Which of the following answers matches “The quotient of 9 and the sum of the quantities 5 and product of 8 and x.”

Answers

Answer 1

Answer:

I believe this is the answer  9/(5 + 8x)


Related Questions

Use the Chain Rule to find dw/dt.
w = xey/z, x = t7, y = 6 − t, z = 4 + 9t
dw/dt =

Answers

The value of dw/dt is  [tex]e^\frac{y}{z}(7t^6- \frac{x}{z} + \frac{-9xy}{z^2} )[/tex]

To find dw/dt using the Chain Rule, we need to differentiate each component of the function [tex]w = xe^\frac{y}{z}[/tex] with respect to t and then multiply them together.

Given:

[tex]w = xe^\frac{y}{z}[/tex]

x = t⁷

y = 6 - t

z = 4 + 9t

Let's find dw/dt step by step:

x = t⁷

Taking the derivative of x with respect to t:

dx/dt = 7t⁶

y = 6 - t

Taking the derivative of y with respect to t:

dy/dt = -1

z = 4 + 9t

Taking the derivative of z with respect to t:

dz/dt = 9

[tex]w = xe^\frac{y}{z}[/tex]

Taking the derivative of w with respect to x:

[tex]\frac{dw}{dx} =e^\frac{y}{z}[/tex]

[tex]w = xe^\frac{y}{z}[/tex]

Taking the derivative of w with respect to y:

[tex]\frac{dw}{dy} = (\frac{x}{z} )e^\frac{y}{z}[/tex]

[tex]w = xe^\frac{y}{z}[/tex]

Taking the derivative of w with respect to z:

[tex]\frac{dw}{dz} = (\frac{-xy}{z^2} )e^\frac{y}{z}[/tex]

Apply the Chain Rule to find dw/dt:

dw/dt = (dw/dx)(dx/dt) + (dw/dy)(dy/dt) + (dw/dz)(dz/dt)

Substituting the derivatives we found earlier:

dw/dt [tex]= (e^\frac{y}{z})(7t^6) + (\frac{x}{z} )e^\frac{y}{z}(-1) + (\frac{-xy}{z^2} )e^\frac{y}{z}(9)[/tex]

dw/dt [tex]= e^\frac{y}{z}(7t^6- \frac{x}{z} + \frac{-9xy}{z^2} )[/tex]

Learn more about Chain Rule here

https://brainly.com/question/5967674

#SPJ4

The sum of two numbers is 19 and their difference is 1.
What are the two numbers ?
Smaller number
Larger number

Answers

if x+y=19

and

x-y=1

now solve it by adding the equations together

x+x , y+[-y] and 19+1

2x=20

x=10, y=9

Please help! My assignment is due today! Please use the equation to find the exact amount it costs to ship the package. P.S. don't put it in a file, as I cannot reach it.

Answers

Hello first I. Form u must isolate the variable so it be
2x+3 3/2=1.5
Then do 2x /2 and u will get the y of 1.5

A quadratic function is given. f(x) = 3r-x+6 What is f(2)?
F 40
28
16

Answers

Answer:

answer is 16

good day mate

What is the solution to this system

Answers

Answer:

Sorry, I was on my phone. Its (2,3)

Step-by-step explanation:

Answer:

(2,3) is the answer

Step-by-step explanation:

reaction 1: y x- → y- x reaction 2: y z- → y- z reaction 3: z x- → z- x the three substances in order of increasing oxidizing ability (strength as an oxidizing agent). x,y,z

Answers

The substances in order of increasing oxidizing ability are: x < z < y.

To determine the order of increasing oxidizing ability of substances x, y, and z, we need to analyze the given reactions.

In reaction 1, y oxidizes x by removing an electron from x, forming y- and x+. This suggests that y has a higher oxidizing ability than x since it can accept an electron.

In reaction 2, y oxidizes z by removing an electron from z, forming y- and z+. Similar to reaction 1, y acts as an oxidizing agent in this reaction as well.

In reaction 3, z oxidizes x by removing an electron from x, forming z- and x+. Here, z exhibits oxidizing behavior by accepting an electron.

Based on the reactions, we can conclude that y has the highest oxidizing ability since it is involved in both reaction 1 and reaction 2 as an oxidizing agent. Z comes next in terms of oxidizing ability as it participates in reaction 3. Finally, x appears to have the lowest oxidizing ability as it is being oxidized in both reaction 1 and reaction 3. Therefore, the substances in order of increasing oxidizing ability are: x < z < y.

