Use the Chain Rule to find dw/dt.
w = xey/z, x = t7, y = 6 − t, z = 4 + 9t
dw/dt =

Answers

Answer 1

The value of dw/dt is  [tex]e^\frac{y}{z}(7t^6- \frac{x}{z} + \frac{-9xy}{z^2} )[/tex]

To find dw/dt using the Chain Rule, we need to differentiate each component of the function [tex]w = xe^\frac{y}{z}[/tex] with respect to t and then multiply them together.

Given:

[tex]w = xe^\frac{y}{z}[/tex]

x = t⁷

y = 6 - t

z = 4 + 9t

Let's find dw/dt step by step:

x = t⁷

Taking the derivative of x with respect to t:

dx/dt = 7t⁶

y = 6 - t

Taking the derivative of y with respect to t:

dy/dt = -1

z = 4 + 9t

Taking the derivative of z with respect to t:

dz/dt = 9

[tex]w = xe^\frac{y}{z}[/tex]

Taking the derivative of w with respect to x:

[tex]\frac{dw}{dx} =e^\frac{y}{z}[/tex]

[tex]w = xe^\frac{y}{z}[/tex]

Taking the derivative of w with respect to y:

[tex]\frac{dw}{dy} = (\frac{x}{z} )e^\frac{y}{z}[/tex]

[tex]w = xe^\frac{y}{z}[/tex]

Taking the derivative of w with respect to z:

[tex]\frac{dw}{dz} = (\frac{-xy}{z^2} )e^\frac{y}{z}[/tex]

Apply the Chain Rule to find dw/dt:

dw/dt = (dw/dx)(dx/dt) + (dw/dy)(dy/dt) + (dw/dz)(dz/dt)

Substituting the derivatives we found earlier:

dw/dt [tex]= (e^\frac{y}{z})(7t^6) + (\frac{x}{z} )e^\frac{y}{z}(-1) + (\frac{-xy}{z^2} )e^\frac{y}{z}(9)[/tex]

dw/dt [tex]= e^\frac{y}{z}(7t^6- \frac{x}{z} + \frac{-9xy}{z^2} )[/tex]

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Related Questions

(3/2)^4= in fraction form help pls

Answers

Answer:

81/16

Step-by-step explanation:

A car salesman sells cars with prices ranging from $5,000 to $45,000. The box plot shows the distribution of the numbers of cars he expects to sell over the next 10 years.

The salesman has observed that many students are looking for cars that cost less than $5,000. If he decides to also deal in cars that cost less than $5,000 and projects selling 200 of them over the next 10 years, how will the distribution be affected?

A. The mean and the median will be the same.
B. The median will shift to the right.
C. The mean will shift to the left.
D. The mean will shift to the right.

Answers

Answer:
I think is A

Jackson Brothers Auto Dealers sells two brands: Honda and GMC. Over the last 3 months, they have sold 175 autos. The company makes $300 profit on each GMC sold and $450 profit on each Honda. If the company has made $60,750 profit in that time, how many of each type of car have they sold?

Answers

Let x be the number of GMC sold

Let y be the number of Honda soldAccording to the given data, we can form the following equations: x+y = 175         ............ (1)300x + 450y = 60,750 ............ (2)

Multiplying equation (1) by 300 on both sides, we get:300x + 300y = 52,500Subtracting this equation from equation (2), we get:150y = 8,250Solving for y, we get:y = 55Substituting the value of y in equation (1),

we get:x + 55 = 175x = 120Therefore, the number of GMCs sold is 120 and the number of Hondas sold is 55.

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The company have sold 50 GMC and 125 Honda for this profit.

Let the number of GMC sold be x and the number of Honda sold be y.

Then:

[tex]x + y = 175[/tex]----------------------(1)

GMC: Profit on one car sold = $300

Therefore, the total profit on x GMC cars sold = $300x

Honda: Profit on one car sold = $450

Therefore, the total profit on y Honda cars sold = $450y

Total profit on x GMC and y Honda sold = $60,750

Therefore, we can write:

[tex]300x + 450y = 60,750[/tex]----------------(2)

Multiplying (1) by 450 and subtracting it from (2) multiplied by 100, we get:

[tex]-150x = 7,500⇒ x = 50[/tex]

Substituting the value of x in (1), we get:

[tex]y = 175 - 50= 125[/tex]

Therefore, the number of GMC sold is 50 and the number of Honda sold is 125.

They have sold 50 GMC and 125 Honda.

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For the given margin of error and confidence level, determine the sample size required. Show your answer in the integer form. You wish to estimate the proportion of shoppers that use credit cards. Obtain a sample size that will ensure a margin of error of at most 0.065 for a 92.5% confidence interval.

