What is the difference between 3/4 and one

Answers

Answer 1

Answer:

3/4 is 0.75 and 1 is 1

Step-by-step explanation:

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Related Questions

Mrs. Avery is going to randomly select one student from her class to read a poem out loud. There are 15 boys and 13 girls in her class

Answers

The probability of selecting  a girl to read the poem out loud in her class is 46.4% .

To calculate the probability of selecting a girl to read a poem out loud in a class of 28 students, we can use the formula:

Probability = Number of Desirable Outcomes / Total Number of Outcomes

Here, the desirable outcome is selecting a girl to read the poem, and the total outcomes are all the students in the class.

Number of Desirable Outcomes:

Mrs. Avery has 13 girls in her class, so there are 13 desirable outcomes.

Total Number of Outcomes:

Mrs. Avery has 28 students in her class, so there are 28 total outcomes.

Probability = Number of Desirable Outcomes / Total Number of Outcomes

Probability = 13 / 28

Probability = 0.464 or 46.4%

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Note: The complete question is -Mrs. Avery is planning to have one student read a poem out loud in class. She has a class of 28 students, consisting of 15 boys and 13 girls. What is the probability that she will select a girl to read the poem out loud?

Consider the function y = 4x + 5 between the limits of z = 1 and 2 = 5. a) Find the arclength L of this curve: L= Round your answer to 3 significant figures. b) Find the area of the surface of revolution, A, that is obtained when the curve is rotated by 2 radians about the a-axis. Do not include the surface areas of the disks that are formed at z = 1 and a = 5. A Round your answer to 3 significant figures.

Answers

Answer: 84π √(17) (rounded to 3 significant figures)

a) To find the arc length of the given curve we need to first evaluate the derivative of y w.r.t. x:dy/dx = 4. The arclength of the curve is given by L = ∫√(1+(dy/dx)^2) dx The value of dy/dx is already given and hence we can substitute the value and integrate .L = ∫√(1+(4)^2) dx = ∫√(17) dx Between the limits z = 1 and 2, x varies from 9 to 13. We need to substitute these values in the integral. L = ∫√(17) dx = √(17) * [x]9^13= √(17) * [13 - 9]= 4 √(17)Answer: 4√17 (rounded to 3 significant figures)

b) The area of the surface of revolution, A, that is obtained when the curve is rotated by 2 radians about the a-axis is given by:A = ∫2π * y √(1+(dy/dx)^2) dx We know that dy/dx = 4 and the value of y is given by 4x+5.A = ∫2π * (4x+5) √(1+(4)^2) dx= ∫2π * (4x+5) √(17) dx Between the limits z = 1 and 2, x varies from 9 to 13. We need to substitute these values in the integral. A = ∫2π * (4x+5) √(17) dx = 2π * √(17) * ∫(4x+5) dx= 2π * √(17) * [2x^2/2 + 5x]9^13= 2π * √(17) * [(26 + 60) - (18 + 20)]= 84π √(17)

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A half-century ago, the mean height of women in a particular country in their 20s was 62.9 inches. Assume that the heights of today's women in their 20s are approximately normally distributed with a standard deviation of 2.87 inches.
If the mean height today is the same as that of a half-century ago, what percentage of all samples of 21 of today's women in their 20s have mean heights of at least 64.76 inches?
About _____ % of all samples have mean heights of at least 64.76 inches.

Answers

Approximately 0.11 percent of all samples have mean heights of at least 64.76 inches.

Given: 50 years prior, the mean level of ladies in a specific country in their 20s was 62.9 inches. With a standard deviation of 2.87 inches, women in their 20s today have heights that are roughly typical. We must determine the proportion of all 21 samples that have mean heights of at least 64.76 inches among today's women in their 20s. Bit by bit clarification:

Let μ be the mean level of ladies in this day and age and allow n to be the example size. We can find the likelihood of an example mean being more prominent than or equivalent to 64.76 inches utilizing the z-score recipe, as follows: z = (x - μ)/(σ/√n) = (64.76 - 62.9)/(2.87/√21) = 3.06The likelihood that an example of 21 ladies will have a mean level more noteworthy than or equivalent to 64.76 inches is equivalent to the likelihood that a typical irregular variable Z is more noteworthy than or equivalent to 3.06.

