It should be noted that since the combined dimension of the eigenspaces of A is 5 and there are only 2 eigenvalues, A cannot be diagonalizable.
How to explain the informationA 2x2 matrix can have at most 2 distinct eigenvalues. Since A has eigenvalues λ₁ = 2 and λ₁ = -7, these must be the only two eigenvalues.
The algebraic multiplicity of an eigenvalue is the number of times that eigenvalue appears in the characteristic polynomial of the matrix. In this case, the algebraic multiplicity of λ₁ = 2 is 2 and the algebraic multiplicity of λ₁ = -7 is 3. This means that the characteristic polynomial of A must be of the form (t-2)^2(t+7)^3.
The dimension of the eigenspace associated with an eigenvalue is equal to the algebraic multiplicity of that eigenvalue. In this case, the dimension of the eigenspace associated with λ₁ = 2 is 2 and the dimension of the eigenspace associated with λ₁ = -7 is 3. This means that the combined dimension of the eigenspaces of A is 5.
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Guided Practice
Find the square.
(c + 1)2
A.
c2 + 1
B.
c2 + c + 1
C.
c2 + 2c + 1
Answer:
C
Step-by-step explanation:
(c + 1)(c+1) = c² + c + c + 1 = c² + 2c + 1
will mark brainliest also its not 6 and 5
Help me plz! I need help!
Answer:
function 2
Step-by-step explanation:
i looked at the table, and since t (which is the x-coordinate in this case) was 0, that means that 5.25 is the y-coordinate and is greater than 5 in the first equation.
Need help on this one too
Answer:
sin(θ)=4√41/41
cos(θ)=5√41/41
tan(θ)=4/5
cot(θ)=5/4
sec(θ)=√41/5
csc(θ)=√41/4
Step-by-step explanation:
please answer this for me?
Answer:
n/a
Step-by-step explanation:
how does it feel
9) set 21 and 22 be rings with identities ter and 1R₂, respectively. Prove that the set of all Toleals of R1X22 = $ Il x I₂: It is on Ideal of 21 and is an ideal of R2}.
The Set of all ideals of R₁×R₂, denoted as I₁×I₂, is an ideal of R₁×R₂, and it is also an ideal of R₁ and R₂ separately.
To prove that the set of all ideals of R₁×R₂, denoted as I₁×I₂, is an ideal of R₁×R₂, we need to demonstrate that it satisfies the necessary properties of an ideal.
1. Closure under addition: Let (a, b) and (c, d) be two elements in I₁×I₂. We need to show that their sum, (a, b) + (c, d), is also in I₁×I₂. Since both (a, b) and (c, d) are in their respective ideals, this implies that a+c is in I₁ and b+d is in I₂. Therefore, (a+c, b+d) is in I₁×I₂, showing closure under addition.
2. Closure under scalar multiplication: Let (a, b) be an element in I₁×I₂ and (r, s) be an arbitrary element in R₁×R₂. We need to show that their scalar product, (a, b)(r, s), is in I₁×I₂. Since a is in I₁, and R₁ is a ring with identity, we have ar is in I₁. Similarly, since b is in I₂ and R₂ is a ring with identity, we have bs is in I₂. Therefore, (ar, bs) is in I₁×I₂, demonstrating closure under scalar multiplication.
3. Contains additive identity: The additive identity in R₁×R₂ is (0, 0). Since both I₁ and I₂ are ideals, they contain their respective additive identities. Therefore, (0, 0) is in I₁×I₂.
Since the set of all ideals of R₁×R₂, denoted as I₁×I₂, satisfies closure under addition, closure under scalar multiplication, and contains the additive identity, it meets the definition of an ideal of R₁×R₂.
Additionally, since I₁×I₂ is a subset of both I₁ and I₂, it is an ideal of R₁ and R₂ individually.
In conclusion, the set of all ideals of R₁×R₂, denoted as I₁×I₂, is an ideal of R₁×R₂, and it is also an ideal of R₁ and R₂ separately.
