Let's start solving the given problem. Suppose that an urn contains 3 different types of balls: red, green, and blue. Let pi denote the proportion of red balls, p2 denote the proportion of green balls, and p3 denote the proportion of blue balls.
Here Pi = 1.
Suppose also that 100 balls are selected with replacement, and there are exactly 38 red, 29 green and 33 blue.
We need to find the M.L.E. p; of p1, i = 1, 2, 3.
The probability of obtaining red ball from the urn = pi. The probability of obtaining green ball from the urn = p2. The probability of obtaining blue ball from the urn = p3
Given that, 100 balls are selected with replacement.
Let's calculate the probability of getting 38 red, 29 green, and 33 blue balls from the urn,
P(38 Red and 29 Green and 33 Blue) = P(Red)38 x P(Green)29 x P(Blue)33 = p₁³⁸ x p₂²⁹ x p₃³³
Therefore, the likelihood of obtaining the 38 red, 29 green, and 33 blue balls is L(p1,p2,p3) = p₁³⁸ x p₂²⁹ x p₃³³
Since, L(p1,p2,p3) is a continuous function, so we have to find the critical points of the function to obtain the minimum value of p₁. Let's take natural logarithm on both sides of the function, we get ln
L(p1,p2,p3) = 38 ln p₁ + 29 ln p₂ + 33 ln p₃.
So, taking partial differentiation with respect to p1, p2 and p3 and equating them to 0. We get the following equations,∂ ln L / ∂p1 = 38/p1 = 0∂ ln L / ∂p2 = 29/p2 = 0∂ ln L / ∂p3 = 33/p3 = 0On
solving the above three equations, we get p1 = 38/100 = 0.38p2 = 29/100 = 0.29p3 = 33/100 = 0.33
Therefore, P₁= 0.38, S= 0.29, P3 = 0.33. Hence, the required solution is P₁= 0.38, S= 0.29, P3 = 0.33.
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" Let set A be the set of all real numbers. For all x and y in A, xRy | xl sy. Determine if the relation is each of these and explain why or why not. (a) Reflexive YES NO (b) Symmetric YES NO
"
Relation of each of these are:
(a) Reflexive: NO
(b) Symmetric: YES
(a) Reflexive: No.
The relation R is not reflexive because there exist elements x in set A for which x is not related to itself. For example, if we take x = 0, then 0 is not less than or equal to 0, so xRx does not hold.
(b) Symmetric: Yes.
The relation R is symmetric because for any x and y in set A, if xRy holds, then yRx also holds. This is because if x is less than or equal to y, then y is greater than or equal to x, satisfying the symmetry property of the relation.
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Guided Practice
Fill in the blank.
(z−4)(2z+1)=[tex]2z^{2}[/tex]− ___ z−4
A.
7z
B.
9
C.
7
Answer: Gradpoint answer
C.
7
Step-by-step explanation: Math.way answer
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
Exact Form:
z = 0 , 7/ 4
Decimal Form:
z = 0 , 1.75
Mixed Number Form:
z = 0 , 1 3/ 4
Answer:
7
Step-by-step explanation:
(z – 4)(2z + 1) = z(2z + 1) – 4(2z + 1) = 2z2 + z – 8z – 4 = 2z2 – 7z – 4
The second term is –7z, so 7 fills in the blank.
В обращении находится 250 карандашей по 8 д. ед. за единицу, 500 ручек по 12 д. ед. за единицу, 2000 тетрадей по 10 д. ед. за единицу и 412 дневников по 14 д. ед. за единицу. Найти количество денег необходимых для обращения.
Answer:
Ты русский? на этом сайте только американцы они тебе не помогут ни чем
Step-by-step explanation:
Please Answer This, the question is on the picture. it needs to be a fraction
will mark brainllest if its right, no links!
Answer:
x = 19.5 or 19 1/2
Step-by-step explanation:
cos 41 = 14.7/x
x = 19.5
Hi, can someone please help, and possibly explain the answer please.