Answers

The sample size required to ensure a margin of error of at most 0.065 for a 92.5% confidence interval is 523.

To estimate the proportion of shoppers using credit cards with a desired margin of error and confidence level, determining the appropriate sample size is crucial.

In this scenario, we aim to achieve a margin of error of no more than 0.065 for a 92.5% confidence interval. The sample size required to fulfill these criteria is 523.

To comprehend the significance of these calculations, it's essential to understand the concepts of margin of error and confidence level. The margin of error represents the maximum amount of uncertainty we can tolerate in our estimate.

In this case, we want our estimate of the proportion of shoppers using credit cards to be accurate within ±0.065. A smaller margin of error indicates greater precision in our estimate.

The confidence level, on the other hand, reflects the level of certainty we have in the accuracy of our estimate.

A confidence level of 92.5% implies that if we were to repeat the sampling process numerous times, we would expect approximately 92.5% of the resulting confidence intervals to contain the true proportion of credit card-using shoppers.

The formula to calculate the sample size required for a proportion estimation is based on the desired margin of error, confidence level, and an assumed proportion (usually 0.5 for maximum variability).

This formula incorporates a z-value, which corresponds to the desired confidence level. For a 92.5% confidence level, the z-value is approximately 1.81.

By plugging the values into the formula and solving for the sample size, we find that a sample size of 523 is necessary to estimate the proportion of shoppers using credit cards with a margin of error no greater than 0.065 and a confidence level of 92.5%.

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What is the ratio of yellow butterflies to total butterflies? Choose the correct option

Answers

Answer:2/3

Step-by-step explanation: there is 2 yellow out of 3 butterfiles

Solve the problem. Use synthetic division and the remainder theorem to determine if [x−(3−2i)] is a factor of f(x)=x2−6x+13. Select one: a. No b. Yes

Answers

Using synthetic division and the remainder theorem, we can determine if [x−(3−2i)] is a factor of f(x)=x^2−6x+13.

To determine if [x−(3−2i)] is a factor of f(x)=x^2−6x+13, we can use synthetic division. First, we need to rewrite the given factor in the form x - c, where c is the conjugate of 3 - 2i, which is 3 + 2i.

Performing synthetic division with 3 + 2i as the divisor: f(x)=x^2−6x+13, we can use synthetic division. First, we need to rewrite the given factor in the form x - c, where c is the conjugate of 3 - 2i, which is 3 + 2i.

Performing synthetic division with 3 + 2i as the divisor:

 3 - 2i  |  1   -6   13

           __________________

           (remainder)

If the remainder is zero, then [x−(3−2i)] is a factor of f(x). However, if the remainder is nonzero, then [x−(3−2i)] is not a factor of f(x). Therefore, based on the result of the synthetic division, we can determine if [x−(3−2i)] is a factor of f(x).

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please help me .......​

Answers

Answer:

A

Step-by-step explanation:

Can someone help me on this I’m struggling to figure it out...

Answers

Answer:

It's D

Step-by-step explanation:

HELPPPPPPPPPPPPP meeeee please

Answers

Step-by-step explanation:

5. 4b = b + b + b + b (A)

4b = 2b + 2b (C)

6. 111 = 14a

a = 111/14

a = 7.92

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PLEASE HELP!


The blank of y in 17y is 17.



Its either term, variable or coefficient

Answers

The answer is Coefficient because a coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression

In the term, 17y 17 is the coefficient of 17y.

What are coefficients and like terms?

A quantity or number that is combined with a variable is known as a coefficient. The variable is often multiplied by an integer, which is then printed next to it.

Terms that have the same variables raised to the same power are referred to as like terms. The only difference is in the numerical coefficients.

The term 17y together is a variable, In 17y 'y' is also a variable.

In front of 'y' the constant number is 17 and it is called the coefficient of 'y'.

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find the slope. (no units needed)

Answers

Answer: 4/5

Step-by-step explanation: It is 8/10, but if you simplify it, it is 4/5.

Flow many years after the tree is planted does the model predict the tree will reach a height of 65 feet?

Answers

B

this is the answer

Warm-Up: Perpendicular Bisector
1.
What is WY? Explain your reasoning.

