1) 16
2) -6 -(-17) = -6 +17= 11
3) 19 -(-2) = 19 + 2 = 21
4) -13 + 20 = 7
5) -22
6) -9
7) -19
8) -6
9) -17
10) -20
11) -15 -(-10) = -15 + 10 = -5
12) -1
13) 30
14) 11 -(-9) = 11 + 9 = 20
15) 16
16) -21
1) Which of the following is a measurement of length? *
O the amount of water in a pool
O the height of a building
how many blocks of concrete cover a sidewalk
O the amount of writing space on a page
Name the figure below in two different ways.
Answer:
LDM
MDL
Step-by-step explanation:
The names of a figure are gotten from the points on the figure. The names of the figure are LDM and MDL.
There are three points on the given figure, and these points are: point L, point D and point M, where Point D is between L and M.
This means that, when naming the figure, alphabet D must be at the middle while alphabets M and L can be at either sides of D.
So, the possible names of the figure are: LDM and MDL.
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Proving triangles similar
Answer: AA
Step-by-step explanation:
You can do vertical angles or alternate interior angles. Hope this helps :)
Which graph represents the function f(x)=|x−1|−3 ?
Lawrence got a car loan from a bank, with the car as collateral. What kind of loan did he get?
Answer:
secured loan
Step-by-step explanation:
Answer: Here
Step-by-step explanation:
You Go
In a class of 23 students, 9 play an instrument and 7 play a sport. There are 3
students who play an instrument and also play a sport. What is the
probability that a student does not play an instrument given that they play a
sport?
Answer:
4/7
Step-by-step explanation:
The probability that a student does not play an instrument given that they play a sport is 4/23.
What is probability?It is the chance of an event to occur from a total number of outcomes.
The formula for probability is given as:
Probability = Number of required events / Total number of outcomes.
We have,
Total number of students = 23
From the Venn diagram,
Number of students who play sport but not an instrument = 4
The probability that a student does not play an instrument given that they play a sport.
= 4/23
Thus,
The probability is 4/23.
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A rectangle is 17 inches long and 7 inches wide find the area
Answer:
119
Step-by-step explanation:
A=w 1=7x17=119
find the value of x. round to the nearest tenth if needed.
[tex]6^{2}+8^{2}=x^{2} \\36+64=x^{2} \\100=x^{2} \\x=10[/tex]
Identify the 3D shape shown below. Choose 1 answer: A Cone B Cylinder © Sphere
Answer:
Cylinder
Step-by-step explanation:
A cone is a 3D triangle with a circular base, and a sphere is a 3D circle
Answer:
CYLIDER
Step-by-step explanation:
NO LINKS ONLY ANSWERS (25 POINTS)
Arrange the equations in the correct sequence to rewrite the formula for displacement, d=vt-1/2at^2, to find a. In the formula, d is displacement, v is final velocity, a is acceleration, and t is time.
There is a total of 3 answer slots.
Answers:
d = v(initial)t + 1/2(at^2)
v(final) = √(v(initial)^2 + 2ad)
a = 2(d-v(initial)t) / t^2
t = -v(initial)±√(v(initial)^2 + 2ad) / a
Answer:
1. vt-d=1/2at^2
2. d-vt=1/2at^2
3. a=2(d-vt)/t^2
Step-by-step explanation:
The average value of a function f(x, y, z) over a solid region E is defined to be fave = 1 V(E) E f(x, y, z) dV where V(E) is the volume of E. For instance, if ???? is a density function, then ????ave is the average density of E. Find the average value of the function f(x, y, z) = 3x2z + 3y2z over the region enclosed by the paraboloid z = 4 − x2 − y2 and the plane z = 0.
Answer:
The average function [tex]f_{avg}[/tex] value = 4
Step-by-step explanation:
Given that:
[tex]f(x,y,z) = 3x^2z+3y^2z[/tex]
The enclosed region [tex]z = 4 -x^2 -y^2[/tex] and the plane z = 0.