Answer:
[tex]x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}[/tex]
Step-by-step explanation:
Quadratic formula: [tex]x=\frac{-b\±\sqrt{b^2-4ac} }{2a}[/tex] when the equation is [tex]0=ax^2+bx+c[/tex]
The given equation is [tex]1=-2x+3x^2+1[/tex]. Let's first arrange this so its format looks like [tex]y=ax^2+bx+c[/tex]:
[tex]1=-2x+3x^2+1[/tex]
[tex]1=3x^2-2x+1[/tex]
Subtract 1 from both sides of the equation
[tex]1-1=3x^2-2x+1-1\\0=3x^2-2x+0[/tex]
Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:
[tex]x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}[/tex]
I hope this helps!
The answer is 3/4 What could the question be?
Answer:
how many brain cells do you have compared to the average person?
Step-by-step explanation:
- Andrew plays on a basketball team. In his final game, he scored of
2/5
the total number of points his team scored. If his team scored a total
of 35 total points, how many points did Andrew score?
h
A:35
B:14
C:21
D:25
Answer: 14
Step-by-step explanation:
to find the answer we must figure out what half of 35 points is because Andrew scored 2/5 of 35.
we can write the equation like this:
2/5 of 35 = Andrew's points
2/5 of 35 = 14
therefore 2/5 of 35 is 14
therefore Andrew scored 14 points.
A 13 meter ladder is leaning against a wall. It reaches 12 meters up the wall How far is the base of the ladder from the base of the wal
Answer:
5
Step-by-step explanation:
Pythagorean Theorem. The 13-meter ladder is leaning against a wall, so it's the hypotenuse.
It reaches 12 meters up, so 12 is one leg.
[tex]a^{2} +b^{2}=c^{2}[/tex]
[tex]a^{2}+12^{2}=13^{2}[/tex]
[tex]a^{2}+144=169[/tex]
[tex]a^{2}=25[/tex]
a = 5
The scale on a drawing is 1 cm = 4.5 meters. If the length of the drawing is 6.2 cm, what is the actual length in meters?
Answer:
I think the awnser is 27.9
Step-by-step explanation:
4.5*6.2=27.9
Someone plz help me giving brainliest
Answer
Use the fact that 45 times 1/9 = 5. Them multiply by 8 to get the answer, 40.
Step-by-step explanation:
Recall the set T form part 1 of the test: T = {(z,y) € NxN: 1≤z+y≤ 4, z 21 and y ≥ 1}. Moreover, recall the joint pmf of two discrete random variables X and Y: Pxy (z,y) = P(X = 1, Y = y) = { (1+y), if (r,y) eT 0, otherwise. (a) (1 pt) Briefly explain why X and Y are dependent random variables. (b) (2 pts) Compute E[XY]. (c) (2 pts) Determine the covariance of X and Y. Hint. Use the marginal pmf you obtained from part 1 (along with symmetry between X and Y).
(a) Explanation: In order to prove that X and Y are dependent random variables, we need to show that: pX,Y(x,y)≠pX(x)pY(y) when (x,y) ∈ T which means the joint probability of X and Y is not equal to the product of the marginal probability of X and Y.
For (x,y) ∈ T, pX,Y(x,y) = P (X=1, Y=y) = 1+y
But pX(x) = P(X=1) = Σ pX,Y(1, y) = Σ (1+y)
where the summation is taken over all y for which (1, y) ∈ T. For (1,1) ∈ T,
we get pX,Y(1,1) = 2 and pX(1) = Σ pX,Y(1,y) = 2 + 3 = 5. So, pX,Y(1,1) ≠ pX(1)pY(1) which implies that X and Y are dependent random variables.
(b) E[XY] = Σ Σ xy pX,Y(x,y) where the summation is taken over all x and y for which pX,Y(x,y) > 0.
