please prove that empty sets and singletons are always connected ?

Answers

Answer 1

Both the empty set (∅) and singleton sets are considered connected. The empty set is connected by definition, and a singleton set is connected because it cannot be divided into two non-empty open sets.

The statement that empty sets and singletons are always connected is true. Let's prove it for both cases:

1. Empty Set (∅):

The empty set (∅) is considered connected by definition. A set is said to be connected if there are no two non-empty open sets whose union is the set and whose intersection is empty. Since the empty set does not contain any elements, there are no open sets to consider, and thus it satisfies the definition of connectedness. In other words, there are no non-empty sets to separate the empty set, making it connected.

2. Singleton Set ({x}):

A singleton set, which contains only one element, is also connected. To prove this, let's assume the singleton set {x} is not connected. This means there exist two non-empty open sets A and B such that {x} is the union of A and B, and A and B have an empty intersection.

Since A and B are non-empty and their union is {x}, it means that each of them contains at least one point from the singleton set {x}. However, since the intersection of A and B is empty, it implies that A and B cannot contain any additional points other than x. This contradicts the assumption that A and B are open sets since they do not contain any points other than x.

Therefore, the assumption that {x} is not connected leads to a contradiction. Hence, {x} must be connected.

In conclusion, both the empty set and singleton sets are always connected.

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Related Questions

In a study of spat dating es were asked them in the same time to What other out of the popu 23,50710090 What is the concerto? D-lichte places need was the other the contacto OA TN repostane posting tone OR Weather to the memo and on dem O. We second have the end மொயமால மாமா mg 140 Newt 0 View an example Get more help Help me solve this C M a o 0 10 1 In a study of speed dating male subjects were asked to rate the attractiveness of their female dates, and a sample of the results is listed below (1 = not attractivo 10 = extremely attractive) Construct a confidence interval using a 95% confidence level What do the results tell about the mean attractiveness ratings of the population of all adult females? 6,9,3,9, 6, 6, 8, 8, 7, 10,5,9 What is the confidence interval for the population mean? [<<(Round to one decimal place as needed) west point(s) possible in a study of speed dating, male subjects were asked to rate the attractiveness of their female dates, and a sample of the results is listed below (1 = not attractive 10 = extremely attractive) Construct a confidence interval using a 95% confidence level What do the results tell about the mean attractiveness ratings of the population of all adult females? 6,9,3,9,6,6,8,8.7. 10,5,9 PO What is the confidence interval for the population mean? <-- (Round to one decimal place as needed) What does the confidence interval tell about the population of all adult fernales? Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice. ative Area from the LEF 02 O A. The results tell nothing about the population of all adult females, because participants in speed dating are not a representative sample of the population of all adult females 5000 5178 03 5120 5517 5990 5871

Answers

Confidence interval are 5.9 < μ < 8.5 for the population mean.

Given:

Let x = 6,9,3,9, 6, 6, 8, 8, 7, 10,5,9

N = 12, ∑x = 86 x = 86/12 = 7.16

[tex]s=\sqrt{\frac{(x-\bar x)^2}{N-1} } = \sqrt{\frac{(6-7.16)^2+.....+(9-7.16)}{12-1} }[/tex]

[tex]\sqrt{\frac{45.66}{11} } =2.03[/tex]

At 98% confidence interval.

[tex]z=1-\frac{95}{100} =0.05\\[/tex]

[tex]t=2.201[/tex]

Confidence interval.

[tex]\bar x \pm t\frac{s}{\sqrt{n} } = 7.16\pm 2.201(\frac{2.03}{\sqrt{12} } )[/tex]

[tex]5.9 < \mu < 8.5[/tex]

Therefore, 95% confidence interval are 5.9 < μ < 8.5

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given the rectangular coordinates (-8,15), which of the following polar coordinate pairs represents the same point in radians?

a(17,2.65)
b(-17,-1.08)
c(12.7,2.65)
d(-12.7,-0.49)

Answers

Answer:

1. (x,y)=

2. (3, 480°), (3,-240°), (-3, -60°)

3. (-17, -1.08)

4. on the second circle from the center and 153° clockwise from the horizontal axis

Step-by-step explanation:

took quiz...100%

How much interest is earned on a principal of $316 invested at an interest rate of 9%
compounded annually for four years?