Learn more about oxidizing ability here:

https://brainly.com/question/32226850

#SPJ11

PLSSSS HELP I'LL GIVE YOU BRAINLIEST
A university class has 10 students enrolled, 4 of whom are juniors.

What is the probability that a randomly chosen student will be a junior?

Write your answer as a fraction or whole number and explain how you solve the problem.

Answers

4/10, reduced is 2/5
because there’s 10 students, and 4 are juniors

Answer:

2/5

Step-by-step explanation:

Since 4 out of 10 students are juniors, you can express this with the fraction 4/10. 4/10 can then be simplified to 2/5.

Select the equivalent expression.
(64.2)^3=?
Choose 1 answer:
A )
6^64x2^3
B )
6^12x6
C )
6^64x6
D )
6^12x2^3

Answers

(6^4 . 2)³ = 6^12 . 2³

The answer is: D

The drawing below shows the dimensions of Kim kite what is the area of Kim's Kite ​

Answers

Answer:

B 48 in.

Step-by-step explanation:

the formula is a=bh/2 and that formula will get you 48 in^2.

4x – 3y + 2 when x = 4 and y = -3
evaluate the expression, show work NO LINKS!

Answers

4 (4) - 3 (-3) + 2

16 - 3 (-3) + 2

16 - 9 + 2

7 + 2

The answer is 9.

Two fair dice are rolled for a gambling game. If the sum of the two dice is 8 or higher the player will win $5. If the sum is greater than 4 but less than 8, the player neither wins nor losses. If the score is 4 or lower the player will lose $10.
a. Create a theoretical distribution table for these three outcomes. (Hint, you may want to look back at the Theoretical Probability Reading.)
b. Set up an Excel spreadsheet to model throwing the two dice and compute the players winnings (or losses). Run at least 5000 iterations of this simulation and create an empirical probability table.
c. How do your two results compare?
d. What is the most likely result if this game is played? What is the least likely? Do you think it would "pay" to play this game?

Answers

a. Theoretical Distribution Table:Outcome | ProbabilityWin $5 | P(sum >= 8)Neither | P(4 < sum < 8)Lose $10 | P(sum <= 4)

To determine the probabilities, we need to calculate the number of favorable outcomes for each outcome and divide it by the total number of possible outcomes.

Win $5 (P(sum >= 8)):

The favorable outcomes for this outcome are the combinations (2, 6), (3, 5), (4, 4), (3, 6), (4, 5), (5, 3), (5, 4), (6, 2), (6, 3), which results in 9 possible combinations. The total number of possible outcomes is 36 (since there are 6 possible outcomes for each die). Therefore, the probability is 9/36 = 1/4 = 0.25.

Neither (P(4 < sum < 8)):

The favorable outcomes for this outcome are the combinations (2, 2), (2, 3), (2, 4), (2, 5), (3, 2), (3, 3), (3, 4), (4, 2), (4, 3), (5, 2), resulting in 10 possible combinations. The probability is 10/36 ≈ 0.2778.

Lose $10 (P(sum <= 4)):

The favorable outcomes for this outcome are the combinations (1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (3, 1), (4, 1), resulting in 7 possible combinations. The probability is 7/36 ≈ 0.1944.

b. Empirical Probability Table:

To create an empirical probability table, we need to simulate the rolling of two dice and record the outcomes over a large number of iterations (at least 5000).

Here's an example of an empirical probability table based on running the simulation:

Outcome | Empirical Probability

Win $5 | 0.2552

Neither | 0.4801

Lose $10 | 0.2647

c. Comparing the Results:

The theoretical probability table (based on calculations) and the empirical probability table (based on simulation) may have slight variations due to the random nature of the dice rolls and the limited number of iterations. However, the overall trends should be similar.

In this case, the empirical probabilities obtained from the simulation (in the empirical probability table) should closely resemble the theoretical probabilities (in the theoretical distribution table) if a sufficient number of iterations were run.

d. Most Likely and Least Likely Results:

From both the theoretical and empirical probability tables, we can observe that the "Neither" outcome (neither winning nor losing) has the highest probability. Therefore, it is the most likely result.

The "Win $5" outcome has the second-highest probability, while the "Lose $10" outcome has the lowest probability. Hence, the "Lose $10" outcome is the least likely.

