If m and n are relatively prime, the numerator (an + bm) and denominator (mn) have no common factors other than 1, and therefore, (an + bm)/(mn) is in lowest terms.
To prove that (an + bm)/(mn) is in lowest terms if and only if m and n are relatively prime, we will need to establish two separate claims:
Claim 1: If (an + bm)/(mn) is in lowest terms, then m and n are relatively prime.
Claim 2: If m and n are relatively prime, then (an + bm)/(mn) is in lowest terms.
Proof of Claim 1:
Let's assume that (an + bm)/(mn) is in lowest terms. This means that the numerator (an + bm) and the denominator (mn) have no common factors other than 1.
Suppose m and n are not relatively prime, which means they have a common factor greater than 1.
Let's say that factor is d, where d > 1. Then we can express m and n as follows: m = dx and n = dy, where x and y are integers.
Now, we rewrite the numerator (an + bm) as follows:
an + bm = an + b(dx) = n(a + bx/d)
Since m = dx and n = dy, we have (an + bm)/(mn) = (n(a + bx/d))/(dx * dy) = (a + bx/d)/(xy).
We can see that both the numerator (a + bx/d) and the denominator (xy) have the factor d.
This contradicts our assumption that (an + bm)/(mn) is in lowest terms, as they have a common factor greater than 1.
Therefore, m and n must be relatively prime.
Proof of Claim 2:
Now, let's assume that m and n are relatively prime, which means they have no common factors other than 1.
To show that (an + bm)/(mn) is in lowest terms, we need to demonstrate that its numerator and denominator have no common factors other than 1.
Let's suppose that the numerator (an + bm) and the denominator (mn) have a common factor d, where d > 1.
This implies that d divides both an + bm and mn.
Since d divides mn, we can express m and n as follows: m = dx and n = dy, where x and y are integers.
Now, let's rewrite the numerator (an + bm) as follows:
an + bm = an + b(dx) = n(a + bx/d)
We can see that d divides both n and the expression (a + bx/d). Therefore, d also divides the numerator (an + bm).
However, we initially assumed that (an + bm)/(mn) is in lowest terms, which means the numerator and denominator have no common factors other than 1. This contradicts the assumption that they have a common factor d > 1.
Thus, if m and n are relatively prime, the numerator (an + bm) and denominator (mn) have no common factors other than 1, and therefore, (an + bm)/(mn) is in lowest terms.
By proving both Claim 1 and Claim 2, we have established that (an + bm)/(mn) is in lowest terms if and only if m and n are relatively prime.
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Set up an integral that represents the length of the part of the parametric curve shown in the graph.
x = 9t^2 − 3t^3, y = 3t^2 − 6t
The x y-coordinate plane is given. The curve starts at the point (12, 9), goes down and left becoming more steep, changes direction at approximately the origin, goes down and right becoming less steep, changes direction at the point (6, −3), goes up and right becoming more steep, changes direction at the approximate point (12, 0), goes up and left becoming less steep, and stops at the point (0, 9).
To find the length of the parametric curve described by the equations x = 9t^2 − 3t^3 and y = 3t^2 − 6t, we can set up an integral using the arc length formula. The curve starts at point (12, 9) and ends at point (0, 9), with several changes in direction along the way.
The length of a curve can be calculated using the arc length formula. For a parametric curve defined by x = f(t) and y = g(t), the arc length can be expressed as:
L = ∫[a,b] √[(dx/dt)^2 + (dy/dt)^2] dt.
In this case, we have x = 9t^2 − 3t^3 and y = 3t^2 − 6t. To find the length of the curve, we need to determine the interval [a, b] over which t varies.
From the given information, we can see that the curve starts at (12, 9) and ends at (0, 9). By solving the equation x = 9t^2 − 3t^3 for t, we find that t = 0 at x = 0, and t = 2 at x = 12. Therefore, the interval of integration is [0, 2].
