West Co.'s 2016 financial statements were authorized for issue by its directors on 28 April 2017 and the annual general meeting will be held on 1 June 2017. Slow moving inventories held at one of its warehouses were valued at its cost of $350.000 at 31 December 2016.On 4 April 2016,70% of this inventory was sold for $120,000 on which West Co.'s sales staff earned a commission of $10,000. On 1 January 2018. an entity borrowed $12 million for the construction of a building that is estimated to cost $30 million. Only $5 million was utilised during the year and the balance of $7 million was invested temporarily in a fixed deposit which yielded an interest of 5% per annum. Total interest accrued on the borrowing of $12 million for the year 2016 was $0.84 million Hazelnut Co leased out tangible non-current assets as operating leases. At 1 January 2016, the carrying amount of such assets was $40 million while the remaining useful life was 10 years. These assets were leased out on operating leases that have recently expired. On 31 December 2016, the company is undecided to whether sell or lease the assets to customers under operating leases but wants to recognise it as held for sale. The fair value less selling costs of the asset is $37 million and the value in use is estimated at $38 million. For each of the above situation: i. Identify the relevant MERS i. Explain the accounting treatment Prepare relevant journal entries (note: for the financial year-end is 31 December 2016)

Answers

Answer 1

Identification of the relevant MERS: Slow moving inventories (cost $350,000) held at West Co.'s warehouseTotal borrowing of $12 million for the construction of a building Non-current tangible assets held by Hazelnut CoThe accounting treatment for each of the above situations and relevant journal entries are as follows:

Accounting Treatment for Slow moving inventories held at West Co.'s warehouse. The slow-moving inventories held at West Co.'s warehouse will be valued at its cost of $350,000 at 31 December 2016. Since 70% of the inventory was sold, the remaining inventory will be valued at 30% of $350,000 = $105,000The accounting entry to record the sale of the inventory and the commission earned is as follows :Accounting Treatment for Slow moving inventories soldDateAccountTitlesDebitCredit4 April 2016Cost of Goods Sold 84,000Slow moving Inventories 84,000(70% x $350,000)Sales Commission 10,000Sales 10,000(70% x $120,000)Accounting Treatment for Non-current assets held by Hazelnut CoOn 31 December 2016, Hazelnut Co is undecided whether to sell or lease out the non-current assets, but it wants to recognize them as held for sale. The fair value less selling costs of the asset is $37 million, and the value in use is estimated at $38 million. Since the fair value less selling costs is lower than the value in use, the recoverable amount of the asset is lower than the carrying amount, and the asset will be written down.The accounting entry to write down the asset and recognize it as held for sale is as follows:Accounting Treatment for Non-current assets held by Hazelnut CoDateAccountTitlesDebitCredit31 December 2016Loss on Impairment 2,000,000Non-current Assets Held for Sale 2,000,000(Write down of non-current asset to fair value less selling costs of $37m)As of 31 December 2016, Hazelnut Co will recognize depreciation expense for the non-current assets for the year. The accounting entry to recognize the depreciation expense is as follows:Accounting Treatment for Depreciation of Non-current assets held by Hazelnut CoDateAccountTitlesDebitCredit31 December 2016Depreciation Expense 4,000,000Accumulated Depreciation - Non-current Assets 4,000,000(10% x $40,000,000)iii. Accounting Treatment for Total borrowing of $12 million for the construction of a buildingOn 1 January 2018, an entity borrowed $12 million for the construction of a building that is estimated to cost $30 million. Only $5 million was utilized during the year, and the balance of $7 million was invested temporarily in a fixed deposit which yielded an interest of 5% per annum. Total interest accrued on the borrowing of $12 million for the year 2016 was $0.84 million.On 31 December 2016, the entity will recognize the interest expense for the interest accrued on the borrowing of $12 million.The accounting entry to record the interest expense is as follows:Accounting Treatment for Total borrowing of $12 millionDateAccountTitlesDebitCredit31 December 2016Interest Expense 840,000Interest Payable 840,000(5% x $12,000,000)Thus, the accounting treatment for slow-moving inventories sold and non-current assets held by Hazelnut Co includes the recognition of losses due to impairment. The accounting treatment for total borrowing of $12 million includes the recognition of interest expense.

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Answer 2

The relevant MERS for each situation are as follows:

i. West Co.: Inventory

ii. The entity: Borrowing

iii. Hazelnut Co.: Assets

The accounting treatments and journal entries for each situation are given below:

i. West Co.: Inventory

The accounting treatment for slow-moving inventory valuation is to record the inventory’s cost of $350,000 on the balance sheet. When 70% of the inventory is sold for $120,000, the sales amount of $120,000 is recognized on the income statement, while the commission amount of $10,000 is recognized as selling expenses.

The journal entry is as follows:

Income statement: Dr. Cash $120,000Cr.

Revenue $120,000

Dr. Commission expense $10,000Cr.

Cash $10,000

Balance sheet:

Dr. Inventory $245,000Cr.

Cost of goods sold $245,000

ii. The entity: Borrowing

When an entity borrows funds, it records the principal amount on the balance sheet as a liability and recognizes interest expenses as the cost of borrowing. The interest amount for the year 2016 was $0.84 million. Therefore, the journal entry is as follows:

Balance sheet:

Dr. Cash $5,000,000

Dr. Fixed deposit $7,000,000 Cr.

Borrowing $12,000,000

Income statement:

Dr. Interest expense $0.84 million Cr.

Cash $0.84 million

iii. Hazelnut Co.: Assets

When an asset is recognized as held for sale, it is carried at the lower of the fair value less selling costs or value in use. The carrying amount of the asset is reduced to its fair value less selling costs.

The journal entry is as follows:

Balance sheet:

Dr. Provision for impairment $1 million Cr.

Tangible non-current assets $1 million

Balance sheet:

Dr. Tangible non-current assets $3 million Cr.

Provision for impairment $3 million

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Related Questions

The units for square centimeters are written as
Check all that apply.
O A. cm2
B. sq. cm
C. km2
D. sq.m
E cm

Answers

The answers are A and B.
The answer is a and b

let f be a function with derivative given by f x ¢( ) = 3 x + 1. what is the length of the graph of y f = ( )x from x = 0 to x = 1.5 ?

Answers

If "f" is function with derivative as f'(x) = √(x³ + 1), then length of graph of y = f(x) from x = 0 to x = 1.5 is (b) 2.497.

To find the length of the graph of y = f(x) from x = 0 to x = 1.5, we use the arc-length formula for a function y = f(x):

Length = ∫ᵇₐ√(1 + [f'(x)]²) dx,

Given the derivative : f'(x) = √(x³ + 1), we substitute it into the arc-length formula:

Length = [tex]\int\limits^{1.5}_{0}[/tex] √(1 + (√(x³ + 1))²) dx,

Simplifying the expression inside the square root:

We get,

Length = [tex]\int\limits^{1.5}_{0}[/tex] √(1 + x³ + 1) dx

= [tex]\int\limits^{1.5}_{0}[/tex]√(x³ + 2) dx

= 2.497.

Therefore, the correct option is (b).

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The given question is incomplete, the complete question is

Let f be a function with derivative given by f'(x) = √(x³ + 1). What is the length of the graph of y = f(x) from x = 0 to x = 1.5?

(a) 4.266

(b) 2.497

(c) 2.278

(d) 1.976

which of the following expressions is equivalent to -10?
a.-7 3
b.-3 - 7
c.3 - 7
d.7 - 3

Answers

The expression which is equivalent to -10 is the option b, -3 - 7.

Explanation:

We can use subtraction and addition of integers to get the value of the given expression. We can write the given expression as;

-3 - 7 = -10 (-3 - 7)

The addition of two negative integers will always give a negative integer. When we subtract a larger negative integer from a smaller negative integer, we will get a negative integer.

If we add -3 and -7 we will get -10. This makes the option b the correct answer.

