When a population mean is compared to to the mean of all possible sample means of size 25, the two means are

a. equal

b. not equal

c. different by 1 standard error of the mean

d. normally distributed

The quantity f divided by g of 8 is 5, which is answer choice D.

To find f divided by g of 8, we need to plug in x = 8 into both f(x) and g(x), then divide f(8) by g(8).

f(x) = 3x + 1

f(8) = 3(8) + 1

f(8) = 25

g(x) = x - 3

g(8) = 8 - 3

g(8) = 5

Now, we can divide f(8) by g(8) to get:

f(8) / g(8) = 25 / 5

f(8) / g(8) = 5

Alternatively, we can find f divided by g of x generally by first applying the functions to x:

f(x) / g(x) = (3x + 1) / (x - 3)

We can then plug in x = 8 and simplify:

f(8)  g(8) = (3(8) + 1) / (8 - 3)

f(8) / g(8) = 25 / 5

f(8) / g(8) = 5

Regardless of the method we use, we find that f divided by g of 8 is 5.(option-d)

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The total cost of seeded avocadoes is $1.52 (approx).

Given data:

As-purchased unit cost of avocado = $1.21 per pound

Yield percentage = 72%

Convert the given quantity of avocadoes into pounds.

1 ounce = 1/16 pounds28 ounces = (28/16) pounds= 1.75 pounds

Find out the cost of 1 pound of avocado

As per the given data, the as-purchased unit cost of Avocado's is $1.21 per pound.

Find out the cost of 1.75 pounds of avocado= (1.75 x 1.21) dollars= $2.1175.

Calculate the yield amount.

After calculating the yield percentage, we can find the amount of avocado we can use after we remove the peel and seed.

Yield amount = (yield percentage × amount as purchased)/100Yield amount

= (72 × 1.75) / 100= 1.26 pounds.

Find out the cost of yield amount

Cost of yield amount = (cost of 1.75 pounds of avocado × yield amount)/1.75

Cost of yield amount = ($2.1175 × 1.26) / 1.75

Cost of yield amount = $1.5246

Hence, the total cost of 28 ounces of peeled and seeded avocadoes is $1.52 (approx).

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Answer:

its 62!

p-by-step explanation:

Answer:

62.

Step-by-step explanation:

A=2(wl+hl+hw)=2·(3·5+2·5+2·3)=62

Answer:

y=3x+2

Step-by-step explanation:

y=mx+b

b=2

m=3

plug in

y=3x+2

Nike reported total revenues of $44.5 billion for the year ending in May 31, 2021. Footwear accounted for 66% of Nike's total revenues in 2021, the percentage of Nike's total revenues that relates to sales of footwear is 66%.

The balance sheet shows that accounts receivable increased by $1,714 during the year, but some of that amount relates to mergers and acquisitions rather than additional credit sales. You will get the right amount of increased receivables from additional credit sales during the year by looking at the operating section of the statement of cash flows.

The operating section of the statement of cash flows shows that Nike collected $42.8 billion from customers in the year ending May 31, 2021. This is the amount of cash that Nike received from customers for the sales of its products and services.

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If a student obtained the standard value z= 1.8, then the exam grade is 680.

Given, a placement exam has a measure of x = 500 and a standard deviation of s = 100, and a student obtained the standard value z = 1.8, and we are to find the exam grade.

In order to find the exam grade, we can use the formula, z = (x - μ) / σ where x is the score, μ is the mean, and σ is the standard deviation.

Substituting the given values, we get1.8 = (x - 500) / 100

Multiplying both sides by 100, we get180 = x - 500

Adding 500 to both sides, we get680 = x

Therefore, the exam grade is 680.So, the correct option is d. 680.

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the answer are 4kg ,12kg and 20 kg

Answer:

the answer is D

hope it help

Answer: D, x²-6x+9

Step-by-step explanation:

(x-3)² is the same as (x-3)(x-3).

So you would do:

x times x=x²

x times -3=-3x

-3 times x=-3x

-3 times -3=9

The equation would look like this:

x²-3x-3x+9

Then you would have to collect the like terms. Like terms are terms that have the same variables and powers. So it would look like this:

x²-6x+9

Hope this helps :)

The value of the expression 6x(y^2 - z) when x = 0, y = -1, and z = 2 is 0.

