Student is attempting to hit a target 4 meters from the edge of the desk that is 1.4 m tall marble rules of a table horizontally as shown below according to the above information in diagram what velocity must a marble have to strike the target?

Answer:

All 7 Dragonballs

Explanation:

the dragonball Summon shenron which will then grant you a wish

Answer:

I don't know how to show the work but I just had this question and the answer is 9.24kg.

Explanation:

Answer:

a. 0.122 ft b. -70 Btu/h ft² c. 633.33 °F

Explanation:

a. Since the rate of heat loss dQ/dt = kAΔT/d where k = thermal conductivity, A = area, ΔT = temperature gradient and d = thickness of insulation.

Now [dQ/dt]/A = kΔT/d

Given that [dQ/dt]/A = rate of heat loss per unit area = -900Btu/h ft², k = 0.10 Btu/h ft ℉(for asbestos), ΔT = T₂ - T₁ = 500 °F - 1600 °F = -1100 °F. We need to find the thickness of asbestos, d. So,

d = kΔT/[dQ/dt]/A

d = 0.10 Btu/h ft ℉ × -1100 °F/-900Btu/h ft²

d = 0.122 ft

b. If the 3 in thick Kaolin is added to the outside of the asbestos, and the outside temperature of the asbestos is 250℉, the heat loss due to the Kaolin is thus

[dQ/dt]/A = k'ΔT'/d'

k' = 0.07 Btu/h ft ℉(for Kaolin), ΔT' = T₂ - T₁ = 250 °F - 500 °F = -250 °F and d' = 3 in = 3/12 ft = 0.25 ft

[dQ/dt]/A = 0.07 Btu/h ft ℉ × -250 °F/0.25 ft

[dQ/dt]/A  = -70 Btu/h ft²

c. To find the temperature at the interface, the total heat flux equals the individual heat loss from the asbestos and kaolin. So

[dQ/dt]/A = k(T₂ - T₁)/d + k'(T₃ - T₂)/d' where  [dQ/dt]/A = -900Btu/h ft², k = 0.10 Btu/h ft ℉(for asbestos), k' = 0.07 Btu/h ft ℉(for Kaolin), T₁ = 1600 °F, T₂ = unknown and T₃ = 250℉.

Substituting these values into the equation, we have

-900Btu/h ft² = 0.10 Btu/h ft ℉(T₂ - 1600 °F)/0.122 ft + 0.07 Btu/h ft ℉(250℉ - T₂)/0.25 ft

-900Btu/h ft² = 0.82 Btu/h ft ℉(T₂ - 1600 °F) + 0.28Btu/h ft ℉(250℉ - T₂)

-900 °F = 0.82(T₂ - 1600 °F) + 0.28(250℉ - T₂)

-900 °F = 0.82T₂  - 1312°F + 70 °F - 0.28T₂

collecting like terms, we have

-900 °F + 1312°F - 70 °F = 0.82T₂   - 0.28T₂

342 °F = 0.54T₂

Dividing both sides by 0.54, we have

T₂ = 342 °F/0.54

T₂ = 633.33 °F

The thickness of asbestos required is 0.122 ft.

The heat flux will be -70 Btu/h ft²

And the temperature of the interface is 633.33 °F.  

(i) the rate of heat loss :

dQ/dt = kAΔT/d

where k = thermal conductivity, A = area, ΔT = temperature gradient, and

d = thickness of insulation.

[dQ/dt]/A = kΔT/d

Given that [dQ/dt]/A = rate of heat loss per unit area = -900Btu/h ft²,

k = 0.10 Btu/h ft ℉,

ΔT = 500 °F - 1600 °F = -1100 °F

We have to find the thickness of asbestos that is d.

d = kΔT/[dQ/dt]/A

d = 0.10 Btu/h ft ℉ × -1100 °F/-900Btu/h ft²

d = 0.122 ft is the thickness required.

(ii) a 3-in thick Kaolin is added to the outside of the asbestos

outside temperature of the asbestos is 250℉,

the heat loss due to the Kaolin is:

[dQ/dt]/A = k'ΔT'/d'

k' = 0.07 Btu/h ft ℉(for Kaolin), ΔT' = T₂ - T₁ = 250 °F - 500 °F = -250 °F and d' = 3 in = 3/12 ft = 0.25 ft

[dQ/dt]/A = 0.07 Btu/h ft ℉ × -250 °F/0.25 ft

[dQ/dt]/A  = -70 Btu/h ft²

(iii) temperature at the interface

the total heat flux :

[dQ/dt]/A = k(T₂ - T₁)/d + k'(T₃ - T₂)/d'

where  [dQ/dt]/A = -900 Btu/h ft²,

k = 0.10 Btu/h ft ℉  (for asbestos),

k' = 0.07 Btu/h ft ℉  (for Kaolin),

T₁ = 1600 °F and T₃ = 250℉.

