simple random sample of size n-35 is obtained. Complete parts a through e below. B Click here to view the t-Distribution Area in Right Tail (a) Does the population have to be normaly distributed totest this hypothesis? Why? OA. Yes, because n230. O B. No, because n2 30 C. Yes, because the sample is random. D. No, because the test is two-tailed. (b) If x 101.9 and s 5.7, compute the test statistic. The test statistic is to(Round to two decimal places as needed.) (c) Draw a t-distribution with the area that represents the P-value shaded. Choose the correct graph below. Ов. Ос.

Answer:

200

Step-by-step explanation:

15% is 0.15

0.15x = 30

x = 30/0.15 = 200

The inverse Laplace transform of F(s) = (s + 3)² (s + 5) is given by L⁻¹{F} = 1/2 * e^(-3t) - t * e^(-3t) + 1/2 * e^(-5t).

To determine the inverse Laplace transform of F(s) = (s + 3)² (s + 5), we can use the properties and formulas of Laplace transforms.

The inverse Laplace transform of F(s) can be obtained by applying partial fraction decomposition, followed by looking up the corresponding inverse Laplace transform in a table of Laplace transforms.

Let's first factorize F(s):

F(s) = (s + 3)² (s + 5)

Next, we perform partial fraction decomposition. We express F(s) as the sum of simpler fractions:

F(s) = A/(s + 3) + B/(s + 3)² + C/(s + 5)

To find the values of A, B, and C, we can equate the numerator of F(s) with the sum of the numerators in the partial fraction decomposition:

(s + 3)² (s + 5) = A(s + 3)(s + 5) + B(s + 5) + C(s + 3)²

Expanding the equations and collecting like terms, we get:

s² + 8s + 15 = (A + C)s² + (8A + 3C + B)s + (15A + 5B)

Equating the coefficients of the terms on both sides, we have the following system of equations:

A + C = 1

8A + 3C + B = 8

15A + 5B = 15

Solving this system of equations, we find A = 1/2, B = -1/2, and C = 1/2.

Now, we can rewrite F(s) in terms of the partial fractions:

F(s) = 1/2/(s + 3) + (-1/2)/(s + 3)² + 1/2/(s + 5)

Looking up the inverse Laplace transform of each term in the table, we find:

L⁻¹{1/2/(s + 3)} = 1/2 * e^(-3t)

L⁻¹{(-1/2)/(s + 3)²} = -t * e^(-3t)

L⁻¹{1/2/(s + 5)} = 1/2 * e^(-5t)

Therefore, the inverse Laplace transform of F(s) is:

L⁻¹{F} = 1/2 * e^(-3t) - t * e^(-3t) + 1/2 * e^(-5t)

This is the desired result for the inverse Laplace transform of F(s).

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Answer: a = -7.68

STEPS:

- Subtract 13.61 from both sides

- Simplify

- Divide both sides by 3

Answer:

I cannot solve it step-by-step because like I'm helping other people cuz I'm busy with my homework so just I'm going to direct you the question you're supposed to solve simultaneous equation by any method example elimination method substitution method then you get the answer if you get stuck you can inform me

The component of the displacement vector are: Horizontal component = -75 m Vertical component = 129.9 m (approx)

Given that the superhero flew 150 m at an angle of 120° with respect to the positive x-axis. We need to find the components of displacement vector.

Let's consider the given figure: Here, AB represents the displacement vector. AC represents the horizontal component of displacement vector and BC represents the vertical component of displacement vector.

The horizontal component can be calculated as: AC = AB cos θ

Here, θ = 120° and AB = 150 mAC = 150 cos 120°AC = -75 m (Negative sign indicates that the displacement is in the negative direction of the x-axis)

The vertical component can be calculated as: BC = AB sin θHere, θ = 120° and AB = 150 mBC = 150 sin 120°BC = 129.9 m (Approx)

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Given information: A superhero flew 150 m at a 120-degree angle with respect to the positive x-axis. The x-component of the displacement vector is 75 m and the y-component of the displacement vector is 129.9 m.

Components of displacement vector: The component of displacement vector with respect to the x-axis is called the x-component of displacement vector.

Similarly, the component of displacement vector with respect to the y-axis is called the y-component of displacement vector.

As per the given information, the angle of displacement vector is 120 degrees with respect to the positive x-axis.

So, the angle of the vector with respect to the negative x-axis is 180 - 120 = 60 degrees (supplementary angles).

Now, the horizontal component (x-component) of the vector is given by the product of the magnitude and the cosine of the angle with respect to the x-axis.

Let the x-component of displacement vector be x.

Then, x = 150 cos 60°

x = 75 m.