To find the value of the algebraic expression 6x(y^2 - z) when x = 0, y = -1, and z = 2, we substitute the given values into the expression.

First, let's evaluate the inner expression (y^2 - z):

Substituting y = -1 and z = 2, we have (-1)^2 - 2 = 1 - 2 = -1.

Now, we substitute x = 0 and the result of the inner expression (-1) into the outer expression:

6x(y^2 - z) = 6(0)(-1) = 0.

Therefore, when x = 0, y = -1, and z = 2, the value of the expression 6x(y^2 - z) is 0.

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Answer:

There are 10 odd numbers: {1, 3, 5, 7, 9, 11, 13, 15, 17, 19} There are 4 factors of 8: {1, 2, 4, 8} There is 1 number in both lists: {1} Probability of an odd or a factor of 8 = (10 + 4 - 1)/20 = 13/20

Answer:

x=6

Step-by-step explanation:

[tex]\frac{9}{3} =\frac{6}{2}[/tex]      

Answer:

about 10 hershy kisses

Step-by-step explanation:

Sorry If wrong :(

Answer:

this is true but what do we have to do?

Step-by-step explanation:

Answer: x = 35, angle 1 = 85, angle 2 = 70, angle 3 = 25

Step-by-step explanation:

Finding x: 85+2x+x-10=180

3x= 105

x= 35

x-10 = angle 3 due to a property of parallels lines so put x in to get that angle 3 is 25 degrees

angle 2x = 70 degrees

70 + 25+angle 1 = 180

angle 1 = 85

angle 2 = 180-85-25 = 70

Answer:

30%

Step-by-step explanation:

Answer:

I. Length = 600 meters

II. Width = 30 meters

Step-by-step explanation:

Given the following data;

Length = 120m

Width = 6m

Drawing scale = 1:5

To find the length and width using the given drawing scale;

This ultimately implies that, with this drawing scale, the length and width of the rectangle would increase by a factor of 5 (multiplied by 5) i.e the rectangle is 5 times bigger in real-life than on the diagram.

For the length;

120 * 5 = 600 meters

For the width;

6 * 5 = 30 meters

Therefore, the dimensions of the rectangle using the given drawing scale is 600 meters by 30 meters.

Answer:

86 degrees

Step-by-step explanation:

180 - (74 + 20) = 86

Answer:

[tex] {x}^{3} {y}^{3} [/tex]

Step-by-step explanation:

Given,

Width of the rectangular prism

= x

Length of the rectangular prism

[tex] = {x}^{2} y[/tex]

Height of the rectangular prism

[tex] = {y}^{2} [/tex]

Therefore,

Volume of the rectangular prism

= Width × Length × Height

[tex] = x \times {x}^{2} y \times {y}^{2} [/tex]

[tex] = {x}^{3} {y}^{3} [/tex]

Hence,

The required volume of the rectangular prism is

Option J:

[tex] {x}^{3} {y}^{3} [/tex]

Answer:

Step-by-step explanation:

Sum of given angles:

Sum of given angles:

Answer: The zeros of the  quadratic function  are: 5/2+(1/2)*sqrt(31), 5/2-(1/2)*sqrt(31)

Step-by-step explanation:

The statement "Some unsound arguments are valid" is false.

The statement "Some unsound arguments are valid" is false.

A valid argument is a statement that follows the rules of logic.

An argument is known to be sound when it is valid and has true premises. When the premises of an argument are correct, the argument is considered sound. When an argument is valid, it follows logically from its premises, which are the statements that provide evidence or support for the argument's conclusion.

The unsound argument is the one that contains at least one false premise.

The sound argument is the one that contains only true premises and is valid (that is, follows logically from the premises).

If an argument is unsound, it can never be valid because it contains at least one false premise.

Therefore, the statement "Some unsound arguments are valid" is false.