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TILAPIA FISH!!!!!!!!!
Answer:
yes.
................................
You need help with anything??
The second quartile for the numbers:
231,423,521,139,347,400,345 is
A 231
B 347
C 330,
D 423
Which of the following measures of variability is dependent on every value in a Set of data?
A Range
B. Standard deviation
C A and B
D. Neither A nor B
Which one of these statistics is unaffected by Outliers?
A Mean
B. Interquartile range
C Standard deviation
D. Range
The second quartile for the numbers 231, 423, 521, 139, 347, 400, 345 is 347. The median value is the second quartile
. So, when the numbers are arranged in ascending order, 347 is in the middle.
The following measures of variability is dependent on every value in a Set of data:
Standard deviation is the measure of variability that is dependent on every value in a Set of data.
Standard deviation is a measure that is used to quantify the amount of variation or dispersion of a set of data values.
Among these statistics, the Interquartile range is unaffected by outliers. The IQR is the distance between the first quartile (Q1) and the third quartile (Q3), which represents the middle 50% of the data.
The interquartile range (IQR) is unaffected by outliers because it only uses the values of the data points located at the 25th and 75th percentile of the data set to measure variability.
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NEED HELP!! NO Absurd answers!
Use technology or a z-score table to answer the question.
The normal admission price to see a movie at different theaters is normally distributed with a mean of $11.80 and a standard deviation of $1.15.
Approximately what percent of theaters charge more than $10 to see the movie?
5.8%
19.8%
80.2%
94.2%
Answer:
Approximately 94% of theaters charge more than $10 to see the movie.
Step-by-step explanation:
Use a calculator with distribution functions such as normalcdf(
Here we have normalcdf(10,1000,11.80, 1.15) = 0.941
Approximately 94% of theaters charge more than $10 to see the movie. This agrees with the last answer choice.
Here is an equation and all the steps Clare and Lin took to solve it. Are both of their solutions correct? Explain your reasoning.
Answer:
Both solutions are correct
Step-by-step explanation:
Given
Expression:
[tex]14x - 2x +3 = 3(5x + 9)[/tex]
See attachment for Clare and Lins' solution
Required
Determine if they are correct or not
[tex]14x - 2x +3 = 3(5x + 9)[/tex]
Open bracket
[tex]14x - 2x + 3 = 15x + 27[/tex]
Collect like terms
[tex]14x - 2x -15x = -3 + 27[/tex]
[tex]-3x = 24[/tex]
Divide by -3
[tex]x = \frac{24}{-3}[/tex]
[tex]x = -8[/tex]
Both solutions are correct
To test the hypothesis that the population standard deviation sigma 12.1, a sample size n=7 yields a sample standard deviation 10.394. Calculate the P- value and choose the correct conclusion. Your answer: The P-value 0.016 is not significant and so does not strongly suggest that sigma<12.1. The P-value 0.016 is The P-value 0.016 is significant and so strongly suggests that sigma<12.1. The P-value 0.381 is not significant and so does not strongly suggest that sigma<12.1. The P-value 0.381 is O significant and so strongly suggests that sigma<12.1. The P-value 0.021 is not significant and so does not strongly suggest that sigma<12.1. The P-value 0.021 is significant and so strongly suggests that sigma<12.1. suggests that sigma<12.1. The P-value 0.015 is not significant and so does not strongly suggest that sigma<12.1. The P-value 0.015 is significant and so strongly suggests that sigma<12.1. The P-value 0.199 is not significant and so does not strongly suggest that sigma<12.1. The P-value 0.199 is O significant and so strongly suggests that sigma<12.1.
The calculated p-value is 0.016, which is significant. However, it does not strongly suggest that the population standard deviation (sigma) is less than 12.1.
In hypothesis testing, the p-value is used to determine the strength of evidence against the null hypothesis. In this case, the null hypothesis is that the population standard deviation (sigma) is equal to 12.1. The alternative hypothesis would be that sigma is less than 12.1.