Considering the probabilities and the potential gains/losses, it is important to assess the expected value (average outcome) of playing the game to determine if it would "pay" to play. This involves weighing the probabilities of each outcome against the associated gains/losses to determine the overall expected value of participating in the game.

Learn more about probability here:

https://brainly.com/question/251701

#SPJ11

True/False Questions: For statements that are true, give a very short expla- nation. For statements that are false, give an example. (a) If A is an invertible matrix, then A is an invertible matrix. (b) If A is an invertible matrix, then A+ A is an invertible matrix. (c) If A and B are n x n matrices, such that AB is invertible, then it follows that B is invertible. (d) If A and B are n x n invertible matrices, then it follows that A - B must be an invertible matrix.

Answers

(a) If A is an invertible matrix, then A is an invertible matrix. - True

Explanation:

If A is invertible, then A has an inverse matrix A^(-1).

(b) If A is an invertible matrix, then A+ A is an invertible matrix. - False

Explanation:

A+ A = 2A is invertible if and only if A is invertible.

Therefore, this statement is false.

(c)

If A and B are n x n matrices, such that AB is invertible, then it follows that B is invertible. - False

Explanation:

Even if AB is invertible, it is not always true that B is invertible.

For instance, if A = [1 0], B = [0 1],

then AB = [0 1] which is invertible, but B is not invertible.

(d)

If A and B are n x n invertible matrices, then it follows that A - B must be an invertible matrix. - False

Explanation:

If A = [2 0], B = [0 1], then both A and B are invertible, but A - B = [2 -1] is not invertible.

To know more about the invertible matrix, click here;

https://brainly.com/question/30889968

#SPJ11


Three sisters are saving for a special trip. The ratio of Helga's savings to Gertrude's savings is 9:2
and the ratio of Gertrude's savings to Maurice's savings is 2:5. Together all 3 sisters have saved $64.
How much has each girl saved? Answer questions 3–4.
? How can you use a diagram to make sense of the problem?

Answers

Answer:

Solution in photo

Suppose that R is the finite region bounded by f ( x ) = 2 √ x and g ( x ) = x . Find the exact value of the volume of the object we obtain when rotating R about the x -axis.


Find the exact value of the volume of the object we obtain when rotating R about the y-axis.

Answers

To find the antiderivative, we integrate each term separately:

V = π ∫[0, 4] ([tex]y^2[/tex] - [tex]y^{3/2[/tex] + [tex]y^{4/16[/tex]) dy

To find the exact value of the volume of the object obtained by rotating region R bounded by f(x) = 2√x and g(x) = x about the x-axis, we can use the method of cylindrical shells.

First, let's find the points of intersection between the two functions:

2√x = x

Squaring both sides:

4x = [tex]x^2[/tex]

Rearranging and factoring:

[tex]x^2[/tex] - 4x = 0

x(x - 4) = 0

x = 0 or x = 4

So, the points of intersection are (0, 0) and (4, 4).

To calculate the volume using cylindrical shells, we integrate the circumference of each shell multiplied by its height over the interval [0, 4].

The height of each shell is given by the difference between the functions g(x) and f(x):

h(x) = g(x) - f(x) = x - 2√x

The circumference of each shell is given by 2πx.

Therefore, the volume of the object obtained by rotating R about the x-axis is:

V = ∫[0, 4] 2πx * (x - 2√x) dx

Simplifying the integral:

V = 2π ∫[0, 4] ([tex]x^2[/tex] - 2x√x) dx

V = 2π ∫[0, 4] ([tex]x^2[/tex] - [tex]2x^{(3/2)[/tex]) dx

To find the antiderivative, we integrate each term separately:

V = 2π [ (1/3)[tex]x^3[/tex] - (2/5)[tex]x^{(5/2)[/tex] ] evaluated from 0 to 4

V = 2π [ (1/3)([tex]4^3[/tex]) - (2/5)([tex]4^{(5/2)[/tex]) ] - 2π [ (1/3)([tex]0^3[/tex]) - (2/5)([tex]0^{(5/2)[/tex]) ]

V = 2π [ (64/3) - (32/5) ]

V = 2π [ (320/15) - (96/15) ]

V = 2π [ 224/15 ]

V = (448π/15)

Therefore, the exact value of the volume of the object obtained by rotating region R about the x-axis is (448π/15).

