Let V be the set of those polynomials ax2 + bx + CE P2 such that a+b+c= 0. Is V a subspace of P2? Explain. If V is a subspace then find the a basis of V.

Answer:

.02

Step-by-step explanation:

The answer option that is true include the following: D. Slack = (LF-LS).

Project management is a strategic process that involves the design, planning, developing, leading and execution of a project plan or activities, especially by using a set of skills, knowledge, tools, techniques and experience to achieve the set goals and objectives of creating a unique product or service.

Under project management, the slack of a project can be calculated by taking the difference between the activity's latest start and earliest start time.

In this context, the slack of a project is the difference between its latest finishing time (LF) and earliest finishing time (LS):

Slack = (LF - LS)

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Answer:

The standard method for solving an equation like 3x + 5 = 26 is to use the Subtraction Property of Equality and then the Division Property of Equality.

Step-by-step explanation:

To solve, you subtract both sides by 5 first. Then you divide both sides by 3 to isolate the x.

Answer:

step 5

Step-by-step explanation:

Answer:

Explanation:

given f(x) = 3x - 1

for f(x) = 2

3x - 1 = 2

3x = 2 + 1

3x = 3

x = 3/3

x = 1

Answer:

i think it is b

Step-by-step explanation:

Answer:

OA

Step-by-step explanation:

18+12=30

6×3=18

6×2=12

18+12=30

hope this helps

Answer:

Which of the following is equal to the expression listed below?

18 + 12

OA. 6(3+2)

OB. (6 x 3)(6 x 2)

OC. 6+ (3 x 2)

OD. (6 + 3)(6 + 2)

Step-by-step explanation:

the answer is (B)

A unit rate is a ratio comparing quantities measured in different units. Unit rates are most useful in finding an equivalent ratio, proportion, and also a missing value in a ratio table.

A ratio table can be used to solve a problem. Find a missing value in a ratio table by using a pattern of multiplying each time or by writing an equivalent ratio. Unit rates can be used to make rate statements consisting of equivalent ratios (fractions). The missing value refers to one value in the ratio that is not provided and has to be found by calculation or by estimation.A ratio is a comparison of two or more values that can be written in different forms, including fraction form, ratio form, and percentage form. A unit rate is a type of ratio that compares a quantity to exactly one unit of another quantity.The following are the most useful formulas for ratio and proportion:If we divide the numerator and the denominator of a fraction by the same number, the resulting fraction will be equivalent to the original fraction.If the same number is multiplied to both the numerator and denominator of a fraction, the resulting fraction will be equivalent to the original fraction. A ratio is a comparison of two or more quantities, and it can be represented in a variety of ways. A unit rate is a ratio that compares a quantity to one unit of another quantity. Unit rates can be used to create equivalent ratios that are similar to one another. In a ratio table, a missing value can be found by using a pattern of multiplying or by writing an equivalent ratio.

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The missing value in a ratio table can be found by using a pattern of multiplying each time, multiplying, and writing an equivalent ratio.

A ratio is a comparison of two quantities measured in the same units.

A unit rate is a rate that compares a quantity to exactly one unit of another quantity.

They can be used to make rate conversions consisting of equivalent ratios (fractions).

A ratio table can be used to solve a problem.

The missing value in a ratio table can be found by using a pattern of multiplying each time, multiplying, and writing an equivalent ratio.

So, A ratio is a ratio comparing quantities measured in different units.

A unit rate is a rate that compares a quantity to exactly one unit of another quantity.

Unit rates can be used to make rate conversions consisting of equivalent ratios (fractions).

A ratio table can be used to solve a problem.

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The equations you mentioned:

1. y = xy:

To solve this differential equation, we can separate the variables and integrate both sides.

dy/y = x dx

Integrating both sides gives:

ln|y| = (1/2)x² + C

Exponentiating both sides gives the general solution:

|y| = [tex]e^{((1/2)x^2 + C)[/tex]

Taking the positive and negative values of y, we get two branches of solutions:

y = [tex]Ae^{(1/2)x^2[/tex] and y = [tex]-Ae^{(1/2)x^2[/tex], where A is an arbitrary constant.

2. xy = 2y:

Rearranging the equation, we get:

xy - 2y = 0

Factoring out y, we have:

y(x - 2) = 0

This equation has two solutions:

y = 0 and x - 2 = 0, which leads to x = 2.