To set up the integral, we calculate the derivatives dx/dt and dy/dt, and then substitute them into the arc length formula. Simplifying the expression inside the square root and integrating over the interval [0, 2], we can evaluate the integral to find the length of the curve.
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Sam drinks water at an incredible rate. She drinks 2 1/5 liters of water every 3/4 of an hour. Sam drinks water at a constant rate. About how much water does Sam drink per hour?
Answer:
2.9 litres
or
2 14/15 litres
Step-by-step explanation:
To determine the amount of water Sam drinks in an hour, divide the total amount drunk by the number of hours
Amount drank in an hour = total litres drunk / time
[tex]2\frac{1}{5}[/tex] ÷ [tex]\frac{3}{4}[/tex]
[tex]\frac{11}{5}[/tex] × [tex]\frac{4}{3}[/tex] = [tex]\frac{44}{15}[/tex] = 2[tex]\frac{14}{15}[/tex] litres
3) Arjun was shopping for avocados, which were listed $0.90 each. He brought six avocados to the checkout lane, where he learned that there was a sale on avocados. With the discount, he was charged $4.86 before tax. What was the percent discount on each avocado?
Answer:
Step-by-step explanation:
Total discount = 6×$0.90 - $4.86 = $0.54
discount each = $0.54/6 ≈ $0.09
$0.09/$0.90 = 0.10 = 10%
Solve the following system of equations using Desmos.....x-3y=-2 and x+3y=16
Answer:
(7, 3 )
Step-by-step explanation:
Given the 2 equations
x - 3y = - 2 → (1)
x + 3y = 16 → (2)
Adding (1) and (2) term by term will eliminate the y- term
2x + 0 = 14
2x = 14 ( divide both sides by 2 )
x = 7
Substitute x = 7 into either of the 2 equations and solve for y
Substituting into (2)
7 + 3y = 16 ( subtract 7 from both sides )
3y = 9 ( divide both sides by 3 )
y = 3
solution is (7, 3 )
Which function would be produced by a horizontal stretch of the graph of y = sqrt(x) followed by a reflection in the x - axis ?
Answer:
the answer is the first one
Step-by-step explanation:
Explanation: be im smart
Function transformation involves changing the form of a function
A function that could represent the transformed function is function (c) [tex]f(x) = -\sqrt{\frac 12 x}[/tex]
The equation of the function is given as:
[tex]f(x) = \sqrt x[/tex]
The rule of horizontal stretch is:
[tex](x,y) \to (ax,y)[/tex]
Where:
[tex]0 < a < 1[/tex]
Take for instance:
[tex]a = \frac 12[/tex]
So, we have:
[tex]f(x) = \sqrt{\frac 12 x}[/tex]
Next, the function is reflected in across the x-axis.
The rule of this transformation is:
[tex](x,y) \to (x,-y)[/tex]
So, we have:
[tex]f(x) = -\sqrt{\frac 12 x}[/tex]
Hence, a function that could represent the transformed function is function (c)
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Express 5: 8 in the ratio n : 1
Answer:
0.625 : 1
Step-by-step explanation:
5 : 8
→ Divide both sides by 8 to get it to 1
(5 ÷ 8) : (8 ÷ 8)
→ Simplify
0.625 : 1
What’s the volume of the prism
Answer:
384 cubic inches (in^3)
Step-by-step explanation:
volume = length * width * height
So find the volume of the large rectangle of the prism, then find the volume of the small rectangle of the prism. Add the two volumes together and the sum is your final answer.
I would appreciate Brainliest, but no worries.
How many sqftwks are used when producing a K flat of cucumbers
for grafting that spent 6 weeks on a bench in the greenhouse?
The number of square feet-weeks used when producing a K flat of cucumbers for grafting is not provided.
To determine the number of sqftwks (square feet-weeks) used when producing a K flat of cucumbers for grafting that spent 6 weeks on a bench in the greenhouse, we need additional information.
The term "sqftwks" represents the product of the area in square feet and the duration in weeks. However, the specific values for the area and the duration of cucumber growth are not provided in the question.