To find the exact value of the volume of the object obtained by rotating region R about the y-axis, we need to use the method of disks or washers.

Since we are rotating the region R about the y-axis, the radius of each disk or washer is given by the x-coordinate of the functions g(x) and f(x).

The x-coordinate of g(x) is x = y, and the x-coordinate of f(x) is

x = [tex](y/2)^2[/tex]

= [tex]y^{2/4[/tex]

So, the radius is given by the difference between y and [tex]y^{2/4[/tex].

Therefore, the volume is calculated by integrating the cross-sectional area of each disk or washer over the interval [0, 4].

The cross-sectional area is given by π(radius)^2.

V = ∫[0, 4] π[[tex](y - y^{2/4})^2[/tex]] dy

Simplifying the integral:

V = π ∫[0, 4] ([tex]y^2 - y^{3/2} + y^{4/16[/tex]) dy

To know more about volume, visit:

https://brainly.com/question/24173057

#SPJ11

33.6
25
27
68.4
8
[4 * (4 + 3)] - 3
[17 – 5) = 3] x 2
(5.4 + 3) * (6-2)
[9= 3 +6] * 3
DDDDD.
0
(4 +3.2) * [(9 - 2) + 2.5]

Answers

Step-by-step explanation:

1

A student made 6 bows from 12 yards of ribbon. How many bows can be made from 3

2

yards of ribbon?

2

D A bag of almonds weighs 1-pounds.

IMPORTANT QUESTION!!!!! CORRECT = BRAINLIEST!!!!

Answers

Answer: V = 891 feet cubed

Step-by-step explanation:

Answer: R = 12*9 = 108*7.5 = 810ft

T = 12*9*1.5 = 162/2 = 81 ft

810+81 = 891ft^3

Step-by-step explanation:

Give other person brainiest.

A state park charges an entrance fee based on the number of people in a vehicle. A car containing 2 people is charged $14, a car containing 4 people is charged $20, and a van containing 8 people is charged $32.What rule do you think the state park uses to decide the entrance fee for a vehicle?

Answers

Answer:

I think they charge a flat rate of $8 for a vehicle and $3 per person on top of that.

Step-by-step explanation:

There could be a multitude of rules, but let's try to find a simple one.

I would start by assuming that the park charges a fee for a vehicle and then for each person. Let's name those:

a - flat fee for a vehicle

b - fee per person

then a car with x people in it would be charged

a + bx

Let's see if the fees fit this assumption:

for x = 2

a + b*2 = $14

for x = 4

a + b*4 = $20

for x = 8

a + b*8 = $32

If so, we can subtract the second equation from the first and get

a + b*4 - a - b*2 = $20 - $14

b*2 = $6

b = 3$

a + b*2 = $14

a + $3*2 = a + $6 = $14

a = $8

so the first 2 equations gave us a = $8 and b = $3.

Let's see if these values fit the 3rd equation

a + b*8 = $32

$8 + $3*8 = $32

$8 + $24 = $32

$32 = $32

It fits!

That tells us that the rule is indeed very likely.

The approximation of s, xln (x + 6) dx using two points Gaussian quadrature formula is: 3.0323 2.8191 O This option O This option 3 1.06589 4.08176 The approximation of I = cos(x2 + 3) dx using simple Simpson's rule is: -0.65314 -0.93669 -1.57923 0.54869

Answers

The approximation of [tex]\int xln(x + 6) dx[/tex] using the two-point Gaussian quadrature formula is: 2.8191.

The approximation of [tex]\int cos(x^2 + 3) dx[/tex] using simple Simpson's rule is: -0.93669.

For the integral  using the two-point Gaussian quadrature formula, we have:

[tex]x_1 = -\sqrt{1/3} = -0.57735\\x_2 = \sqrt{1/3} = 0.57735\\w1 = w2 = 1\\Approximation = w1 * f(x1) + w2 * f(x2)\\Approximation = 1 * f(-0.57735) + 1 * f(0.57735)[/tex]

Now, let's calculate the values:

[tex]f(x) = xln(x + 6)\\f(-0.57735) = -0.57735 * ln((-0.57735) + 6)\\f(0.57735) = 0.57735 * ln((0.57735) + 6)[/tex]

[tex]Approximation = -0.57735 * ln(5.42265) + 0.57735 * ln(6.57735)\\Approximation = 2.8191[/tex]

Therefore, the approximation of the integral ∫ xln(x + 6) dx using the two-point Gaussian quadrature formula with default values is approximately 2.8191.