Substituting the values, we get, E[XY] = Σ Σ xy (1+y) where the summation is taken over all (x,y) ∈ T.
So, E[XY] = (1+1) (1+1) + (1+2) (1+2) + (1+3) (1+3) = 2*2 + 3*4 + 4*6 = 2 + 12 + 24 = 38.
(c) Covariance of X and Y can be determined as follows: Cov(X,Y) = E(XY) - E(X)E(Y)Now, E(X) = Σ x pX(x) and E(Y) = Σ y pY(y)
Substituting the values, we get E(X) = 5/9 and E(Y) = 20/9
Therefore, Cov(X, Y) = E(XY) - E(X)E(Y) = 38 - (5/9) (20/9) = 38 - 100/81 = 998/81.
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Help me please! I will give 20 points and Brainliest!
Given the arithmetic sequence of -21,-6,9,24,... , find an explicit rule for the nth term
Answer:
n = -21 + 15(n-1)
7) Determine if the polynomials below are in the point polynomial time Justynach an! (points ==-+ 2022 in Riel (b) 3 points / 20021011.101 +2022 in C[x]. (c) 3 points] /= x+ 2022 in F7649[*] (Note that 7649 is prime. (d) pon-2 +3 in (e) [4 points] / -6° - 21x + 700 in Q[*]. (f) 14 points) f = 625x3 - 6633r2 + 86- 8855 in Qlur).
Let us check the given polynomials for point polynomial time as follows:
(a) Justynach an! (points ==-+ 2022 in Riel) This polynomial is not in point polynomial time because there is no condition on the polynomial and points.
(b) 3 points / 20021011.101 +2022 in C[x] This polynomial is not in point polynomial time because the given points are not on the polynomial.
(c) /= x+ 2022 in F7649[*] This polynomial is in point polynomial time because it is a monic polynomial and the given point is on the polynomial.
(d) pon-2 +3 This polynomial is not in point polynomial time because it is a constant polynomial and there are no points to verify.
(e) [4 points] / -6° - 21x + 700 in Q[*] This polynomial is in point polynomial time because all the points are on the polynomial.
(f) f = 625x3 - 6633r2 + 86- 8855 in Qlur. This polynomial is in point polynomial time because all the points are on the polynomial.
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Provide an appropriate response, Compute the standardized test statistic x 2 to test the claim o 2.38.7 it n - 12. 52-32.4, and a -0.05. O 0.492 12.961 18.490 9.209
The standardized test statistic is 12.961
To test the claim that σ = 2.38.7 with n - 12, a = -0.05 and 52-32.4,
we need to calculate the standardized test statistic.
The appropriate response is 12.961.
So, the standardized test statistic is calculated as follows:
`x = (n - 1)s² / σ²`
Where `n` is the sample size, `s` is the sample standard deviation, and `σ` is the population standard deviation.
`n = 12, s = 52 - 32.4 = 19.6, and σ = 2.38.7`
Then, `x² = (12 - 1)(19.6)² / (2.38.7)² = 12.961`
Therefore, the appropriate response is 12.961`.
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The probability of having a pet is 40%, if you knew that anyone
who has a pet visits a vet (vet means animals' doctor)
with probability =90%. Then the probability of having a pet and
visiting a vet is
The probability of both having a pet and visiting a vet is 0.36 or 36%.
To find the probability of both having a pet and visiting a vet, we multiply the probability of having a pet by the probability of visiting a vet given that the person has a pet.
Let:
P(pet) = probability of having a pet = 40% = 0.40
P(vet | pet) = probability of visiting a vet given that the person has a pet = 90% = 0.90
The probability of having a pet and visiting a vet is given by:
P(pet and vet) = P(pet) * P(vet | pet)
P(pet and vet) = 0.40 * 0.90
P(pet and vet) = 0.36
Therefore, the probability of both having a pet and visiting a vet is 0.36 or 36%.
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What is an outcome variable in a survey project? What
is its purpose?