The vertical component (y-component) of the vector is given by the product of the magnitude and the sine of the angle with respect to the x-axis.

Let the y-component of displacement vector be y.

Then, y = 150 sin 60°

y = 129.9 m.

Therefore, the x-component of the displacement vector is 75 m and the y-component of the displacement vector is 129.9 m.

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To find the value of the constant k, we need to integrate the probability density function (PDF) over its entire range and set it equal to 1, since the total area under the PDF should be 1.

(a) Calculating the value of the constant K:

∫[from -1 to 1] kx² dx = 1

Integrating, we get:

(k/3) [x³] from -1 to 1 = 1

(k/3)(1³ - (-1)³) = 1

(k/3)(1 + 1) = 1

(2k/3) = 1

2k = 3

k = 3/2

Therefore, the value of the constant k is 3/2.

(b) Calculating the mean and variance of X:

To find the mean (μ), we need to calculate the expected value of X. Since the PDF is symmetric around x = 0, the mean will be 0.

μ = 0

To find the variance (σ²), we need to calculate the second moment of X around its mean.

σ² = ∫[from -1 to 1] x² * f(x) dx

Substituting the PDF f(x) = (3/2)x²:

σ² = ∫[from -1 to 1] x² * (3/2)x² dx

σ² = (3/2) ∫[from -1 to 1] x^4 dx

σ² = (3/2) * (1/5) [x^5] from -1 to 1

σ² = (3/2) * (1/5) * (1^5 - (-1)^5)

σ² = (3/2) * (1/5) * (1 - (-1))

σ² = (3/2) * (1/5) * 2

σ² = 3/5

Therefore, the mean of X is 0, and the variance is 3/5.

(c) The cumulative distribution function (CDF) of X is found by integrating the PDF from negative infinity to x:

F(x) = ∫[from -∞ to x] f(t) dt

For the given PDF f(x) = (3/2)x², the cumulative distribution function can be calculated as follows:

F(x) = ∫[from -∞ to x] (3/2)t² dt

F(x) = (3/2) ∫[from -∞ to x] t² dt

F(x) = (3/2) * (1/3) [t³] from -∞ to x

F(x) = (1/2) x³

Therefore, the cumulative distribution function (CDF) of X is F(x) = (1/2) x³.

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Answer:

143 ft2

Step-by-step explanation:

Formula for parrallelogram: A= BxH

13x11= 143

The margin of error for a 97% confidence interval for (p1 - p2) is 0.159.

To find the margin of error (E) for a 97% confidence interval for (p1 - p2), we can use the following formula:

E = Z * sqrt((p1 * (1 - p1) / n1) + (p2 * (1 - p2) / n2))

Where:

Z is the z-score corresponding to the desired confidence level. For a 97% confidence level, the z-score is approximately 2.170.

p1 and p2 are the sample proportions for populations 1 and 2, respectively.

n1 and n2 are the sample sizes for populations 1 and 2, respectively.

To calculate p1 and p2, we divide the sample counts (x1 and x2) by their respective sample sizes (n1 and n2).

p1 = x1 / n1 = 62 / 108 ≈ 0.574

p2 = x2 / n2 = 235 / 723 ≈ 0.325

Substituting the values into the formula, we have:

E = 2.170 * sqrt((0.574 * (1 - 0.574) / 108) + (0.325 * (1 - 0.325) / 723))

Calculating this expression, we find:

E ≈ 2.170 * sqrt(0.004957 + 0.000443)

≈ 2.170 * sqrt(0.005400)

≈ 2.170 * 0.073486

≈ 0.159

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The probability that the event E does not happen is:

P(not E) = 0.61

First, remember that for any experiment with N outcomes, the sum of the N probabilities for these outcomes must be 1.

Then if we have two outcomes, E happens or E does not happen, we have:

P(E) + P(not E) = 1

Replace the value that we know:

0.39 + p(not E) = 1

Solve for the probability we want:

P(not E) = 1 - 0.39

P(not E) = 0.61

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Answer:

answer is y = 3/4x - 5

Step-by-step explanation:

picture below.

The 3/4 comes from the line. You would use rise over run to find the slope, which in this case is 3/4. and the -5 is basically the y-intercept

The required answer is The literature review should be completed before developing a research hypothesis or research questions for a quantitative study.

Explanation :

The role of literature review in the qualitative study.To examine the problem of attrition from an online doctoral program in a qualitative study, a literature review is essential to identifying the theoretical frameworks and practices for reducing attrition. Researchers need to review the current theories on student retention, persistence, and attrition to examine the factors contributing to these trends.

