Predict the sign of the entropy change, ΔS∘, for each of the reaction displayed.
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Ag+(aq)+Cl-(aq)→AgCl(s)
2KCIO3(s)+2KCI(s)+302(g)
2N2O(g) 2N2(g)+02(g)
2Mg(s)+O2(g)→2MgO(s)
C7H16(g)+1102(g)→7CO2(g)+8H2O(g)
H2O(1)→H2O(g)
Positive
Negative

Answers

Answer 1

The given reaction involves the evaporation of water. When water is heated, it evaporates into steam. The randomness and disorder increases as a result of the reaction. Therefore, the sign of reaction ΔS∘ is positive.

Entropy change, ΔS∘ is the difference between the entropy of the products and the entropy of the reactants. The entropy change, ΔS∘, for the given reactions can be predicted as follows:

Ag+(aq)+Cl-(aq)→AgCl(s):

The given reaction involves two aqueous ions forming a precipitate. Hence, the randomness and disorder decreases as a result of the reaction. Therefore, the sign of ΔS∘ is negative.

2KCIO3(s)+2KCI(s)+302(g):

The given reaction involves solid, aqueous, and gaseous states of matter. When potassium chlorate is heated, it decomposes into potassium chloride and oxygen gas. The randomness and disorder increases as a result of the reaction. Therefore, the sign of ΔS∘ is positive.

2N2O(g) 2N2(g)+02(g):

The given reaction involves two gases combining to form another gas. The randomness and disorder decreases as a result of the reaction. Therefore, the sign of ΔS∘ is negative.

2Mg(s)+O2(g)→2MgO(s):

The given reaction involves the reaction between a solid and a gas. When magnesium reacts with oxygen gas, magnesium oxide is formed. The randomness and disorder decreases as a result of the reaction. Therefore, the sign of ΔS∘ is negative.

C7H16(g)+1102(g)→7CO2(g)+8H2O(g):

The given reaction involves the combustion of heptane. When heptane burns, carbon dioxide and water are formed. The randomness and disorder increases as a result of the reaction. Therefore, the sign of ΔS∘ is positive.

H2O(1)→H2O(g):

The given reaction involves the evaporation of water. When water is heated, it evaporates into steam. The randomness and disorder increases as a result of the reaction. Therefore, the sign of ΔS∘ is positive.

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Related Questions

When the molecules in a gas lose energy the gas will turn into a liquid.


A. True
B. False

Answers

Answer:

true

Explanation:

Answer:

true

Explanation:

when the temperature of the gas is decreased or pressure on the gas is increased, the gas becomes liquid at a certain temperature or pressure.

When CuCl2 reacts with NaNO3, copper (II) nitrate and sodium chloride are formed.
a) Write the balanced equation for the reaction given above:
CuCl2 + NaNO3 à Cu(NO3)2 + NaCl

Answers

Answer:

CuCl2 + 2NaNO3 -------> Cu(NO3)2 + 2NaCl

hope this helps

good day mate

In addition to showing the ratio of atoms in a molecule, what else do the subscripts in a formula tell us?​

Answers

Answer:

See explanation

Explanation:

Usually, when we write a chemical formula for any compound or other chemical specie, we use subscripts to;

Indicate the ratio of atoms of each element present in the compound or chemical specieShow the number of atoms of each element present in the compound or chemical specie.

Hence, the subscripts written after chemical formulas have more than one function as described above.

In H2SO4 for instance, there are two hydrogen atoms, one sulphur atom and four oxygen atoms as shown in the chemical formula.

How many moles are 2.20 x 10^25 atoms of zinc?
Please answer quick will give Brainliest!

Answers

Answer:

1.3244 x 10⁴⁹ atoms of zinc

Explanation:

2.20 x 10²⁵ moles

To convert from moles to atoms, we multiply by Avogadro's Number, 6.02 x 10²³

2.20 x 10²⁵ • 6.02 x 10²³

= 1.3244 x 10⁴⁹ atoms of zinc

Hope this helps!

Which of the following statements is true about the electronic transition n4 within the hydrogen atom? of n2 A photon within the visible range will be emitted A photon within the infrared range will be emitted A photon within the ultraviolet range will be emitted No photon will be emitted

Answers

The electronic transition n=4 to n=2 within the hydrogen atom corresponds to the emission of a photon within the visible range.

The electronic transitions in hydrogen atoms involve the movement of an electron from one energy level (n) to another. The energy of the emitted photon is given by the difference in energy between the initial and final energy levels.

In this case, the transition n=4 to n=2 corresponds to an electron moving from the fourth energy level to the second energy level. This transition results in the emission of a photon. The energy of the emitted photon is equal to the energy difference between these two levels.

The energy of a photon is directly related to its wavelength. Photons with higher energy have shorter wavelengths, and photons with lower energy have longer wavelengths. The visible range of light is characterized by photons with wavelengths between approximately 400 to 700 nanometers.

Since the n=4 to n=2 transition corresponds to the emission of a photon, and the visible range falls within this energy range, the correct statement is that a photon within the visible range will be emitted during this electronic transition.

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predict the charge on the predominant species of the peptide e−d−k−r−a−s−t at ph 5.0 .

Answers

At pH 5.0, the predominant species of the peptide E-D-K-R-A-S-T has a net positive charge of +2.

To predict the charge on the predominant species of the peptide E-D-K-R-A-S-T at pH 5.0, we need to consider the pKa values of the amino acids involved and the pH of the solution. The pKa values represent the acidity or basicity of the functional groups present in the amino acids.

1. At pH 5.0, the carboxyl group of glutamic acid (E) and aspartic acid (D) will be protonated, resulting in a positive charge on these amino acids. So, E and D will have a positive charge.

2. Lysine (K), arginine (R), histidine (H), and the N-terminus of the peptide have amino groups that can act as bases. At pH 5.0, these amino groups will be protonated, resulting in a positive charge on K, R, H, and the N-terminus.

3. Threonine (T), serine (S), and the C-terminus of the peptide do not have ionizable groups at pH 5.0 and will remain uncharged.

Therefore, at pH 5.0, the predominant species of the peptide E-D-K-R-A-S-T will have a net positive charge due to the protonation of E, D, K, R, H, and the N-terminus. The charge can be represented as follows:

E-D-K-R-A-S-T (at pH 5.0): 2+

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how can we find out the mass of the marble

Answers

In a collection of marbles, 25% of the marbles have a mass of 5.00 g and 75% of the marbles have a mass of 7.00 g. The average mass of a marble is 6.50 g.

if the isentropic efficiency of the turbine is 80%, calculate the actual work output of the turbine, in kj/kg.

Answers

The required actual work output of the turbine is 1.2 Mj/kg.

If the isentropic efficiency of the turbine is 80%, calculate the actual work output of the turbine, in kj/kg.A steam turbine receives steam at a particular pressure and temperature and discharges it at a lower pressure and temperature. In general, the steam turbine's work output is less than the maximum possible work output, which is known as the isentropic turbine work output. The ratio of the actual turbine work output to the isentropic turbine work output is known as the isentropic turbine efficiency.ηt = Wtisentropic/WtactualWhere,ηt = isentropic turbine efficiencyWtisentropic = isentropic turbine work outputWtactual = actual turbine work outputGiven, isentropic efficiency of the turbine is 80%.ηt = 80% or ηt = 0.8We know thatWtactual = ηt x Wtisentropicor Wtisentropic = Wtactual/ ηtWe also know thath1 = 3.6 Mj/kgh2 = 2.1 Mj/kghence,Δh = h1 - h2 = 3.6 - 2.1 = 1.5 Mj/kgNow we have, Wtisentropic = Δh = 1.5 Mj/kgWtactual = ηt x Wtisentropic = 0.8 x 1.5= 1.2 Mj/kgTherefore, the actual work output of the turbine is 1.2 Mj/kg.

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9. Which of the following would increase the
validity of Experiment 2?
A. Testing magnets with a volume less
than 0.04
B. Testing magnets made of iron instead
of ceramic
C. Testing generators with larger
vibrations
D. Testing a generator with coils fewer
than 2050
.

Answers

I think the answer is C.

A rod, X has a positive charge of 8. An otherwise identical rod, Y has a negative charge of 4. The rods are touched together, and then separated.


1.When they touch, what particles move between them?

2.Did the particles move from "X" or "Y" or from "Y" to "X"?