Answers

Answer:

$130.06

Step-by-step explanation:

Interest is calculated as shown;

I = A - P

A is the amount

P is the principal

Given

Principal = $316

Rate R = 9% = 0.09

Time t = 4yrs

Substiutte and get Amount A

A  =P(1+r)^n

A = 316 (1+0.09)^4

A = 316(1.09)^4

A = 316(1.4116)

A = 446.06

Interest = 446.06 - 316

Interest = 130.06

Hence the interest is $130.06

What is the midpoint of EF with endpoints E (−9,7) and F(0,−4)?

Answers

Answer:

midpoint = -4.5, 1.5

Step-by-step explanation:

x1 = -9, y1 = 7, x2=0 , y2=-4

midpoint = (x1 +x2)/2 , (y1 + y2)/2

= (-9 + 0)/2 , (7 + -4)/2

=-9/2 , 3/2

midpoint = -4.5, 1.5

The driveshaft lifespan is measured in operating hours before failure, and the distribution of lifespans is known to follow a Gamma distribution. A sample of 50 driveshafts is carefully tracked until failure and their lifespans are measured to have sample mean of 1274 hours, and a standard deviation of 108 hours.

(a)Assuming a normal distribution with the mean and standard deviation of the sample, estimate the proportion of driveshafts that would fail prior to reaching 1200 operating hours.

(b)Using the central limit theorem and corresponding normality assumption, calculate a 95% confi- dence interval for the true mean lifespan.

Answers

a. The estimated proportion of driveshafts that would fail prior to reaching 1200 operating hours is approximately 0.246, or 24.6%.

b. The 95% confidence interval for the true mean lifespan is approximately (1244.79, 1303.21) hours.

How to calculate the value

(a) First, we need to standardize the value 1200 using the sample mean and standard deviation. We calculate the z-score as follows:

z = (x - μ) / σ,

z = (1200 - 1274) / 108

≈ -0.685

Using a standard normal distribution table or calculator, we find that the proportion is approximately 0.246.

(b) The formula for the confidence interval is:

CI = x ± z * (σ / √n),

CI = 1274 ± 1.96 * (108 / √50)

CI = 1274 ± 1.96 * (108 / √50)

CI ≈ 1274 ± 1.96 * 15.297

The 95% confidence interval for the true mean lifespan is approximately (1244.79, 1303.21) hours.

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You add 11/4 tablespoons of olive oil for every 3/2 tablespoons of balsamic vinegar to make 34 tablespoons of bread dip. How much olive oil and balsamic vinegar do you use?

You use ___ tablespoons of olive oil and

___ tablespoons of balsamic vinegar.

Answers

Answer:

The amount of olive oil and balsamic vinegar to use are;

You use 22 tablespoons of olive oil and 12 tablespoons of balsamic vinegar

Step-by-step explanation:

From the question, we have;

The number of tablespoons of olive oil added for every 3/2 tablespoon of balsamic vinegar = 11/4 tablespoons

Therefore, in the mixture, the ratio of olive oil to balsamic vinegar = 11/4:3/2

Let 'x', and 'y' represent the the number of tablespoons of olive oil and balsamic vinegar, in the mixture 34 tablespoons of bread dip, we can write;

x + y = 34 tablespoons

x/y = (11/4)/(3/2) = 11/6

∴ x = 11/6 × y

∴ x + y = 11/6 × y + y = 34

11/6 × y + y = 17·y/6 = 34

17·y = 34 × 6 = 204

y = 204/17 = 12

The number of tablespoons of balsamic vinegar in the bead dip, y = 12 tablespoons of balsamic vinegar

x = 11/6 × y = 11/6 × 12 = 22

The number of tablespoons of olive oil in the bead dip, x = 22 tablespoons of olive oil.