By reviewing related literature, researchers gain insight into how student attrition is approached in existing literature. Additionally, literature review helps in developing the research problem and objectives, identifying gaps in the current literature that the study can fill. This provides a solid foundation for conducting qualitative research and enables the researcher to identify the gaps and the direction the study should take.

When should you complete a literature review for a quantitative study?For a quantitative study of the factors that predict attrition from a doctoral program, a literature review should be completed before determining your research hypothesis or research questions.

A literature review is essential as it helps researchers to identify the current literature, theories, and research studies conducted in the area of attrition in doctoral programs.

By conducting a literature review, the researcher can identify gaps, inconsistencies, and areas that require more attention. This allows researchers to develop an appropriate research design, research questions, and hypotheses that address the identified gaps in the literature.

Thus, the literature review should be completed before developing a research hypothesis or research questions for a quantitative study.

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Joanne's plan pays $2400 for her July losses, as she is responsible for 20% of the covered expenses during that month.

Joanne's health insurance plan with a $1000 deductible, 80% coinsurance, and a $5000 out-of-pocket cap requires her to pay for her medical expenses until she reaches the deductible.

After reaching the deductible, she is responsible for 20% of the covered expenses, up to the out-of-pocket cap. The plan pays the remaining percentage of covered expenses.

To calculate how much the plan pays for Joanne's July losses, we need to consider her deductible, coinsurance, and out-of-pocket cap.

In March, Joanne incurs $1000 in covered medical expenses.

Since this amount is equal to her deductible, she is responsible for paying the full amount out of pocket.

In July, Joanne incurs $3000 in covered expenses. Since she has already met her deductible, the coinsurance comes into play.

According to the plan's coinsurance rate of 80%,

Joanne is responsible for 20% of the covered expenses.

Therefore, Joanne is responsible for paying 20% of $3000, which is $600.

The plan will pay the remaining 80% of the covered expenses, which is $2400.

In December, Joanne incurs $30,000 in covered expenses. Since she has already met her deductible and reached her out-of-pocket cap, the plan pays 100% of the covered expenses.

Therefore, the plan will pay the full $30,000 for her December losses.

To summarize, Joanne's plan pays $2400 for her July losses, as she is responsible for 20% of the covered expenses during that month.

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In the first question, based on the given regression equation, if a student spends 5 hours studying for a test, the predicted test score would be 50 + 7(5) = 85.

In the second question, the information provided is unclear and incomplete. The given text appears to contain multiple unrelated statements and lacks sufficient context or specific details to answer the question regarding the critical value for hypothesis testing.

1. For the first question, the regression equation is given as y = 50 + 7x, where y represents the test score and x represents the number of hours studied. To find the test score when a student spends 5 hours studying, we substitute x = 5 into the equation: y = 50 + 7(5) = 85.

2. However, the second question is unclear and does not provide sufficient information or context to determine the intended calculation or answer. It mentions something about applicant interviews, regression output, and ANOVA, but the information is not well-defined or organized. Without specific details and clear instructions, it is not possible to provide a meaningful response.

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Answer:

A.) The base is 5 and the exponent is 3

B.) The base is 4 the exponent is 7

C.) The base is 3 the exponent is 4

D.) The base is 6 the exponent is 8

Step-by-step explanation:

1. The population is increasing for 0 < P < 4100. The answer in interval notation is (0, 4100).

2. The population is decreasing for P > 4100. The answer in interval notation is (4100, ∞).

3. The equilibrium solutions are P = 0 and P = 4100.

To determine when the population is increasing or decreasing, we need to examine the sign of the derivative dP/dt.

1. For what values of P is the population increasing?

The population is increasing when dP/dt > 0.

In this case, we have dP/dt = 1.1P(1 - P/4100).

To find the values of P for which the population is increasing, we need to solve the inequality 1.1P(1 - P/4100) > 0.

To do this, we can consider the sign of each factor:

1.1 is positive.

P is the variable.

(1 - P/4100) is positive when P < 4100 and negative when P > 4100.

From this, we can determine the intervals where the population is increasing:

When P < 0 (since P cannot be negative in a population context), the term 1.1P is negative, so the entire expression is negative. The population is not increasing in this interval.

When 0 < P < 4100, both 1.1P and (1 - P/4100) are positive, so the entire expression is positive. The population is increasing in this interval.

When P > 4100, 1.1P is positive, but (1 - P/4100) is negative. The entire expression is negative. The population is not increasing in this interval.

Therefore, the population is increasing for 0 < P < 4100. The answer in interval notation is (0, 4100).

2. For what values of P is the population decreasing?

The population is decreasing when dP/dt < 0.