To calculate the number of sqftwks, we would need to know the area occupied by the K flat of cucumbers and the time spent in the greenhouse. Without these specific values, it is not possible to determine the number of sqftwks used for cucumber production.
Therefore, based on the given information, we cannot calculate the number of sqftwks used when producing a K flat of cucumbers for grafting that spent 6 weeks on a bench in the greenhouse.
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Joshua is going to invest $9,000 and leave it in an account for 5 years. Assuming the
interest is compounded continuously, what interest rate, to the nearest tenth of a
percent, would be required in order for Joshua to end up with $12,500?
Answer:
Step-by-step explanation:
Answer:
6.6%
Step-by-step explanation:
A pyramid with a rectangular base has a volume of 60 cubic feet and a height of 6 feet. The width of the rectangular base is 4 feet. Find the length of the rectangular base.
Answer:
length=2.5feet
Step-by-step explanation:
Volume =Base area * height
6/60=(4*length) * 6/6
10=4length
length=10÷4
=2.5feet
The length of the pyramid is 7.5 feet.
What is a pyramid with rectangular base?'A rectangular pyramid is a type of pyramid with the base shaped like a rectangle but the sides are shaped like a triangle. A pyramid usually has triangular sides but with different bases.'
According to the given problem,
Volume = 60 cubic feet
Height = 6 feet
Width of rectangular base = 4 feet
Let the length be x,
Volume =[tex]\frac{L * W * H}{3}[/tex]
⇒ 60 = [tex]\frac{x*6*4}{3}[/tex]
⇒ 180 = 24x
⇒ x = [tex]\frac{180}{24}[/tex]
⇒ x =[tex]\frac{45}{6}[/tex] = 7.5
Hence, we can conclude that the value of the length of the rectangular base is 7.5 feet.
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i need help please i'll give brainly
Answer:
60 +24 = 84
Step-by-step explanation:jjjjjhjhjhj
6 x 4 +5 x 12
Let X is uniformly distributed over (0,1) and Y is exponentially distributed with parameter lambda = 2. Furthermore assume X and Y are independent. The cumulative distribution of Z = X + Y is P{Z lessthanorequalto a} = P{X + Y lessthanorequalto a} =___________________________for 0 < a < 1 P{Z lessthanorequalto a} = P{X + Y lessthanorequalto a} =___________________________for 0 < a < infinity The cumulative distribution of T = x/y is P({T lessthanorequalto a} = P{X/a lessthanorequalto Y} =___________________________for_________< a
To find the cumulative distribution function (CDF) of Z = X + Y, where X is uniformly distributed over (0,1) and Y is exponentially distributed with parameter lambda = 2, we can use the properties of independent random variables.
For 0 < a < 1, we have:
P(Z ≤ a) = P(X + Y ≤ a)
Since X and Y are independent, we can write this as:
P(Z ≤ a) = ∫∫ P(X ≤ x, Y ≤ a - x) dxdy
Since X is uniformly distributed over (0,1) and Y is exponentially distributed with parameter lambda = 2, we have their respective probability density functions (PDFs):
fX(x) = 1, 0 ≤ x ≤ 1
fY(y) = 2e^(-2y), y ≥ 0
Now, we can calculate the CDF of Z:
P(Z ≤ a) = ∫∫ P(X ≤ x, Y ≤ a - x) dxdy
= ∫∫ fX(x) * fY(y) dxdy, since X and Y are independent
= ∫∫ 1 *[tex]2e^(-2y)[/tex] dxdy, for 0 ≤ x ≤ 1 and y ≥ 0
Integrating with respect to x from 0 to 1 and with respect to y from 0 to a - x, we get:
P(Z ≤ a) = ∫[0,1]∫[0,a-x] 1 * 2[tex]e^(-2y)[/tex]dydx
= ∫[0,1] [[tex]-e^(-2y)[/tex]] [0,a-x] dx
= ∫[0,1] (1 - [tex]e^(-2(a-x)[/tex])) dx
Evaluating the integral, we have:
P(Z ≤ a) = [x - [tex]xe^(-2(a-x))[/tex]] [0,1]
= (1 - e^(-2a))
Therefore, the cumulative distribution function (CDF) of Z is:
P(Z ≤ a) = [tex](1 - e^(-2a)),[/tex] for 0 < a < 1
For 0 < a < ∞, the cumulative distribution function of Z remains the same:
P(Z ≤ a) = (1 - e^(-2a)), for 0 < a < ∞
Now, let's move on to the cumulative distribution function of T = X/Y.
