each position can be filled with one of three possible characters (0, 1, or 2), we have three choices for each position.

Therefore, the total number of strings of length 5 can be calculated as:

Number of strings = Number of choices for position 1 × Number of choices for position 2 × Number of choices for position 3 × Number of choices for position 4 × Number of choices for position 5

Number of strings = 3 × 3 × 3 × 3 × 3 = 3^5 = 243

So, there are 243 strings of length 5 over the alphabet {0, 1, 2}.

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The information given in question is that the length of the string is 5.

Alphabet {0,1,2}

Therefore, there are 243 strings of length 5 over the alphabet {0, 1, 2}.

To find the number of strings of length 5 over the alphabet {0, 1, 2}, we need to consider the number of choices we have for each position in the string.

There are three choices (0, 1, or 2) for each position, and since we have five positions, the total number of strings of length 5 is given by:

[tex]$$3^5 = \boxed{243}$$[/tex]

Therefore, there are 243 strings of length 5 over the alphabet {0, 1, 2}.

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139

ffsahshanjwjsjudke

Answer:

Answer:

C. 40

Step-by-step explanation:

[tex]\frac{25}{100} = \frac{10}{y}[/tex]

[tex]\frac{1}{4} = \frac{10}{y}[/tex] (cross multiply)

40 = 1y (rewrite)

y = 40

Answer:

Because you didnt pay for brainly.

If you do, no adds :D

Its a lot easier to be honest

Answer: Because the advertisements are corporations' way of making a market with the internet. They pay a fee to have their adds placed on sites and above videos, and by watching them, that generates revenue for the content creator and the hosting domain itself.    

you welcome

Step-by-step explanation:

To approximate the area under the graph of the function F(x) = 0.2x³ + 2x² - 0.2x - 2 over the interval (-9, -4) using 5 subintervals and left endpoints, we can use the left Riemann sum method. The total area under the graph of F(x) over the interval (-9, -4).

To approximate the area using the left Riemann sum method, we start by dividing the interval (-9, -4) into 5 subintervals of equal width. The width of each subinterval can be calculated as (b - a) / n, where b is the upper limit of the interval (-4), a is the lower limit of the interval (-9), and n is the number of subintervals (5 in this case).

Next, we evaluate the function F(x) at the left endpoint of each subinterval to find the height of the rectangles. For the left Riemann sum, the left endpoint of each subinterval is used as the height. In this case, we evaluate F(x) at x = -9, -7, -5, -3, and -1.

Once we have the width and height of each rectangle, we can calculate the area of each rectangle by multiplying the width and height. Finally, we sum up the areas of all the rectangles to approximate the total area under the graph of F(x) over the interval (-9, -4).

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answer is y=-3x+(-1/3)

The percentage of arrests for people who received Multisystemic Therapy (MST) can be calculated by dividing the number of individuals arrested in the MST group (87) by the total number of individuals.

Percentage of arrests for MST group = (87/215) * 100 ≈ 40.47%

To determine if therapy caused significantly fewer arrests at a 0.05 significance level, we need to compare this percentage with the percentage of arrests in the control group.

The percentage of arrests for the control group can be calculated in a similar manner by dividing the number of individuals arrested in the control group (74) by the total number of individuals in the control group (196), and multiplying by 100.

Percentage of arrests for control group = (74/196) * 100 ≈ 37.76%

Comparing the sample percentages, we find that the percentage of arrests for people who received MST (40.47%) is slightly higher than the percentage of arrests for the control group (37.76%).

To determine if this difference is statistically significant at a 0.05 significance level, we would need to perform a hypothesis test, such as a chi-square test, to compare the observed frequencies with the expected frequencies under the assumption that therapy has no effect on reducing arrests.

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Answer:

One big change during Kublai's reign was that foreigners became the rulers and administrators. Since they didn't trust the local people, they moved in a large number of Muslims and other people to help them rule the empire. The Mongols had their own religious belief called Shamanism.

The first derivative of the given function with respect to x is 0.9x^(-0.1)y^1.8 and the first derivative of the given function with respect to y is 1.8x^0.9y^0.8.

The given function is f(x, y) = x^0.9y^1.8. The question is to find the first derivative of the given function with respect to x and y respectively.

Here are the solutions; The first derivative of the given function with respect to x is given by ∂f(x, y)/∂x:∂f(x, y)/∂x = 0.9x^(-0.1)y^1.8

On the other hand, the first derivative of the given function with respect to y is given by ∂f(x, y)/∂y:∂f(x, y)/∂y = 1.8x^0.9y^(1.8 - 1)∂f(x, y)/∂y = 1.8x^0.9y^0.8

Therefore, the first derivative of the given function with respect to x is 0.9x^(-0.1)y^1.8 and the first derivative of the given function with respect to y is 1.8x^0.9y^0.8.

The above steps use the concept of partial derivatives of a function with respect to a variable that can be applied in such types of questions.

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The given function is

[tex]f(x,y) = x⁰.⁹ y¹.⁸[/tex]

Now, let's find the first derivative of the function with respect to x and y.

First derivative of the function with respect to x:

We have to use the chain rule here.

According to the chain rule,

the derivative of the outer function is multiplied by the derivative of the inner function.

The inner function is [tex]y¹.⁸,[/tex]

whose derivative with respect to x is 0.

Therefore, we only have to differentiate the outer function with respect to x.

[tex]f(x,y) = x⁰.⁹ y¹.⁸∂f/∂x = ∂/∂x (x⁰.⁹ y¹.⁸)∂f/∂x = 0.⁹x^(-0.1) y¹.⁸∂f/∂x = 0.⁹y¹.⁸/x^0.1[/tex]

First derivative of the function with respect to y:

We have to use the chain rule here.

According to the chain rule, the derivative of the outer function is multiplied by the derivative of the inner function.

The inner function is [tex]x⁰.⁹,[/tex]

whose derivative with respect to y is 0.

Therefore, we only have to differentiate the outer function with respect to y.

[tex]f(x,y) = x⁰.⁹ y¹.⁸∂f/∂y = ∂/∂y (x⁰.⁹ y¹.⁸)∂f/∂y = 1.⁸ x⁰.⁹ y^(0.8)∂f/∂y = 1.⁸x^0.9 y^0.8[/tex]

Hence, the first derivative of the given function with respect to x is

[tex]0.⁹y¹.⁸/x^0.1[/tex]

and with respect to y is [tex]1.⁸x^0.9 y^0.8.[/tex]

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Answer:

7.6

Step-by-step explanation:

-3 multiple by y and -3 multiple by 2 resolve to 7.6....

Answer:

56

Step-by-step explanation:

Answer:

C. 12

hope they help

first mile $2.25 plus $3.50 ×12= $42.00+2.25=44.25

We are given a formula that uses the integral representation of Jy(x): $${x\over 2}\left[J_{v-1}(x) - J_{v+1}(x)\right] = v\int_0^\infty t^{v-1} J_{v-1}(xt)\,dt$$

We will use this formula to show that the spherical Bessel functions $j _v(x)$ are expressible in terms of trigonometric functions. Let $y=v-1$.

Substituting $v=y+1$, we have: $${x\over 2}\left[J_y(x) - J_{y+2}(x)\right] = (y+1)\int_0^\infty t^y J_y(xt)\,dt$$

This expression is known as a recurrence relation for spherical Bessel functions. Let us use this to derive the identity that was requested:

$${x\over 2}\left[J_{v-1}(x) - J_{v+1}(x)\right] = (v+1)\int_0^\infty t^v J_v(xt)\,dt - v\int_0^\infty t^v J_{v-1}(xt)\,dt$$

Rearranging and using the recurrence relation, we obtain:

$$J_{v+1}(x) = {2v\over x}J_v(x) - J_{v-1}(x)$$$$\begin{aligned}\sin x\,j_v(x) &= \sin x\left[{1\over x}J_v(x)\right]\\&= {1\over 2x}\left[J_{v-1}(x) - J_{v+1}(x)\right]\\&= {v+1\over x}\int_0^\infty t^v J_v(xt)\,dt - {v\over x}\int_0^\infty t^v J_{v-1}(xt)\,dt\end{aligned}$$

Similarly, $$x^2\cos x\,j_v(x) = {v\over x}\int_0^\infty t^v J_v(xt)\,dt + {v+1\over x}\int_0^\infty t^v J_{v-1}(xt)\,dt$$

Hence, we have shown that $j_v(x)$ can be expressed in terms of trigonometric functions as follows:$$\begin{aligned}\sin x\,j_v(x) &= {v+1\over x}\int_0^\infty t^v J_v(xt)\,dt - {v\over x}\int_0^\infty t^v J_{v-1}(xt)\,dt\\\cos x\,j_v(x) &= {v\over x}\int_0^\infty t^v J_v(xt)\,dt + {v+1\over x}\int_0^\infty t^v J_{v-1}(xt)\,dt\end{aligned}$$

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Answer:

your answer is w=144

Step-by-step explanation:

(36÷3=12)(2x6=12)

Answer:  144

Step-by-step explanation:

Answer:

AC=6

Step-by-step explanation:

You can see that  ABC is 4 times bigger that HIJ because of lines AB and HI. HI(with a value of one) had to be multiplied by four to equal AB (a value of 4). Use this same rule to find the side AC.

1.5(the length of HJ) times 4 =6.

Answer:  C

Step-by-step explanation: C because there is obviously a correlation yet we cannot determine if there is causation or not.

Find the sum:

1.1.1 2+6+(-7) + 10 = 11

​

11=11

Answer:

Equal to.

Step-by-step explanation:

The 0 at the end of 9.90 does not add any value to the number because its 0.

Answer:

It is equal.

Step-by-step explanation:

9.90 = 9.9 , it's the same as the 0 does not count on it.

Answer:

3 stamps

Step-by-step explanation: 42 stamps in equal groups would be 6 stickers/group.

6+3 = 9 stickers in each pile

there was 7 piles so multiply 7 by the 9 stickers in each pile

7· 9 = 63  

5 · 12 = 60, so she gave her friends 60 stickers

63-60 = 3  

Answer:

1=function

2=not function

3=function

4=function

5=function

6=not function

7=not function

8=function

Here are five other iterated integrals that are equal to the given iterated integral:
∫₀ʸ ∫⁺∞ₓ ∫¹₀ f(x, y, z)dz dx dy
∫₀ʸ ∫¹₀ ∫ʸ ∞ f(x, y, z)dz dx dy
∫⁺∞₁₀ ∫₀ʸ ∫ʸ ₀ f(x, y, z)dz dy dx
∫¹ᵧ ∫⁺∞₁₀ ∫₀ x f(x, y, z)dz dx dy
∫⁺∞₀ ∫⁺∞₁₀ ∫ʸ ₀ f(x, y, z)dz dx dy

The given iterated integral ∫¹₀ ∫¹ᵧ ∫ʸ ₀ f(x, y, z)dx dx dy represents the integration of a function f(x, y, z) over a region defined by the limits of integration. To obtain five other equivalent iterated integrals, we can rearrange the order of integration and modify the limits accordingly. Each integral represents the same volume or value as the given iterated integral, but the order of integration and limits may vary.
The key is to ensure that the new integrals cover the same region as the original one. The limits in each integral should define the appropriate range for each variable to maintain the equivalence. By rearranging the order of integration and adjusting the limits accordingly, we can obtain these alternative expressions that are equal to the given iterated integral.

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It will take approximately 9 years and 2 months for quarterly deposits of $625, with an interest rate of 8.48% compounded quarterly, to accumulate to $20,440.

To calculate the time it takes for the deposits to accumulate to the desired amount, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A = the accumulated amount

P = the principal amount (initial deposit)

r = the annual interest rate (converted to a decimal)

n = the number of times interest is compounded per year

t = the number of years

In this case, the principal amount (P) is $625, the interest rate (r) is 8.48% (or 0.0848 as a decimal), the number of times interest is compounded per year (n) is 4 (quarterly compounded), and the desired accumulated amount (A) is $20,440.

We need to solve for t, the number of years. Rearranging the formula, we have:

t = (log(A/P)) / (n * log(1 + r/n))

Plugging in the values, we get:

t = (log(20440/625)) / (4 * log(1 + 0.0848/4))

Calculating this, we find that t is approximately 9.18 years. Converting this to years and months, we get approximately 9 years and 2 months. Therefore, it will take around 9 years and 2 months for the quarterly deposits of $625 to accumulate to $20,440 at an interest rate of 8.48% compounded quarterly.

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Answer:

x=−2 and y=3/2

Step-by-step explanation:

see picture

The linear map is  not surjective but injective.

A linear map is an operation between two vector spaces that preserves the properties of addition and scalar multiplication; therefore, it is a linear transformation.

Here is how to determine if the following linear maps are surjective or injective.

(a) The derivative map T: P3(R) → P₂(R); P₂(R); p(x) → d/dx -p(x) is an example of a linear map,

where P3(R) and P₂(R) are the vector spaces of polynomials of degree at most 3 and 2 with coefficients in R, respectively.

Moreover, d/dx is the derivative operator acting on the polynomial p(x).

The kernel of the linear map T is the subspace of P3(R) consisting of polynomials p(x) with T(p(x)) = d/dx -p(x) = 0, i.e., p(x) is constant.

However, a constant polynomial of degree zero is not in the range of T, since it has no derivative. Therefore, the linear map T is injective and not surjective.

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