The structure supports a distributed load of 15 kN/m. The limiting stress in rod (1) is 370 MPa, and the limiting stress in each pin (a, b, c) is 200 MPa.
The given information provides details about the distributed load and the limiting stress in the components of the structure. The distributed load of 15 kN/m indicates that the structure is subjected to a uniform force distribution along its length. This load is essential to consider when analyzing the stress and deformation of the components.
In the structure, rod (1) has a limiting stress of 370 MPa. This implies that the maximum stress that rod (1) can withstand without experiencing failure or deformation is 370 MPa. Therefore, it is crucial to ensure that the stress induced by the applied load does not exceed this limit in order to maintain the structural integrity of rod (1).
Furthermore, each pin (a, b, c) has a limiting stress of 200 MPa. Pins are often used to connect and support structural elements, such as beams and rods. The limiting stress of 200 MPa indicates the maximum stress these pins can endure before they fail. It is necessary to ensure that the stresses on the pins caused by the load distribution and their respective connections do not surpass this threshold to prevent pin failure.
To design a safe and reliable structure, engineers must consider these limiting stresses and ensure that the applied loads and resulting stresses are within the permissible limits for both rod (1) and the pins (a, b, c). By carefully analyzing the structural components and their stress distributions, suitable materials and design modifications can be implemented to meet the required safety standards and ensure the longevity of the structure.
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Surface areas 98 Find the shaded area. Round to the nearest tenth if necessary. 22 mm 18 mm 9 mm
Answer:
297 sq mm
Step-by-step explanation:
Area of Rectangle: 22 x 18 = 396
Area of Triangle: (1/2)(22)(9) = 99
Area of Rectangle - Area of Triangle = Area of Shaded area
396 - 99 = 297
Which logarithmic equation correctly rewrites this exponential equation?
Answer:
A. [tex] log_{8}(64) = x[/tex]
Step-by-step explanation:
[tex] {8}^{x} = 64 \\ \\ \implies log_{8}(64) = x[/tex]
Ms. Clark spent $89.85 on sewing kits that cost $5 each plus $4.85 tax on the total bill. How many kits did she buy?
The sewing kits bought by Ms, Clark is 17 in number.
What are equation models?The equation model is defined as the model of the given situation in the form of an equation using variables and constants.
Here,
As given in the question, Ms. Clark spent $89.85 on sewing kits that cost $5 each plus $4.85 tax on the total bill.
Let the number of sewing kits be x,
According to the question,
5x + 4.85 = 89.85
5x = 89.85 - 4.85
5x = 85
x = 17
Thus, the sewing kits bought by Ms, Clark is 17 in number.
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plssss help
answer it plssssssssss
What type of continuous distribution (normal, positively or negatively skewed, bimodal, exponential) would best represent the following situations? a) The age of people who have retired. b) The number of red Smarties in boxes of Smarties. c) The shoe sizes of Stouffvillians. d) The wait time between calls to Pizza Pizza.
If the continuous distribution is given then The age of people who have retired represents Normal distribution.
a) The age of people who have retired would likely follow a normal distribution, as it tends to have a symmetric bell-shaped curve.
b) The number of red Smarties in boxes of Smarties would have a discrete distribution, as it can only take on certain whole numbers and cannot be fractionally or continuously measured.
c) The shoe sizes of Stouffvillians may exhibit a bimodal distribution, as there might be two distinct peaks indicating two groups with different average shoe sizes.
d) The wait time between calls to Pizza Pizza could potentially follow an exponential distribution, as it is often used to model the time between events in a Poisson process, such as the arrival of phone calls. The distribution would have a long tail, representing longer wait times occurring less frequently.
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The roots of 3x2 + x = 14 are
1. imaginary
2. real,rational,equal
3.real,rational,unequal
4.real,irrational,unequal
Answer:
3
Step-by-step explanation:
3x2 +x −14 = 0 12 −4(3)(−14) = 1+168 =169 = 132
The roots of 3x² + x = 14 are real, irrational and unequal
What is Quadratic equation?A quadratic equation is a second-order polynomial equation in a single variable x, ax² + bx +c=0 with a ≠ 0 .
Given equation is :
3x² + x = 14
3x² + x - 14=0
we have, a=3, b=1 c=-14
D= b²-4ac
= 1²-4*3*(-14)
= 1+168
= 169
As, D>0
Hence, the roots are real.
Now,
x= -b±√b²-4ac/2a
= -1±√169/2*3
=-1±13/6
x= -1-13/6 and x= -1+13/6
x= -7/3 and x= 12/6=2
Hence, the roots are real, irrational and unequal.
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What is the area of the polygon given below
Identify each scatterplot below with an appropriate value of r.
Answer:
A would be the answer
Step-by-step and
help please! i dont understand how i'm supposed to fill the table if i dont have all the information
Solve: 4x^2 = 32 thanks
Answer:
D.Step-by-step explanation:
It is difficult to describe, but you just need to follow through the steps acorddingly.On a coordinate grid, a scale drawing of a banner is shaped like a parallelogram with verticals at (-15,10), (0,-5), (30,-5), and (15,10. Each square on the grid represents 1 square inch. What is the area of the banner?
The area of the banner is 562.5 square units.
To calculate the area of the banner, we can divide it into two triangles and then find the sum of their areas.
First, let's calculate the base and height of each triangle:
Triangle 1: Vertices (-15,10), (0,-5), and (30,-5)
The base of Triangle 1 is the distance between (-15,10) and (30,-5), which is 30 - (-15) = 45 units.
The height of Triangle 1 is the distance between (-15,10) and (0,-5), which is 10 - (-5) = 15 units.
Triangle 2: Vertices (0,-5), (30,-5), and (15,10)
The base of Triangle 2 is the distance between (0,-5) and (15,10), which is 15 units.
The height of Triangle 2 is the distance between (0,-5) and (30,-5), which is 30 - 0 = 30 units.
Now, let's calculate the area of each triangle using the formula for the area of a triangle: Area = (base * height) / 2.
Area of Triangle 1 = (45 units * 15 units) / 2 = 337.5 square units
Area of Triangle 2 = (15 units * 30 units) / 2 = 225 square units
Finally, to find the total area of the banner, we sum the areas of the two triangles:
Total Area = Area of Triangle 1 + Area of Triangle 2
Total Area = 337.5 square units + 225 square units
Total Area = 562.5 square units
Therefore, the area of the banner is 562.5 square units.
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Victoria ate 4\16 of a small pizza for lunch. How is this fraction written as a decimal?
Answer:
0.25
Step-by-step explanation:
4/16 --> 1/4 and 1/4 = 0.25
How would I do this??
The list below shows the number of miles Chris rode his bike on each of nine consecutive days. 9, 3, 1, 4, 8, 2, 6, 8, 5
Read the questions and write your answer for each part. Make sure to label each part: Part A, Part B and Part C. Write your answers in complete sentences.
Part A: Create a box-and-whisker plot with the above data. You may use the snipping tool to use the number line shown, or you may use a different number line. Upload your box-and-whisker plot using the "insert" or "+" option.
Part B: How far does Chris need to ride on the 10th day to have a mean distance of 6 miles? Show or explain your work.
Part C: On the 10th day, if Chris rides 20 miles, how will this change the mean?
A box-and-whisker plot needs to be created. To have a mean distance of 6 miles on the 10th day, Chris needs to ride a specific distance. If Chris rides 20 miles on the 10th day, it will change the mean distance.
Part A: To create a box-and-whisker plot, we need to arrange the given data in ascending order: 1, 2, 3, 4, 5, 6, 8, 8, 9. The plot will consist of a box representing the interquartile range (from the first quartile to the third quartile), a line within the box representing the median, and whiskers extending to the minimum and maximum values (excluding outliers if any).
Part B: To determine how far Chris needs to ride on the 10th day to have a mean distance of 6 miles, we need to consider the current total sum of distances and the total number of days. By calculating the difference between the desired mean and the current mean, we can determine the additional distance Chris needs to ride on the 10th day.
Part C: If Chris rides 20 miles on the 10th day, it will change the mean distance. The extent of the change in the mean depends on the initial data. To calculate the new mean, we need to include the additional distance (20 miles) and recalculate the mean using the updated total sum of distances and the total number of days.
Note: Without knowing the total number of days and the current sum of distances, precise calculations for Parts B and C cannot be provided.
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Answer!!!!! Help!!!
Answer:
The answer is postulate
What is the area of this tile
Answer:
12 in^2
Step-by-step explanation:
Answer: 12in^2
Step-by-step explanation:
The augmented matrix of a system of linear equations AX = B was reduced to upper-triangular form so that 2 1 0 1 2 [AB] 0 -1 31 0 0 mln where m and n are real numbers. State all values of m and/or n such that the following statements are true. (a) Matrix A is invertible. (b) The system AX = B has no solutions. (c) The system AX = B has an infinite number of solutions. (d) Columns of the augmented matrix (AB) are linearly independent. (e) The system AX = 0 has a unique solution. (f) At least one eigenvalue of the matrix A is zero. (g) Columns of the matrix A form a basis in R3.
a. Matrix A is invertible when |A| = -m ≠ 0 then statement true.
b. The system AX = B has no solution when m = 0 and n ≠ 0 has a real number then statement true.
c. The system AX = B has an infinite number of solutions when m = n = 0 then statement true.
d. Columns of the augmented matrix (AB) are linearly independent when m ≠ 0 and n= 0 then statement true.
e. The system AX = 0 has a unique solution when m ≠ 0 then statement true.
f. At least one eigenvalue of the matrix A is zero when m = 0 then statement true.
g. Columns of the matrix A form a basis in R³ when m ≠ 0 then statement true.
Given that,
The augmented matrix of a system of linear equations AX = B was reduced to upper-triangular form so that
[A|B] = [tex]\left[\begin{array}{ccc}2&1&0 \ | \ 2\\0&-1&3 \ | \ 1 \\0&0&m \ | \ n\end{array}\right][/tex]
Where m and n are real numbers.
We know that,
a. We have to prove matrix A is invertible.
For A to be invertible.
|A| ≠ 0
|A| is the determinant of the matrix A.
|A| = 2(-m) -1(0) + 0(0) = -m
Here, m is the real number.
So, |A| = -m ≠ 0
Therefore, Matrix A is invertible when |A| = -m ≠ 0 then statement true.
b. We have to prove the system AX = B has no solution.
When Rank[A|B] > Rank[A]
m = 0 and n ≠ 0 has a real number
Therefore, The system AX = B has no solution when m = 0 and n ≠ 0 has a real number then statement true.
c. We have to prove the system AX = B has an infinite number of solutions.
When m = n = 0, and Rank[A] < 3
Therefore, The system AX = B has an infinite number of solutions when m = n = 0 then statement true.
d. We have to prove columns of the augmented matrix (AB) are linearly independent.
When m ≠ 0 and m∈R and n= 0
Therefore, Columns of the augmented matrix (AB) are linearly independent when m ≠ 0 and n= 0 then statement true.
e. We have to prove the system AX = 0 has a unique solution.
When [tex]\left[\begin{array}{ccc}2&1&0 \\0&-1&3 \\0&0&m \end{array}\right]\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}0\\0\\0\end{array}\right][/tex]
The equation are 2x + y = 0, -y + 3z = 0 and mz = 0
m ≠ 0 should be any real number except zero.
Therefore, The system AX = 0 has a unique solution when m ≠ 0 then statement true.
f. We have to prove at least one eigenvalue of the matrix A is zero.
When λ = 2, 1, m
m = 0 then eigen value is zero
Therefore, At least one eigenvalue of the matrix A is zero when m = 0 then statement true.
g. We have to prove columns of the matrix A form a basis in R³.
When m ≠ 0
Therefore, Columns of the matrix A form a basis in R³ when m ≠ 0 then statement true.
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regression analysis was applied and the least squares regression line was found to be ŷ = 400 3x. what would the residual be for an observed value of (2, 402)?
The Residual for an observed value of (2, 402) is -4.
The regression analysis and the least squares regression line was found to be ŷ = 400 3x.