Answers

Answer: WY = 27

Step-by-step explanation:

Due to WX being a Perpendicular Bisector WY = WZ

4x - 5 = 2x + 11

Add 5 to both sides

4x = 2x + 16

Subtract 2x from both sides

2x = 16

Divide by 2

x = 8

So 4x - 5 of x = 8

4*8 = 32 - 5 =27

Answer:

27

Step-by-step explanation:

WY = WZ because XZ = XY

[tex]2x + 11 = 4x - 5\\(2x + 11) - 11 = (4x - 5) -11\\2x = 4x - 16\\-2x = -16\\x = 8\\\\WY = 4x - 5\\WY = 4(8) -5\\WY = 32 - 5\\WY = 27[/tex]

Help me with this asp please

Answers

The x-coordinate of the endpoint of the line segment is 2.

The y-coordinate of the endpoint is -6.

To find the x-coordinate of the endpoint of the line segment, we can use the midpoint formula.

Given that one endpoint is at (10, 12) and the midpoint is at (6, 9), we can denote the coordinates of the other endpoint as (x, y).

Using the midpoint formula, we have:

x-coordinate of the endpoint = 2 * x-coordinate of the midpoint - x-coordinate of the known endpoint

x = 2 * 6 - 10

x = 12 - 10

x = 2

To find the y-coordinate of the endpoint of the line segment, we can use the midpoint formula. We know that the midpoint of the line segment is (6, 9) and one endpoint is (10, 12).

Let the coordinates of the other endpoint be (x, y). Using the midpoint formula, we can set up the following equation:

(10 + x) / 2 = 6

Simplifying the equation, we have:

10 + x = 12

Subtracting 10 from both sides:

x = 2

Therefore, the x-coordinate of the endpoint is 2. Now, we need to find the y-coordinate. Since we know that the endpoint is (2, y), we can use the given endpoint (10, 12) to find the y-coordinate:

12 + y / 2 = 9

Subtracting 12 from both sides:

y / 2 = -3

Multiplying both sides by 2:

y = -6

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Use one step of Euler's Method with Ar = .3 to approximate y(1.3) where y(x) is the solution of the differential equation y'(x) = 2xeª — y, with initial data y(1) = 0.

Answers

Using Euler's Method with a step size of 0.3 and the given initial data and differential equation, the approximate value of y(1.3) is 0.3 × 2[tex]e^{0.3[/tex].

To approximate the value of y(1.3) using Euler's Method, we need to take one step with a step size of h and update the y-value accordingly. Here's how to do it step by step:

Determine the step size, h. In this case, we want to approximate y(1.3) using the initial data at y(1). Since we know that x increases from 1 to 1.3, the step size is h = 1.3 - 1 = 0.3.

Calculate the slope at the initial point (x0, y0). The slope can be found using the given differential equation y'(x) = 2x[tex]e^a[/tex] - y. Plugging in the values x0 = 1 and y0 = 0, we get:

y'(1) = 2(1)[tex]e^{0.3[/tex] - 0 = 2[tex]e^{0.3[/tex].

Compute the approximate value of y at the next step. Using Euler's Method, we can update the y-value as follows:

y1 = y0 + h × y'(x0, y0)

= 0 + 0.3 × 2[tex]e^{0.3[/tex].

Evaluating the expression:

y1 = 0.3 × 2[tex]e^{0.3[/tex].

This gives us the approximate value of y(1.3) using Euler's Method with the given initial data and differential equation.

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if f(x) = 1/4x 1 and g(x) = 4(1/4x 1), what is the slope of the graph of g?

Answers

The slope of the graph of the function g(x) is 1, indicating that for every unit increase in x, the corresponding value of g(x) increases by 1.

To find the slope of the graph of the function g(x), we can use the power rule of differentiation. Let's differentiate g(x) step by step:

Step 1: Express g(x) in a simplified form.

g(x) = 4(1/4[tex]x^1[/tex])

Step 2: Simplify the expression.

g(x) = x

Step 3: Differentiate g(x) to find the slope.

The derivative of g(x) with respect to x is simply 1, as the derivative of x with respect to itself is 1.

Therefore, the slope of the graph of g(x) is 1.

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[5 points) X is places in an account which carries a nominal annual interest rate of 2.5% compounded monthly. After five years, the accumulated value is places in an account which earns a nominal annual interest rate of 3.2% compounded quarterly. The value of this account in eight years is $10,000. Find X.

Answers

The initial value of X can be determined using compound interest calculations. X is invested in an account with a nominal annual interest rate of 2.5%, compounded on a monthly basis, for a period of five years. After the initial period, X is then transferred to another account with a nominal annual interest rate of 3.2%, compounded on a quarterly basis, for a total duration of eight years. The approximate value of X at the end of this investment period is $6,573.83.

To solve for X, we will substitute the first equation into the second equation and solve for X. Let's proceed with the calculations:

The first equation is: FV = X(1 + 0.025/12)^(12*5)

The second equation is: $10,000 = X(1 + 0.032/4)^(48)(1 + 0.025/12)^(125)

We can substitute the first equation into the second equation:

$10,000 = [X(1 + 0.025/12)^(125)] * (1 + 0.032/4)^(48)

$10,000 = X * (1 + 0.025/12)^(125) * (1 + 0.032/4)^(48)

Now we can simplify the equation:

$10,000 = X * (1.002083)^60 * (1.008)^32

Divide both sides of the equation by [(1.002083)^60 * (1.008)^32] to solve for X:

X = $10,000 / [(1.002083)^60 * (1.008)^32]

Using a calculator, we can find the value of X:

X ≈ $10,000 / (1.138877 * 1.335893)

X ≈ $10,000 / 1.521364

X ≈ $6,573.83

Therefore, the value of X is approximately $6,573.83.

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What is the distance between A(7, 4) and B(2, −8)?

Answers

Answer:

The distance would 13 square units

Step-by-step explanation:

Well follow the formula

=√(2−1)^2+(2−1)^2

Plug in everything and solve, remeber to follow order of operations

A delivery company purchases a $20,000 van. The value of the van depreciates at a rate of 19% per year. How many years will it take before the van is worth half its original purchase price? Round to the nearest tenth of a year.

A 1.7 years
B 4.0 years
C 3.3 years

Answers

The answer is C because u need to find the prcentage first which is 19%of 20000 is 3800 to find the answer is u need to multiple 3800 with any answer given like 1.7 or 4.0 or 3.3....here u go the answer nearest 10000 is 3.3 year because half of its original price...

The longest run way at an airport has the shape of a rectangle and an area of 1,573,000 sq ft. This run way is 130 feet wide. How long is the run way?

Answers

Answer:

12,100 feet

Step-by-step explanation:

The longest run way at an airport has the shape of a rectangle and an area of 1,573,000 sq ft. This run way is 130 feet wide. How long is the run way?

The area of a rectangle = Length × Width

Width = 130 feet

Area = 1,573,000 sq ft

The Length = Area/Width

= 1,573,000 sq ft/130 feet

= 12,100 feet

Therefore, the runaway is 12,100 feet long.

Find the area of the larger sector.
Round to the nearest tenth.
2559
13.4 miles
Area = [ ? ]miles2
Enter

Answers

Step-by-step explanation:

the formula for the area of a sector is

(x°(r^2)π)/360

with x being the angle

r bring the radius of the circle

(255(13.4)^2π)/360

399.6

Hope that helps :)

Answer:

The answer is 399.6 not 399.4. I put 399.6 as my answer on acellus and I got it right.

While taking inventory at her pastry shop, Aisha realizes that she had 1/4 of a box of baking powder yesterday, but the supply is now down to 1/6 of a box. How much more baking powder did Aisha have yesterday?

Answers

Answer:

1/12

Step-by-step explanation:

[tex]\frac{1}{4} - \frac{1}{6}[/tex]

[tex]\frac{6 - 4}{24}[/tex]

[tex]\frac{2}{24}[/tex]

Converting to its simplest form, divide numerator and denominator by 2 = 1/12

Assuming that the sample variances are continuous measurements, find the probability that a random sample of 30 observations, from a normal population with variance 92= 5, will have a sample variance of s2 that is a) greater than 7.338; b) between 2.766 and 7.883.

Answers

a) chi-square = (30-1) * 7.338 / 5 = 42.456 b) The probability of having a sample variance between 2.766 and 7.883 is the difference between the cumulative probabilities of chi-square2 and chi-square1.

Answer to the aforemention questions

To find the probability in both cases, we need to use the chi-square distribution with n-1 degrees of freedom, where n is the sample size.

a) To find the probability that the sample variance is greater than 7.338, we need to find the upper tail probability of the chi-square distribution.

The chi-square statistic is calculated as:

chi-square = (n-1) * s^2 / sigma^2

In this case, n = 30, s^2 = 7.338, and sigma^2 = 5.

chi-square = (30-1) * 7.338 / 5 = 42.456

b) To find the probability that the sample variance is between 2.766 and 7.883, we need to find the cumulative probability within that range.

First, we calculate the chi-square statistics for both values:

chi-square1 = (30-1) * 2.766 / 5 = 15.359

chi-square2 = (30-1) * 7.883 / 5 = 43.179

The probability of having a sample variance between 2.766 and 7.883 is the difference between the cumulative probabilities of chi-square2 and chi-square1.

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HELP ASAP!!! question in picture!!!

Answers

Answer:

Y=3x-17

Step-by-step explanation:

I graphed it

Factor 8b^3 – 4b^2 a - 18b + 9a completely.