A p-value of 0.016 means that if the null hypothesis were true (sigma = 12.1), there is a 1.6% chance of obtaining a sample with a standard deviation of 10.394 or lower. Typically, a p-value below a chosen significance level (e.g., 0.05) is considered statistically significant. However, in this case, the p-value of 0.016 is still relatively close to the significance level, indicating a moderate level of evidence against the null hypothesis.
Therefore, based on the given information, we can conclude that the p-value of 0.016 is significant, but it does not strongly suggest that the population standard deviation is less than 12.1. Strong evidence would require a smaller p-value, further away from the significance level, to support the alternative hypothesis.
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Please help im not good at theses
Answer:
[tex]y=\frac{1}{4} x-3[/tex]
Step-by-step explanation:
y=mx+b -- m = slope, b = y-int
Using the definition of the matrix exponential, calculate et for A = - b) Using the definition of the matrix exponential, calculate et for B = - c) Using the definition of the matrix exponential, A from part (a) and B from part (b), calculate e(A+B)t d) Is it true in general that, for nxn matrices A and B, etBt= eAt = e(A+B) ? Justify your answer.
a) The matrix exponential for matrix A is [tex]e^t[/tex]A = I + tA.
b) The matrix exponential for matrix B is [tex]e^t[/tex]B = I + tB.
c) To calculate [tex]e^{(A+B)t}[/tex], we substitute A and B into the matrix exponential definition and simplify the expression.
d) It is not generally true that [tex]e^t[/tex]B * [tex]e^t[/tex]A = [tex]e^t[/tex]A+B. The exponential of the sum of matrices is not equal to the product of their individual exponentials, unless the matrices commute.
a) For matrix A, the matrix exponential [tex]e^t[/tex]A is calculated as [tex]e^t[/tex]A = I + tA, where I is the identity matrix.
b) For matrix B, the matrix exponential[tex]e^t[/tex]B is calculated as [tex]e^t[/tex]B = I + tB, where I is the identity matrix.
c) To calculate [tex]e^{(A+B)t}[/tex], we substitute A and B into the matrix exponential definition:
[tex]e^{(A+B)t}[/tex] = I + t(A+B).
Expanding the expression further:
[tex]e^{(A+B)t}[/tex] = I + tA + tB.
d) It is not true in general that [tex]e^t[/tex]B * [tex]e^t[/tex]A = [tex]e^t[/tex](A+B). This equality holds only when matrices A and B commute, meaning AB = BA.
In the general case where A and B do not commute, [tex]e^t[/tex]B * [tex]e^t[/tex]A is not equal to [tex]e^t[/tex](A+B). The matrix exponential does not have the property of distributivity over addition, unlike regular exponentiation.
Therefore, the justification for this answer is that matrix exponentials do not follow the same rules as scalar exponentials when it comes to addition and multiplication.
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What is 40x + 4y = 24
Answer:
sorry but your question can't be solved any further because it doesn't have any like termsand you can't add40x and4y together it's impossible unless you multiply
Tom's dad is putting crown molding around the top of all of the walls in Tom's bedroom. The dimensions of his bedroom are shown. A rectangle that is eleven and three-fourths feet wide and fifteen and three-fourths feet long. Each foot of crown molding costs $0.85. What is the total cost of the crown molding?
Answer:
$157.30
Step-by-step explanation:
Width of the rectangular bedroom = 11 3/4 feet
Length of the rectangular bedroom = 15 3/4 feet
Area of the rectangular bedroom = length × width
= 15 3/4 × 11 3/4
= 63/4 × 47/4
= 2,961 / 16
= 185.0625 feet ²
Area of the rectangular bedroom = 185.0625 feet ²
Cost of each foot of crown molding = $0.85
Total cost of the crown molding = 185.0625 × $0.85
= $157.303125
Approximately,
Total cost of the crown molding = $157.30
PLEASE HELP WILL MARK BRAINLIEST
Answer:
36
Step-by-step explanation:
There are 30 red marbles and the ratio of black to yellow is 4/5, so 4/5=orange/green=orange/30.