-900 = 0.10(T₂ - 1600 °F)/0.122 + 0.07(250℉ - T₂)/0.25

-900 = 0.82(T₂ - 1600 °F) + 0.28(250℉ - T₂)

-900 °F = 0.82(T₂ - 1600 °F) + 0.28(250℉ - T₂)

-900 °F = 0.82T₂  - 1312°F + 70 °F - 0.28T₂

-900 °F + 1312°F - 70 °F = 0.82T₂   - 0.28T₂

342 °F = 0.54T₂

Dividing both sides by 0.54, we have

T₂ = 342 °F/0.54

T₂ = 633.33 °F

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Answer:

m2 = 13950 [kg]

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which is defined as the product of mass by velocity, and can be determined by means of the following expression:

P = m*v

where:

P = lineal momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

Now that momentum is conserved, we need to analyze the conditions before the collision and after the collision. In this way we must propose the following equation:

ΣPbefore = ΣPafter

(m1*v1) + (m2*v2) = (m1+m2)*v3

where:

m1 = mass of the railroad car = 9300 [kg]

v1 = velocity of the railroad car before the collision = 15 [m/s]

m2 = mass of the box car [kg]

v2 = velocity of the boxcar before the collision = 0 (the car is at rest)

(m1 + m2) = combined mass of the cars, they stick together after the collision [kg]

v3 = combined velocity of the cars after the collision = 6 [m/s]

(9300*15) + (m2*0) = (m1+m2)*6

139500 = (6*9300) + 6*m2

83700 = 6*m2

m2 = 13950 [kg]

The mass of the second railroad car which was initially at rest is 13950kg.

Given the data in the question;

Mass of railroad car2; [tex]m_2 = \ ?[/tex]

Since railroad car2 was initially at rest,

After the strike, the wo cars stick together and moved

To determine the mass of the second railroad car, we use conservation of linear momentum:

[tex]m_1u_1 + m_2u_2 = (m_1 + m_2 )v[/tex]

We substitute our given values into the equation

[tex](9300kg * 15m/s) + ( m_2 * 0 ) = ( 9300kg + m_2 )6m/s\\\\9300kg * 15m/s = ( 9300kg + m_2 )6m/s\\\\139500kg.m/s = 55800kg.m/s + ( m_2 * 6m/s )\\\\139500kg.m/s - 55800kg.m/s = m_2 * 6m/s\\\\83700kg.m/s = m_2 * 6m/s\\\\m_2 = \frac{83700kg.m/s}{6m/s} \\\\m_2 = 13950kg[/tex]

Therefore, the mass of the second railroad car which was initially at rest is 13950kg.

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Answer:

4200 Newtons

Explanation:

Force = mass x acceleration

1200 x 3.5 = 4200

Answer: Option B.

Explanation:

I guess that this refers to the Badminton rules, particularly to the position of the racket (or the head of the racket, where the "head" is the part with the net, that you use to hit the shuttle) when serving.

The head of the racket must be swung from below your waist. So the head of the racket must be below your waist before you do the service (With a part of the head is enough).

Then the correct option is B. Below the waist.

The correct matching of the organisms to their descriptions is given below:

Any organic, living system that performs as an independent unit is referred to as an organism. Cells comprise all living things. Multicellular mammals, plants, and fungi are examples of multicellular creatures. Unicellular microorganisms include bacteria and archaea.

All kinds of creatures can have the capacity for procreation, growth and development, maintenance, and to some extent, stimulus-response. Multicellular organisms such as beetles, tetrapods, mushrooms, and vascular plants grow a variety of tissues and organs.

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hey! i just wanted to ask if you found the answer because i’m looking for it

Answer:

the innermost layer of the earth

Explanation:

the earth has an outer core liquid and an inner core solid they are not chemically distinct from each other but they are chemically distinct from the mantle the core is mainly composed of nickel and iron

Answer:

20 m

Explanation:

by the formula,

                         [tex]2aS = V_{f}^{2} - V_{i}^2[/tex]

                         2 x 10 x S = 20^2 - 0

                         20S = 400

                         [tex]S = \frac{400}{20}[/tex]

                          S = 20 m  

Answer:

I think it is 2m/s2

Explanation:

Have a great day:)

Answer:

a chemical property can be observed without changing the identity of the substance.