In a survey project, an outcome variable refers to the variable that represents the main focus or result of interest in the study.
What is an outcome variable?In a survey project, the outcome variable, otherwise known as the dependent variable, represents the main focus or result of interest.
It is the variable researchers seek to measure or predict based on the collected data. The purpose of an outcome variable is to provide insights into the specific aspect being studied, enabling researchers to understand relationships between independent variables and the outcome.
Analyzing the outcome variable allows for drawing conclusions, identifying patterns, and determining the impact of various factors. It serves as a crucial metric for evaluating success, making informed decisions, and drawing meaningful conclusions from the survey findings.
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Can you construct a triangle that has side lengths 4 m, 5 m, and 9 m? yes no
Answer:
Yes
Step-by-step explanation:
A triangle can have any side lengths as long as they all touch to make a triangle
Answer:
yes
Step-by-step explanation:
you just had to divide then subtract
9. Find x. Round answer to nearest whole number.
A) 58
B) 59
C) 60
D) 61
Answer:
the answer. is 60 because you round of 64
fill in the blank.one dimension, ________blank, is used to classify social media and is shown in figure 20-1 on the x-axis, ranging from "words" to "animation."
One dimension, called "media richness," is used to classify social media and is shown on the x-axis of Figure 20-1. It ranges from "words" to "animation" and represents the level of interactivity and information.
In the context of social media, the concept of media richness refers to the degree of richness or complexity in the communication channel. It is a measure of the ability of a medium to convey information effectively, facilitate understanding, and support interaction between users.
Media richness is influenced by factors such as the presence of nonverbal cues, immediate feedback, personalization, and the capacity for multiple communication channels. Figure 20-1 likely represents a graphical representation or classification of social media based on their media richness.
The x-axis of the figure represents the continuum of media richness, ranging from "words" to "animation." At one end of the spectrum, "words" represent text-based communication platforms that primarily rely on written content. As we move towards the other end, "animation" represents media that incorporate rich visual and interactive elements such as videos, graphics, and multimedia features.
By placing different social media platforms along this dimension, Figure 20-1 provides a visual representation of their relative media richness levels. It helps in understanding the varying capabilities and characteristics of different social media platforms and their potential for communication, engagement, and information sharing.
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NEED HELP PLEASE AND THANK YOU.
40% of my grade
What is the relationship between the angles?!!???
If $120.99 is charged for 654 units of electricity used,find the cost of one unit of electricity
Answer: 0.185
Step-by-step explanation:
Divide 120.99 and 654:
120.99÷654=0.185
So the final answer is 0.185 units.
In a recent year, a research organization found that 300 of the 433 respondents who reported earning less than $30,000 per year said they were social networking users. At the other end of the income scale, 353 of the 546 respondents reporting earnings of $75,000 or more were social networking users. Let any difference refer to subtracting high-income values from low-income values. Complete parts a through d below. Assume that any necessary assumptions and conditions are satisfied.
a) Find the proportions of each income group who are social networking users.
The proportion of the low-income group who are social networking users is ____
The proportion of the high-income group who are social networking users is_____
(Round to four decimal places as needed.)
b) What is the difference in proportions? _____(Round to four decimal places as needed.)
c) What is the standard error of the difference? _____(Round to four decimal places as needed.)
d) Find a 99% confidence interval for the difference between these proportions. _____
The proportion of the low-income group who are social networking users is approximately 0.6928, and the proportion of the high-income group who are social networking users is approximately 0.6464.
a) To find the proportions, we divide the number of social networking users in each income group by the total number of respondents in that group. For the low-income group, the proportion is 300/433 ≈ 0.6928. For the high-income group, the proportion is 353/546 ≈ 0.6464.
b) The difference in proportions is obtained by subtracting the proportion of the high-income group from the proportion of the low-income group. The difference is approximately 0.6928 - 0.6464 = 0.0464.