30 is 6 times 5, so black=6 times 4=24. There are 24 black marbles.
Total of black and yellow=24+30=54.
40% of the marbles are green so 60% are black/yellow. Also 60% is 54 marbles.
60% is 60/100=3/5 so 3/5 of the total is 54 marbles, therefore 1/5 is 54/3=18 and 2/5 is the number of red marbles=2 times 18=36 red marbles.
to be honest i can't think of anything original for the visual thing, but i think the pi chart from the person above me would work well
Answer: 36
Step-by-step explanation: 2/5 of marbles are red, and 4:5 ratio is multiplied by 6 because there are 30 yellow marbles and so 3/5 of the marbles are 54 and 2/5 are 36. For visual model draw a pi chart with 40% red, 33% yellow, and 27% black.
1. Select all of the situations below that model this fraction. *
Captionless Image
A. 243 people were at the park. 20 people were playing volleyball. How many people were not playing volleyball?
B. Marcy's bookshelf had 20 shelves. She had 243 books. How many books would go on each shelf if she put the same number of books on each shelf?
C. Josh made $243 in 20 days. How much did he earn each day?
D. Sally and Len bicycled 243 miles in 20 days. How many miles did they bicycle each day?
Answer:
A. 223 were not playing volleyball
B. 12 books on each shelf with 3 books left over..
C. 12.15$ a day
D. 12.15 miles per day.
Step-by-step explanation:
A. Subtract 20 from 243.
B. Since books cant be divided into fractions, you take 243 divided by 20, which is 12.15. However, we have to say 12 with 3 leftover because books isn't money, a distance measure, etc. and cannot be cut into pieces.
C. 243 / 20 is 12.15
D. 243 / 20 is 12.15
simplify the following 10^9÷10^7
Answer:
Step-by-step explanation:
[tex]10^9 \div 10^7\\=\frac{10^9}{10^7} \\=10^9 \times 10^{-7}\\=10^{9-7}\\=10^2\\=100[/tex]
Which equation represents the line that passes through the point (3, –1) and is perpendicular to the graph of x + 4y = 10?
Answer:
y=6x+7
Step-by-step explanation:
Let A = {a,b,c}, B = {1, 2, 3, 4), and C = {w, x, y, z), and let R= {(2, 1), (6, 3), (6, 4), (C, 3)} and S = {(1, y), (1, 2), (2, w), (3, z)}. What is the composition relation ( RS) of R with S?
The pair (6, 3) in R, (6, 4) in R, and (C, 3) in R couldn't be matched with any pair in S, so they are not included in the composition relation RS.
To find the composition relation RS of R with S, we need to combine the ordered pairs in R and S in a way that the second element of each pair in R matches the first element of the pair in S.
Let's perform the composition:
R = {(2, 1), (6, 3), (6, 4), (C, 3)}
S = {(1, y), (1, 2), (2, w), (3, z)}
To form RS, we match the second element of each pair in R with the first element of each pair in S:
(2, 1) in R matches with (1, y) in S, so we combine them to form (2, y).
(2, 1) in R matches with (1, 2) in S, so we combine them to form (2, 2).
(6, 3) in R doesn't match with any pair in S.
(6, 4) in R doesn't match with any pair in S.
(C, 3) in R doesn't match with any pair in S.
Therefore, the composition relation RS is: RS = {(2, y), (2, 2)}
The pair (6, 3) in R, (6, 4) in R, and (C, 3) in R couldn't be matched with any pair in S, so they are not included in the composition relation RS.
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What is the best definition for “sample” as used in statistics?
the entire population of the group
a part of the population that represents the entire population
the difference between the maximum and minimum values observed
a measure of how much the values within a population vary
Answer:
a part of the population that represents the entire population
Step-by-step explanation:
Answer:
I think it is the second option
I hope it helps you
On any weekday during the semester, the probability that Beth does yoga is 0.75, the probability that Beth walks is 0.40, and the probability that Beth does both is equal to 0.20. Round your answers to two decimals. Write your answers in the form O.XX! What is the probability that Beth does yoga knowing that she walked? What is the probability that Beth walks knowing that she did yoga? Are the events "Beth does yoga" and "Beth walks" independent events? Are the events "Beth does yoga" and "Beth walks" dependent events?