Solve for v.
6v-7+2(5v+1) = -2(v + 4)

Answers

Answer:

v = -1/6

Step-by-step explanation:

Combine all like terms, getting 18v = -3. Then, divide both sides by 18 to get -3/18, or v = -1/6

Hopefully this helps- let me know if you have any questions!

Y= -3/2x +3 is the same line as x + y =

Answers

I don’t know this question but you can’t divided by number and multiply

The lenght of an arc in a circle with radius 8 inches is 3.2π. determine the measure of the arc​

Answers

Answer:

72

Step-by-step explanation:

32pi×360/2pi(8)=72

central angle= arc length 360/2pi×r

The measure of the arc is 72 degree

What is mean by Circle?

The circle is a closed two dimensional figure , in which the set of all points is equidistance from the center.

The measure of the arc, we use the formula:

⇒ Arc length = (angle measure / 360°) x 2πr

where r is the radius of the circle.

Now, We know that;

The radius is 8 inches, and that the arc length is 3.2π inches.

So, we can plug in those values and solve for the angle measure:

3.2π = (angle measure / 360°) x 2π(8)

3.2π = (angle measure / 360°) x 16π

Divide both sides by 16π:

0.2 = angle measure / 360°

Multiply both sides by 360°:

Angle measure = 72°

Thus, The measure of the arc is 72 degree

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Write the system x' = e²tx - 8ty + 7 sin(t), y' = 2 tan(t) y + 7x - 2 cos(t) in the form Use prime notation for derivatives and write x and ï', etc., instead of ï(t), x'(t), or dr. 1-1 dt = P60 [*] + F(0). P(t)

Answers

The system in the requested form, using prime notation for derivatives and ï notation for variables, is ï' = e^2tï - 8tï' + 7sin(t) and ï'' = 2tan(t)ï' + 7ï - 2cos(t).

The system can be written in the form:

x' = e^2tx - 8ty + 7sin(t)

y' = 2tan(t)y + 7x - 2cos(t)

Using prime notation for derivatives, the system becomes:

x' = e^2tx - 8ty + 7sin(t)

y' = 2tan(t)y + 7x - 2cos(t)

Furthermore, we can write x and y using ï' notation as:

x = ï

y = ï'

Substituting these expressions into the system, we have:

ï' = e^2tï - 8tï' + 7sin(t)

ï'' = 2tan(t)ï' + 7ï - 2cos(t)

In summary, the system in the requested form is:

ï' = e^2tï - 8tï' + 7sin(t)

ï'' = 2tan(t)ï' + 7ï - 2cos(t)

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Solve Systems of Equations Algebraically.
y=x-8
y=5x

Answers

Answer:

(- 2, - 10 )

Step-by-step explanation:

Given the 2 equations

y = x - 8 → (1)

y = 5x → (2)

Substitute y = 5x into (1)

5x = x - 8 ( subtract x from both sides )

4x = - 8 ( divide both sides by 4 )

x = - 2

Substitute x = - 2 into either of the 2 equations for y

Substituting into (1)

y = - 2 - 8 = - 10

solution is (- 2, - 10 )

Twenty-five wooden beams were ordered for a construction project. The sample mean and the sample standard deviation were measured: xbar = 260 cm, s = 2 cm. Calculated confidence interval for the mean is [259.32;260.68].
Which confidence level was chosen? assume distribution to be normal.

Answers

The answer tο the questiοn "Which cοnfidence level was chοsen?" is that it cannοt be determined based οn the given infοrmatiοn.

What is Statistical Inference?

Statistical inference refers tο the prοcess οf drawing cοnclusiοns οr making predictiοns abοut a pοpulatiοn based οn sample data. It invοlves using statistical methοds and techniques tο analyze the data and make inferences abοut the underlying pοpulatiοn parameters. Statistical inference allοws researchers tο generalize their findings frοm a sample tο the entire pοpulatiοn and make infοrmed decisiοns οr predictiοns.

Twenty-five wοοden beams were οrdered fοr a cοnstructiοn prοject. The sample means and the sample standard deviatiοn was measured:[tex]\bar{x} = 260 \, \text{cm}$, $s = 2 \, \text{cm}$.[/tex] The calculated confidence interval for the mean is [tex][259.32; 260.68]$.[/tex]

To determine the confidence level chosen, we need to consider the properties of a confidence interval. In this case, the confidence interval is given as[tex]$[259.32; 260.68]$[/tex], which represents an interval estimate for the population mean.