Over an area E, the average value of a function f(x,y,z) is:
[tex]f_{avg} = \dfrac{1}{V_{E}} \iiint_E f(x,y,z) dV ------ (1)[/tex]
where;
[tex]V_E[/tex] = volume of region E
To find the volume use cylindrical coordinates;
[tex]x=rcos \theta; \ \ \ y = rsin \theta; \ \ \ z = z[/tex]
Then;
E = 0 ≤ r ≤2, 0 ≤ θ ≤ 2π, 0 ≤ z ≤ 4 - r²
[tex]V_E = \int^{2 \pi}_{0} \int^{2}_{0} \int^{4-r^2}_{0} \ rdzdrd \theta[/tex]
[tex]V_E = \int^{2 \pi}_{0} \int^{2}_{0} r(4-r^2) \ drd \theta[/tex]
[tex]V_E = \int^{2 \pi}_{0} \int^{2}_{0} (4r-r^3) \ drd \theta[/tex]
[tex]V_E = \int^{2 \pi}_{0} \Big(2r^2- \dfrac{r^4}{4} \Big)^2_0 \ d \theta[/tex]
[tex]V_E = 4(2 \pi)\\\\ V_E = 8 \pi[/tex]
However, from equation (1):
[tex]f_{avg} = \dfrac{1}{V_E} \iiint_E f(x,y,z) \ dV \\ \\ = \dfrac{1}{8 \pi} \iiint_E (3x^2z + 3y^2 z) dV \\ \\ = \dfrac{1}{8 \pi } \int^{2 \pi}_{0} \int^{2 }_{0} \int^{4 - r^2}_{0} \ \ 3zr^2 \ rdzdrd\theta \\ \\ = \dfrac{3}{8 \pi} \int^{2 \pi}_{0} \int^{2 }_{0} \Big(\dfrac{z^2}{2}\Big)^{4-r^2}_{0} \ r^3 drd\theta \\ \\ = \dfrac{3}{16 \pi} \int^{2 \pi}_{0} \int^{2 }_{0} (4-r^2)^2 \ r^3 \ dr d\theta[/tex]
[tex]= \dfrac{3}{16 \pi} \int^{2 \pi}_{0} \int^{2 }_{0} (16-8r^2 + r^4)r^3 \ dr d\theta \\ \\ = \dfrac{3}{16 \pi} \int^{2 \pi}_{0} \int^{2 }_{0} (16r^3 -8r^5 + r^7) \ dr d \theta \\ \\ = = \dfrac{3}{16 \pi} \int^{2 \pi}_{0} \Big (4r^4 - \dfrac{8}{6}r^6 + \dfrac{r^8}{8} \Big)^2_0 \ d \theta \\ \\ = \dfrac{3}{16 \pi } (2 \pi) \Big (64 - \dfrac{8}{6} \times 64 \times \dfrac{256}{8} \Big) \\ \\ = \dfrac{3}{16 \pi} (2 \pi) (\dfrac{32}{3}) \\ \\ = 4[/tex]
Helppppppp plzzzzzzzzz
Ewan HH
Step-by-step explanation:
Ewanjajsbehudbeiisiejebejehehehheehhehehe
Answer:
???
Step-by-step explanation:
Pls help I’ll pay u 30$ if it’s right
Answer:
8 5 7 1 3 2 4 6
Step-by-step explanation:
my Cashsap kinqcollin
Anyone can help me with questions
Answer:
3x+18+4x+15=180
7x+33=180
7x=147
x=21
solve for x in the equation
Answer:
third option
Step-by-step explanation:
subtract 125/4 from each side to get:
x² + 11x -1
use quadratic formula to get:
-11 ± √121 - 4(-1)/2
= -11 ± ([tex]\sqrt{125}[/tex]) / 2
* [tex]\sqrt{125}[/tex] = [tex]\sqrt{25}[/tex] · [tex]\sqrt{5}[/tex] = 5[tex]\sqrt{5}[/tex]
= -11 ± (5[tex]\sqrt{5}[/tex]) / 2
A pelican has a wingspan of 8 wholes 1/5 feet.
An eagle has a wingspan of 6 wholes 2/3 feet.
How much longer is the wingspan
of a pelican?
Answer:
The wingspan of a pelican is 1 8/15 feet longer than the wingspan of an eagle.
