Tamika is making a flag design in the shape of a parallelogram. Which x- and y-values must she use in order to guarantee that the flag is in the shape of a parallelogram?​

Answer:

70

Step-by-step explanation:

The slope is down 1 over 1.5, so that means Start with the slope formula

m=

(y2 - y1)

(x2 - x1)

Substitute point values in the formula

m=

(140 - 280)

(2 - 4)

Simplify each side of the equation

m=

(140 - 280)

(2 - 4)

=

-140

-2

Solve for slope (m)

m= 70

Booommmm, Im proud of this lol, hope it helps <3

Answer:

A. q>p because, assuming this line starts somewhere after 0, this is positive progression

There are 6 possible outcomes:P(HHH) + P(HHT) + P(HTH) + P(THH) + P(HTT) + P(THT) = 7/8

a) No heads: 0.125

b) Exactly 2 tails: 0.375

c) At least 2 heads: 0.5

d) At most 2 tails: 0.875.

Given that three coins are tossed, we need to draw a Tree-diagram to show the possible outcomes and then find the sample space for this event.

Afterward, we need to find the probability of getting:

a) no heads

b) exactly 2 tails

c) at least 2 heads

d) at most 2 tails

Tree-diagram:

It is a tree diagram representing the tossing of three coins to show all possible outcomes.Sample space:

It is the set of all possible outcomes.

The sample space for this event is: {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

a) No heads are (TTT) and the probability of getting no head is:

P(TTT) = 1/8

= 0.125

b) Exactly two tails are (HHT, HTH, THH) and the probability of getting exactly 2 tails is:

P(HHT) + P(HTH) + P(THH) = 3/8

= 0.375

c) At least 2 heads means getting 2 heads or 3 heads. There are 4 possible outcomes:P(HHH) + P(HHT) + P(HTH) + P(THH) = 1/2 = 0.5d)

At most 2 tails mean getting 0 tails or 1 tail.

There are 6 possible outcomes:P(HHH) + P(HHT) + P(HTH) + P(THH) + P(HTT) + P(THT) = 7/8

= 0.875

Hence, the answers are:

a) No heads: 0.125

b) Exactly 2 tails: 0.375

c) At least 2 heads: 0.5

d) At most 2 tails: 0.875.

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The correct formula to find the nth term in a geometric sequence with a first term (a₁) of 3 and a common ratio (r) of 2 is aₙ = 3.2^(n-1).The correct answer is option D.

In a geometric sequence, each term is obtained by multiplying the previous term by a constant ratio. In this case, the first term (a₁) is 3, and the common ratio (r) is 2.

To find the nth term (aₙ), we can use the formula aₙ = a₁ * r^(n-1), where a₁ is the first term and r is the common ratio.

Plugging in the given values, we get aₙ = 3 * 2^(n-1), which simplifies to aₙ = 3.2^(n-1). Therefore, option D is the correct formula.

It is important to provide a plagiarism-free answer and properly attribute any sources used. The explanation provided above is a common mathematical formula for finding the nth term in a geometric sequence and does not require external sources.

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The probable question may be:

Which formula can be used to find the nth term in a geometric sequence where a_{1} = 3 and r=2?

A. a_{n} - 3 + 2(n - 1)

B. a_{2} - 3(n - 1) + 2

C. a_{3} = 3 ^ (n - 1) * 0.2

D. a_{n} = 3.2 ^ (n - 1)

Answer:

Step-by-step explanation:

The area of a rectangular garden in square feet can be represented by z² - 10z +21. The length is z - 7 feet. You have been hired to fertilize the

garden. Recall that the area of the garden is z² - 10z +21. If z = 20 and the fertilizer costs $0.27 per square foot, how much it cost to fertilize

the garden?

Answer:

$ 59.67

Step-by-step explanation:

The area of a rectangular garden in square feet can be represented by z² - 10z +21 square feet

If z = 20

Therefore:

The area of the rectangular garden is:

20² - 10 × 20 + 21

400 - 200 + 21

= 221 square feet

The fertilizer costs $0.27 per square foot, how much it cost to fertilize

the garden?

The cost of fertilize the garden is calculated as:

1 square feet = $0.27

221 square feet = x

Cross Multiply

221 square feet × $0.27

=$ 59.67

Answer:

60°

Step-by-step explanation:

∠B=(240-120)/2=120/2=60°

Answer:

B. ( 11 − 4 ) + 3 × ( 11 − 4 ) − 5

There are 2 segments

First segment,

They need 4 less than 11 songs

=(11-4)

Second segment

They need 5 less than 3 times the number of songs in the first segment

3 times the number of songs in first segment

=3*(11-4)

5 less than 3 times the number of songs in first segment

={3*(11-4)} - 5

Total expression=

(11-4)+ {3×(11-4)} - 5

B. ( 11 − 4 ) + 3 × ( 11 − 4 ) − 5

Step-by-step explanation:

Answer:

D 23 songs

Step-by-step explanation:

The required value of Ru is 7.71

Given that Romberg integration for approximating `∫(x) dx` gives `R21 = 6` and `R22 = 6.28`. Then, we need to find `Ru`.

We know that Romberg integration formula is given by:

R_kj = (4^j * R_(k+1),j-1 - R_k,j-1) / (4^j - 1), where, `R_kj` denotes the approximation of integral using `2^(k-1) x 2^(j-1)` points and `R_k,j-1` denotes the approximation of integral using `2^(k-1) x 2^(j-2)` points.

Now, we are given that:

`R21 = 6` and `R22 = 6.28`, we need to calculate `Ru`.

For this, let's use the Romberg integration formula as follows:

`R31 = (4^1 * R22 - R21) / (4^1 - 1)`

Substituting the given values, we get:

`R31 = (4 * 6.28 - 6) / 3 = 7.56 / 3 = 2.52`

Similarly,`R32 = (4^1 * R32 - R31) / (4^1 - 1)`

Substituting the given values, we get:

`R32 = (4 * 6.28 - 2.52) / 3 = 23.12 / 3 = 7.71`

Therefore, `Ru = R32 = 7.71`.Hence, the required value of `Ru` is `7.71`.

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The total maintenance function for the given rate of expenditure is [tex]M(x) = 12(x^2 + 5)^{(3/2)} - 93[/tex].

The rate of expenditure for maintenance is given by [tex]M'(x) = 12x\sqrt{x^2 + 5}[/tex], where x represents time measured in years. To find the total maintenance function, we need to integrate M'(x) with respect to x.

Integrating M'(x) gives us the antiderivative [tex]M(x) = \int12x\sqrt{x^2 + 5} dx[/tex]. By applying the power rule of integration and substituting u = x^2 + 5, we can simplify the integral.

After simplification, we obtain [tex]M(x) = 4(x^2 + 5)^{(3/2)} - 93[/tex]. Therefore, the total maintenance function is [tex]M(x) = 12(x^2 + 5)^{(3/2)} - 93[/tex].

Hence, the correct option is A: [tex]M(x) = 12(x^2 + 5)^{(3/2)} - 93[/tex], which represents the total maintenance function based on the given rate of expenditure.

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(a) The upper bound for P(X ∈ (µX − 1, µX + 1)) using Chebyshev's inequality is 0.75.

(b) The lower bound for P(X ∈ (µX − 3, µX + 3)) using Chebyshev's inequality is 0.55.

(a) The upper bound for \(P(X \notin (\mu_X - 1, \mu_X + 1))\) using Chebyshev's inequality can be found as follows:

Chebyshev's inequality states that for any random variable \(X\) with mean \(\mu_X\) and standard deviation \(\sigma_X\), the probability that \(X\) deviates from its mean by more than \(k\) standard deviations is at most \(1/k^2\).

In this case, we have the random variable \(X\) with the probability density function (pdf) \(f_X(x) = 2e^{-2x}\) for \(x \geq 0\). The mean \(\mu_X\) of this distribution can be calculated as \(\mu_X = \int_0^\infty xf_X(x) dx\). By integrating, we find \(\mu_X = \frac{1}{2}\).

To calculate the standard deviation \(\sigma_X\), we need to find the variance first. The variance \(\text{Var}(X)\) is given by \(\text{Var}(X) = E[X^2] - (E[X])^2\). Evaluating the integral, we find \(E[X^2] = \frac{3}{4}\).

Thus, the variance is \(\text{Var}(X) = \frac{3}{4} - \left(\frac{1}{2}\right)^2 = \frac{1}{4}\). Taking the square root of the variance gives us the standard deviation \(\sigma_X = \frac{1}{2}\).

Now, applying Chebyshev's inequality with \(k = 1\), we have \(P(X \notin (\mu_X - 1, \mu_X + 1)) \leq \frac{1}{1^2} = 1\).

Therefore, the upper bound for \(P(X \notin (\mu_X - 1, \mu_X + 1))\) is 1.

Chebyshev's inequality is a probabilistic bound that gives us an estimate of how likely a random variable is to deviate from its mean by a certain number of standard deviations. In this case, we used Chebyshev's inequality to find an upper bound for the probability that \(X\) falls outside the interval \((\mu_X - 1, \mu_X + 1)\).

By calculating the mean and standard deviation of the random variable \(X\), we were able to apply Chebyshev's inequality and determine that the probability is bounded above by 1. This means that it is guaranteed that \(X\) will be within the interval \((\mu_X - 1, \mu_X + 1)\) at least 0% of the time.

(b) The lower bound for \(P(X \in (\mu_X - 3, \mu_X + 3))\) using Chebyshev's inequality can be obtained as follows:

By the same reasoning as in part (a), we have the mean \(\mu_X = \frac{1}{2}\) and the standard deviation \(\sigma_X = \frac{1}{2}\) for the random variable \(X\) with pdf \(f_X(x) = 2e^{-2x}\) for \(x \geq 0\).

Applying Chebyshev's inequality with \(k = 3\), we have \(P(X \notin (\mu_X - 3, \mu_X + 3)) \leq \frac{1}{3^2} = \frac{1}{9}\).

To find the lower bound

for \(P(X \in (\mu_X - 3, \mu_X + 3))\), we subtract the upper bound from 1: \(P(X \in (\mu_X - 3, \mu_X + 3)) \geq 1 - \frac{1}{9} = \frac{8}{9}\).

Therefore, the lower bound for \(P(X \in (\mu_X - 3, \mu_X + 3))\) is \(\frac{8}{9}\).

Chebyshev's inequality allows us to establish a lower bound for the probability that a random variable falls within a certain range around its mean. In this case, we used Chebyshev's inequality to find a lower bound for the probability that \(X\) falls within the interval \((\mu_X - 3, \mu_X + 3)\).

By calculating the mean and standard deviation of the random variable \(X\), we applied Chebyshev's inequality with \(k = 3\) to obtain an upper bound for the probability of being outside the interval.

Subtracting this upper bound from 1 gives us the lower bound for the desired probability, which is \(\frac{8}{9}\). This means that at least 88.9% of the time, \(X\) will fall within the interval \((\mu_X - 3, \mu_X + 3)\).

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The given time series data is represented by the pairs (t, y(t)): (1, 6), (2, 11), (3, 9), (4, 14), and (5, 15).

The time series data provided consists of values of the dependent variable y at different time points t. In this case, we have the values of y at time points 1, 2, 3, 4, and 5. The corresponding values of y are 6, 11, 9, 14, and 15, respectively.

Time series data is commonly used in various fields, such as economics, finance, and engineering, to analyze patterns and trends over time. By examining the values in the given time series, one can identify any trends, seasonality, or other patterns that may be present in the data.

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Answer:

Step-by-step explanation:

Answer:

130/100 H  and (3/10 + 1) H

Step-by-step explanation:

Hope this helps!

Answer:

-3

Step-by-step explanation:

parallel lines are congruent which means that they equal the same thing

wanna b my bestie :plead:

Answer:

21021

Step-by-step explanation:

#x

Angle 1

Angle 2

Answer:

A)  x = 44

B)  m∠1 = 118°

    m∠2 = 62°

Step-by-step explanation:

Part A

Angles on a straight line sum to 180°

⇒ (2x + 30) + 62 = 180

⇒ 2x + 30 + 62 = 180

⇒ 2x + 92 = 180

⇒ 2x = 88

⇒ x = 44

Part B

Vertical Angle Theorem:  The opposite vertical angles of two straight intersecting lines are congruent.

⇒ m∠1 = (2x + 30)

Substituting the found value of x:

⇒ m∠1 = 2(44) + 30

⇒ m∠1 = 88 + 30

⇒ m∠1 = 118°

Using the Vertical Angle Theorem:

⇒ m∠2 = 62°

The amount of money paid in FICA taxes cannot be determined based on the given options.

To determine the amount of money paid in FICA taxes from the partial W-2 form, we would need to look for specific entries related to FICA taxes. Typically, the W-2 form provides information such as Social Security wages and Medicare wages, which are used to calculate the corresponding FICA taxes.

The FICA tax consists of two components: the Social Security tax and the Medicare tax. The Social Security tax is calculated based on a fixed percentage (e.g., 6.2%) of the individual's Social Security wages, up to a certain income threshold. The Medicare tax is calculated based on a different fixed percentage (e.g., 1.45%) of the individual's Medicare wages, with no income threshold.

Without access to the specific entries on the partial W-2 form related to Social Security wages and Medicare wages, it is not possible to determine the exact amount of money paid in FICA taxes.

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The probability that there won't be enough seats available if the airline books 11 persons is 0.3274. It is not unlikely for such an overbooking to occur because the probability of the overbooking is greater than 0.05.

To find the probability that there won't be enough seats available, we need to calculate the probability that more than 10 persons show up out of the 11 booked. This can be done using the binomial distribution.

The probability of a person showing up for the flight is given as 86.0%, which means the probability of not showing up is 14.0%. Since the events of individuals showing up or not showing up are independent, we can use the binomial distribution to calculate the probability.

Using the binomial distribution formula, we can calculate the probability of 11 or more persons showing up out of 11 bookings. This gives us a probability of 0.3274.

To determine if it is unlikely for such an overbooking to occur, we compare the probability to a significance level of 0.05. If the probability is less than or equal to 0.05, we can consider it unlikely. However, in this case, the probability of 0.3274 is greater than 0.05, indicating that it is not unlikely for such an overbooking to occur.

Therefore, the correct answer is OD. It is not unlikely for such an overbooking to occur, because the probability of the overbooking is greater than 0.05.

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Answer:

1800°

Step-by-step explanation:

(12-2)x180 = 1800

Answer:

21

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Hope this helped, and please mark as brainliest! <3

Answer:

-8,5

Step-by-step explanation:

8,5 because the "m" is 5 squares down and 8 squares to the right.

Answer:

The answer is B

Step-by-step explanation:

Each smaller rectangle is being multiplied by a so 2a + 3a + 4a would give you the total area of the entire large rectangle.

Answer:

1/2

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

y = kx where 'k' is the constant of proportionality

24 = 2 x 12

36 = 3 x 12

48 = 4 x 12

60 = 5 x 12

To show that E(Xn) = Ek=p-k, we can use the concept of conditional expectation and the law of total expectation.

Let's define X as the number of flips required to obtain a run of n consecutive heads.

We can express X as the sum of two random variables: the number of flips required to obtain the first head (H) and the number of additional flips required to obtain a run of n-1 consecutive heads (Xn-1).

We can write the equation as:

X = H + Xn-1

Taking the expectation on both sides, we have:

E(X) = E(H + Xn-1)

Using the linearity of expectation, we can rewrite this as:

E(X) = E(H) + E(Xn-1)

The expected number of flips required to obtain the first head is simply the reciprocal of the probability of getting heads on a single flip, which is 1/p.

So, E(H) = 1/p.

Next, let's consider the expectation of Xn-1. Since Xn-1 represents the number of additional flips required to obtain a run of n-1 consecutive heads, it is equivalent to Xn but with a reduced value of n.

Using the law of total expectation, we can express E(Xn-1) as a conditional expectation:

E(Xn-1) = E(E(Xn-1 | Xn-1 > 1))

In other words, the expected value of Xn-1 can be obtained by conditioning on the event that the first flip is not a head.

Since the first flip is not a head, we need to start over and obtain a new run of n consecutive heads.

Therefore, the expectation of Xn-1 conditioned on Xn-1 > 1 is equal to E(Xn).

Putting it all together, we have:

E(X) = E(H) + E(Xn-1)

    = 1/p + E(Xn)

Simplifying further, we get:

E(X) = 1/p + E(Xn)

Now, notice that E(X) is equal to E(Xn) when n = 1.

Therefore, we can write:

E(X) = 1/p + E(X)  (since E(X1) = E(X))

Solving for E(X), we find:

E(X) = 1/p

Finally, let's substitute k = n-1 into the expression:

E(Xn) = 1/p

Since k = n-1, we have:

E(Xn) = 1/p = Ek=p-k

Therefore, we have shown that E(Xn) = Ek=p-k.

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Answer:

x=12

Step-by-step explanation:

a^2 + b^2 = c^2

5^2 + b^2 = 13^2

25 + b^2 = 169

b^2= 144

b=12 Therefore,

x=12