A confidence interval is typically written as [tex]\bar{x} \pm E$,[/tex]where [tex]$\bar{x}$[/tex] is the sample mean and E is the margin οf errοr. The margin οf errοr depends οn the sample size, standard deviatiοn, and the desired level οf cοnfidence.

In the given infοrmatiοn, the sample mean [tex]$\bar{x}$[/tex] is 260 cm, and the sample standard deviatiοn s is 2 cm. Hοwever, the level οf cοnfidence is nοt directly prοvided.

Tο determine the cοnfidence level chοsen, we need additiοnal infοrmatiοn abοut the calculatiοn οr the specific cοnfidence level used. Withοut this infοrmatiοn, we cannοt determine the exact cοnfidence level that cοrrespοnds tο the given cοnfidence interval.

Therefοre, the answer tο the questiοn "Which cοnfidence level was chοsen?" is that it cannοt be determined based οn the given infοrmatiοn.

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Which of the following variables could theoretically be measured on a continuous scale? (a) Method of contraception used (b) length of time of residence in a state (c) task completion time (d) intelligence (e) authoritarianism (f) alienation (g) county of residence.

Answers

The variable that could theoretically be measured on a continuous scale is task completion time.

Task completion time is the duration between the initiation and completion of a specific task. It is continuous as it can take a large range of values on a continuous scale without any gap. It is frequently calculated in various businesses and researches to determine the efficiency and productivity of a particular task or process.

The other variables, such as method of contraception used, length of time of residence in a state, intelligence, authoritarianism, alienation, and county of residence, are all discrete variables. These variables take non-numerical values and are separate from each other by a gap.

These variables can be classified and counted into different categories, such as the number of individuals using a particular method of contraception, number of years of residence in a particular state, number of individuals belonging to a particular county, or number of individuals showing authoritarianism.

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Joe has been riding his bicycle at a speed of 12 mph and has gone 48 miles. How long has he been riding?

Answers

Answer:

Joe's been riding 4 hours because if you divide 48 by 12 it gives you 4 and it's by hours so it would be 4 hours. point blank period.

Step-by-step explanation:

Find the area under the standard normal distribution curve between z=0 and z=0.25. Use The Standard Normal Distribution Table and enter the answer to 4 decimal places.
The area between the two z values is ______

Answers

The area under the standard normal distribution curve between z=0 and z=0.25 is 0.0987.

First cumulative probability = z = 0 and

Second cumulative probability = z = 0.25

The Standard Normal Distribution Table, often known as the Z-table, may be used to determine the area under the standard normal distribution curve between z=0 and z=0.25. The table shows the total likelihood (area) up to a specified z-value. The cumulative probability, which can be found by looking up the z-value of 0 in the table, is 0.5000. The cumulative probability is 0.5987 when we look up the z-value of 0.25.

Calculating the area -

Area = First cumulative probability - Second cumulative probability

= 0.5987 - 0.5000

= 0.0987

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what is the area of the rectangular pool below whose dimension are 2 x +1 and units x-1 units​

Answers

Answer:

(2x+1)(x-1) = 2x^2 - x - 1

Step-by-step explanation:

Answer:

2x^2 - x - 1

Step-by-step explanation:

Lets rewrite it to the area formula

(2x+1)(x-1)

Simplify-(distributive property of multiplication)

(2x*x) + (2x*-1) + (1*x) + (1*-1) =

Simplify

2x^2 + (-2x) + x + (-1)

Simplify

2x^2 - x - 1

The answer is 2x^2 - x - 1

If my answer is wrong, pls correct me

If you like my answer and my explanation, mark me as brainliest!

-Chetan K

X^2-18x-2=0. Which number would have to be added to “complete the square”?