Answers

Answer:

1.  electrons

2. From "Y" to "X"

Explanation:

1. Electrons move between the rod since the electrons are the only charge carriers which are free to move.

2. The particles move from from "Y" to "X"  since the electrons are the only charge carriers which are free to move. The positive charge on rod x is due to a deficit of electrons while the negative charge on rod Y is due to the excess of electrons. When the rods come together, the electrons move from "Y" to "X" since the electrons are the only charge carriers which are free to move.

How are white blood cells linked to the lymphatic system?

Answers

Answer:

The lymphatic system produces white blood cells, known as lymphocytes. There are two types of lymphocyte, T cells and B cells. They both travel through the lymphatic system. As they reach the lymph nodes, they are filtered and become activated by contact with viruses, bacteria, foreign particles, and so on in the lymph fluid.

Explanation:

Which one of the following systems has the highest entropy?
10 mL of water at 100°C
10 mL of water at 50°C
10 mL of water at 10°C

Answers

Answer: a

Explanation:

The highest entropy will be 0 mL of water at 100°C.

What is entropy?

Entropy is just a measured physical quality that will be most usually linked with disorder, unpredictability, or uncertainty.

The quantity of random movement in a system increases as more energy is put into it. Entropy rises like a volume increases in a system.

Therefore, the correct answer will be option 1.

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How many molecules are in
6.0 moles of methane (CH4)?

Let's begin by setting up our equation.

What belongs in the green box?

6.0 moles CHA

A. 1 mole CH4
B. 6.02 x 1023 molecules CH4

Answers

It’s B
Because 6.02

a) Water has a molar mass of 18 g/mol and a density of 1000 kg/m3 (or 1 g/cm3). Based on this data, estimate the number of water molecules per unit surface area of water.
b) The coordination number of water (i.e., the average number of "neighbors" each water molecule has) in the liquid state is 4. Neighboring water molecules attract each other via hydrogen bonds, each of which has a binding energy of roughly 10–20 J (although this number depends relatively strongly on temperature). Use this information to estimate the surface tension of water. How does your estimate compare to the observed figure (
γ water = 0.072 N/m ) (hints: Keep in mind that we can think of
surface tension as surface energy per unit area, and consider the energy needed to bring a molecule from the bulk to the surface)?

Answers

The estimate is still useful because it provides insight into the behavior of water molecules at the surface of the liquid.

Molar mass of water, M = 18g/molDensity of water, ρ = 1g/cm³ = 1000kg/m³The number of molecules per unit surface area of water can be estimated as follows:Number of water molecules per unit volume of water = Avogadro's number, NA / MNumber of water molecules per unit volume of water = 6.022 × 10²³ / 18 = 3.345 × 10²² / molThe number of molecules per unit surface area of water = the number of molecules per unit volume of water × the thickness of the water layer on the surface= 3.345 × 10²² / m³ × 1 × 10⁻⁸ m= 3.345 × 10¹⁴ / m²b)Given:Coordination number of water, CN = 4Binding energy of hydrogen bond, E = 10⁻²⁰ JThe surface tension of water, γ water = 0.072 N/mEnergy required to bring one molecule from the bulk of the liquid to the surface of the liquid, ΔE= γ water × AThe total binding energy of a water molecule in the liquid state = the binding energy of one hydrogen bond × the coordination number= 10⁻²⁰ J/bond × 4 bonds = 4 × 10⁻²⁰ JThe number of molecules per unit surface area of water = the energy required to bring one molecule from the bulk of the liquid to the surface of the liquid / the total binding energy of a water molecule in the liquid state= ΔE / 4 × 10⁻²⁰= 0.072 / (4 × 10⁻²⁰)= 1.8 × 10²⁰The surface tension of water can also be expressed as follows:γ water = (N / A) × EThe number of hydrogen bonds per unit area, N / A = γ water / E= 0.072 / 10⁻²⁰ = 7.2 × 10¹⁸ / m²The difference between the estimated value and the observed value is relatively large (about a factor of 25). It is because this is just an estimate, and it does not consider all the factors affecting the surface tension of water. However, the estimate is still useful because it provides insight into the behavior of water molecules at the surface of the liquid.

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Answer it right for a brainliest

Answers

Answer:

plz I. need a brainliest

Explanation:

I hope you have a good day

Barney was a dinosaur from our imagination.....

write the chemical equation for the reaction of monohydrogen phosphate ion, hpo42− , with water.