Answers

Answer:

85

Step-by-step explanation:

Answer:

(2b-a)x(2b-3)x(2b+3)

Step-by-step explanation:

-6x - 14 > 10 what is the answer to this problem, please helt

Answers

Answer:

Inequality Form:

x < - 4

Interval Notation:

( − ∞ , − 4 )

Step-by-step explanation:

In a large population of college-educated adults, the mean IQ is 112 with standard deviation 50.62. Suppose 30 adults from this population are randomly selected for a market research campaign. The distribution of the sample mean IQ is: a. approximately Normal, with mean 112 and standard deviation 1.443. b. approximately Normal, with mean 112 and standard deviation 4.564. c. approximately Normal, with mean equal to the observed value of the sample mean and standard deviation 25. d. approximately Normal, with mean 112 and standard deviation 9.241.

Answers

Given:  Population mean IQ = 112Population standard deviation IQ = 50.62Sample size (n) = 30To find: Distribution of the sample mean IQ

The Central Limit Theorem states that for a large sample size, the distribution of sample means will be approximately Normal with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size . Let's calculate the standard deviation of the sample mean IQ:

Standard deviation of sample mean IQ = (Population standard deviation IQ) / √n= 50.62 / √30= 9.241 (approx.)Therefore, the distribution of the sample mean IQ is approximately Normal, with mean 112 and standard deviation 9.241. The correct option is (d).

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Simplify each radical expression, if possible 3v/7-5^4v/7

Answers

Answer:

cannot be simplified

Step -by-step explanation:

[tex]3\sqrt{7} - 5\sqrt[4]{7} \\[/tex]

The indexes are not the same so the radicals cannot be combined.

cannot be simplified

What is the mode of the data set? {102, 102, 100, 94, 102} Enter your answer in the box.

Answers

Answer:

102

Step-by-step explanation:

The mode is the number that appears the most in the data set. 102 appears 3 times while the others only once

what is the true solution to 3 l n 2 l n 8 = 2 l n (4 x)x = 1x = 2x = 4x = 8

Answers

The true solution to the equation is x ≈ 0.688. By simplifying the equation and solving for x, we find the approximate value.

To find the true solution to the equation 3ln(2ln8) = 2ln(4x)x = 1x = 2x = 4x = 8, we need to simplify the equation and solve for x.

First, let's break down the equation step by step:

3ln(2ln8) = 2ln(4x)x = 1x = 2x = 4x = 8

By simplifying each expression, we have:

3ln(ln8) = 2ln(4x)x = x = 2x = 4x = 8

Now, let's focus on the middle expression, 2ln(4x)x. Using the properties of logarithms, we can rewrite it as:

ln((4x)^2) = x

Simplifying further:

ln(16x^2) = x

Exponentiating both sides:

16x^2 = e^x

This is a transcendental equation that cannot be solved algebraically. However, using numerical methods or a graphing calculator, we find the approximate solution:

x ≈ 0.688

Therefore, the true solution to the equation is x ≈ 0.688.

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Which set of numbers cannot represent the lengths of the sides of a triangle A) 7,9,12 B) 8,6,7 C) 8,20,12 D) 10,13,20 The atmospheric pressure on an object decreases as altitude increases. If a is the height (in km) above sea level,then the pressure P(a) (in mmHg) is approximated by P(a) = 760e-0.13a. Determine the atmospheric pressure at8.47 km. Round to the nearest whole unit. .50 ml of a solution are diluted to a volume of 100 ml. The concentration of the dilutedsolution is 2 M. What was the concentration of the original solution?pls answer asap! will mark as brainly ist!! Intuitively, a larger sample should lead to a smaller confidence interval (fixing the level of confidence). Which of the following most accurately gives a reason for this in the mathematics we use to make the confidence interval? And the t'-value associated to the t-distribution goes down because t_n have "smaller tails" as n gets large. (And other aspects remain the same.)r The standard error goes down because of the greater sample size in the denominator. (And other aspects remain the same.) The standard error goes down because the standard deviation of the sample will go down. And the t*-value associated to the t-distribution goes down because t_n have "smaller tails" as n gets large. O The standard error goes down because the standard deviation of the sample will go down. (And other aspects remain the same.) The mean will be more accurate with a larger sample size. The standard error goes down because of the greater sample size in the denominator. And the t-value associated to the t-distribution goes down because t_n have "smaller tails" as n gets large. Consider the relationship between UV exposure (e.g. UV exposure...Consider the relationship between UV exposure (e.g. UV exposure time) and colony formation in trp1-289 yeast plated on SD medium. 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