This probability is approximately 0.0011, or 0.11 percent, according to a typical normal table or calculator. This means that approximately 0.11 percent of all samples have mean heights of at least 64.76 inches.

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A sample of data with n = 66 observations is used to run a multiple regression with 7 independent variables.
If this data set has SST = 2326.9523 and SSR = 1632.8843, what is the value of the F-statistic for the test of overall significance of this regression relationship?

Answers

The value of the F-statistic for the test of overall significance of this regression relationship is approximately 11.245.

Given:SST = 2326.9523 SSR = 1632.8843 Independent variables = 7

Observations = 66Formula used:F = (SSR/K) / (SSE / (n-K-1))

Where SSR = Regression sum of squares SSE = Error sum of squaresK = Number of independent variables n = Number of observations

To calculate the F-statistic, we first need to calculate SSE which is given by:SSE = SST - SSR = 2326.9523 - 1632.8843 = 693.068

The degrees of freedom for the regression are K and the degrees of freedom for the error term are n - K - 1 = 66 - 7 - 1 = 58

The value of the F-statistic is given by:F = (SSR/K) / (SSE / (n-K-1))= (1632.8843/7) / (693.068 / 58)= 11.245

Therefore, the value of the F-statistic for the test of overall significance of this regression relationship is approximately 11.245.

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The 4th term of an arithmetic sequence is 24 and the 12th term is 56, what is the first term?​

Answers

First term = 12
Solution:
A4 = 24
A12 = 56
An = A1 + (n-1)d; this defines the formula of an arithmetic series
A4 = 24 = A1 + (4-1)d
A4 = 24 = A1 + 3d
A12 = 56 = A1 + (12-1)d
A12 = 56 = A1 + 11d
Subtract A4 from A12 to get d (distance)
(56 = A1 + 11d) - (24 = A1 +3d)
32 = 8d
d = 4
Substitute d = 4 into A4
A4 = 24 = A1 + 3(d)
24 = A1 + 3(4)
24 = A1 + 12
24 - 12 = A1
12 = A1

Answer:

First term = 12

Step-by-step explanation:

A4 = 24

A12 = 56

An = A1 + (n-1)d; this defines the formula of an arithmetic series

A4 = 24 = A1 + (4-1)d

A4 = 24 = A1 + 3d

A12 = 56 = A1 + (12-1)d

A12 = 56 = A1 + 11d

Subtract A4 from A12 to get d (distance)

(56 = A1 + 11d) - (24 = A1 +3d)

32 = 8d

d = 4

Substitute d = 4 into A4

A4 = 24 = A1 + 3(d)

24 = A1 + 3(4)

24 = A1 + 12

24 - 12 = A1

12 = A1

Plz help been stuck for a while now

Answers

13.5 is the answer !

WILL GIVE BRAINLIEST identify the domain of the function

Answers

Answer: The horizontal extent of the graph is -3 to 1, so the domain of f is (-3,1]

Step-by-step explanation:

The range is [-4,0]

a toy rocket is fired into the air from the top of a barn its height H above the ground in yards after T seconds is given by the function h of T is equal to -5 t^2 + 10t + 20
1.what is the maximum height of the rocket
2. how long was the rocket in the air before hitting the ground
3.at what time(s) will the rocket be at a height of 22 yards ​

Answers

Answer:

45

Step-by-step explanation:

x = -30/2(-5)

x = -30/(-10)

x = 3 sec

.

Plug above into equation to find height:

h=-5t^2 + 30t

h=-5*3^2 + 30(3)

h=-5*9 + 30(3)

h=-45 + 90

h=45

You estimate that there are 56 marbles in a jar. The actual amount is 70 marbles. Find the percent error.

Answers

Answer:

80 percent of 70 is 56, so you were 20% wrong?

The percent error is 20%

let me know if you need anything else :)

Can someone help me with this. Will Mark brainliest.