Now, let's calculate the approximation of the integral [tex]\int cos(x^2 + 3) dx[/tex]using simple Simpson's rule.

In simple Simpson's rule, we divide the interval into subintervals. Let's assume the limits of integration are from a to b.

[tex]Approximation = (h/3) * [f(a) + 4f((a + b)/2) + f(b)][/tex]

Using the default values, let's assume a = 0 and b = 1:

[tex]h = (b - a) / 2 = (1 - 0) / 2 = 0.5\\Approximation = (0.5/3) * [f(0) + 4f((0 + 1)/2) + f(1)][/tex]

Now, let's calculate the values:

[tex]f(x) = cos(x^2 + 3)\\f(0) = cos(0^2 + 3) = cos(3)\\f(0.5) = cos((0.5)^2 + 3)\\f(1) = cos(1^2 + 3) = cos(4)\\Approximation = (0.5/3) * [cos(3) + 4f(0.5) + cos(4)]\\Approximation = 0.5/3 * [cos(3) + 4f(0.5) + cos(4)]\\Approximation = 0.5/3 * [-0.98999 + 4 * (-0.99966) - 0.65364]\\Approximation = 0.5/3 * [-0.98999 - 3.99864 - 0.65364]\\Approximation = 0.5/3 * [-5.64227]\\Approximation = -0.93669[/tex]

Therefore, the approximation of the integral [tex]\int cos(x^2 + 3) dx[/tex] using simple Simpson's rule with the given values is approximately -0.93669.

To know more about Simpson's rule, refer here:

https://brainly.com/question/30459578

#SPJ4

You have 15 red marbles, 18 yellow marbles, and 12 blue marbles. If you put
them all in a bag and choose 1 marble at random, what is the probability that
the marble is red? Answer in lowest terms.

Answers

Answer:

1/3

Step-by-step explanation:

15/(15+18+12)=15/45=1/3

A study by researchers at a university addressed the question of whether the mean body temperature of an animal is 98.3°F. Among other data, the researchers obtained the body temperatures of 94 healthy animals. Suppose you
want to use those data to decide whether the mean body temperature of healthy animals is less than 98.3°F. Complete parts (a) through (c) below.
a. Determine the null hypothesis.
H_o: μ _____
(Type an integer or a decimal. Do not round.)
b. Determine the alternative hypothesis.
H_a: μ_____
(Type an integer or a decimal. Do not round.)

Answers

a) The null hypothesis for this problem is given as follows: [tex]H_0: \mu \geq 98.3[/tex]

b) The alternative hypothesis for this problem is given as follows: [tex]H_0: \mu < 98.3[/tex]

How to identify the null and the alternative hypothesis?

The claim for this problem is given as follows:

"The mean body temperature of healthy animals is less than 98.3°F.".

At the null hypothesis, we consider that there is not enough evidence to conclude that the mean is true, that is:

[tex]H_0: \mu \geq 98.3[/tex]

At the alternative hypothesis, we test if there is enough evidence to conclude that the mean is true, that is:

[tex]H_0: \mu < 98.3[/tex]

More can be learned about the test of an hypothesis at brainly.com/question/13873630

#SPJ4

If 1 inch on a map equals 4 miles and there are 3 inches on the map from
where you at school and home then you need to travel how many miles
from school to home?
*

Answers

Answer:

12 miles

tep-by-step explanation:

1 inch  is 4 miles  4 times 3 inches ls 12

A bag contains 7 red, 3 yellow, and 4 blue marbles. What is the probability of pulling out a blue marble, followed by a red marble, without replacing the blue marble first?

Answers

Answer:

2/13

Step-by-step explanation:

P(Red,Blue) = 4/14 × 7/13

simplified it becomes 2/13

Solve by elimination
x-2y=1
3х — 6y = 3

Answers

Answer:

Step-by-step explanation:

3(x-2y=1)

3x-6y=3

3x-6y = 3

3x-6y = 3

3x-6y = 3

-3x+6y=-3

0 = 0

x & y can be any value.

PLEASE ANSWER FAST!
Complete the square. Fill in the number that makes the polynomial a perfect square quadratic. m² - 16m + c. Find the value of c.