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Answer:

Step-by-step explanation:

Answer:

area = 175 cm^2

Step-by-step explanation:

area = base * height

area = 5 cm + 35 cm

area = 175 cm^2

Given:Standard deviation, s = $2000Confidence level = 96%Margin of error, E = $500We have to find the sample size, n.

Sample size formula is given as:\[n={\left(\frac{z\text{/}2\times s}  {E}\right)}^{2}\]Where, z/2 is the z-score at a 96% confidence level. Using the standard normal table, we can get the value of z/2 as follows:z/2 = 1.750Incorporating all the values in the formula, we get:\[n={\left(\frac{1.750\times 2000}{500}\right)}^{2}\] Simplifying,\[n=21\]Therefore, a sample size of 21 is required if we wish to be 96% confident that our mean will be within $500 of the true mean salary of college instructors.

To determine the sample size needed to be 96% confident that the mean salary will be within $500 of the true mean salary, we can use the formula for sample size in a confidence interval.

The formula is:

n = (Z * σ / E)^2

Where:

n is the required sample size

Z is the z-score corresponding to the desired confidence level (in this case, 96% confidence level)

σ is the standard deviation of the population (given as $2000)

E is the maximum error tolerance (given as $500)

First, we need to find the z-score corresponding to a 96% confidence level. The remaining 4% is split evenly between the two tails of the distribution, so we look up the z-score that corresponds to the upper tail of 2% (100% - 96% = 4% divided by 2).

Using a standard normal distribution table or a calculator, the z-score for a 2% upper tail is approximately 2.05.

Now we can substitute the values into the formula:

n = (Z * σ / E)^2

n = (2.05 * 2000 / 500)^2

Calculating this expression:

n = (4100 / 500)^2

n = 8.2^2

n = 67.24

Rounding up to the next whole number, the required sample size is approximately 68.

Therefore, a sample size of 68 is needed to be 96% confident that the mean salary will be within $500 of the true mean salary of college instructors.

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Given information: The starting salaries of college instructors have a standard deviation (SD) of $2000. The sample size that is needed if we want to be 96% confident that our mean will be within $500 of the true mean salary of college instructors is to be calculated.

Hence, 49 is the sample size that is needed if we want to be 96% confident that our mean will be within $500 of the true mean salary of college instructors.

The formula for the sample size required is as follows:

[tex]n = [(Z \times \sigma) / E]^{2}[/tex]

Here, Z is the value from the normal distribution for a given confidence level, σ is population standard deviation, E is the maximum error or the margin of error, which is [tex]\$500n = [(Z \times \sigma) / E]^2[/tex]

On substituting the given values, we get:

[tex]n = [(Z \times \sigma) / E]^2[/tex]

[tex]n= [(Z \times \$2000) / \$500]^2[/tex]

[tex]n = [(1.7507 \times \$2000) / \$500]^2[/tex]

[tex]n = (7.003 \times 7.003)[/tex]

n = 49 (rounded off to the next whole number)

Hence, 49 is the sample size that is needed if we want to be 96% confident that our mean will be within $500 of the true mean salary of college instructors.

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To solve the initial value problems using the Laplace transform, we can apply the Laplace transform to the given differential equations and initial conditions.

For the first problem, the Laplace transform of the differential equation is s^2Y(s) + 5sY(s) + 2Y(s) = 0. Solving for Y(s), we find Y(s) = -3/(s+1).

Taking the inverse Laplace transform, we obtain the solution y(t) = -3e^(-t). For the second problem, the Laplace transform of the differential equation is sY(s) + 4Y(s) + 3/(s+1) = -2. Solving for Y(s), we find Y(s) = (-2s - 1)/(s^2 + 4s + 3). Taking the inverse Laplace transform, we obtain the solution y(t) = (-2t - 1)e^(-t).

a) The Laplace transform of the given differential equation is:

s^2Y(s) + 5sY(s) + 2Y(s) = 0

Using the initial condition Y(0) = -1 and Y'(0) = 3, we can apply the initial value theorem to obtain:

Y(s) = -1/s + 3

Taking the inverse Laplace transform of Y(s), we find:

y(t) = -3e^(-t)

b) The Laplace transform of the given differential equation is:

sY(s) + 4Y(s) + 3/(s+1) = -2

Using the initial condition Y(0) = -1, we can apply the initial value theorem to obtain:

Y(s) = (-2s - 1)/(s^2 + 4s + 3)

Taking the inverse Laplace transform of Y(s), we find:

y(t) = (-2t - 1)e^(-t)

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Answer:

x ≈ 36.09

Step-by-step explanation:

Complete question

Use △DEF, shown below, to answer the question that follows: Triangle DEF where angle E is a right angle. DE measures x. DF measures 55. Angle D measures 49 degrees. What is the value of x rounded to the nearest hundredth? Type the numeric answer only in the box below.

According to the diagram

m<E = 90 degrees

m<D = 49 degrees

DF = 55 = hypotenuse

DE = x = adjacent

EF = opposite

According to SOH CAH TOA identity;

Cos theta = adj/hyp

Cos m<D = DE/DF

Cos 49 = x/55

x = 55cos49

x = 55(0.6561)

x = 36.0855

x ≈ 36.09 (to the nearest hundredth)

Answer:

x ≈ 36.09

correct on khan

Step-by-step explanation:

Answer:

x = 5

x = 2

Step-by-step explanation:

2(2x + 4) = 8x - 12

2x + 4 = 4x - 6

x + 2 = 2x - 3

x = 5

Question 17

8/4 = (x + 2)/(2x - 2)

2(2x - 2) = x + 2

4x - 4 = x + 2

3x = 6

x = 2

Answer:

I am not able to answer your question because I am unsure of what to solve for. :/

Step-by-step explanation:

Answer:

pt B: (-1, -8)

Step-by-step explanation:

(x - 7)/2 = -4

x - 7 = -8

x = -1

(y-6)/2 = -7

y - 6 = -14

y = -8

the conditional probability pr[x>1000 | x>500] is P(x > 500) = 1 - CDF(500).

Given that x has an exponential likelihood thickness work with β = 500, we are able to compute the likelihood that x is more noteworthy than 500, i.e., P(x > 500).

For an exponential conveyance with parameter β, the likelihood thickness work (PDF) is given by:

f(x) = (1/β) * e^(-x/β), where x ≥ 0.

To discover P(x > 500), we got to coordinate the PDF from 500 to limitlessness:

P(x > 500) = ∫[500, ∞] (1/β) * e^(-x/β) dx.

Let's calculate this likelihood:

P(x > 500) = ∫[500, ∞] (1/500) * e^(-x/500) dx.

To calculate this indispensably, ready to utilize the truth that the necessity of the PDF over its whole extent is rise to 1. So, ready to revamp the likelihood as:

P(x > 500) = 1 - P(x ≤ 500).

Since the exponential conveyance is memoryless, P(x ≤ 500) is break even with the total conveyance work (CDF) at 500.

P(x > 500) = 1 - CDF(500).

The CDF of the exponential dissemination is given by:

CDF(x) = ∫[0, x] (1/β) * e^(-t/β) dt.

To calculate P(x > 500), we have to assess CDF(500) and subtract it from 1.

Presently, let's calculate P(x > 500):

P(x > 500) = 1 - CDF(500)

= 1 - ∫[0, 500] (1/500) * e^(-t/500) dt.

To calculate the conditional probability P(x > 1000 | x > 500), we have to consider the occasion that x > 500 is our modern test space. The conditional probability is at that point given by:

P(x > 1000 | x > 500) = P(x > 1000, x > 500) / P(x > 500).

Since x takes after an exponential conveyance, it is memoryless, which implies the likelihood of x > 1000 given x > 500 is the same as the likelihood of x > 500. Hence, we have:

P(x > 1000 | x > 500) = P(x > 500) = 1 - CDF(500).

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Answer:

b

Step-by-step explanation:

took the test good luck

Answer:

Explained below

Step-by-step explanation:

I shall explain this

Add all the numbers together and divide by the number of numbers

[tex]78 + 81 + 89 + 75 + 76 + 91 + 10963 + 80 + 87 + 91 + 95 = answer \div 11 [/tex]