Explanation:

a physical property is a characteristic that can be observed without changing the substance into another substance. The object reacts with acid to form water.

The answers is 30 miles per hour, the driver is speeding the car up,     section-H, 12 minutes, section-D, and 65 miles per hour.

Answer:

Momentum is directly proportional to the object's mass and also its velocity. Thus the greater an object's mass or the greater its velocity, the greater its momentum. Momentum p is a vector having the same direction as the velocity v. The SI unit for momentum is kg · m/s.

Answer:

Momentum is directly proportional to the object's mass and also its velocity. Thus the greater an object's mass or the greater its velocity, the greater its momentum. Momentum p is a vector having the same direction as the velocity v. The SI unit for momentum is kg · m/s.

Explanation:

¡Hellow!

For this problem, first, lets convert the seconds in hours:

5,4x10³[tex]\rightarrow[/tex] 5400

h = sec / 3600

h = 5400 s / 3600

h = 1,5

Let's recabe information:

d (Distance) = 386 km

t (Time) = 1,5 h

v (Velocity) = ?

For calculate velocity, let's applicate formula:

                                                    [tex]\boxed{\boxed{\textbf{d = v * t} } }[/tex]

Reeplace according we information:

386 km = v * 1,5 h

v = 386 km / 1,5 h

v = 257,33 km/h

The velocity of the train is of 257,33 kilometers for hour.

Extra:

For convert km/h to m/s, we divide the velocity of km/h for 3,6:

m/s = km/h / 3,6

Let's reeplace:

m/s = 257,33 km/h / 3,6

m/s = 71,48

¿Good Luck?

It should be the first one, F= mXa (F = m times a).

Answer:

B) 48 metres

Explanation:

Answer:

i believe the answer is true

Explanation:

everything was created in the big bang

Answer:  are u single

Explanation:

Answer:

The vacuum of outer space is not caused by the expansion of the universe, but is caused by gravity.

Explanation:

Answer:

New days begin at 180° longitude.

Explanation:

Answer:

a = 1.458 [m/s²]

Explanation:

To be able to solve this type of problems it is always advisable to make a free body diagram with the forces acting on the body.

Attached is an image with the free body diagram and the proposed equations, the explanation of obtaining the equations will be described below.

Let's take the movement to the left as positive, i.e. all forces going to the left have a positive sign.

Let's use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

To the left we have the two forces of tension by the cosine of the angle. And to the right the frictional force. The resultant of these forces is equal to the product of the mass (mass of the child plus the mass of the sled), by acceleration.

Answer:

The correct option is;

c. 12.8 cm

Explanation:

The given parameters are;

The length of each spring = 12 m  = 0.12 m

Given that the masses and the springs are vertically oriented, we have;

The mass on the first spring = 3 × 6.4 = 19.2 kg

The weight on the first spring = 19.2 kg × 9.81 m/s² = 188.352 N

The extension of the first spring = 188.352 N/7,800 N/m ≈ 0.02415 m

The mass on the second spring = 2 × 6.4 = 12.8 kg

The weight on the second spring = 12.8 kg × 9.81 m/s² = 125.568 N

The extension of the second spring = 125.568 N/7,800 N/m ≈ 0.016098 m

The mass on the third spring = 1 × 6.4 = 6.4 kg

The weight on the third spring = 6.4 kg × 9.81 m/s² = 62.784 N

The extension of the third (bottom) spring = 62.784 N/7,800 N/m ≈ 0.00805 m

The total length of the bottom spring = Original length of the bottom spring + Extension of the bottom spring

The total length of the bottom spring ≈ 0.12 m + 0.00805 m = 0.12805 m

The total length of the bottom spring ≈ 0.12805 m ≈ 12.81 cm

The bottom spring will be approximately 12.81 cm long.

Answer:

presence or absence of wind

Explanation:

When establishing a relationship between two variables the effect one variable has on the other is studied. The variable that changes with respect to the other is the dependent variable while the other variable is called the independent variable.

Here the distance the football covers in the presence and absence of wind is studied. So, the presence or absence of wind is the independent variable.

Answer:

about 16 hours

Explanation:

if driving 55mph for 16 hrs you will travel about 880 miles