Answers

Answer:

[tex]\sqrt{53}[/tex]

Step-by-step explanation:

Use the distance formula:

[tex]\sqrt{(x1-x2)^2+(y1-y2)^2}[/tex]

plug in (-5,6) for (x1,y1) and (-3,-1) for (x2,y2)

[tex]\sqrt{(-5-(-3))^2+(6-(-1))^2}[/tex]

[tex]\sqrt{4+49}[/tex]

[tex]\sqrt{53}[/tex]

Hope that helps :)

There are some hens and some sheeps are in a farm,total number of animals are 10 and total number of their legs are 32 1.Find number of hens? 2. Find number of sheeps?

Answers

Answer: The number of hens are 4 and number of sheeps are 6

Step-by-step explanation:

Given : Total animals = 10

Total number of legs = 32

Let number of hens = h  and number of sheep = s

Thus h+s = 10    (1)

Now each hen has two legs and each sheep has 4 legs :[tex]2\times h+4\times s=32[/tex]   (2)

Solving for h and s we get:

s = 6 , h =4

Thus number of hens are 4 and number of sheeps are 6








Q2 Solve the following initial value problem 1 y" + 4y = r - sin 3x y(0) = 1, (0) by using method of undetermined coefficients. (10 marks)

Answers

The given initial value problem using the method of undetermined coefficients. The final solution to the initial value problem is y = cos(2x) + x - (1/9)*sin(3x).

To solve the given initial value problem, we begin by finding the general solution to the associated homogeneous equation. The homogeneous equation is given by y'' + 4y = 0. The characteristic equation is obtained by substituting y = e^(mx) into the equation, resulting in the quadratic equation m^2 + 4 = 0. Solving this equation yields two distinct roots: m_1 = 2i and m_2 = -2i. Thus, the general solution to the homogeneous equation is y_h = c_1cos(2x) + c_2sin(2x), where c_1 and c_2 are arbitrary constants.

Next, we assume a particular solution in the form of y_p = Ax + B + Csin(3x) + Dcos(3x), where A, B, C, and D are undetermined coefficients. We substitute this particular solution into the given differential equation and solve for the coefficients. Comparing the coefficients of like terms, we find A = 0, B = 1, C = -1/9, and D = 0.

The particular solution is y_p = x - (1/9)*sin(3x), and the complete solution is obtained by adding the particular solution to the homogeneous solution: y = y_h + y_p. Applying the initial condition y(0) = 1, we find that c_1 = 1 and c_2 = 0. Therefore, the final solution to the initial value problem is y = cos(2x) + x - (1/9)*sin(3x).

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For which values of n does K, the complete graph on n vertices, have an Euler cycle? (b) Are there any K, 's that have Euler trails but not Euler cycles? (c) For which values of rand s does the bipartite graph Khave an Euler cycle?

Answers

(a) The complete graph [tex]K_n[/tex] has an Euler cycle if and only if n is an even number greater than or equal to 2.

(b) There are no complete graphs [tex]K_n[/tex] that have Euler trails but not Euler cycles. A complete graph always has an Euler cycle if it has an Euler trail.

(c) The bipartite graph [tex]K_r[/tex],s has an Euler cycle if and only if both r and s are even numbers greater than or equal to 2.

(a) To determine the values of n for which the complete graph [tex]K_n[/tex] has an Euler cycle, we need to understand the conditions for an Euler cycle to exist in a graph.

An Euler cycle is a closed walk in a graph that visits every edge exactly once and starts and ends at the same vertex. In order for a graph to have an Euler cycle, it must satisfy the following conditions:

All vertices in the graph have even degrees (an even number of edges incident to them).

The graph is connected, meaning there is a path between any two vertices.

Now let's apply these conditions to the complete graph [tex]K_n[/tex].

Degree of Vertices: In a complete graph [tex]K_n[/tex], each vertex is connected to every other vertex. Therefore, each vertex has a degree of n-1, as it is connected to n-1 other vertices. Since n-1 is always an odd number, it means that all vertices in [tex]K_n[/tex] have odd degrees. Hence, [tex]K_n[/tex] does not have an Euler cycle for any value of n.