Answers

Step-by-step explanation:

its83

(a+b)^2=a^2+2ab+b^2

x^2+(-9)2x-2=0

b^2=81

83+(-2)=81

How are youaefljsofjsnjvlsdnbvjklxfclkjmzlv

Answers

GOOD BUT ANYONE WANT TO HELP ME WITH MY HISTORY BEFORE I FAIL

if h(x) = 3(x + 6), find h(-1).
a.3
b.9
c.15
d.21​

Answers

It will be 15 I Believe

Find the common difference of the arithmetic sequence -3, -9, -15

Answers

Answer:

they are subtracting 6 from each number

The curb weight of a new car is 3,347 pounds. How much does the car weigh?

Answers

Answer: 3,347 pounds

Step-by-step explanation:

Curb weight is simply the weight of a car with no passengers, cargo, or anyting other than the standard base model options.

Basically it's the weight of a base model car sitting on the dealership lot.  Curb weight would be different if ANYTHING is added to the base model car such as a passenger, any cargo, or any upgrades aftermarket or otherwise.

Answer:

Not sure if this the correct type of way your looking but its between 1 and 2 tons which is 1000

Step-by-step explanation:

I think...

How am I supposed to do this?

Answers

Take it step by step by doing the 2 fractions on top

Can someone please help me with this

Answers

Answer:

Step-by-step explanation:

5- There are 2 right-angled triangles and 1 equilateral triangle or you can just say triangles

6- area for a triangle is a=bh(1/2)

so 4×3=12(1/2)=6

and 4×3=12(1/2)=6

In both triangles, they're a=6

7- 4×6=24(1/2)=12

the top flag is a=12

8-12+6+6=24

9- the rectangular flag has an area of 24 since a=bh and the added areas of the triangles are 24. I conclude that these are two ways of finding the area of this rectangular flag.

hope this helps : )

Triangle ABC is an isosceles triangle where angles angle A and B are congruent of angle B measures 35 what is the measurement of angle c

Answers

Answer:

m<C = 110

Step-by-step explanation:

<a = <b

<b = 35 so,

<a = 35

<c = x

<a + <b + <c = 180

35 + 35 + x = 180

70 + x = 180

x = 180 - 70

x = 110

HELP ASAP!!! select all the descriptions that apply to the transformation!

Answers

Answer: A and B

Step-by-step explanation:

The shape is moving from right to left and down

when comparing the f(x) = x2 2x and g(x) = log(2x 1), on which interval are both functions negative? (–[infinity], –2) (–2, 0) (–1, 1) (–[infinity], [infinity])

Answers

To find out on which interval are both functions f(x) = x^2 + 2x and g(x) = log (2x + 1) negative, we need to analyze the intervals of negative values of both functions.

We can plot their graphs to have a better understanding:

Graphs of f(x) = x² + 2x and g(x) = log(2x + 1)

Now, we need to observe the intervals where both functions lie below the x-axis: The function f(x) = x^2 + 2x is below the x-axis on the interval (-∞, -2).

The function g(x) = log(2x + 1) is below the x-axis on the interval (-1/2, 0).

Therefore, the interval on which both functions are negative is (-2, 0).Thus, the correct option is (–2, 0).

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we are conducting many hypothesis tests to test a claim. In every case, assume that the null hypothesis is true. Approximately how many of the tests will incorrectly find significance?
40 tests using a significance level of 10%.

Answers

is there any answer choices or is it a free write


Please please help I swear I will give you brainlist if it’s right and please explain for part a and part b thank you

Answers

Answer:

A. Reduction

B. 2

Step-by-step explanation:

A: A reduction is when the image is getting smaller. The apostrophes show the new, or second, image. It is called "prime." Because the prime is smaller than the original, it is a reduction.

B: Scale factor is when you divide, which number changes it. In other words, the image moved from 4 to 2, from 2 to 1, etc, which means we are DIVIDING by 2.

hi amazing people please help i’ll give brainliest thanks!

Answers

Answer:

to present another's viewpoint

Answer:-

D, to analyze specific data i guess

A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, X, is found to be 100, and the sample standard deviation found to be 8.
Construct a 98% confidence interval about µ, if the sample size n, is 20.
Lower bound ______ Upper bound _______
(Round to one decimal place as needed.)