3. y = [tex]e^x[/tex] - y:

Rearranging the equation, we get:

y + y = [tex]e^x[/tex]

Combining like terms, we have:

2y = [tex]e^x[/tex]

Dividing both sides by 2, we get:

y = (1/2)[tex]e^x[/tex]

4. y = (1 + y²)[tex]e^x[/tex]:

Rearranging the equation, we get:

y - y² = [tex]e^x[/tex]

Factoring out y, we have:

y(1 - y) = [tex]e^x[/tex]

This equation has two solutions:

y = 0 and 1 - y = [tex]e^x[/tex], which leads to y = 1 - [tex]e^x[/tex].

5. y = xy + y:

Rearranging the equation, we get:

y - xy - y = 0

Combining like terms, we have:

-xy = 0

This equation has two solutions:

x = 0 and y = 0.

6. y = y[tex]e^x[/tex] - 2[tex]e^x[/tex] + y - 2:

Rearranging the equation, we get:

y[tex]e^x[/tex] - y = 2[tex]e^x[/tex]- 2

Factoring out y, we have:

y([tex]e^x[/tex] - 1) = 2([tex]e^x[/tex] - 1)

Dividing both sides by ([tex]e^x[/tex] - 1), we get:

y = 2

7. y = x/(y + 2):

Rearranging the equation, we get:

y(y + 2) = x

Expanding the equation, we have:

y² + 2y - x = 0

This equation doesn't have a general solution in terms of elementary functions. It can be solved numerically or using approximation methods.

8. y = xy/(x - 1):

Rearranging the equation, we get:

(x - 1)y = xy

Dividing both sides by y and rearranging, we have:

x - 1 = x/y

Solving for y, we get:

y = x/(x - 1)

9. x²y = ylny - y:

This is a nonlinear differential equation that doesn't have a general solution in terms of elementary functions. It can be solved numerically or using approximation methods.

10. xy - y = 2x²y:

Rearranging the equation, we get:

xy - 2x²y - y = 0

Factoring out y, we have:

y(x - 2x² - 1) = 0

This equation has two solutions:

y = 0 and x - 2x² - 1 = 0, which leads to x = (1 ± √3)/2.

11. y - 3y² = x + 2y:

Rearranging the equation, we get:

-3y² + y + 2y - x = 0

Combining like terms, we have:

-3y² + 3y - x = 0

This equation doesn't have a general solution in terms of elementary functions. It can be solved numerically or using approximation methods.

12. y = (2xy + 2x)/(x² - 1):

Rearranging the equation, we get:

y(x² - 1) = 2xy + 2x

Expanding the equation, we have:

x²y - y = 2xy + 2x

Combining like terms, we get:

x²y - 2xy - y - 2x = 0

This equation doesn't have a general solution in terms of elementary functions. It can be solved numerically or using approximation methods.

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Answer:

120 pi

Step-by-step explanation:

a. 1/3pi(6)^2(10)

just plug them into the calculator using pi.

b. pi is more accurate because you aren't round to 3.14. If you use 3.14 your answer will be rounded and not an exact number.

The volume of the cone is 120π.

Because 3.14 is an approximation to π which is accurate to about one twentieth of a percent.

The volume of the cone is;

[tex]\rm Volume \ of \ cone=\dfrac{1}{3}\pi r^2h\\\\Where \ r= radius , \ h = height[/tex]

A trap to catch fruit flies uses a cone in a jar.

The cone is shown with a height of 10 centimeters (cm) and a radius of 6 centimeters (cm.)

1. The volume of the cone is;

[tex]\rm Volume \ of \ cone=\dfrac{1}{3}\pi r^2h\\\\ Volume \ of \ cone=\dfrac{1}{3}\times \pi \times 6^2\times 10\\\\ Volume \ of \ cone=\dfrac{1}{3}\times \pi \times 36\times 10\\\\ Volume \ of \ cone=120\pi \\\\[/tex]

The volume of the cone is 120π.

2. Because 3.14 is an approximation to π which is accurate to about one twentieth of a percent.

If you are dealing with everyday physical measurements, this accuracy for π will likely exceed the accuracy of your measurement (such as your height to within a millimetre or four hundredths of an inch!). Hence a calculated answer would not be more accurate than if you simply used 3.14 or, just to be sure, 3.142.

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Answer: x= 4y/7 - 1/7

7x/4+ 1/4

Step-by-step explanation:

The correct answer i.e. mean difference is (a) 0.

What is the mean difference?

The mean difference is a statistical measure that represents the average difference between pairs of values in a dataset. It is calculated by taking the sum of all the differences and dividing it by the total number of pairs.

To calculate the mean difference, follow these steps:

Identify the pairs of values in your dataset for which you want to calculate the difference.

Calculate the difference between each pair of values.

Sum up all the differences.

Divide the sum by the total number of pairs.

In a correlated t-test, the null hypothesis assumes that the mean difference between paired observations is zero, indicating no effect of the independent variable. Therefore, if the independent variable has no effect, the sample difference scores are expected to be a random sample from a population where the mean difference score, denoted as μd, equals 0.

Hence, the correct answer is (a) 0.

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Answer:

0

Step-by-step explanation:

Apply Only the Outside and Inside Method of the Foil Method.

[tex]7 \times - \frac{1}{2} = - 3.5x[/tex]

[tex] \frac{1}{2} \times 7x = 3.5x[/tex]

Add them together

[tex] - 3.5x + 3.5x = 0[/tex]

So our b value is 0.

Answer:

The nearest gumdrop required will be 30.

Step-by-step explanation:

We will find the circumference of the cake which has 12 inches diameter

Radius = diameter / 2 = 12 / 2 = 6 inches

C = 2 x 3.14 x radius

C = 2 x 3.14 x 6 = 37.68 inches

The gum drop dia = 1.25 inches

The total gum drops required to cover 37.68 inches = 37.68 / 1.25 = 30.144

The nearest gumdrop required will be 30.

Answer:

The answer is x<3

Answer:

Option 2

Step-by-step explanation:

if an input produces more than one output, the table does not represent a function.

Step-by-step explanation:

[tex]180 - 35 - 65 = \\ = 145 - 65 = \\ = 80[/tex]

Answer:

i BELIVE it will be 50 I’m super sorry if I’m wrong lovly.

Step-by-step explanation:

Answer: 9 hours

We would get:

1 hour of work = $18

162 divided by 18 = 9

So she would have to work 9 hours

Answer:

9 hours

Step-by-step explanation:

Step One: A rate is the same thing as ratio. This just means that there is a proportion. For example, for every 3 dogs, there are 4 cats. This would mean that for 6 dogs there are 8 cats, and so on.

Step Two: Okay, because these numbers are larger, it is easiest to scale it back to one. The proportion or rate given is $234/13 hours. We would divide by 13 to get it to 1: $18/1 hour. The proportion is usually a decimal, but these numbers happen to divide nicely.

Step Three: Now, we can do 162/18 to see what the scale is, or how much times larger it is: 162/18=9.

Step Four: Lastly, just do 1 times 9, which tells it is 9 hours. To check the work, make sure 9 is less than the original proportion; it should take less time to make less money. 9 is less than 13, so this is the answer!

Let P be the vector space of polynomials of degree at most.

(a) is a subspace of P.

(b) is not a subspace of P.

(c) is a subspace of P.

(d) is a subspace of P.

(a) {p(x) = P₂|p(2)=0}

This subset consists of polynomials in P₂ that evaluate to 0 at x = 2. To check if it is a subspace, we need to verify the three conditions:

The zero polynomial is in this subset since it evaluates to 0 at x = 2.

Let p₁(x) and p₂(x) be two polynomials in this subset. If p₁(2) = 0 and p₂(2) = 0, then (p₁ + p₂)(2) = p₁(2) + p₂(2) = 0 + 0 = 0. Hence, the subset is closed under vector addition.

Let p(x) be a polynomial in this subset, and c be a scalar. If p(2) = 0, then (cp)(2) = c(p(2)) = c(0) = 0. Hence, the subset is closed under scalar multiplication.

Therefore, (a) is a subspace of P.

(b) {p(z) € P₂ | x-p'(x) + p(x) = 0}

This subset consists of polynomials in P₂ that satisfy the equation x - p'(x) + p(x) = 0. To check if it is a subspace, we need to verify the three conditions:

The zero polynomial is not in this subset since it does not satisfy the equation x - p'(x) + p(x) = 0.