Connectivity: A complete graph [tex]K_n[/tex] is always fully connected, meaning there is a direct edge between every pair of vertices. Therefore, the connectivity condition is satisfied for any value of n.

Based on these conditions, we can conclude that the complete graph [tex]K_n[/tex] does not have an Euler cycle for any value of n.

(b) since [tex]K_n[/tex] does not have an Euler cycle for any value of n, it also implies that there are no [tex]K_n[/tex] graphs that have Euler trails but not Euler cycles.

(c) The bipartite graph [tex]K_r[/tex],s is a complete bipartite graph with two sets of vertices, one with r vertices and the other with s vertices. To have an Euler cycle in this bipartite graph, the following conditions must be met:

All vertices in each set have even degrees.

The number of vertices in each set must be equal.

Since the complete bipartite graph [tex]K_r[/tex],s has all vertices with degree s in one set and degree r in the other set, it means that both r and s must be even numbers for all vertices to have even degrees. Additionally, the number of vertices in each set must be equal for the graph to be bipartite. Therefore, an Euler cycle exists in the bipartite graph [tex]K_r[/tex],s if and only if both r and s are even numbers.

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please answer asap
i will mark brainliest
Which equation can be used to solve for in the following diagram?
Choose 1 answer:
А) 105 + (50 – 70) = 90
B) 105 + (5x – 70) = 180
C) 105 = (5x – 70)
D) 105 +90 = (5x - 70)

Answers

Answer:

C) 5x-70=105

Step-by-step explanation:

As marked in the graph, angle 105 and angle (5x-70) equal to each other because they are vertically opposite angles therefore we have equation C)


C) 105 = (5x – 70)
Seems correct

I don’t have time to do it help me please

Answers

Answer:

4=3  5=10 6= YOu would add more dots accordingly 7=4

Step-by-step explanation:

hoped this helped!

If c ⊥ b and a || c, what is m∠2?

Answers

Answer:

A) 90°

Step-by-step explanation:

if lines b and c are perpendicular then all 8 angles measure 90 degrees


7
not using theorem in book. prove statement:
Let n be an integer. If a and b are integers such that a is
divisible by n and b is divisible by a, then a − b is divisible by
n

Answers

To prove the statement, let's assume that a and b are integers such that a is divisible by n and b is divisible by a.

Since a is divisible by n, we can write a = kn for some integer k.

Similarly, since b is divisible by a, we can write b = am for some integer m.Now, let's find the difference a - b:

a - b = kn - am

Factoring out common terms, we get:

a - b = n(k - m)

Since k and m are integers, their difference (k - m) is also an integer.

Therefore, we have expressed a - b as the product of n and an integer (k - m), which means that a - b is divisible by n.

Hence, we have proved that if a and b are integers such that a is divisible by n and b is divisible by a, then a - b is divisible by n, without using any specific theorem from a book.

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2.07x2.4 plz help quick i need this

Answers

Answer:

2.07x2.4=4.968

Step-by-step explanation:

Answer:

4.968

Step-by-step explanation:

Figure out the x-intercept and y-intercept in given equation of the line.
6x + 2y = 12

Answers

Answer:

x intercept=2

y intercept=6

Step-by-step explanation:

to find x and y intercepts, plug in 0 for x and y

x intercept-

6x+2(0)=12

6x=12

x=2

y intercept-

6(0)+2y=12

2y=12

y=6

Assuming the profit of one airport is regulated by a rate-of-return (ROR) based regulation, the allowed ROR is 2%. The estimated airport asset that can be used as base in 2020 is about $100 million. Then, the maximum profit the airport can collect is _____.

Answers

Assuming the profit of one airport is regulated by a rate-of-return (ROR) based regulation of 2% and the estimated airport asset for 2020 is about $100 million, the maximum profit the airport can generate is $2 million.

How the maximum profit is computed:

The maximum profit of the airport is a function of the multiplication of the estimated asset and the allowed maximum rate of return.

The rate of return is the percentage of total returns expressed as a quotient of the total assets multiplied by 100.

The allowed maximum rate of return = 2%

Estimated asset of the airport for 2020 = $100 million

The maximum profit = $2 million ($100 million x 2%)

Thus, the airport's maximum profit for 2020 is $2 million.

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(50 POINTS) Express each sum using summation notation.
14. 3 + 3^2/2 + 3^3/3 ... + 3^n/n
15. 1 + 3 + 5 + 7 +... [2(12) - 1]

Answers

I'm on my school computer so the picture is blocked sorry :(

Answer:

the answer is in the photo hope it help

A five-year project that will require $3,200,000 for new fixed assets will be depreciated straight-line to a zero book value over six years. At the end of the project, the fixed assets can be sold for $640,000. The tax rate is 32% and the required rate of return is 13.30%. What is the amount of the aftertax salvage value?

Answers

As per the given values, the after-tax salvage value is $435,200.

Amount required = $3,200,000

Time = 6 years

Calculating the accumulated depreciation -

Amount/ Number of years

=  $3,200,000 / 6

= $533,333.3.

Calculating the accumulated depreciation at project end -

= 6 x $533,333.33

= $3,200,000.

Calculating the book value of the fixed assets -

Book value = Cost of fixed assets - Accumulated depreciation

= $3,200,000 - $3,200,000

= $0

Calculating the taxable gain or loss on the sale of the fixed assets -

Taxable gain/loss = Selling price - Book value

= $640,000 - $0

= $640,000

Calculating the tax liability -

Tax liability = Tax rate x Taxable gain

= 0.32 x $640,000

= $204,800

Calculating the after-tax salvage value -

After-tax salvage value = Selling price - Tax liability

= $640,000 - $204,800

= $435,200

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Please help 6th grade math please please help

Answers

Step-by-step explanation:

the beginning number is the beginning of your range the last number is the end of your range

Write a negative integer and a positive integer whose sum is –5.

Answers

Answer:

-18+ 13

-6 + 1

-20 + 15

-7 + 2

Step-by-step explanation:

Ay benefit concert, twelve bands have volunteered to perform but there is only enough time for eight of the bands to play. How many lineups are possible?

Answers

The requried, there are 495 possible combination lineups with eight bands out of twelve for the benefit concert.

To determine the number of possible lineups with eight out of twelve bands performing, we need to calculate the combination.

The number of ways to choose eight bands out of twelve without considering the order is given by the combination formula:

[tex]C(n, r) = \dfrac{n!}{ (r! * (n-r)!)}[/tex]

where n is the total number of bands (12 in this case) and r is the number of bands to be chosen (8 in this case).

Let's calculate it:

[tex]C(12, 8) =\dfrac {12!}{(8! * (12-8)!)}[/tex]

            [tex]= \dfrac{12!} {(8! * 4!)}[/tex]

            = (12 * 11 * 10 * 9) / (4 * 3 * 2 * 1)
            = 495

Thus, there are 495 possible combination lineups with eight bands out of twelve for the benefit concert.

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Find the LCM and HCF of 64 and 72 using prime factors​

Answers

What is the LCM of 64 and 72?

Find the prime factorization of 64.

Find the prime factorization of 72. 72 = 2 × 2 × 2 × 3 × 3.

Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the LCM: LCM = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3.

LCM = 576.

What is the GCF of 64 and 72?

Find the prime factorization of 64. 64 = 2 × 2 × 2 × 2 × 2 × 2.

Find the prime factorization of 72. 72 = 2 × 2 × 2 × 3 × 3.

To find the GCF, multiply all the prime factors common to both numbers: Therefore, GCF = 2 × 2 × 2.

GCF = 8.

Answer:

8x8 and 8x9

Step-by-step explanation:

because 8x8 is 64 and 8x9 is 72

I just need the answer

Question: what’s the volume?

Answers

The volume is 68 in^3

hey what's the answer ?

[tex] \sqrt{36 \times 2 \times 2 \times 3 \times 3} [/tex]

Answers

Step-by-step explanation:

36 is your answer

I hope.it helps mate

have a nice day

#Captainpower

Steves pattern: 4, 25, 130, 665. what is steves pattern?

Answers

Answer: (4+1)*5=25; (25+1)*5=130; (130+1)*5=655.

Step-by-step explanation:

A rectangular pool has an area of 50 square feet. What are the lengths of its sides? There is more than one possible answer. Draw a picture of the possible answers.

Answers

Answer:

10*5 or 25*2

Step-by-step explanation:

There are other answers but those involve decimals and I'm assuming they want whole numbers.

Other Questions
Consider an exchange economy with two market participants A and B, and two goods x and y . Their initial endowments ( Ax, Ay = (3, 15), and ( Bx, By ) = (7, 5), and their utilities are U A (x A, y A ) = x A yA^2 and U B (x B, y B ) = x B y B + y B1-Draw the Edgeworth box representing this exchange economy, the initial endowments, and the Pareto improving allocations.2- Define the equation for the contract curve, and draw the contract curve and the core of this economy.3-Find the price ratio for an optimal allocation in this economy Is the solution set of a nonhomogeneous linear system Ax = b, of m equations in n unknowns, with b = 0, a subspace of R"? Answer yes or no and justify your answer. A customer's check for $1.290 was returned for nonsufficient funds. Which of the following journal entries is needed to adjust for the NSF check? 1,290 O A. Cash Sales Revenue 1,290 1,290 O B. NSF Check Cash 1,290 O C. Accounts Receivable 1,290 Cash 1,290 1,290 O D. Accounts Payable Cash 1,290 User authentication is the fundamental building block and the primary line of defense.a. Trueb. False Let Y represent the profit (or loss) for a certain company X years after 1975. Based on the data shown below, a statistician calculates a linear model Y = 1.09X + 18.77. X 1 19.19 2. 22.28 21.47 4 22.46 5 23.65 6 26.34 7 25.43 29.02 9 28.11 10 31.9 11 28.99 12 31.48 7 00 Use the model to estimate the profit in 1977 y = A highly stressed-out resident of New Jersey commutes each business day to midtown Manhattan. The commuter uses NJ transit. The commuter's 6:15 am train to NYC is cancelled three times during a typical month. The probability of the commuter's moring train being canceled precisely six times in a month is closet to: 50% 68% 95% O 5% QUESTION 16 You conduct an experiment tossing a fair coin. Let (X, Y) be random variables, where X is the number of heads that occurs in two tosses and Y is the number of tails that arises in two tosses. Find P (X=1, Y=1). Separately, find P(X=0, Y= 0). Note you need to find two answers here, and the answer to your first question does not influence the second question- that is, the questions are independent. 0.50 and 0.50 0.0 and 0.50 0.50 and 0.0 O.25 and .25 1. Journalize each of the following transaction in the General Journal provided 2. Create appropriate T-Accounts for the General Journal above 3. Post T-Accounts to a Trial Balance Transaction 1: On January 1, 2011, Carol Finlay formed a new interior-design business by investing $10,000 of her personal funds into the business. The cash was deposited into a bank account opened under the name of Finlay Interiors. The following transactions took place from January 1 to January 31:Transaction 2: On January 1, Finlay Interiors used $2,500 of its cash to purchase supplies Transaction 3: On January 1, Finlay Interiors purchased additional supplies at a cost of $1,100 and furniture at a cost of $6,000, ON CREDIT from CanTech Supply Company. Finlay Interiors will pay for the supplies in 30 days, but has arranged to pay for the furniture by signing a note payable. Transaction 4: On January 10, Finlay Interiors provided consulting services to a dentist and immediately collected $2,200 cash. Transaction 5: On January 10, Finlay Interiors paid $1,000 rent for the month of January. Transaction 6: On January 14, Finlay Interiors paid $700 salary to the business's only employee. Transaction 7: On January 14, a customer and Carol Finlay sign a $65,000 contract that requires Finlay Interiors to do the interior design for an office building currently under construction. Finlay Interiors is expected to perform the