P(T ≤ a) = P(X/Y ≤ a)
Since X and Y are independent, we can write this as:
P(T ≤ a) = ∫∫ P(X/y ≤ a) fX(x) * fY(y) dxdy
Using the given information that X is uniformly distributed over (0,1) and Y is exponentially distributed with parameter lambda = 2, we can substitute their respective PDFs:
P(T ≤ a) = ∫∫ P(X/y ≤ a) * 1 * [tex]2e^(-2y)[/tex]dxdy
= ∫∫ P(X ≤ ay) * 1 * [tex]2e^(-2y)[/tex]dxdy
Now, we need to determine the range of integration for x and y. Since X is between 0 and 1, and Y is greater than or equal to 0, we have:
0 ≤ x ≤ 1
0 ≤ y
Using these limits, we can calculate the CDF of T:
P(T ≤ a) = ∫[0,1]∫[0,∞] P(X ≤ ay) * 1 * [tex]2e^(-2y)[/tex] dydx
To evaluate this integral, we need to consider the range of values for ay. Since a can be any positive real number, ay can range from 0 to ∞.
P(T ≤ a) = ∫[0,1]∫[0,∞] P(X ≤ ay) * 1 * 2[tex]e^(-2y)[/tex] dydx
= ∫[0,1]∫[0,∞] (ay) * 1 * 2[tex]e^(-2y)[/tex] dydx, for ay ≥ 0
Integrating with respect to y from 0 to ∞ and with respect to x from 0 to 1, we have:
P(T ≤ a) = ∫[0,1]∫[0,∞] (ay) * 1 * 2[tex]e^(-2y)[/tex]dydx
= ∫[0,1] (2a / (4 + a^2)) dx
Evaluating the integral, we get:
P(T ≤ a) = (2a / (4 + [tex]a^2)),[/tex] for a > 0
Therefore, the cumulative distribution function (CDF) of T is:
P(T ≤ a) = (2a / (4 + [tex]a^2)),[/tex] for a > 0
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pls help will mark brainlest
Answer:
(5,7) , (2, -3) , (2,4)
Step-by-step explanation:
your first number, the x, is the horizontal number. The second, y, is the vertical number. So if you look at A, the x is 5, and you then have to go up to 7 to reach the intercept
Flordia yum, an ice cream company would like to test the hypothesis that the variance for the number of ounces of ice cream that Americans consume per month is greater than 15. A random sample of 23 people was found to have a standard deviation of 4.4 ounces for the quantity of ice cream consumed per month. The ice cream company would like to test the hypothesis using alpha= 0.05.
If the test statistic exceeds the critical value, we reject the null hypothesis and conclude that there is evidence to support the claim that the variance is greater than 15. Otherwise, if the calculated chi-square value is less than or equal to the critical chi-square value, we fail to reject the null hypothesis.
To test the hypothesis that the variance for the number of ounces of ice cream consumed per month is greater than 15, we can use a chi-square test for variance.
The null and alternative hypotheses for this test are as follows:
Null Hypothesis (H0): The variance for the number of ounces of ice cream consumed per month is equal to or less than 15.
Alternative Hypothesis (H1): The variance for the number of ounces of ice cream consumed per month is greater than 15.
Given a random sample of 23 people with a standard deviation of 4.4 ounces, we can calculate the sample variance as [tex]s^2 = (4.4)^2[/tex] = 19.36.