(1 whole 8/15 feet)
Step-by-step explanation:
We'll need to find a common denominator for the fractions. 15 is the lowest number divisible by both 5 and 3, so we'll use 15. For this problem, it's also easier to convert to improper fractions, in my opinion.
Pelican:
8 1/5 = 41/5
41/5 x 3/3 = 123/15
Eagle:
6 2/3 = 20/3
(20/3) x (5/5) = 100/15
Find the difference:
123/15 - 100/15 = 23/15 = 1 8/15
Please let me know if you have questions.
A sample size 25 is picked up at random from a population which is normally
distributed with a mean of 100 and variance of 36. Calculate-
(a) P-{ X<99}
(b) P{98X
Answer:
a) P(X < 99) = 0.2033.
b) P(98 < X < 100) = 0.4525
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Mean of 100 and variance of 36.
This means that [tex]\mu = 100, \sigma = \sqrt{36} = 6[/tex]
Sample of 25:
This means that [tex]n = 25, s = \frac{6}{\sqrt{25}} = 1.2[/tex]
(a) P(X<99)
This is the pvalue of Z when X = 99. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{99 - 100}{1.2}[/tex]
[tex]Z = -0.83[/tex]
[tex]Z = -0.83[/tex] has a pvalue of 0.2033. So
P(X < 99) = 0.2033.
b) P(98 < X < 100)
This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So
X = 100
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{100 - 100}{1.2}[/tex]
[tex]Z = 0[/tex]
[tex]Z = 0[/tex] has a pvalue of 0.5
X = 98
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{98 - 100}{1.2}[/tex]
[tex]Z = -1.67[/tex]
[tex]Z = -1.67[/tex] has a pvalue of 0.0475
0.5 - 0.0475 = 0.4525
So
P(98 < X < 100) = 0.4525
PLS ANSWER QUICK, HELP
Answer:
1014 in
Step-by-step explanation:
(13 x 13) x 6 = 1014 in^3
Answer:
The answer should be A (676)
Step-by-step explanation:
Teresa is a video game designer andher annual income is $134,723. Teresa must pay income tax of 6%. What is the amount of income tax in dollars and cents that Teresa pays
PLEASE HELP EASY 30 POINTS
Answer:
I want her mollah
Step-by-step explanation:
help plzzzz!!!!!!!!!
Answer:
28.27
Step-by-step explanation:
3.14 x 9
is how to do this problem
Help 80 Points BRAINLIEST FOR CORRECT ANSWER!!!!
Answer:
3x+5-7
Step-by-step explanation:
Answer:
If im not mistaken it should be answer 3. Because you would have to divide amongst groups.
A machine that is programmed to package 1.20 pounds of cereal is being tested for its accuracy In a sample of 36 cereal boxes, the sample mean filling weight is calculated as 1.22 pounds. The population standard deviation is known to be 0.06 pound. Identify the relevant parameter of interest for these quantitative data. The parameter of interest is the proportion filling weight for all cereal packages. The parameter of interest is the average filling weight for all cereal packages.
A-1. Identify the relevant parameter of interest for these quantitative data.
A) The parameter of interest is the average filling weight of all cereal packages.
B) The parameter of interest is the proportion filling weight of all cereal packages.
A-2. Compute its point estimate as well as the margin of error with 95% confidence. (Round intermediate calculations to 4 decimal places.
B-1. Calculate the 95% confidence interval.
B-2. Can we conclude that the packaging machine is operating improperly?
A) Yes, since the confidence interval contains the target filling weight of 1.20.
B) Yes, since the confidence interval does not contain the target filling weight of 1.20.
C) No, since the confidence interval contains the target filling weight of 1.20.
D) No, since the confidence interval does not contain the target filling weight of 1.20.
C. How large a sample must we take if we want the margin of error to be at most 0.01 pound with 95% confidence?
Answer:
A) The parameter of interest is the average filling weight of all cereal packages. ;
Point estimate = 1.22
Margin of Error = 0.0196
Confidence interval = (1.2004, 1.2396)
C) No, since the confidence interval contains the target filling weight of 1.20.