Answers

As per the confidence interval Lower Bound is 94.874 and the Upper Bound is 105.126

Sample Mean = 100

Sample Standard Deviation = 8

Sample Size = 20

Calculating the confidence interval -

Confidence Interval = Sample Mean ± (Critical Value) x (Standard Deviation / √(Sample Size))

Substituting the values

= 100 ± (2.860) x (8 / √20)

= 100 ± 2.860 x (8 / 4.472)

= 100 ± 2.860 x 1.789

= 100 ± 5.126

Calculating the lower bound -

Lower Bound

= 100 - 5.126

= 94.874

Calculating the upper bound -

Upper Bound

= 100 + 5.126

= 105.126

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Calculate the Total Direct Materials cost variance using the above information:a. $9,262.50 Unfavorableb. $9,262.50 Favorablec. $3,780.00 Unfavorabled. $3,562.50 Favorable A mass moves back and forth in simple harmonic motion with amplitude A and period T.(a) In terms of A, through what distance does the mass move in the time T?(b) Through what distance does it move in the time 6.00T? Name a Time YouImproved a Process at Walmart as a freight handler. WhatHappened? transaction-based manipulation includes: group of answer choices spoofing cascading both of the above none of the above Let B1={u1,...,un} and B2=v1,...,vn be the ordinate basis of the vector space V. Let T:VV be the linear operator defined by T U1=V1,T U2=V2, ...,T Un=Vn.Prove that [T]B1B1= [I]B2B1. Hint: Compare the arrays column by column. Bonita Industries produces a product that requires 2.60 pounds of materials per unit. The allowance for waste and spoilage per unit is 0.30 pounds and 0.10 pounds, respectively. 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Fill in the following blanks - just type the numbers with no decimal values without labels, dollar signs, commas, etc.Seller paid = [Blank#3]Seller profit = [Blank#4]BLANK 1:BLANK 2:BLANK 3:BLANK 4: Sketch the low and high-frequency behavior (and explain the difference) of an MOS capacitor with a high-k gate dielectric (epsilon_r = 25) on an p-type semiconductor (epsilon_r = 10, ni = 1013 cm^-3). Mark off the accumulation, depletion, inversion regions, and the approximate location of the flat band and threshold voltages. If the high-frequency capacitance is 250 nF/cm^2 in accumulation and 50 nF/cm^2 in inversion, calculate the dielectric thickness and the depletion width in inversion. Question 5 Bikes Ltd. offers customers a loyalty card whereby customers receive a stamp every time they have their bike tuned up. Upon presentation of 5 stamps, customers are entitled to receive a bike light for $5. It is expected that 75% of the stamps will be redeemed. Tune-ups cost $20 and retail for $50 each; lights cost $10 and retail for $25. 1,000 lights have been purchased as prizes. In 20X9, 6,000 tune-ups were completed and 750 lights given out. Bikes uses the residual value method to allocate the transaction price to performance obligations. Required: (a) Assume Bikes Ltd. is a public company using IFRS. Calculate the following balances at Bikes year- ended December 31, 20X9: total revenue, premium expense, premium inventory, and unearned revenue. Clearly indicate whether each balance is a debit or credit. (b) Assume Bikes Ltd. is a private company using ASPE. Calculate the following balances at Bikes year-ended December 31, 20X9: total revenue, premium expense, premium inventory, and estimated liability for premiums. Clearly indicate whether each balance is a debit or credit. PLEASEEE ANSWER allSolve various time value of money scenarios. (Click the icon to view the scenarios.) (Click the icon to view the present value of $1 table.) (Click the icon to view the future value of $1 table.) (Cli what was the scientific name of the system that allowed more people computer access to a mainframe? A uniform solid sphere has a moment of inertia I about an axis tangent to its surface. What is the moment of inertia of this sphere about an axis through its center? (the moment of inertia of a solid sphere of mass M and radius R with an axis of rotation through its center is 2/5mr^2. The base of S is the region enclosed by the parabola y=1-x and the x-axis. Cross-sections perpendicular to the y-axis are squares.