If p₁(x) and p₂(x) are two polynomials in this subset, (p₁ + p₂)(x) = p₁(x) + p₂(x) satisfies the equation x - (p₁ + p₂)'(x) + (p₁ + p₂)(x) = 0. However, we need to check if it satisfies the equation x - (p₁ + p₂)'(x) + (p₁ + p₂)(x) = 0 for all x, not just at certain points. This condition may not hold, so the subset is not closed under vector addition.

Let p(x) be a polynomial in this subset, and c be a scalar. If we consider cp(x), the equation x - (cp)'(x) + cp(x) = 0 may not hold for all x, depending on the value of c. Therefore, the subset is not closed under scalar multiplication.

Therefore, (b) is not a subspace of P.

(c) {p(z) E P₂|p(0) = p(1)}

This subset consists of polynomials in P₂ that satisfy the equation p(0) = p(1). To check if it is a subspace, we need to verify the three conditions:

The zero polynomial is in this subset since it satisfies the equation p(0) = p(1) (both sides are 0).

If p₁(x) and p₂(x) are two polynomials in this subset, (p₁ + p₂)(x) = p₁(x) + p₂(x) satisfies the equation (p₁ + p₂)(0) = p₁(0) + p₂(0) and (p₁ + p₂)(1) = p₁(1) + p₂(1). Since p₁(0) = p₁(1) and p₂(0) = p₂(1), it follows that (p₁ + p₂)(0) = (p₁ + p₂)(1). Hence, the subset is closed under vector addition.

Let p(x) be a polynomial in this subset, and c be a scalar. If we consider cp(x), the equation (cp)(0) = (cp)(1) holds since p(0) = p(1). Hence, the subset is closed under scalar multiplication.

Therefore, (c) is a subspace of P.

(d) {ar² + (a + 1)x + b | a, b ∈ R}

This subset consists of all polynomials of the form ar² + (a + 1)x + b, where a and b are real numbers. To check if it is a subspace, we need to verify the three conditions:

The zero polynomial is in this subset since it can be written as 0r² + (0 + 1)x + 0 = x.

If p₁(x) and p₂(x) are two polynomials in this subset, their sum p₁(x) + p₂(x) is of the form ar² + (a + 1)x + b, where a and b are real numbers. Hence, the subset is closed under vector addition.

Let p(x) be a polynomial in this subset, and c be a scalar. Then cp(x) is of the form car² + (ca + c)x + cb, where a, b, and c are real numbers. Hence, the subset is closed under scalar multiplication.

Therefore, (d) is a subspace of P.

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Answer:

-1(3x^2) +4x-7

Step-by-step explanation:

grouping

Answer:

  (x +6)² +(y +3)² = 36

Step-by-step explanation:

The standard form equation of a circle with center (h, k) and radius r is ...

  (x -h)² +(y -k)² = r²

__

We have a circle with diameter 12, so its radius is 6. The center is given as (h, k) = (-6, -3), so the equation can be written ...

  (x -(-6))² +(y -(-3))² = 6²

Simplifying this a suitable amount, we have the equation ...

  (x +6)² +(y +3)² = 36

The general nonhomogeneous solution for the given higher-order differential equation, y" – 2y' – y + 2 = 0, can be found by reducing it to a system of first-order differential equations (HODE) and solving the resulting system.

To reduce the higher-order differential equation to a system of first-order differential equations, we introduce two new variables, u and v. We let u = y' and v = y''. By taking the derivatives of these new variables, we have u' = y'' and v' = y'''.

Substituting these expressions into the original equation, we obtain the following system of first-order differential equations:

u' = v
v' = 2u + v - 2

Now, we can solve this system using standard techniques. The characteristic equation associated with this system is r^2 - r - 2 = 0, which factors as (r - 2)(r + 1) = 0. Hence, the eigenvalues of the system are λ₁ = 2 and λ₂ = -1.

For λ₁ = 2, we find the corresponding eigenvector to be [1, 0]. For λ₂ = -1, the eigenvector is [1, -2].

The general solution of the homogeneous system is given by:
u(t) = c₁e^(2t) + c₂e^(-t)
v(t) = c₁e^(2t) + (-2c₁ + c₂)e^(-t)

To find the particular solution, we assume a solution in the form of u_p = At and v_p = Bt + C. Substituting this into the system, we obtain A = -3 and C = -1.

Therefore, the general nonhomogeneous solution to the given higher-order differential equation is:
y(t) = c₁e^(2t) + c₂e^(-t) - 3t - 1.