The probability that Beth does yoga knowing that she walked is 0.50. The probability that Beth walks knowing that she did yoga is 0.27. The events "Beth does yoga" and "Beth walks" are dependent events.
To calculate the probability that Beth does yoga knowing that she walked, we use the formula for conditional probability. The probability of Beth doing yoga given that she walked is equal to the probability of both events occurring (Beth does both) divided by the probability of the given event (Beth walks). In this case, the probability of Beth doing yoga and walking is 0.20, and the probability of Beth walking is 0.40. Therefore, the probability that Beth does yoga knowing that she walked is 0.20/0.40 = 0.50.
Similarly, to calculate the probability that Beth walks knowing that she did yoga, we use the formula for conditional probability. The probability of Beth walking given that she did yoga is equal to the probability of both events occurring (Beth does both) divided by the probability of the given event (Beth does yoga). In this case, the probability of Beth doing yoga and walking is 0.20, and the probability of Beth doing yoga is 0.75. Therefore, the probability that Beth walks knowing that she did yoga is 0.20/0.75 ≈ 0.27.
Since the conditional probabilities are not equal to the individual probabilities of each event, we can conclude that the events "Beth does yoga" and "Beth walks" are dependent events. The occurrence of one event affects the probability of the other event, indicating a dependence between the two activities.
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Solve the system of equations given by elimination:
{y = -x + 1
{y = 4x – 14
A. (-3, 2)
B. (-3,-2)
C. (3,2)
D. (3,-2)
Answer:
y= -x+1
y=4x_14
solution
-x+1=4x-14
-x-4x= -14-1
-5x= -15
-5x/-5= -15/-5
x=3
while y=4x-14
y=4(3)-14
y=12-14
y= -2
Please help me due in 3 Hours WILL GIVE BRAINLIST
Answer:
a.) 200
b.) -56
If I typed out all my work, it would be one LONG answer. I’m just going to include the steps in an attachment. Hope it’s accurate & helpful!
A recent survey of 3,057 individuals asked: "What’s the longest vacation you plan to take this summer?" The following relative frequency distribution summarizes the results. (You may find it useful to reference the z table.)
Response Relative Frequency
A few days 0.21
A few long weekends 0.18
One week 0.36
Two weeks 0.22
a. Construct the 95% confidence interval for the proportion of people who plan to take a one-week vacation this summer. (Round final answers to 3 decimal places.)
b. Construct the 99% confidence interval for the proportion of people who plan to take a one-week vacation this summer. (Round final answers to 3 decimal places.)
c. Which of the two confidence intervals is wider?
multiple choice
95% confidence interval.
99% confidence interval.
A. The 95% self-belief interval for the percentage of humans making plans to take a one-week excursion this summer time is approximately 0.351 to 0.369.
B. The 99% confidence c programming language for the share of people planning to take a one-week vacation this summer time is approximately 0.348 to 0.372.
C. The 99% self-assurance c program language period is wider than the 95% confidence c language.
A. To assemble the 95% confidence c programming language for the percentage of individuals who plan to take a one-week excursion this summer time, we will use the formula for the self-belief c programming language of a proportion:
CI = p ± z * [tex]\sqrt{((p(1 - p)) / n)}[/tex]
in which p is the pattern percentage, z is the z-score corresponding to the preferred self-belief degree, and n is the sample size.
From the given relative frequency distribution, we will see that the proportion of humans planning to take a one-week excursion is 0.36. The pattern size is 3,057.
Using a z-table for a 95% confidence stage, the z-score similar to a two-tailed test is approximately 1.96.
Plugging the values into the formula, we have:
CI = 0.36 ± 1.96 * [tex]\sqrt{((0.36(1 - 0.36)) / 3,057)}[/tex]
Calculating this expression, we get:
CI = 0.36 ± 1.96 *[tex]\sqrt{ (0.2304 / 3,057)}[/tex]
CI = 0.36 ± 1. 96 * 0.00473
CI ≈ 0.36 ± 0.00928
Therefore, the 95% self-belief interval for the percentage of humans making plans to take a one-week excursion this summer time is approximately 0.351 to 0.369.
B. To assemble the 99% self-assurance c programming language, we use the same formula as above however with a unique z-score.
Using a z-table for a 99% self-belief level, the z-rating similar to a two-tailed take a look at is approximately 2.576.
Plugging the values into the formula, we've got:
CI = 0.36 ± 2.576 * [tex]\sqrt{((0.36(1 - 0.36)) / 3,057)}[/tex]
Calculating this expression, we get:
CI = 0.36 ± 2.576 * [tex]\sqrt{(0.2304 / 3,057)}[/tex]
CI = 0.36 ± 2.576 * 0.00473
CI ≈ 0.36 ± 0.01217
Therefore, the 99% confidence c programming language for the share of people planning to take a one-week vacation this summer time is approximately 0.348 to 0.37.
C. The 99% self-assurance c p2rogram language period is wider than the 95% confidence c language. This is because a higher self-belief stage requires a larger margin of mistakes, resulting in a wider range across the factor estimate.
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The height, h metres, of a soccer ball kicked directly upward can be modelled by the equation h(t) = -4.9t2 + 13.1t + 1, where t is the time, in seconds, after the ball was kicked. a) How high is the ball after 2 s? 15 b) After how many seconds does the ball reach a height of 0.5 m? /3 21. Determine the inverse function for f(x)=(x - 2), state the domain and range for the function and its inverse. Write each step. 14 22. A farmer has 600m of fencing to enclose a rectangular area and divide 14 into three sections as shown. a) write a equation to express the total area enclosed as a function of the length x. b) Determine the domain and the range of this area function.
a) The height of the ball after 2 seconds is 7.6 metres.
b) The given function is f(x) = (x - 2).
a) The inverse function of f(x) is g(x) = x + 2.
b) A farmer has 600 metres of fencing to enclose a rectangular area and divide it into 14 sections.
a) The total area enclosed can be expressed as a function of the length of the rectangle x as A(x) = 300x - x².
b) The domain of the area function is (0, 300) and its range is [0, ∞).
a) h(t) = -4.9t² + 13.1t + 1 When the time, t = 2 seconds;
the height of the ball, h(t) =h(2) = -4.9(2)² + 13.1(2) + 1= -4.9(4) + 26.2 + 1= -19.6 + 27.2= 7.6 metres
Therefore, the height of the ball after 2 seconds is 7.6 metres.
b) h(t) = -4.9t² + 13.1t + 1When the height of the ball, h(t) = 0.5 metres; we can write the equation as:
0.5 = -4.9t² + 13.1t + 1
Rearranging,4.9t² - 13.1t + 0.5 - 1 = 0i.e. 4.9t² - 13.1t - 0.5 = 0
Solving using the quadratic formula, t = [-(-13.1) ± √(13.1² - 4(4.9)(-0.5))]/(2(4.9))= [13.1 ± √(171.61)]/9.8≈ 0.138 and t ≈ 2.23
Thus, the ball reaches a height of 0.5 metres twice, at approximately 0.14 seconds and 2.23 seconds.
The given function is f(x) = (x - 2).
a) We can find the inverse of a function by interchanging x and y and then solving for y.
Here, f(x) = (x - 2) so we can write it as x = (y - 2)
Interchanging x and y: x = (y - 2)
Solving for y, we get: y = x + 2
Hence, the inverse function of f(x) is g(x) = x + 2.
b) Domain and range of the function and its inverse
The domain of f(x) is all real numbers. (i.e. -∞ < x < ∞)
The range of f(x) is all real numbers. (i.e. -∞ < f(x) < ∞)
The domain of g(x) is all real numbers. (i.e. -∞ < x < ∞)
The range of g(x) is all real numbers. (i.e. -∞ < g(x) < ∞)
The steps of the solution are given below:
Therefore, the inverse function of f(x) is g(x) = x + 2.