To perform the chi-square test, we calculate the test statistic as follows:
chi-square = (n - 1) × [tex]s^2[/tex] / [tex]\sigma^2[/tex]
where n is the sample size, [tex]s^2[/tex] is the sample variance, and [tex]\sigma^2[/tex] is the hypothesized population variance (15 in this case).
Substituting the values, we get:
chi-square = (23 - 1) × 19.36 / 15 = 29.44
Next, we compare this test statistic to the critical value from the chi-square distribution table with (n - 1) degrees of freedom (22 degrees of freedom in this case) at the given significance level (alpha = 0.05).
If the test statistic is greater than the critical value, we reject the null hypothesis and conclude that the variance for the number of ounces of ice cream consumed per month is greater than 15.
Otherwise, if the test statistic is less than or equal to the critical value, we fail to reject the null hypothesis.
Performing the chi-square test with the given values, we compare the test statistic (29.44) to the critical value from the chi-square distribution table.
If the test statistic exceeds the critical value, we reject the null hypothesis and conclude that the variance for the number of ounces of ice cream consumed per month is greater than 15. Otherwise, we fail to reject the null hypothesis.
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A decision problem X is self-solvable if X = L(MX) for some polynomial-time oracle TM M, whose oracle queries are always strictly shorter than its input. In other words, when M is executed on an input of length n, it queries its oracle only on strings of length less than n. This is a strange situation, where M has oracle access to the problem that it is trying to solve. But when M is trying to determine whether x € X, it cannot simply query its oracle on x for the answer. ከ. (a) Show that TQBF is self-solvable. Be explicit about what assumptions are you making about how for- mulas are encoded into bit strings. (b) Prove that if L is self-solvable then L E PSPACE.
(a) The TQBF oracle used by M satisfies the condition for self-solvability.
It can handle formulas of length strictly shorter than the input length, ensuring that M's oracle queries are always strictly shorter than its input.
To show that TQBF (True Quantified Boolean Formula) is self-solvable, we need to demonstrate that there exists a polynomial-time oracle Turing machine (TM) M that can solve TQBF using an oracle for TQBF.
Assuming that formulas in TQBF are encoded into bit strings in a standard way, we can construct the TM M as follows:
On input x (the encoded TQBF formula), M starts by generating all possible truth assignments for the variables in the formula.
For each truth assignment, M constructs the corresponding quantified Boolean formula and queries the TQBF oracle with this formula.
If the oracle returns "true" for any truth assignment, M accepts x. Otherwise, if the oracle returns "false" for all truth assignments, M rejects x.
Hence, TQBF (True Quantified Boolean Formula) is self-solvable.
(b) If a language L is self-solvable, it implies that L is in PSPACE (polynomial space complexity class).
To prove that if L is self-solvable, then L is in PSPACE, we can show that a polynomial-time oracle TM M with oracle access to L can be simulated by a polynomial-space Turing machine.
Let M' be a polynomial-space Turing machine that simulates M with oracle access to L. Since L is self-solvable, M' can query the oracle on inputs shorter than its own input.
We can construct a polynomial-space Turing machine M'' that simulates M' without the need for an oracle. M'' uses its own polynomial space to simulate the computation of M'. Whenever M' queries the oracle on an input, M'' runs its own simulation for that input length using its available space.
Since M'' only requires polynomial space and simulates the behavior of M', it follows that L is in PSPACE.
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Select the answer closest to the specified areas for a normal density.
(a) The area to the left of 32 on a N(45, 8) distribution. A. 0.948
C. 0.896 D. 0.104
B. 0.052
B. 0.97
(b) The area to the right of 12 on a N(9.4, 1.2) distribution. A. 0.985 C. 0.03 D. 0.015
(c) The area between 43 and 100 on a N(75, 15) distribution: A 0.984 C. 0.936 D. 0.64
The closest answer for each area is B. 0.052, D. 0.015, and C. 0.936, respectively.
(a) The area to the left of 32 on a N(45, 8) distribution. The area to the left of 32 on a N(45, 8) distribution is given by: P(Z < (32 - 45)/8)P(Z < -1.625)= 0.052, approximately. So, the closest answer is B. 0.052.
(b) The area to the right of 12 on a N(9.4, 1.2) distribution. The area to the right of 12 on a N(9.4, 1.2) distribution is given by: P(Z > (12 - 9.4)/1.2)P(Z > 2.166)= 1 - P(Z < 2.166)= 1 - 0.985= 0.015. So, the closest answer is D. 0.015.
(c) The area between 43 and 100 on a N(75, 15) distribution. The area between 43 and 100 on a N(75, 15) distribution is given by: P((43 - 75)/15 < Z < (100 - 75)/15)P(-1.5333 < Z < 1.6666)= P(Z < 1.6666) - P(Z < -1.5333)= 0.9525 - 0.0624= 0.8901. So, the closest answer is C. 0.936.
In conclusion, the closest answer for each area is B. 0.052, D. 0.015, and C. 0.936, respectively.
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4,3,4,7,4,8 step 1 of 3: calculate the value of the sample variance. round your answer to one decimal place.
The sample variance for the given data set is 3.6.
To calculate the sample variance, we follow a series of steps. First, we need to find the mean (average) of the data set. Adding up all the numbers and dividing by the total count gives us the mean, which in this case is (4+3+4+7+4+8)/6 = 30/6 = 5.
Next, we calculate the deviations of each data point from the mean. We subtract the mean from each data point to get the deviations: (4-5), (3-5), (4-5), (7-5), (4-5), and (8-5), which simplify to -1, -2, -1, 2, -1, and 3, respectively.
Then, we square each deviation to eliminate negative values:[tex](-1)^2[/tex], [tex](-2)^2[/tex], [tex](-1)^2[/tex], [tex]2^2[/tex], [tex](-1)^2[/tex], and [tex]3^2[/tex], which simplify to 1, 4, 1, 4, 1, and 9, respectively.
The next step is to find the sum of the squared deviations. Adding up all the squared deviations gives us 20.
Finally, we divide the sum of squared deviations by the total count minus 1 (n-1) to calculate the sample variance: 20/(6-1) = 20/5 = 4.
Rounding the sample variance to one decimal place, we get 3.6 as the final result.
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6,336 ft. = in league
Answer:
6336 feet = 0.3476 nautical leagues
The mean salary at a local industrial plant is $28,600$28,600 with a standard deviation of $4400$4400. The median salary is $25,300$25,300 and the 61st percentile is $29,000$29,000.
Step 2 of 5:
Based on the given information, determine if the following statement is true or false.
Joe's salary of $35,060$35,060 is 1.401.40 standard deviations above the mean.
The statement Joe's salary of $35,060$35,060 is 1.401.40 standard deviations above the mean is false.
To determine if the statement is true or false, we need to calculate the number of standard deviations Joe's salary of $35,060 is above the mean.
Given:
Mean salary = $28,600
Standard deviation = $4,400
Joe's salary = $35,060
To calculate the number of standard deviations above the mean, we can use the formula:
Number of standard deviations = (X - μ) / σ
Where:
X is the value we want to compare (Joe's salary)
μ is the mean
σ is the standard deviation
Plugging in the values, we have:
Number of standard deviations = (35,060 - 28,600) / 4,400
= 6,460 / 4,400
≈ 1.4727
Therefore, Joe's salary of $35,060 is approximately 1.4727 standard deviations above the mean, not 1.40.
The statement is false.
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Why are the triangles congruent
Answer:
The triangles are congruent because they are both exactly the same.
Consider the equation below. (If an answer does not exist, enter DNE.)
f(x) = x4 − 8x2 + 9
(a) Find the interval on which f is increasing. (Enter your answer using interval notation.)
Find the interval on which f is decreasing. (Enter your answer using interval notation.)
The interval on which the function f(x) = x^4 - 8x^2 + 9 is increasing can be expressed in interval notation as (-∞, -2) ∪ (2, ∞). The interval on which the function is decreasing can be expressed as (-2, 2).