In this case, we have dP/dt = 1.1P(1 - P/4100).

To find the values of P for which the population is decreasing, we need to solve the inequality 1.1P(1 - P/4100) < 0.

Using the same analysis as in the previous part, we can determine the intervals where the population is decreasing:

When P < 0, the population is not decreasing.

When 0 < P < 4100, the population is not decreasing.

When P > 4100, the population is decreasing.

Therefore, the population is decreasing for P > 4100. The answer in interval notation is (4100, ∞).

3. What are the equilibrium solutions?

Equilibrium solutions occur when the population remains constant, meaning dP/dt = 0.

In this case, we have dP/dt = 1.1P(1 - P/4100)

                                             = 0.

To find the equilibrium solutions, we solve the equation 1.1P(1 - P/4100) = 0.

This equation is satisfied when either 1.1P = 0 or (1 - P/4100) = 0.

From 1.1P = 0, we have P = 0.

From (1 - P/4100) = 0, we have P = 4100.

Therefore, the equilibrium solutions are P = 0 and P = 4100.

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Answer:

m = 3/4

Step-by-step explanation:

slope of a line equation:

[tex]m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

m = (3-0)/(2-(-2))

m = 3/4

Answer:

x does not equal - 49.

x = 49

Step-by-step explanation:

To find the square you multiply the square root.

- 7 × - 7 = 49

x ≠ - 49

x = 49

Answer:

volume in cubic centimeters = 30 cm³

Step-by-step explanation:

Ratio of mass to volume = 27 g : 10 cm³

what is the volume in cubic centimeters of the sample of metal if mass = 81 g

Let

volume in cubic centimeters = v

Ratio of mass to volume = 81 g : v

Equate both ratios

27 g : 10 cm³ = 81 g : v

27/10 = 81/v

Cross product

27 * v = 10 * 81

27v = 810

v = 810/27

v = 30 cm³

volume in cubic centimeters = 30 cm³

Both the stores together donated 65.5 dozen cookies.

Answer:

26 cents

Step-by-step explanation:

S0, lets just subtract the 10 by the 9.74 to get our answer:

10-9.74

=

0.26

So, lets remember that there are 100 cents in 1 dollar.

So 1 cent would be: 0.01

Our answer we got above is 0.26

So that must be 26 cents.

Answer:

26

Hope this helps! ;)

Answer:

175

Step-by-step explanation:

140

140/4=35

140+35=175

Answer:

B. Ten less than five times a number is greater than twenty-six.

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form:

n > 36 /5

Interval Notation:

( 36 /5 , ∞ )

Answer:

a)b=4

b)x=-9

c)r=6

Step-by-step explanation:

Question 2.

a)5b+6=26

5b=26-6

5b=20

b=4

b)6-x=15

-x=15-6

-x=9

x=-9

c)r/2+2=5

r/2=5-2

r/2=3

Multiply both sides by 2 to remain with r

r/2×2=3×2

r=6.

Answer:

2.8 feet

Step-by-step explanation:

tan(29)=x/5

5tan(29)=x

2.8=x

Answer:

5.7

Step-by-step explanation:

Answer:

We can use the formula for the nth term of an arithmetic sequence to find n:

an = a1 + (n - 1)d

Substituting the given values, we get:

52 = 132 + (n - 1)(-4)

Simplifying and solving for n, we get:

n = 21

So, the sequence has 21 terms.

We can use the formula for the sum of the first n terms of an arithmetic sequence to find Sn:

Sn = n/2(2a1 + (n - 1)d)

Substituting the given values, we get:

Sn = 21/2(2(132) + (21 - 1)(-4))

Simplifying, we get:

Sn = 21/2(264 - 80)

Sn = 21/2(184)

Sn = 1932

Therefore, the sum of the first 21 terms of the arithmetic sequence is 1932.

The probability that the events do not occur is 0.6778`.

The probability that the events do not occur is given by `P(Ac)=1-P(A)` and `P(Bc)=1-P(B)`.

The given probabilities are `P(A)=0.2272` and `P(B)=0.4506`.

Using the formula `P(A∪B)=P(A)+P(B)-P(A∩B)`, we have `P(A∩B) = P(A) + P(B) - P(A∪B)`

Using the fact that the two events are mutually exclusive, we get `P(A∩B) = 0`.

Thus, `P(A∪B) = P(A) + P(B) = 0.2272 + 0.4506 = 0.6778`.

The probability that either A or B but not both occurs is given by `P(AΔB) = P(A∪B) - P(A∩B) = 0.6778 - 0 = 0.6778`.

Hence, the required probability is `P(AΔB) = 0.6778`.

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