The domain of f(x) is all real numbers, and its range is all real numbers.
Similarly, the domain and range of g(x) is all real numbers.
A farmer has 600 metres of fencing to enclose a rectangular area and divide it into 14 sections.
Let x be the length and y be the width of the rectangle.
a) Write an equation to express the total area enclosed as a function of the length x.
Perimeter of the rectangle = Total fencing = 600 metres2(x + y) = 600i.e. x + y = 300
Solving for y, we get:
y = 300 - x
Thus, the area of the rectangle is A(x) = xy = x(300 - x) = 300x - x²
Therefore, the total area enclosed can be expressed as a function of the length of the rectangle x as A(x) = 300x - x².
b) Determine the domain and range of the area function.
The domain of the function is the set of all possible values of x, which in this case is the set of all positive real numbers. (i.e. 0 < x < 300)
The range of the function is the set of all possible values of A(x), which in this case is the set of all non-negative real numbers. (i.e. 0 ≤ A(x) < ∞)
Therefore, the domain of the area function is (0, 300) and its range is [0, ∞).
The steps of the solution are given below:
Therefore, the total area enclosed can be expressed as a function of the length of the rectangle x as A(x) = 300x - x². The domain of the area function is (0, 300) and its range is [0, ∞).
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Compare each set of rational numbers.
-1
2
✓ -1.5
1
o
2
-2
-1
-1 is a negative real and rational integer.
2 is a positive real number
[tex] \sqrt{ - 1.5} [/tex]
is an imaginary or nonreal number.
1 is rational
0 is rational
2 rational counting number
-2 is a negative integer
and do is -1
Which expression is Equivalent to is m<4?
Answer:
first option
Step-by-step explanation:
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ 4 is an exterior angle of the triangle, then
∠ 4 = ∠ 2 + ∠ 3
please help me find the area
Answer: 150m
Step-by-step explanation: you first remove 5 from 20 to get what you should multiply for your triangle then you get 15 and multiply it by 12 to get 180 then you divide by 2 since it’s a triangle, to get 90 then you find the area of the rectangle by multipling 5 by 12 to get 60 then 60+90=150
Answer:
150 meters
Step-by-step explain
He formula for a triangle is a=bh/2. it ends up being a=12x15/2=90.
The formula for a rectangle is 12x5=60.
You take both and add them together and you get 150.
So the answer is 150 meters.
students devise an appropriate solution or recommendation to be implemented, carefully explaining the logic behind the proposal by applying any criteria of Malcolm Baldrige, EFQM or Sheikh Khalifa Excellence awards. of khawarizmi college
Students of Khawarizmi College are expected to devise an appropriate solution or recommendation to be implemented by carefully explaining the logic behind the proposal by applying any criteria of Malcolm Baldrige, EFQM, or Sheikh Khalifa Excellence awards.
The Malcolm Baldrige Criteria for Performance Excellence was first established in 1987 as a set of practices and strategies for US businesses. They've since been updated and are currently in their 2019-2020 edition. The criteria have been adopted by several other countries and serve as a framework for organizational excellence. The Baldrige Criteria are broken down into seven categories:
LeadershipStrategyCustomer MeasurementAnalysis, Knowledge ManagementWorkforce OperationsResultsThe EFQM Excellence Model is a non-prescriptive business framework for organizational improvement. The framework is intended to assist organizations in developing a culture of continuous improvement by encouraging self-assessment, learning, and creativity. It is based on nine criteria that are classified into three groups:Enablers: leadership, people, strategy, partnerships, and resources.
Results: people results, customer results, society results, and business results; Finally, the Sheikh Khalifa Excellence Awards (SKEA) are given to organizations in the UAE that have demonstrated a strong commitment to quality and excellence in their performance.
You can learn more about Malcolm Baldrige at: brainly.com/question/31317540
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