By reducing the given higher-order differential equation to a system of first-order differential equations and solving the resulting system, we found the general nonhomogeneous solution to be y(t) = c₁e^(2t) + c₂e^(-t) - 3t - 1.

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For any positive integer k, the radius of convergence R is: If k ≥ -2, R = 0 (the series diverges for all x). If k < -2, R = ∞ (the series converges for all x).

To find the radius of convergence,

R, of the series Σ[tex][n!^{k+3} / ((k + 3)n)!][/tex][tex]x^n[/tex]  (n = 0 to infinity),

we can use the ratio test.

Step 1: Apply the ratio test

Consider the ratio of consecutive terms:

L = [tex]\lim_{n \to \infty}[/tex] |[tex](n+1)!^{k+3}[/tex] / ((k + 3)(n + 1))!| / [tex]n!^{k+3}[/tex]/ ((k + 3)n)!|

= [tex]\lim_{n \to \infty}[/tex] |[tex](n+1)!^{k+3}[/tex] / [tex]n!^{k+3}[/tex] × ((k + 3)n)! / ((k + 3)(n + 1))!|

= [tex]\lim_{n \to \infty}[/tex] |[tex]n+1^{k+3}[/tex]/ ((k + 3)(n + 1))|

Step 2: Simplify the ratio

L =[tex]\lim_{n \to \infty}[/tex][tex]|(n + 1)^k / (k + 3)|[/tex]

= ∞ if k ≥ -2 (the limit diverges)

= 0 if k < -2 (the limit converges to 0)

Step 3: Determine the radius of convergence

According to the ratio test, the series converges if L < 1,

and diverges if L > 1.

Since the limit L depends on the value of k,

the radius of convergence R varies accordingly:

If k ≥ -2, the series diverges for all values of x.

If k < -2, the series converges for all values of x.

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Answer:

Step-by-step explanation:

28*5 115 sub 115 from 800 then divide 685 by 5 then add 7 into that number 28 times

Answer:

15/

x

136

Step-by-step explanation:

im pretty sure

Answer:

0.11

Step-by-step explanation:

The desirable answer would be 0.11029411∞, and it would go on forever. Therefore, by rounding the designated number above, thou shall get 0.11.

I hope this is of good use.

Respuesta:

120 metros

Explicación paso a paso:

Dado que:

Área del lote cuadrado = 900 m²

Área, A de cuadrado = s²

Donde, s = longitud del lado

s² = 900

Toma el cuadrado de ambos lados

s = raíz cuadrada (900)

s = 30

Se requiere metro lineal de alambre para cercar, el lote será el perímetro del lote cuadrado;

El perímetro del lote cuadrado = 4s

Por eso,

Perímetro del lote cuadrado = 4 * 30

Perímetro del lote cuadrado = 120 m

The simplified expression in the context of this problem is given as follows:

C. -5yz².

Like terms are terms that share these two features listed as follows:

If terms are like terms, then they can be either added or subtracted.

The expression for this problem is given as follows:

4yz²- 5yz² + 7yz² - 5yz² + yz² - 4yz² - 3yz².

The sum of the coefficients is given as follows:

4 - 5 + 7 - 5 + 1 - 4 - 3 = -5.

Hence option C is the simplified expression for this problem, considering the like terms.

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Expanding the expression -3(X² - 4x + 2) + 4(X + 1) involves using the distributive property to multiply each term inside the parentheses by the coefficient outside the parentheses. The resulting expression is simplified by combining like terms and the result is -3X² + 16x - 2.

To expand the given expression, we apply the distributive property. We start by multiplying -3 by each term inside the parentheses: -3(X²) - 3(-4x) - 3(2).

Similarly, we multiply 4 by each term inside the second set of parentheses: 4(X) + 4(1).

The next step is to simplify each multiplication. -3(X²) results in -3X², -3(-4x) simplifies to +12x, and -3(2) simplifies to -6.

Similarly, 4(X) simplifies to 4X, and 4(1) simplifies to 4.

Now, we can combine like terms by adding or subtracting them. In this case, we have -3X² + 12x - 6 + 4X + 4.

Combining the like terms 12x and 4X gives us 16x.

The expression becomes -3X² + 16x - 2.

Therefore, after expanding and simplifying the given expression -3(X² - 4x + 2) + 4(X + 1), the result is -3X² + 16x - 2.

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