c) The standard error of the difference can be calculated using the formula SE = √[(p1(1-p1)/n1) + (p2(1-p2)/n2)], where p1 and p2 are the proportions of social networking users in each group, and n1 and n2 are the sample sizes of each group. Plugging in the values, we get SE ≈ √[(0.6928(1-0.6928)/433) + (0.6464(1-0.6464)/546)] ≈ 0.0348.
d) To construct a confidence interval for the difference between the proportions, we can use the formula CI = (difference ± critical value × SE). For a 99% confidence level, the critical value can be found using a standard normal distribution table, which is approximately 2.576. Plugging in the values, we get the 99% confidence interval ≈ (0.0464 ± 2.576 × 0.0348) ≈ (0.0464 ± 0.0685).
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99 times the sum of v and 9
Answer:
Step-by-step explanation:
99(v + 9) is all you need here.
A Ferris wheel car moves from point C to point D on the circle shown below:
Circle A is shown with points C and D on the circle and the central angle C A D marked 42 degrees. The diameter is 30 feet.
HELP NOW!! 100 POINTS!!! What is the arc length the car traveled, to the nearest hundredth?
7.91 feet
8.32 feet
10.99 feet
11.89 feet
Answer:
10.99
Step-by-step explanation:
Took the test and it said it was this one :)
The arc length of the car traveled, to the nearest hundredth is 10.99feet
The formula for calculating the length of an arc is expressed as:
L = theta/360 × 2pi r
Given that
Radius r = d/2 = 30/2 =15ft
theta = 42 degrees
pi = 3.14
Substitute the given values into the formula as shown
L = 42/360×2(3.14)(15)
L = 42/360×94.2
L = 3956.4/360
L = 10.99feet
This shows that the arc length of the car traveled, to the nearest hundredth is 10.99feet
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What is the surface area of this right rectangular prism glass slab with dimensions of 20 inches by 3 inches by 12 inches?
a.576
b.588
c.672
d.648
Answer:
C. 672
Step-by-step explanation:
Answer:
C) 672
Step-by-step explanation:
the Question is on the image
(1 point) how many different ways can a race with 8 runners be completed? (assume there is no tie.)
There are 40,320 different ways the race with 8 runners can be completed.
To determine the number of different ways a race with 8 runners can be completed, we can use the concept of permutations.
In a race with no tie, the order in which the runners finish matters. We want to find the number of permutations of 8 runners.
The formula to calculate permutations is given by n!, where n represents the number of items being permuted.
In this case, there are 8 runners, so the number of different ways the race can be completed is:
8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40,320.
Each permutation represents a unique arrangement of the runners crossing the finish line. By considering the order of finish for each runner, we account for all possible outcomes in the race.
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A formula of order for approximating the first derivative of a function f gives FO) - 4.50557 for h=1 f(0) - 2.09702 for h=0.5 By using Richardson's extrapolation on the above values, a better approximation of '(0) is: 0.97318 1.00177
A better approximation of f'(0) using Richardson's extrapolation is -6.91412.
To find a better approximation of f'(0) using Richardson's extrapolation, we can apply the formula:
[tex]R(1,1) = f'(h) + (f'(h) - f'(2h))/((1/2)^1 - 1)[/tex], where h is the step size.
Given the values:
f'(1) = -4.50557 (for h = 1)
f'(0.5) = -2.09702 (for h = 0.5)
Let's calculate R(1,1):
[tex]R(1,1) = f'(1) + (f'(1) - f'(0.5))/((1/2)^1 - 1)\\ = -4.50557 + (-4.50557 - (-2.09702))/(2 - 1)\\ = -4.50557 + (-2.40855)/1\\ = -4.50557 - 2.40855\\ = -6.91412.[/tex]
Therefore, a better approximation of f'(0) using Richardson's extrapolation is -6.91412.
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Solve the inequality below and identify the correct answer: X - 2<-4
Answer:
x < -2 ?
Step-by-step explanation: