The dot plots below show the test scores of some mathematics students and some science students:

Based on visual inspection of the dot plots, which group of students appears to have the larger average score?

The mathematics students
The science students
Both groups are similar.
Not enough information is available to draw a conclusion.

1. The probability of at least 25/40 members voting against the resolution is 0.92114

2. the probability of at least 25/40 members voting for the resolution is 0.92114.

We are to find the probability of the following events:

First, we find the number of members who are likely to vote against the resolution from each party.

Number of members from Party A who would vote against the resolution = 60% of 60 = 0.60 × 60 = 36.

Number of members from Party B who would vote against the resolution = 25% of 80 = 0.25 × 80 = 20.

Thus, the total number of members who would vote against the resolution = 36 + 20 = 56.

Number of members who would vote in favor of the resolution = Total members − Number of members who would vote against the resolution= 60 + 80 − 56 = 84.

Let X be the number of members voting against the resolution. If X follows a binomial distribution with n = 40 and p = 56/140 = 0.4, we can find the probability of the events as follows:

1. The probability of at least 25/40 members voting against the resolution:

P(X ≥ 25) = 1 − P(X < 25)

We can use the binomial distribution table to find the probabilities associated with different values of X.

P(X < 25) = P(X = 0) + P(X = 1) + ... + P(X = 24)

Using the binomial distribution formula, we get:

P(X = k) = (nCk) × pk × (1 − p)n−k, where nCk is the number of ways of choosing k members out of n.

Using the formula, we can calculate the probabilities of P(X < 25) and P(X ≥ 25) as follows:

P(X < 25) = 0.000236 + 0.003226 + 0.020408 + 0.076306 + 0.182424 + 0.291878 + 0.338993 + 0.245031= 0.078858P(X ≥ 25) = 1 − P(X < 25)= 1 − 0.078858= 0.92114

Thus, the probability of at least 25/40 members voting against the resolution is 0.92114

2.The probability of at least 25/40 members voting for the resolution:

P(X ≥ 25) = 1 − P(X < 25)

We can use the binomial distribution table to find the probabilities associated with different values of X.P(X < 25) = P(X = 0) + P(X = 1) + ... + P(X = 24)

Using the binomial distribution formula, we get:

P(X = k) = (nCk) × pk × (1 − p)n−k, where nCk is the number of ways of choosing k members out of n.

Using the formula, we can calculate the probabilities of P(X < 25) and P(X ≥ 25) as follows:

P(X < 25) = 0.000236 + 0.003226 + 0.020408 + 0.076306 + 0.182424 + 0.291878 + 0.338993 + 0.245031= 0.078858

P(X ≥ 25) = 1 − P(X < 25)= 1 − 0.078858= 0.92114

Thus, the probability of at least 25/40 members voting for the resolution is 0.92114.

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Answer:

30% or none of these

Step-by-step explanation:

since least of the girls voted for biking it would be the least percent amount.

Hope this helped and have a wonderful day! <3 :))

Answer:

188

Step-by-step explanation:

10*5*4 - 6*2

Answer:

Step-by-step explanation:

3 7 11 15 19 23 27

Answer:

Step-by-step explanation:

h

Answer:

I believe x would be 30

Step-by-step explanation: When you add 20+10 it will give you the other triangle side, which is  30, and then 22+11 will be 33. And for the final side 24+12 will give you 36

The point that is NOT 5 units away from the point (1,4) is (4,0).

Answer:

[tex]y=0.01(4)^x[/tex]

Step-by-step explanation:

Solution: Any value for a variable that makes the equation true.

Reciprocal: Focuses on the use of multiplication and division

Coefficient: A number that is multiplied by a variable in an algebraic expression is a coefficient

Term: A term of an algebraic expression is a number, variable, or product of numbers and variables

Base: The base of a power is the factor that is multiplied repeatedly in the power.

Hope this helps, and have a great day!

Answer:

Solution: any value for a variable that makes an equation true

Reciprocal: focuses on use of multiplication and division

Coefficient: A number being multiplied by a variable in an algebraic expression

Base: the base of a power is a factor that is multiplied repeatedly in power

u got the term definition right

Step-by-step explanation:

The proportion of the low-income group who are social networking users is 0.6514.

The proportion of the high-income group who are social networking users is 0.6144.

We have the following information from the question:

A research organization found that 228 of the 350 respondents who reported earning less than $30,000 per year said they were social networking users.

Another income scale, 290 of the 472 respondents reporting earnings of $75,000 or more were social networking users.

We have to find proportions of each income group who are social networking users.

Low-income group:

228 users / 350 respondents = 0.6514

The proportion of the low-income group who are social networking users is 0.6514.

High-income group:

290 users / 472 respondents = 0.6144

The proportion of the high-income group who are social networking users is 0.6144.

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Similar: If two pairs of corresponding angles in a pair of triangles are congruent, then the triangles are similar. We know this because if two angle pairs are the same, then the third pair must also be equal. When the three angle pairs are all equal, the three pairs of sides must also be in proportion.

____________________________________________________________

Congruent: SAS stands for "side, angle, side" and means that we have two triangles where we know two sides and the included angle are equal. If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.

Answer:

null

Step-by-step explanation:

Answer: 0=53

Step-by-step explanation:

Answer:

look below I got it right

Step-by-step explanation:

look carefully, for some people it’s a, for some it’s different so just look and compare to the answers

Answer:

B 136.8 cm²

Step-by-step explanation:

Add the diameters of the three smaller circles to find the diameter of the largest circle.

D = 3 cm + 2.5 cm + 1.1 cm = 6.6 cm

area = πr²

area = 3.14 × (6.6 cm)²

area = 136.8 cm²

Answer:

50.37

Step-by-step explanation:

Answer: 50.37

Step-by-step explanation:

The probability that a poker hand from a well-shuffled deck is a flush is 0.00198.

The probability that Anne is bluffing, given that at least one player is bluffing is 1.95.

a) Probability that a poker hand from a well-shuffled deck is a flush:

Consider the following points for a poker hand from a well-shuffled deck is a flush:

There are 4 suits in a deck of cards.

There are 13 denominations in each suit.

When choosing a flush hand, any of the suits can be selected.

Therefore, the probability of choosing a suit is: P(Suit) = 4/4 = 1.

Therefore, the probability of selecting a suit is 1.The first card may be of any denomination. Therefore, the probability of selecting any denomination is 1.

Since all 5 cards must have the same suit, the second card must be of the same suit as the first card. Therefore, the probability of selecting the second card of the same suit is:

P(Same Suit) = 12/51

The third card must also be of the same suit as the first card and second card. Therefore, the probability of selecting the third card of the same suit is:

P(Same Suit) = 11/50

The fourth card must also be of the same suit as the first card, second card, and third card. Therefore, the probability of selecting the fourth card of the same suit is:

P(Same Suit) = 10/49

The fifth card must also be of the same suit as the first card, second card, third card, and fourth card. Therefore, the probability of selecting the fifth card of the same suit is:

P(Same Suit) = 9/48

Multiplying all probabilities together, we have:

P(Suit) × P(Same Suit) × P(Same Suit) × P(Same Suit) × P(Same Suit)= 1 × 12/51 × 11/50 × 10/49 × 9/48= 0.00198

Therefore, the probability that a poker hand from a well-shuffled deck is a flush is 0.00198.

Ans: 0.00198.

b) Probability that Anne is bluffing, given that at least one player is bluffing:

Consider the following points for the probability that Anne is bluffing, given that at least one player is bluffing:

Anne has a 20% chance of bluffing.

Barney has a 30% chance of bluffing.

The two players bluff independently.

P(Anne is bluffing) = 20/100 = 1/5P(Barney is bluffing) = 30/100 = 3/10

Let A be the event that Anne is bluffing and B be the event that Barney is bluffing.

Let C be the event that at least one player is bluffing.

P(C) = 1 - P(none is bluffing) = 1 - (1 - P(Anne is bluffing)) × (1 - P(Barney is bluffing))= 1 - (1 - 1/5) × (1 - 3/10)= 1 - (4/5) × (7/10)= 1 - 28/50= 22/50= 11/25

Now, P(A ∩ C) = P(A) × P(C|A)

Where P(C|A) is the probability that at least one player is bluffing given that Anne is bluffing.= (3/10 + 7/10 × 4/5) / (1 - 4/5)= (3/10 + 28/50) / (1/5)= (15/50 + 28/50) / (1/5)= 43/50 × 5= 215/50

Therefore, P(A|C) = P(A ∩ C) / P(C)= 215/50 × 25/11= 1.95

Therefore, the probability that Anne is bluffing, given that at least one player is bluffing is 1.95. Ans: 1.95.

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82sq ftAnswer:

Step-by-step explanation:

Answer:

18 times  a green bead is drawn

Step-by-step explanation:

There are 20 beads in the basket.  The probability of picking a green bead is 6/20 = 3/10.  That means that a green bead would be picked 3/10 of the time.

So, 3/10(60) = 18 times  a green bead is drawn

Answer:

-1, 3, -3

Step-by-step explanation:

I don't see the graph, but you can solve by factoring:

[tex]x^3+x^2-9x-9=0\\x^2(x+1)-9(x+1)=0\\(x+1)(x^2-9)=0\\(x+1)(x+3)(x-3)=0[/tex]

By the factor theorem, the solutions of f(x) are -1, 3, and -3.

The requried solutions of x³ + x² - 9x - 9 = 0 is x = -3, -1, 3. Option C is correct.

Simplification involves applying rules of arithmetic and algebra to remove unnecessary terms, factors, or operations from an expression.

Here,
To find the solutions of equation x³ + x² - 9x - 9 = 0, we need to find the x-intercepts of the graph of the function f(x) = x³ + x² - 9x - 9.

From the graph, we can see that the function intersects the x-axis at three points, which are approximately -3, -1, and 3. Therefore, the solutions of the equation are x = -3, x = -1, and x = 3.

Thus, the correct answer is x = -3, -1, 3.

Options A, B, and D are incorrect because they either do not include all three solutions or include additional solutions that are not present in the graph of the function.

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To find the second derivative of F(x) = [tex]\int\limits^0_x {e^t}^{2} } } \, dx[/tex] dt for x ∈ (0, 1), we can use the fundamental theorem of calculus and apply the chain rule twice. The second derivative is given by F''(x) = [tex]2e^{x^{2} } (1+2x^{2} )[/tex]

To find F''(x), we differentiate F'(x) first. Using the fundamental theorem of calculus, we have F'(x) = [tex]e^{x^{2} }[/tex]. Applying the chain rule, we obtain d/dx([tex]e^{x^{2} }[/tex]) = [tex]2xe^{x^{2} }[/tex].

Now, to find F''(x), we differentiate F'(x) with respect to x. Applying the chain rule again, we have d/dx([tex]2xe^{x^{2} }[/tex]) = [tex]2e^{x^{2} }[/tex] + [tex]4x^{2} e^{x^{2} }[/tex]. Simplifying this expression, we get F''(x) = 2[tex]e^{x^{2} }[/tex](1 + [tex]2e^{x^{2} }[/tex]).

Therefore, the second derivative of F(x) is given by F''(x) = 2[tex]e^{x^{2} }[/tex](1 + 2[tex]{x^{2} }[/tex]) for x ∈ (0, 1). This result shows that the second derivative is always positive for x ∈ (0, 1), indicating that the function is concave up within that interval.

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The investment choice that carries the greatest price risk is common stocks. (Option-A)

Common stocks are shares of ownership in a company and their price can be very volatile, changing rapidly depending on market conditions and factors affecting the company. Their prices can be influenced by factors such as overall economic conditions, company financial performance, and investor sentiment.

On the other hand, preferred stocks and corporate bonds are typically less risky than common stocks. Preferred stocks are a type of stock that pays a fixed dividend and has a priority claim on company assets in the event of bankruptcy, while corporate bonds are debt instruments that pay a fixed interest rate.

Lastly, government bonds are considered the least risky of all of these investment choices because they are backed by the government, which has a reputation for always repaying its debts.

In summary, while all types of investments carry some level of risk, common stocks have the greatest price risk due to their volatility and sensitivity to changing market conditions.(Option-A)

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The exponential model for the data on Hispanic-owned businesses is N(t) =[tex]1.16 e^{(0.084t)[/tex], where t represents the number of years since 1999 and N(t) is the number of businesses in millions.

To find an exponential model for the data, we need to fit it into the general form of an exponential function: N(t) = ae^(kt).

Let's assign t = 0 to correspond to the year 1999 and N(t) represents the number of businesses in millions. We are given two data points: (t=0, N=1.16) and (t=4, N=1.53).

Plugging in the first data point, we have:

1.16 = ae^(k*0) => 1.16 = a.

Next, plugging in the second data point, we get:

1.53 = ae^(4k).

Now, we can substitute a = 1.16 into the second equation:

1.53 = 1.16  e^(4k).

Dividing both sides of the equation by 1.16:

1.32 = e^(4k).

Taking the natural logarithm (ln) of both sides:

ln(1.32) = 4k.

Solving for k:

k = ln(1.32)/4.

Now, we have the values of a = 1.16 and k = ln(1.32)/4. Therefore, the exponential model for the data is:

N(t) = 1.16 * e^((ln(1.32)/4) * t), where t represents the number of years since 1999, and N(t) is the number of businesses in millions.

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Answer:

1/2

Step-by-step explanation:

Paso Uno: [tex]\frac{5}{1}* \frac{5}{1} *\frac{5}{1}* \frac{5}{1} *\frac{5}{1}[/tex]* 1/10= 5/10

Paso Dos: Simplificar:

5/5=1

10/5=2

Paso Tres: fracción es 1/2

Answer:

B. 525 L

Step-by-step explanation:

The solutions are:  (A U B)' = {1, 7, 8, 9} and (A ∩ B) x A = {(3, 2), (3, 3), (3, 4), (4, 2), (4, 3), (4, 4)}.

a. (A U B)' represents the complement of the union of sets A and B. To find (A U B)', we need to list all the elements in the universal set U that are not in the union of sets A and B. The union of sets A and B, A U B, includes all the elements that are in either set A or set B (or both). So, A U B = {2, 3, 4, 5, 6}. The complement of A U B, (A U B)', will contain all the elements in the universal set U that are not in the set A U B. Therefore, (A U B)' = {1, 7, 8, 9}.

b. (A ∩ B) x A represents the Cartesian product of the intersection of sets A and B with set A. To find (A ∩ B) x A, we need to list all possible ordered pairs that can be formed by selecting one element from the intersection of sets A and B and pairing it with an element from set A. The intersection of sets A and B, A ∩ B, contains the elements that are common to both sets A and B. In this case, A ∩ B = {3, 4}.

Now, we take each element from A ∩ B and pair it with each element from set A. So, (A ∩ B) x A = {(3, 2), (3, 3), (3, 4), (4, 2), (4, 3), (4, 4)}. Therefore, (A U B)' = {1, 7, 8, 9} and (A ∩ B) x A = {(3, 2), (3, 3), (3, 4), (4, 2), (4, 3), (4, 4)}.

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Given:

A circle of radius r inscribed in a square.

To find:

The expression for the area of the shaded region.

Solution:

Area of a circle is:

[tex]A_1=\pi r^2[/tex]

Where, r is the radius of the circle.

Area of a square is:

[tex]Area=a^2[/tex]

Where, a is the side of the square.

A circle of radius r inscribed in a square. So, diameter of the circle is equal to the side of the square.

[tex]a=2a[/tex]

So, the area of the square is:

[tex]A_2=(2r)^2[/tex]

[tex]A_2=4r^2[/tex]

Now, the area of the shaded region is the difference between the area of the square and the area of the circle.

[tex]A=A_2-A_1[/tex]

[tex]A=4r^2-\pi r^2[/tex]

[tex]A=4r^2-\pi r^2[/tex]

[tex]A=r^2(4-\pi )[/tex]

Therefore, the correct option is (a).

The solution to the system of equations is (x, y) = (-4, 6).

To solve the system using the addition method, we want to eliminate one variable by adding or subtracting the equations.

Let's solve it step by step:

First, let's multiply the second equation by 6 to make the coefficients of x in both equations equal:

6(x + 5y) = 6(26)

6x + 30y = 156

Now, we can add the modified second equation to the first equation:

(-6x - 8y) + (6x + 30y) = -24 + 156

The -6x and 6x terms cancel each other out:

-8y + 30y = 132

Simplifying the equation further:

22y = 132

To solve for y, divide both sides of the equation by 22:

y = 132 / 22

y = 6

Now that we have the value of y, we can substitute it back into either of the original equations.

Let's use the second equation:

x + 5(6) = 26

x + 30 = 26

x = 26 - 30

x = -4

Therefore, the solution to the system of equations is (x, y) = (-4, 6).

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Complete question =

Solve the system with the addition method:

-6x - 8y = - 24

x + 5y = 26

Answer: (x,y)

Step-by-step explanation:

IN ΔAMN ΔABC

Since MN∣∣BC

∠AMN=∠ABC (Corresponding angles)

∠ANM=∠ACB (Corresponding angles)

∴ΔAMN∼ΔABC(By $$AA similarity criterion)

⇒

AB

AM

=

AC

AN

=

BC

MN

(CPST)

Since, M is mid-point of AB,

AM=

2

1

AB,or,

AB

AM

=

2

1

or,

AB

AM

=

AC

AN

=

2

1

AC

AN

=

2

1

5

AN

=

2

1

[∵AC=5cm]

AN=

2

5

cm=2.5cm

Also,

AB

AM

=

BC

MN

=

2

1

7

MN

=

2

1

[∵BC=7cm]

MN=

2

7

=3.5

Ans=AN=2.5cm and MN=3.5cm

solution

The answers are =

1) False.

2) The closest value to 2.14 would be the appropriate critical T-value for a 95% confidence interval.

1) False.

An investor in the stock market is more likely to prefer a distribution of returns that are right-skewed rather than a normal distribution.

A right-skewed distribution means that there is a higher probability of large positive returns, which is desirable for investors seeking higher profits. In the stock market, there is a phenomenon called "positive skewness," where large gains are more likely than large losses.

Investors typically aim to maximize their returns, and a right-skewed distribution offers the potential for higher returns compared to a normal distribution, which has equal probabilities for gains and losses.

2) The critical T-value for a 95% confidence interval, given a sample size of 15, is closest to 2.14. The critical T-value is determined by the desired confidence level and the degrees of freedom, which is the sample size minus 1. In this case, the sample size is 15, so the degrees of freedom would be 15 - 1 = 14. Looking up the critical T-value in a T-distribution table or using statistical software, the closest value to 2.14 would be the appropriate critical T-value for a 95% confidence interval.

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