Step-by-step explanation:
A) The parameter of interest is the average filling weight of all cereal packages.
The point estimate = sample mean = 1.22
The margin of error with 95% confidence :
Zcritical * σ/sqrt(n)
Zcritical at 95% confidence = 1.96
Margin of Error = 1.96 * 0.06/sqrt(36)
Margin of Error : 1.96 * 0.01
Margin of Error = 0.0196
Confidence interval :
xbar ± margin of error
1.22 ± 0.0196
Lower boundary = 1.22 - 0.0196 = 1.2004
Upper boundary = 1.22 + 0.0196 = 1.2396
(1.2004, 1.2396)
C) No, since the confidence interval contains the target filling weight of 1.20.
Since, the internal contains 1.20, then we can conclude that it is filling properly.
I need the area can someone help meeee pls?
Answer:
54ft
Step-by-step explanation:
9ft x 6ft
What’s the mean median mode and range of the data set 14,18,12,20
Answer:
....
Step-by-step explanation:
mean: 16
median: 16
there is no mode
range: 8
Please help and stop with the links!
Pls help its urgent
Question 1:
In my backyard there are chickens and cows (no other animals). Among them there is a total of 366 eyes and 558 legs. How many chickens do I have in my backyard?
The total animals = 139, and we can substitute this value into equation (3) to obtain:x = 2(139) - 279 => x = -1This doesn't make sense since we can't have negative chickens.
Let the number of chickens be x and the number of cows be y in the backyard. We can create two equations based on the given information:The total number of animals is x + y = total animals ...
(1)The total number of eyes and legs can also be expressed as 2x + 2y = 366 (since each animal has two eyes) and 2x + 4y = 558 (since each chicken has 2 legs and each cow has 4 legs).
Simplifying the equations, we get:x + y = total animals ... (1)x + 2y = 279 ... (2)From equation (1),
we can substitute y = total animals - x in equation (2) to obtain:x + 2(total animals - x) = 279 => 2total animals - x = 279 => x = 2total animals - 279 ... (3)We also know that x + y = total animals, so y = total animals - x.
Substituting equation (3) into this expression, we get:y = total animals - (2total animals - 279) => y = 279 - total animals ... (4)
To find the value of x, we need to know the value of total animals. We can obtain this value by adding equations (1) and (4):x + y + (279 - total animals) = total animals => x + y = 279/2 => x + y = 139.5
Since x and y are both whole numbers, they must add up to an even number. The only possible value is 70 + 69 = 139. Therefore, there must be a mistake in the problem statement or calculations.
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This had me confused i need big help!!!!
Answer:
[tex]3\frac{7}{8}[/tex]
Step-by-step explanation:
Equation: 4 1/7 + 2 1/8 + x= 10 1/7
Convert into improper fractions:
29/7 + 17/8= 71/7
Add fractions
351/56+x= 71/7
Subtract on both sides
X= 31/8 or 3 7/8
f(x)=x^2x+3;f(x)=-2x+12
Answer:
F
(
−
2
x
+
12
)
=
−
8
x
3
+
144
x
2
−
864
x
+
1731
Step-by-step explanation:
A student ties a string around a weight and swings the weight in a circle around her body. If the student
represents the Sun and the weight represents
n 1990, the mean height of women 20 years of age or older was 63.7 inches based on data obtained from theCDC. Suppose that a random sample of 45 women who are 20 years of age or older in 2015 results in a meanheight of 63.9 inches with a standard deviation of 0.5 inch. Does your sample provide sufficient evidencethat women today are taller than in 1990
Answer:
The sample does not provide sufficient evidence that women today are taller than women in 1990.
The difference in mean height is not significant to arrive at such a conclusion.
Step-by-step explanation:
Mean height of women 20 year of age or older in 1990 = 63.7 inches
Mean height of women 20 years of age or older in 2015 = 63.9 inches
The standard deviation of the mean height in 2015 = 0.5 inch
The difference between the two years' mean height is 0.2 (63.9 - 63.7) inch.
This difference is less than the standard deviation of the mean height in 2015.
Therefore, the difference does not provide sufficient evidence that women today are taller than women in 1990.