To determine the intervals of increasing and decreasing, we need to examine the derivative of the function. Taking the derivative of f(x) with respect to x gives us f'(x) = 4x^3 - 16x. To find the intervals of increasing and decreasing, we need to analyze the sign of the derivative. The derivative is positive when x < -2 and x > 2, indicating an increasing function. The derivative is negative when -2 < x < 2, indicating a decreasing function.
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10x+9y=-17
10x-2y=16
Answer:
they both = eachother
10x+9y=-17 = 10x-2y=16
Step-by-step explanation:
A cylindrical gas tank holds approximately 401.92 cubic feet of fuel. The radius of the tank is 4 feet. Find the height of the tank in feet. Use 3.14 for π. PLEASE HURRY I NEED THIS
Answer:
8 ft
Step-by-step explanation:
Given:
Volume = 401.92
radius = 4 feet
Volume of cylinder: [tex]\pi[/tex]r^2h
3.14 * 4^2 * h = 401.92 cubic feet
3.14 * 16 * h = 401.92 cubic feet
50.24 * h = 401.92
h = 8 ft
A group of students were asked if they like Math class and if they like English class.
Partial results are shown in the table.
Like Math
Don't Like Math
Like English
х
9
Don't Like English
26
у
.
Of the students who like math, 40% don't like English.
Of the students who don't like math, 75% don't like English
What is the value of x + y?
A. 35
B. 57
C. 65
D. 66
2. Describe a rigid motion or composition of rigid motions that maps the rectangular bench at (0, 10)and
the adjacent flagpole onto the other short rectangular bench and flagpole.
Answer:
See Explanation
Step-by-step explanation:
Given
Let the bench be B and the flagpole be T.
So:
[tex]B = (0,10)[/tex] --- given
The flagpole is represented by the triangular shape labelled T.
So, we have:
[tex]T = (6,9)[/tex]
See attachment for the rectangular bench and the flagpole
From the attached image, the location of the other bench is:
[tex]B' = (0,-10)[/tex]
And the location of the other flagpole is:
[tex]T' = (-6,9)[/tex]
So, we have:
[tex]B = (0,10)[/tex] ==> [tex]B' = (0,-10)[/tex]
[tex]T = (6,9)[/tex] ==> [tex]T' = (-6,9)[/tex]
When a point is reflected from [tex](x,y)[/tex] to [tex](x,-y)[/tex], the transformation rule is reflection across x-axis.
So the rigid transformation that takes [tex]B = (0,10)[/tex] to [tex]B' = (0,-10)[/tex] is: reflection across x-axis.
When a point is reflected from [tex](x,y)[/tex] to [tex](-x,y)[/tex], the transformation rule is reflection across y-axis.
So the rigid transformation that takes [tex]T = (6,9)[/tex] to [tex]T' = (-6,9)[/tex] is: reflection across y-axis.
will give brainiest + 40 points
Which graph represents the function p(x) = |x – 1|?
Answer:
I think it's the second I e at the top
What is the solution to the equation 4x + 2(x − 3) = 3x + x − 12? (1 point) −3 −1 1 3
please help it would be reallyyyy nice tysmmwmsmssmm
Answer:
I think it is 30
Step-by-step explanation:
Answer:
x = 30
Step-by-step explanation:
The angles shown are vertical angles
If you didn't know vertical angles are congruent
That being said we create an equation to solve for x
(because vertical angles are congruent) 104 = 3x + 14
now that we have created an equation we want to solve for x
Step 1 subtract 14 from each side
104 - 14 = 90
14 - 14 cancels out
now we have 90 = 3x
step 2 divide each side by 3
90/3=30
3x/3=x
we're left with x = 30
What is the measure of ∠x?
Answer:
117+x=180°(sum of straight line)
Step-by-step explanation:
x=180-117
x=63
7x-12+3x+28=180 degrees
Please help ASAP
Answer:
180 degrees
Step-by-step explanation:
i think im not sure??????? i hope im right
you put it in the question