The observed value is (2, 402).To find the residual for an observed value of (2, 402),
we need to use the formula for residual
Residual = Observed value - Predicted value
where Observed value = (2, 402) , Predicted value = ŷ = 400 + 3x , Putting x = 2 in the above equation
we get,
ŷ = 400 + 3(2) = 406
Now, Residual = Observed value - Predicted value= 402 - 406= -4
Therefore, the residual for an observed value of (2, 402) is -4.
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Find the GCF of the monomials: 18x² and 21x²y
A)3x
B)3x²
C)3xy
D)3x²y
PLEASE HELP MEEE
How much money would produce $70 as simple interest at 3.5% per
annum?
Answer:
$2000
Step-by-step explanation:
Simple Interest = $70
Rate = 3.5%
Time = 1
Principal = ?
Simple Interest = (Principal × Rate × Time)/100
Principal = (Simple Interest × 100)/(Rate × Time)
Principal = (70 × 100)/(3.5 × 1)
Principal = 7000/3.5
Principal = 14000/7
Principal = 2000
Determine a series of transformations that would map Figure C onto Figure D plz help asap
Answer:
Rotation about 180*
Translation about 7 units to the right and 8 down
Step-by-step explanation:
someone please help!
Answer:
12 units
Step-by-step explanation:
1st, I found the distance for the two parallel sides on the hexagon. I counted the lines to be 2 units each, which makes 4 units. And since all sides of a hexagon are equal. All the sides make 12 units, or centimeters. Therefore, the perimeter is 12 units
Thomas walks 10 miles in 120 minutes. Select all of the unit rates below that
describe Thomas' walk. Show your work.
a) He can walk 1 mile in 12 minutes
b) He can walk 12 miles in 1 minute
c) He can walk of a mile in 1 minute
1
d) it takes him of a minute to walk 1 mile
12
12
Answer:
Hi! The answer to your question is B) He can walk 12 miles in 1 minute.
To find Unit rate divide the biggest number by the smallest; Example: [tex]120/10[/tex]
Step-by-step explanation:
☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆
☆Brainliest is greatly appreciated!☆
Hope this helps!!
- Brooklynn Deka
How many different ways can you have 55¢ in change using only quarters, dimes and nickels?
A. 1
B. 5
C. 11
D. 15
Answer: 11 times
Step-by-step explanation:
Have a wonderful day!
a circle has an arc of length 48π that is intercepted by a central angle of 120°. what is the radius of the circle? enter your answer in the box. 72 units
The radius of the circle is 144 units.
To find the radius of the circle, we can use the formula that relates the circumference of a circle to its radius and the central angle intercepted by an arc.
The formula is:
Arc length = 2πr * (θ/360)
Where:
Arc length is the length of the intercepted arc
r is the radius of the circle
θ is the central angle in degrees
In this case, we are given that the arc length is 48π and the central angle is 120°. Let's substitute these values into the formula and solve for r:
48π = 2πr * (120/360)
Simplifying the equation:
48 = 2r * (120/360)
48 = r * (1/3)
r = 48 * 3
r = 144
Therefore, the radius of the circle is 144 units.
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Find the perimeter of 13.2 yd, 6.2 yd, 11yd
Answer: 900.24
Step-by-step explanation:
Perimeter=L•W•H
Jacob distributed a survey to his fellow students asking them how many hours they'd spent playing sports in the past day. He also asked them to rate their mood on a scale from 0 to 10, with 10 being the happiest. A line was fit to the data to model the relationship.
Which of these linear equations best describes the given model?
Choose 1 answer:
5x+1.5
1.5x+5
−1.5x+5
Based on this equation, estimate the mood rating for a student that spent 2.52, point, 5 hours playing sports.
Round your answer to the nearest hundredth.
Answer:8.75
Step-by-step explanation:
Answer: it’s B
Step-by-step explanation:
Help!! please. will mark brainstest
Answer:(1,0)
Step-by-step explanation:
Just help me please?!?!?!
Answer:
the last one
Step-by-step explanation:
I need help please
What is the area?
____ Square millimeters