services during February and March.Transaction 8: On January 15, Finlay Interiors provided consulting services and rented furniture to a customer and billed the customer $1,600 for the consulting services and $300 for the rental of the office furniture.Transaction 9: On January 25, 10 days after billing the customer in transaction #8, received full payment from that customer. Transaction 10: On January 25, Finlay Interiors paid $900 of the amount owing to CanTech Supply Company. Transaction11: Carol Finlay withdrew $600 cash from the business for her PERSONAL use. In this problem you will derive the efficiency of a CSMA/CD like multiple access protocol. In this protocol the time is slotted and all nodes are synchronised to the slot times. The length of a slot in this case is much less the than the actual time to transmit one frame. Let the slot length be S seconds Let the frame length be L bits Let the transmission rate be R bps Let the number of nodes be N and assume that each node has an infinite amount of packets to send Assume the propagation delay is much less than S, so that all nodes can detect a collision before the end of the slot. The protocol operates as below: o Ifa node has not acquired the channel, all nodes contend with probability p. If exactly 1 user transmit in that slot, then that user keep possession of the channel for the next k slots, transmitting an entire frame. o If a node has the possession of the channel, other nodes refrain from transmitting until that node finish transmitting the frame. Once the transmission completes all nodes again compete for the channel. Avery leans a 24-foot ladder against a wall so that it forms an angle of 80 with the ground. How high up the wall does the ladder reach? Round your answer to the nearest tenth of a foot if necessary. 4. If the European Central Bank starts to raise its policy interest rate before the Federal Reserve starts to raise United States interest rates, what do you predict will happen to the dollar/euro exc If the system of inequalities y2x+1 and y>21x1 is graphed in the xy-plane above, which quadrant contains no solutions to the system? Let A be a 3 x 3 matrix and B be a 5 x 3 matrix. Which of the following are defined? Circle all that apply. a) 2A b) A + B c) AB d) BA e) det (A) f) det(B) 8) tr(A) h) tr(B) i) A? j) BT if a, b, and c are the vertices of a triangle, find ab bc ca. find the title of each course that has been taken by student b00000003 but not by student b00000004. Write the prime factorization of each number as a product of powers. (a) 12^9. 36^15. 169^3 (b) 16^13. 14^7.81^14 For each of the following six program fragments:a. Give an analysis of the running time (Big-Oh will do).b. Implement the code in the language of your choice, and give the running timefor several values of N.c. Compare your analysis with the actual running times.Chapter 2 Algorithm Analysis(1) sum = 0;for( i = 0; i < n; ++i )++sum;(2) sum = 0;for( i = 0; i < n; ++i )for( j = 0; j < n; ++j )++sum;(3) sum = 0;for( i = 0; i < n; ++i )for( j = 0; j < n * n; ++j )++sum;(4) sum = 0;for( i = 0; i < n; ++i )for( j = 0; j < i; ++j )++sum;(5) sum = 0;for( i = 0; i < n; ++i )for( j = 0; j < i * i; ++j )for( k = 0; k < j; ++k )++sum;(6) sum = 0;for( i = 1; i < n; ++i )for( j = 1; j < i * i; ++j )if( j % i == 0 )for( k = 0; k < j; ++k )++sum; Solve by using the method of Laplace transforms: y" 6y' + 5y = 3e^(-x); y(0) = 2; y'(0) = 3Solve by using the method of Laplace transforms: y" + 9y = 2x + 4; y(0) = 0; y'(0) = 1 A company sells its product subject to a warranty that covers the cost of parts for repairs during the six months after the date of sale. Warranty costs are estimated to be 6% of sales. During the month of June, the company performed warranty work using $12,000 worth of parts for the warranty repairs. The total sales for June were equal to $450,000.1. Record the warranty expense for the month of June.2. Record the cost of the warranty work completed in June. is the system of equations consistent and independent, consistent and dependent, or inconsistent? y=3x 12y=6x 2 Notory public shall not complete a notarial certificate on any instrument that influences a person to enter, or not to enter a lawful transaction involving a notary true or false