Please help me in this!!!!!!

The significance level of 0.01 indicates that we want to use a 1% level of significance to evaluate the evidence against the null hypothesis.

The null and alternative hypotheses for testing the claim that the majority of college students' cell phone bills are paid by their parents can be stated as follows:

Null hypothesis (H0): The majority of college students' cell phone bills are not paid by their parents.

Alternative hypothesis (Ha): The majority of college students' cell phone bills are paid by their parents.

In this scenario, the null hypothesis assumes that the proportion of college students whose parents pay their cell phone bills is less than 50% (not a majority), while the alternative hypothesis suggests that the proportion is greater than or equal to 50% (a majority). The significance level of 0.01 indicates that we want to use a 1% level of significance to evaluate the evidence against the null hypothesis.

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The answer to given statements are

1. the correct answer is b) An m x r matrix.

2. Markov chain

3. rejection region

1. The product C = AB of an m x n matrix A and an n x r matrix B will result in an m x r matrix.

Therefore, the correct answer is b) An m x r matrix.

2. A sequence {Xₙ} of state matrices that are related by the equation Xk+1 = PXk, where P is a stochastic (probability) matrix, is called a Markov chain.

3. In hypothesis testing, each level of significance α has a critical value C that determines the rejection region for H0.

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Answer:

B cannot be factored into a perfect square

The probability that the aggregate losses for the entire portfolio will exceed 6,000 can be determined by calculating the cumulative distribution function (CDF) of the Gamma distribution without using the Central Limit Theorem. Alternatively, using the Central Limit Theorem, the approximate probability can be estimated by treating the sum of 16 independent risks as a normal distribution with a mean of 4000 and a standard deviation of 4.

(a) Without using the Central Limit Theorem, the probability that the aggregate losses for the entire portfolio will exceed 6,000 can be determined by calculating the cumulative distribution function (CDF) of the Gamma distribution for the sum of 16 independent risks. Since each risk follows a Gamma distribution with parameters θ = 250 and α = 1, the sum of 16 risks will follow a Gamma distribution with parameters θ' = 16 * 250 = 4000 and α' = 16 * 1 = 16. By evaluating the CDF at the value of 6,000, we can find the probability that the aggregate losses exceed 6,000.

(b) Using the Central Limit Theorem, we can approximate the distribution of the sum of 16 independent risks as a normal distribution. According to the theorem, as the number of independent and identically distributed (IID) risks increases, the distribution of their sum approaches a normal distribution with mean μ' = n * μ and standard deviation σ' = √(n * σ^2), where n is the number of risks, μ is the mean of each risk, and σ is the standard deviation of each risk.

In this case, with 16 independent risks, the approximate distribution of the aggregate losses will be a normal distribution with mean μ' = 16 * 250 = 4000 and standard deviation σ' = [tex]\sqrt{ (16 * 1^2)}[/tex] = 4. By calculating the probability that the normal distribution exceeds 6,000, we can estimate the approximate probability of the aggregate losses exceeding 6,000.

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Answer:

interest = $108

Step-by-step explanation:

interest = p * r * t

interest = 600*0.06*3

interest = $108

The mean of the data set is approximately 210.94. The median of the data set is 101. The mode of the data set is 343.

To determine the mean, median, and mode of the data set:

Data set: 343, 45, 340, SN, 105, 343, 29, 340, 101, 343, alelse, 1, 340, 343, 101, 312, 142, 340, 36

To calculate the mean, we need to find the average of all the values in the data set. However, it seems that there are some non-numeric entries like "SN" and "alelse." We need to remove these non-numeric entries before calculating the mean.

After removing the non-numeric entries, the data set becomes: 343, 45, 340, 105, 343, 29, 340, 101, 343, 1, 340, 343, 101, 312, 142, 340, 36.

Mean: Sum all the values and divide by the number of values.

Mean = (343 + 45 + 340 + 105 + 343 + 29 + 340 + 101 + 343 + 1 + 340 + 343 + 101 + 312 + 142 + 340 + 36) / 17

Mean ≈ 210.94 (rounded to two decimal places)

To calculate the median, we need to find the middle value of the data set when it is arranged in ascending order. If the number of values is odd, the median is the middle value. If the number of values is even, the median is the average of the two middle values.

Arranging the data set in ascending order: 1, 29, 36, 45, 101, 101, 105, 142, 312, 340, 340, 340, 343, 343, 343, 343, 340.

Median: Since the number of values is odd (17), the median is the middle value.

Median = 101

To calculate the mode, we need to find the value(s) that appear(s) most frequently in the data set.

Mode: In this data set, the value 343 appears most frequently, so the mode is 343.

In summary:

Mean ≈ 210.94

Median = 101

Mode = 343

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Answer:

18 shirts

Step-by-step explanation:

75% of 24

convert 75% to decimal number

75% is 0.75

0.75 x 24 = 18

Answer:

volume = 2520 mm³

Step-by-step explanation:

v = 2x12x7x15 = 2520 mm³

Answer:

1,500

Step-by-step explanation:

Answer:

85 wpm

Step-by-step explanation:

From the scatter plot, we can see the following;

At 20 hours, average typing speed = 34 wpm

At 30 hours, the average typing speed = 40 wpm

At 40 hours, the average typing speed = 51 wpm

At 50 hours, the average typing speed = 65 wpm

Average differences = ((40 - 34) + (51 - 40) + (65 - 51))/3 = 10.3

Approximating to a whole number = 10

Now, we can approximate that at 60 hours, average typing speed = 65 + 10 = 75 wpm

At 70 hours, the average typing speed = 75 + 10 = 85 wpm

Answer:

85 wpm

Step-by-step explanation:

I took this test!

The area D is bounded by the lines x = 0, y = 3 – 37, and y = 3x – 3. To calculate the iterated double integral for ∫∫xdA over D, the value of the iterated double integral ∫∫xdA over the area D is 0.

To set up the iterated double integral for ∫∫xdA over D, we first need to determine the limits of integration for x and y. Looking at the given lines, x = 0 indicates that x varies from 0 to some upper limit. The line y = 3 – 37 represents a horizontal line, indicating that y has a constant value of 3 – 37, which simplifies to -34. The line y = 3x – 3 represents a slanted line with a slope of 3, indicating that y varies linearly with x.

To find the limits of integration for x, we need to determine the x-values where the slanted line and the vertical line intersect. Setting 3x – 3 equal to 0, we find x = 1. Substituting this value back into the slanted line equation, we get y = 3(1) – 3 = 0. Therefore, x varies from 0 to 1.

For y, since it has a constant value of -34, the limits of integration for y are -34 to -34.

Setting up the iterated double integral, we have ∫∫xdA = ∫[0 to 1]∫[-34 to -34] x dy dx. Integrating with respect to y first, we have ∫[0 to 1] x(-34 - (-34)) dx, which simplifies to ∫[0 to 1] 0 dx. Finally, integrating with respect to x, we get 0. Therefore, the value of the iterated double integral ∫∫xdA over the area D is 0.

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Answer:

Hi

Step-by-step explanation:

The answer is B and D.

Hope it's correct.

Answer:

90 cm

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, then

50 ÷ 20 = 2.5

The legs of the similar triangle are 2.5 times the original legs, that is

legs of similar triangle = 2.5 × 36 cm = 90 cm

Answer:

(15f + 37f + 52 + 55) = ?

15f + 37f = 52f

52 + 55 = 107

So, (15f + 37f + 52 + 55) = 52f + 107.

Step-by-step explanation:

Hope that this helps! :)

Have a great rest of your day/night!

By completing the square, the equation in standard form is (x - 2)² + (y + 4)² = 4².

In Mathematics and Geometry, the standard form of the equation of a circle is modeled by this mathematical equation;

(x - h)² + (y - k)² = r²

Where:

From the information provided below, we have the following equation of a circle:

x² - 4x + y² + 8y = -4

x² - 4x + (-4/2)² + y² + 8y + (8/2)² = -4 + (-4/2)² + (8/2)²

x² - 4x + 4 + y² + 8y + 16 = -4 + 4 + 16

(x - 2)² + (y + 4)² = 16

(x - 2)² + (y + 4)² = 4²

Therefore, the center (h, k) is (2, -4) and the radius is equal to 4 units.

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Complete Question:

Complete the square to rewrite the following equation in standard form. x² - 4x + y² + 8y = -4.

(a) The z-score for an age of 30 years is approximately 0.6857.

(b) The winner's age of 30 years is roughly 0.6857 standard deviations above the mean age of the winners (27.6 years), indicating they were slightly older than the average age.

(a) To transform the age of 30 years to a z-score, we use the formula:

z = (x - μ) / σ

where:

x = individual value (age of the winner) = 30 years

μ = mean age = 27.6 years

σ = standard deviation = 3.5 years

Plugging in the values, we get:

z = (30 - 27.6) / 3.5

Calculating this expression, we find:

z ≈ 0.6857

Therefore, the z-score for an age of 30 years is approximately 0.6857.

(b) Interpretation of the results:

The z-score indicates the number of standard deviations an individual value (in this case, the age of the winner) deviates from the mean. A positive z-score suggests that the individual value is above the mean.

In this context, the z-score of approximately 0.6857 means that the age of the winner (30 years) is roughly 0.6857 standard deviations above the mean age of the winners (27.6 years). This suggests that the winner in that recent year was slightly older than the average age of the tournament winners.

By using z-scores, we can compare and interpret individual values within the context of a distribution, such as the bell-shaped distribution of ages in the cycling tournament winners.

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Answer: A time series graph is useful for representing the frequencies of a data category over a period of several years.

Explanation:                                                                                                           Time series graphs are usually employed when it is critical to examine data values and trends over time. A time series graph displays changes in data over time. It is usually used to depict economic, social, or physical characteristics that are measurable over time.                                                    A time series is a collection of observations or data taken at regular intervals over time and used to track and analyze changes in data over time.

   Time series graphs display data over time on a graph with time on the x-axis and a measured value, such as temperature or height, on the y-axis. The graph can display change trends over time as well as seasonal or other patterns, in addition to providing insight into how data values are changing over time.

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Answer:

q=(1,5) t=(-2,3)r=(3,-1)s=(0,0)

Step-by-step explanation:

Answer:

1) [tex]x^{2}\cdot y[/tex] - It is a monomial with two variables: [tex]x[/tex], [tex]y[/tex]

2) [tex]3\cdot x^{3}+x^{3}[/tex] - It is binomial reductible to a monomial due to like terms. Number of variables: [tex]x[/tex]

3) [tex]a^{2}\cdot b^{3}\cdot c^{4}[/tex] - It is a monomial with three variables: [tex]a[/tex], [tex]b[/tex], [tex]c[/tex]

4) [tex]2\cdot x^{2}-3=n[/tex] - It is binomial equivalent to a monomial. Number of variables: [tex]x[/tex], [tex]n[/tex].

5) [tex]x^{2}-y+2\cdot x^{2} = 3[/tex] - It is trinomial reductible to a binomial due to like terms. And equivalent to a constant. Number of variables: [tex]x[/tex], [tex]y[/tex]

Step-by-step explanation:

We proceed to explain the context on each case and answer appropriately:

1) [tex]x^{2}\cdot y[/tex] - It is a monomial with two variables: [tex]x[/tex], [tex]y[/tex]

2) [tex]3\cdot x^{3}+x^{3}[/tex] - It is binomial reductible to a monomial due to like terms. Number of variables: [tex]x[/tex]

3) [tex]a^{2}\cdot b^{3}\cdot c^{4}[/tex] - It is a monomial with three variables: [tex]a[/tex], [tex]b[/tex], [tex]c[/tex]

4) [tex]2\cdot x^{2}-3=n[/tex] - It is binomial equivalent to a monomial. Number of variables: [tex]x[/tex], [tex]n[/tex].

5) [tex]x^{2}-y+2\cdot x^{2} = 3[/tex] - It is trinomial reductible to a binomial due to like terms. And equivalent to a constant. Number of variables: [tex]x[/tex], [tex]y[/tex]

Answer:

1/4

Step-by-step explanation:

Answer:

this point is 72 digri ok

The expression "a > b" is evaluated before the other expressions.

How to evaluate an expression?

Follow the order of operations (PEMDAS/BODMAS). Evaluate the expression following the order of operations or the rules of precedence.

Let's break down the given statement and determine the order of evaluation for each expression:

if (a > b && c == d || a == 10 && b > a * b)

The statement consists of two logical expressions connected by the "&&" and "||" operators. To determine the order of evaluation, we need to consider operator precedence and associativity.

1. Parentheses: As there are no parentheses in the statement, we move on to the next step.

2. "&&" Operator: The "&&" operator has higher precedence than the "||" operator, so expressions connected by "&&" are evaluated before those connected by "||".

The first expression connected by "&&" is "a > b". Let's call this Expression 1.

The second expression connected by "&&" is "c == d". Let's call this Expression 2.

3. "||" Operator: The "||" operator has lower precedence than the "&&" operator.

The first expression connected by "||" is Expression 1 (a > b) && (c == d).

The second expression connected by "||" is "a == 10" && "b > a * b". Let's call this Expression 3.

Now, let's evaluate each expression in the given order:

Expression 1: a > b

Expression 2: c == d

Expression 3: a == 10 && b > a * b

Therefore, the expression evaluated first in the given statement is Expression 1: a > b.

To summarize, in the statement "if (a > b && c == d || a == 10 && b > a * b)", the expression "a > b" is evaluated first.

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Answer: B

The surface area of the right cylinder is 140π cubic units or 439.60 cubic units.

Step-by-step explanation:

We have formula to find the surface area of a right cylinder.

Surface area = 2πr(h + r)

Given: r = 5 and h = 9,

Now plug in the value of r and h in the above formula, we get

Surface area = 2π.5 (9 + 5)

= 10π(14)

Surface area = 140π

The value of π = 3.14, when we plug in the value of π, we get

The surface area = 140 × 3.14

= 439.60 cubic units.

Therefore, the surface area of the right cylinder is 140π cubic units or 439.60 cubic units.

Hope this helped!!!

Let the side of a cube be "a". The volume of the cube is "a³".

If all sides of the cube are halved, each side will now measure "a/2".Therefore, the new volume will be (a/2)³ cubic units. That is:a³ / 8 cubic units. The new volume of the cube will be reduced to 1/8 of its original volume.

A block is a three-layered strong item limited by six square faces, features or sides, with three gathering at every vertex. It looks like a hexagon from the corner, and its net usually looks like a cross. The block is the main customary hexahedron and is one of the five Non-romantic solids.

The volume of any three-dimensional solid is simply defined as the amount of space it occupies. A cube, cuboid, cone, cylinder, or sphere are all examples of these solids. The volumes of different shapes vary.

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In summary:

The relation R is reflexive. The relation R is not symmetric. The relation R is antisymmetric. The relation R is transitive.

Let's analyze the properties of the relation R:

Reflexive:

A relation R is reflexive if every element in the set is related to itself. In this case, we need to check if (a, a) belongs to R for every a in the set.

For the given relation R: (a, b) belongs to R if and only if a - b = 0.

Since a - a = 0, (a, a) satisfies the condition and is in R for every a in the set. Therefore, the relation R is reflexive.

Symmetric:

A relation R is symmetric if for every (a, b) belongs to R, (b, a) must also be in R.

For the given relation R: (a, b) belongs to R if and only if a - b = 0.

However, if a - b = 0, it does not imply that b - a = 0. Therefore, the relation R is not symmetric.

Antisymmetric:

A relation R is antisymmetric if for every distinct (a, b) belongs to R, (b, a) cannot be in R.

For the given relation R: (a, b) belongs to R if and only if a - b = 0.

Since a - b = 0 implies b - a = 0, it means that if (a, b) and (b, a) are in R, then a must be equal to b. Thus, for distinct elements a and b, it is not possible for both (a, b) and (b, a) to be in R. Therefore, the relation R is antisymmetric.

Transitive:

A relation R is transitive if for every (a, b) and (b, c) belongs to R, (a, c) must also be in R.

For the given relation R: (a, b) belongs to R if and only if a - b = 0.

If a - b = 0 and b - c = 0, it implies that a - c = 0. Therefore, if (a, b) and (b, c) are in R, then (a, c) is also in R. Thus, the relation R is transitive.

In summary:

The relation R is reflexive.

The relation R is not symmetric.

The relation R is antisymmetric.

The relation R is transitive.

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Answer:

2/11

Step-by-step explanation:

Let's say x = 0.18181818..

Then, 100x = 18.1818181....

so, if you put x in the repeating decimal in 18.1818,

you get the equation,

100x = 18+x

so, 99x = 18

x = 18/99 = 2/11

Answer:

18/100 = 9/50

Answer is 9/50

Do you really think you’re going to give me brainliest lol

Answer:

the answers is A and E  <3

Step-by-step explanation:

i took this test

Given:

An athlete who makes [tex]4\dfrac{3}{4}[/tex] laps in 3 mins 45 seconds on a 400m field.

To find:

The speed of the athlete in m/s.

Solution:

We know that,

Distance covered in 1 lap = 400 m

Distance covered in [tex]4\dfrac{3}{4}[/tex] laps = [tex]4\dfrac{3}{4}\times 400[/tex] m

                                               = [tex]\dfrac{19}{4}\times 400[/tex] m

                                               = [tex]1900[/tex] m

We know that,

1 minute = 60 seconds

3 minutes = 180 seconds

3 minutes 45 second = 180 + 45 seconds

                                   = 225 second

The speed of the athlete is:

[tex]Speed=\dfrac{Distance}{Time}[/tex]

[tex]Speed=\dfrac{1900}{225}[/tex]

[tex]Speed\approx 8.44[/tex]

Therefore, the speed of the athlete is about 8.44 m/s.

The correct substitution to rewrite the equation 16(x^3 + 1)^2 - 22(x^3 + 1) - 3 = 0 as a quadratic equation is:

c. u = (x^3 + 1)^2

By substituting u = (x^3 + 1)^2, the equation can be rewritten as 16u - 22u - 3 = 0, which is a quadratic equation in terms of u.

To solve the quadratic equation for u, you can use factoring, completing the square, or the quadratic formula. Once you find the solutions for u, you can substitute back (x^3 + 1)^2 for u to obtain the solutions for the original equation.

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