Answers

The chemical equation for the reaction of the monohydrogen phosphate ion (HPO₄²⁻) with water (H₂O) is: HPO₄²⁻ + H₂O → H₂PO₄⁻ + OH⁻

In this reaction, the monohydrogen phosphate ion reacts with water to form dihydrogen phosphate (H₂PO₄⁻) and hydroxide ion (OH⁻). The monohydrogen phosphate ion donates a proton (H⁺) to a water molecule, resulting in the formation of the dihydrogen phosphate ion.

Simultaneously, the water molecule accepts the proton, leading to the production of the hydroxide ion. This reaction can occur because the monohydrogen phosphate ion is amphoteric, meaning it can act as both an acid and a base.

The resulting products, dihydrogen phosphate and hydroxide ions, contribute to the pH and ionic balance in aqueous solutions.

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the energy transformation that occurs when a firework goes off is a chemical to thermal to light and sound. however, some of the energy is destroyed during the explosion

Answers

Answer:

false

Explanation:

energy can't be destroyed

Gerald's science teacher mixed liquid X and liquid Y, both at room-temperature, in a large beaker. two beakers of clear solutions to the left of a right-pointed arrow, and a large beaker with a clear solution to the right of the arrow The mixture in the large beaker still looked clear like water, but when the students, one at a time, carefully touched the outside of the large beaker, it felt warm to the touch. Why did the large beaker most likely feel warm? A. The two liquids were not soluble in water. B. The release of a gas heated the solution. C. A chemical reaction produced a new substance. D. The energy of mixing warmed the liquids.

Answers

Answer:

c

Explanation:

A chemical reaction produced a new substance. In a chemical reaction, the atoms that make up the reactants are rearranged to produce various products.

What is chemical reaction?

chemical reaction, the transformation of one or more chemicals (the reactants) into one or more distinct compounds (the products). Chemical elements or chemical compounds make up substances.

A chemical reaction is one in which  two or more reactants will react to form a new substance. When new substance will form it will produce heat. Therefore, when science teacher was mixing two liquids it was generating heat.

Heating a substance allow molecules to move faster. When heat is given to the object it will move fast. When heat will apply to a solid it will turn into liquid. When heat is supplied to the liquid it will turn into gas.

Therefore, A chemical reaction produced a new substance. In a chemical reaction, the atoms that make up the reactants are rearranged to produce various products.

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Madison is heating two different liquids. For each liquid, she wants to compare the temperatures at which gas bubbles form, rise, and begin to escape. What physical property is Madison using to compare the liquids?Immersive Reader boiling point conductivity melting point solubility

Answers

Answer:

I think its boiling point conductivity

Answer: boiling point

Explanation:

Got it right

How many molecules are there in 24 grams of HSO₃?

Answers

1.2×1023 molecules
That should be you’re answer. Have a good day ☺️

What mass of iron (ciron= 0.11 cal/g°C) would need 1450 cal of energy in order to raise its temperature by 19.7°C

Answers

Answer: m=Q/c*\Delta TQ/c∗ΔT = 1450cal/(0.11cal/g* 19.7ºC)=669.12 g1450cal/(0.11cal/g∗19.7ºC)=669.12g

Answer: 669.12g iron.

Explanation:

Are water waves transverse or longitudinal? How do you know? Own words please. No files or links either.

Answers

Answer:

Transverse waves are known by motion being perpendicular to the waves movements. Longitudinal waves move in a direction parallel to the way the wave moves. Water waves are an example of both as they move in a clockwise motion.

Explanation:

( Sorry if it is not the best answer but I did my best by researching )

Balance the equation :
CoBr3 + CaSO4

please define how many atoms each element contain

Answers

Answer:

im not 2100][dskcmaln,NMCS KHJBXsjk[pl,;maxkcjxnxxxxxxxxxxxxxas'j

Explanation:

mnkc

the form of energy that your lunch represents is?
A) electrical
B) chemical
C) thermal
D) nuclear

Answers

The answer is B. Have a good day.

H,(8) + 1,65) - HI(g) (H = 26 kJ/mol.. Hg) + 44 1,(g) HI(g) AH=-5.0 kJ/mol... Based on the information above, what is the enthalpy change for the sublimation of iodine, represented below? 1 (s) 1,08) A. 15 kJ/mol... B 21 kJ/mol. C. 31 kJ/mol.D. 42 kJ/mol, E. 62 kJ/mol.