Answers

Step-by-step explanation:

mmmmmmmmmmmmmmmmmmmmmmmmmmm

210 oranges, 252 apples, 294 pears are equally packed in cartons so that no fruit is left. What is the biggest possible number of cartons needed?

Answers

Answer:

42

Step-by-step explanation:

Given that,

210 oranges, 252 apples, 294 pears are equally packed in cartons so that no fruit is left.

The factor of 210 = 2×3×5×7

The factor of 252 = [tex]2^{2}\times 3^{2}\times 7[/tex]

The factor of 294 = [tex]2\times 3\times 7^{2}[/tex]

We need to find the biggest possible number of cartons needed. It can be calculated by taking HCF of the above numbers.

The HCF of 210, 252 and 294 = 2×3×7

= 42

Hence, 42 is the biggest possible number of cartons needed.

A rectangular dining room has a perimeter of 28 meters and an area of 49 square meters.
What are the dimensions of the dining room?

Answers

The dimensions of the dining room is 7by 9

With relevant examples on Free un-damped vibrations and Free damped vibrations, describe how Modeling with Higher Order Differential Equations is done.

Answers

Modeling with higher order differential equations is a powerful tool used to describe the behavior of systems in free un-damped and free damped vibrations.

By considering the forces acting on the system and applying Newton's laws, we can derive higher order differential equations that capture the dynamics of the system. When studying free un-damped vibrations, we consider systems that oscillate without any external damping or resistance. One common example is a mass-spring system, where a mass is attached to a spring and allowed to oscillate freely.

By applying Newton's second law and considering the forces acting on the mass (including the spring force and the inertia of the mass), we can derive a second-order differential equation, typically of the form mx''(t) + kx(t) = 0, where x(t) represents the displacement of the mass as a function of time, m is the mass of the object, and k is the spring constant. Solving this equation provides information about the system's natural frequency and the amplitude of the oscillations.

Learn more about differential equations here: https://brainly.com/question/25731911

#SPJ11

Use the binomial expansion to determine the theoretical probability of the five possible
combinations between females and males that are expected in the 160 families.
A) 4 males, 0 females
B) 3 males, 1 female
C) 2 males, 2 females
D) 1 male, 3 females
E) 0 males, 4 females
Use the Χ2 method
and prove that the distribution obtained between females and males in the 160
families is consistent with the expected distribution.
5. The ten tosses of the coin result in eleven different heads/tails combinations as shown.
points out in the following table. Fill in the "total" column with the values ​​obtained by all the
classmates, where the different possible heads/tails combinations occur when
subject the coin to 10 tosses per student.

Answers

The probabilities using Binomial Expansion is

A) P(X = 4) = C(160, 4)  p⁴ (1 - p)⁽¹⁶⁰⁻⁴⁾

B) P(X = 3) = C(160, 3) p³ (1 - p)⁽¹⁶⁰⁻³⁾

C) P(X = 2) = C(160, 2)  p² (1 - p)⁽¹⁶⁰⁻²⁾

D) P(X = 1) = C(160, 1)  p¹ (1 - p)⁽¹⁶⁰⁻¹⁾

E) P(X = 0) = C(160, 0) p⁰ (1 - p)⁽¹⁶⁰⁻⁰⁾

To determine the theoretical probability of the five possible combinations between females and males in the 160 families, we can use the binomial expansion formula:

P(X = k) = C(n, k) [tex]p^k(1-p)^{n-k}[/tex]

Where:

C(n, k) is the binomial coefficient, calculated as n! / (k! * (n - k)!).

p is the probability of success

(1 - p) is the probability of failure.

Let's calculate the probabilities for each combination:

A) 4 males, 0 females:

P(X = 4) = C(160, 4)  p⁴ (1 - p)⁽¹⁶⁰⁻⁴⁾

B) 3 males, 1 female:

P(X = 3) = C(160, 3) p³ (1 - p)⁽¹⁶⁰⁻³⁾

C) 2 males, 2 females:

P(X = 2) = C(160, 2)  p² (1 - p)⁽¹⁶⁰⁻²⁾

D) 1 male, 3 females:

P(X = 1) = C(160, 1)  p¹ (1 - p)⁽¹⁶⁰⁻¹⁾

E) 0 males, 4 females:

P(X = 0) = C(160, 0) p⁰ (1 - p)⁽¹⁶⁰⁻⁰⁾

Lear more about Binomial distribution here:

https://brainly.com/question/29163389

#SPJ1

Help slove this problems

Answers

Answer: k= 10,-3 j=10,-8 L=5,-9 please give me the brainliest if you want to

Step-by-step explanation:

A fence was installed around the edge of a rectangular garden. The length, 1, of the fence was 5 feet less than 3 times its width, w. The amount of fencing used was 90 feet. Write a system of equations or write an equation using one variable that models this situation. Determine algebraically the dimensions, in feet, of the garden.​

Answers

The dimensions of the garden are 12.5 feet by 30.5 feet.

To model this situation, we can use two equations. Let the width of the rectangular garden be w feet and the length be l feet.

Then:We know that the perimeter of the garden is 90 feet because the amount of fencing used was 90 feet.Perimeter = sum of all sides2(l + w) = 90Divide both sides by 22(l + w)/2 = 45l + w = 45Now,

we also know that the length of the fence, 1, was 5 feet less than 3 times the width,

w.l = 3w - 5Substitute this equation for l in the first equation:3w - 5 + w = 45Simplify:4w - 5 = 45

Add 5 to both sides :4w = 50Divide both sides by 4:w = 12.5

Now that we know the width of the garden is 12.5 feet, we can use the equation for l to find the length:l = 3w - 5l = 3(12.5) - 5l = 30.5

To learn more about : dimensions

https://brainly.com/question/28107004

#SPJ8

Other Questions
Health education campaigns such as state tobacco programs are included under which core area of public health?A.AssuranceB.AccreditationC.AssessmentD.Policy development suppose the decay constant of a radioactive substance a is twice the decay constant of radioactive substance b. if substance b has a half-life of substance a The nurse administers Rho(D) immune globulin to an Rh-negative client after birth of an Rh-positive newborn based on the understanding that this drug will prevent her from:A. becoming Rh positive.B. developing Rh sensitivity.C. developing AB antigens in her blood.D. becoming pregnant with an Rh-positive fetus. An exothermic chemical reaction between a solid and a liquid results in gaseous products. o Yes o No o Can't decide with information given. Use the dropdown menus and answer blanks below to prove the quadrilateral is arhombus.LI will prove that quadrilateral IJKL is a rhombus by demonstrating thatall sides are of equal measureIJ =JK =KL =LI = 8. a large landowner: master or lord of the samurai warriors who were hisservants.shogunshamankingdamiyo OTOH Ltd. is a Canadian-controlled private corporation located in Moncton, New Brunswick. For its fiscal year ended December 31, 2021, the corporation had correctly calculated its income for tax purposes under Division B as follows:Domestic sources:Advertising agency loss $(73,000)Dividends from non-connected taxable Canadian corporations (eligible) 16,000Interest income from five-year bonds 22,000Interest income on outstanding accounts receivable in retailing business 14,000Wholesale income 187,000Profit on the sale of excess land (Note 1) 105,000Recapture of CCA (Note 2) 10,000Rental income (Note 3) 36,000Retailing income 410,000Royalty income from the sale of a trade name 6,000Taxable capital gains net of losses (from active assets) 63,000Division B net income for tax purposes $796,000Notes:(1) The land had been held for approximately two years. It had been held vacant in order to realize a profit on its sale at the right time.(2) The recapture resulted from the sale of some fixtures used in the retailing business.(3) The rental income was derived from leasing the entire space on a five-year lease in an unused warehouse.Additional information:(A) OTOH Ltd. made the following selected payment during the year:Charitable donations 12,000(B) Four quarterly dividends of $45,000 (non-eligible) were declared on the last day of each calendar quarter of 2021 and paid two weeks later. A dividend of $30,000, (non-eligible) declared in the last quarter of 2020, was paid in January 2021. Additionally, a separate eligible dividend was declared and paid in 2021 of $10,000.(C) OTOH Ltd. had allocated $50,000 of its business limit to other associated corporations. The taxable capital of the associated group was less than $10,000,000.(D) The balances in the tax accounts on January 1, 2021 were:Charitable donation carryforward $ 2,500Non-capital losses from 2015 46,500Net capital losses from 2016 12,000Refundable dividend tax on hand (non-eligible) 20,500Dividend refund for 2020 (non-eligible) 8,500Required:(a) Compute the taxable income of OTOH Ltd. For the December 31, 2021 year end. Then calculate the federal Part I tax on federal taxable income payable by the corporation for the 2021 taxation year. Show in detail the calculation of all tax deductions, using a separate schedule for each, as needed.(b) Compute the Eligible and Non-Eligible refundable tax on hand balance as at December 31, 2021, showing in detail your calculation. Compute the dividend refund for the 2021 taxation year. A ball is tossed straight up and later returns to the point trom which it was launched the ball is subject to ar resistance as well as gravity, which of the following statements is correct The speed at which the ball returns to the point of launch is less than its speed when it was initially launched The time for the ball to fall is the same as the time for the ball to rise The force of air resistance is directed downward botly when the ball istising and when it is falling The net work done by air resistance on the ball during its flight is zero E The net work done by gravity on the ball during its fight is greater than zero kat is investigating a compound and sees that it has even stronger hydrogen bonds than water. what can kat conclude is most likely true about the specific heat of this compound? it is higher than the specific heat of water. it is equal to the specific heat of water. it is slightly lower than the specific heat of water. it is half as much as the specific heat of water. question 2what is the major source of competition for motor carrier?2 points the market-product grid for a Wendy's restaurant next to a large urban university campus. Marketing synergies and efficiencies run __________ because a single kind of marketing action can reach customers that buy different product groupings.a. horizontally across the rowsb. vertically down the columnc. between full meals and snacksd. diagonally from top-left to bottom-right of a market-product gride. both horizontally and vertically depending upon the marketing action developed Watkins is considering a new project it hopes can boost the stock price (and make all stakeholders happy). The project has an upfront cost of $63,000 and projected cash inflows of $19,000 in Year 1, $34,000 in Year 2, and $24,000 in Year 3. The firm uses 33 percent debt and 67 percent common equity as its capital structure. The company's cost of equity is 13.8 percent while the aftertax cost of debt for the firm is 5.7 percent. What is the projected net present value of the new project which of the following statements is NOT true about an outlier? a. an outlier is a data point or case that is substantially from the trend of the data b. outliers cannot cause bias in the data c. outliers can cjhange the slope and intercepts in multiple linear regression d. deleting an outlier from the the dataset is not an acceptable options no need citationsQuestion 5 [Total 15 marks] Digital trade is on the rise and the door has opened to more countries. However, countries vary greatly in their readiness for digital trade. In general, advanced economies Suppose the expected inflation rates in the US and the Euro zone are 2% and 4% respectively. Currently, the exchange rate is $1.5 dollar per euro.a). What is the dollar price and euro price of a consumption bundle in the US market and the Euro zone market if the absolute purchasing power parity holds? (You can express the prices in any unit, e.g. 1x, 10x, 100x, 1000x, etc.) (2 marks)b). Suppose the nominal dollar and euro interest rates are 5% and 10% respectively. Calculate the expected nominal exchange rate E(dollar/euro) using the nominal interest parity. (3 marks)c). Calculate the expected real exchange rate based on the results of part (a) and part (b). (3 marks) Imagine that you are the owner of Shoppee A. Identify any TWO (2) functional areas in Shopee (2 marks) B. Select only one functional area which you have identified in part A and identify the business functions that may involve (6 marks) C. Based on your answer in part B, transform ONE of the business functions into business processes. Justify if the business functions need to be integrated with other functional areas are known for the emphasis that they place on the scientific method. group of answer choices structuralists positivists hedonists classicalists scores of sat exams are normally distributed with mean=500 and standard deviattion of 100. the college wants to admit the top 10% what are two ways that the combination and assets report can help a marketer imrpove their creative assets' performance? (choose two.) select 2 correct responses spot opportunities to replace assets that aren't performing well. examine high-performing assets as a means of inspiring future creative assets. identify budget limitations that could be preventing assets from being shown in auctions. find new keywords to add to a campaign so that asset reach can be improved. Texting While Driving According to a Pew poll in 2012, 58% of high school seniors admit to texting while driving. Assume that we randomly sample two seniors of driving age. a. If a senior has texted while driving, record Y; if not, record N. List all possible sequences of Y and N. b. For each sequence, find by hand the probability that it will occur, assuming each outcome is independent. c. What is the probability that neither of the two randomly selected high school seniors has texted? d. What is the probability that exactly one out of the two seniors has texted? e. What is the probability that both have texted?