Answers

The enthalpy change for the sublimation of iodine I₂(s) → I₂(g) is 62 kJ/mol.

The correct answer is E: 62 kJ/mol

What is the enthalpy change for the sublimation of iodine?

The enthalpy change for the sublimation of iodine (I₂) is determined using Hess's Law which states that the total enthalpy change of a reaction is independent of the pathway taken.

Given the two equations:

½ H₂(g) + ½ I₂(s) → HI(g) ΔH = 26 kJ/mol  ---- (1)

½ H₂(g) + ½ I₂(g) → HI(g) ΔH = -5.0 kJ/mol ---- (2)

The equation of the sublimation of iodine is given below as follows:

I₂(s) → I₂(g)

Subtracting equation 2 from equation 1 to eliminate HI (g) gives the equation of the sublimation of iodine:

[½ H₂(g) + ½ I₂(s) → HI(g)] - [½ H₂(g) + ½ I₂(g) → HI(g)] = 26 kJ/mol - (-5.0 kJ/mol)

Simplifying:

½ I₂(s) → ½ I₂(g) ΔH = 31 kJ/mol

Multiplying the equation above by 2 gives the equation of the sublimation of iodine

I₂(s) → I₂(g) = 62 kJ/mol

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determine the molar mass of water. WRITE THE UNITS​

Answers

You can use the periodic table.
H2O = Water
Two hydrogen
One oxygen
I don’t know if your numbers are rounded but if you look at your periodic table, you will see a number close to 1.008 for hydrogen and a number close to 15.999 for oxygen. You can multiple the number for hydrogen twice and add 15.999. You should get a number close to 18.015 g/mol.

If you initially have a gas with a pressure of 0.950 atm and a temperature of 35 °C and you heat it to 65 °C, what is the new pressure if volume and moles are held constant? (P2 = 1.04 atm)

Answers

Explanation:

fgIf the piston moves so as to increase the pressure of the gas to 2.94 atm, ... new volume of the cylinder? ... A gas has a pressure of 699.0 mm Hg at 40.0°C. What is the temperature (in C) ...

How is meiosis different from mitosis

Answers

Answer:

A - meiosis results in two genetically identical offspring cell

Explanation:

Mitosis produces two diploid (2n) somatic cells that are genetically identical to each other and the original parent cell, whereas meiosis produces four haploid (n) gametes that are genetically unique from each other and the original parent (germ) cell.

Answer:

The answer is C

Explanation:

I took the test on AP3X

for a particular redox reaction, mno2 is oxidized to mno−4 and ag is reduced to ag . complete and balance the equation for this reaction in basic solution.

Answers

The given redox reaction can be represented in the following way: MnO₂ → MnO⁴⁻ + Ag → Ag+

To balance the redox reaction, the following steps are to be followed:

1: First, balance the net ionic equation with the help of half-reactions:

MnO2 → MnO⁴⁻+ e- [Oxidation Half-Reaction]

Ag+ + e- → Ag [Reduction Half-Reaction]

2: Determine the number of electrons that are required to balance the half-reactions. The oxidation half-reaction requires five electrons.

MnO₂ → MnO⁴⁻+ 5e-

The reduction half-reaction requires one electron.

Ag+ + e- → Ag

3: Find the least common multiple of the electrons required in the half-reactions, and use it to balance the equation. The least common multiple of 5 and 1 is 5. To balance the equation, multiply the oxidation half-reaction by 1 and the reduction half-reaction by 5. This will give us the following balanced equation:

5MnO₂ + 16H₂O + Ag → 5MnO⁴⁻ + 8OH- + 4Ag+

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In the following reaction, the partial
pressure at equilibrium for each of the
products, CO and water vapor at 990°
C, is 11.0 atm and the partial pressure
for each of the reactants, H2 and CO2,
at equilibrium is 8.70 atm. What is Kp?
H2(g) + CO2(g) + H2O(g) + CO(g)
Kp = [?]

Answers

Answer:

H2+CO2=H2O+CO

Kp=(pCO)(pH2O)/(pH2)(pCO2)

= 11×11/8.70×8.70

=1.60

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