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From Hardcover Book, Marsden/Tromba, Vector Calculus, 6th ed., Section 2.1., # 40) Using polar coordinates, describe the level curves of the function defined by f (x, y) = - 2xy (22+y2) if (x, y) + (0,0) and f(0,0) = 0.

Answers

The level curves of the function f(x, y) = -2xy / (2^2 + y^2) in polar coordinates consist of lines θ = π/2 + kπ and θ = kπ, as well as the upper half and lower half of the unit circle depending on the sign of the function. These level curves represent the points (r, θ) where the function f(r, θ) is constant.

To describe the level curves of the function f(x, y) = -2xy / (2^2 + y^2), we can first express the function in terms of polar coordinates. Let's substitute x = r cos(θ) and y = r sin(θ) into the function:

f(r, θ) = -2(r cos(θ))(r sin(θ)) / (r^2 + (r sin(θ))^2)

Simplifying this expression, we get:

f(r, θ) = -2r^2 cos(θ) sin(θ) / (r^2 + r^2 sin^2(θ))

Now, we can further simplify this expression:

f(r, θ) = -2r^2 cos(θ) sin(θ) / (r^2(1 + sin^2(θ)))

f(r, θ) = -2 cos(θ) sin(θ) / (1 + sin^2(θ))

The level curves of this function represent the points (r, θ) in polar coordinates where f(r, θ) is constant. Let's consider a few cases:

1. When f(r, θ) = 0:

  This occurs when -2 cos(θ) sin(θ) / (1 + sin^2(θ)) = 0. Since the numerator is zero, we have either cos(θ) = 0 or sin(θ) = 0. These correspond to the lines θ = π/2 + kπ and θ = kπ, where k is an integer.

2. When f(r, θ) > 0:

  In this case, the numerator -2 cos(θ) sin(θ) is positive. For the denominator 1 + sin^2(θ) to be positive, sin^2(θ) must be positive. Therefore, the level curves lie in the regions where sin(θ) > 0, which corresponds to the upper half of the unit circle.

3. When f(r, θ) < 0:

  Similar to the previous case, the level curves lie in the regions where sin(θ) < 0, which corresponds to the lower half of the unit circle.

In summary, the level curves of the function f(x, y) = -2xy / (2^2 + y^2) in polar coordinates consist of lines θ = π/2 + kπ and θ = kπ, as well as the upper half and lower half of the unit circle depending on the sign of the function.

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(q17) A geologist finds out that a radioactive substance A that he found in the caves of Africa decays at a rate of 0.03 percent every year. What is the probability that an atom of this substance chosen at random will decay in the next 70 years?

Answers

None of the given options is the answer.

To calculate the probability of decay for substance A over the next 70 years, we need to consider the decay rate of 0.03 percent per year.

The decay rate of 0.03 percent per year can be converted to a decimal by dividing it by 100: 0.03 / 100 = 0.0003.

The probability of an atom decaying in a given year is equal to the decay rate, which is 0.0003.

To calculate the probability of an atom not decaying in a given year, we subtract the decay rate from 1: 1 - 0.0003 = 0.9997.

The probability of an atom not decaying over the next 70 years can be calculated by multiplying the probability of not decaying in each year together: (0.9997)^70 ≈ 0.9704.

Therefore, the probability of an atom decaying in the next 70 years is equal to 1 minus the probability of not decaying: 1 - 0.9704 ≈ 0.0296.

So, the probability that an atom of substance A chosen at random will decay in the next 70 years is approximately 0.0296 or 2.96%.

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Solve the system of equations using the substitution method. Show your work and be sure to include the solution to the system.

Answers

Points form:
(3.2)
Equation form:
X
x=3,y=2

What is the value of Point C on the number line below?

A) 0.208
B) 0.28
C) 0.302
D) 0.32

Answers

Answer:

0.28

Step-by-step explanation:

All you need to do is count.

0.20, 0.21, 0.22, 0.23, 0.24, 0.25, 0.26, 0.27, 0.28, 0.29, 0.30

                                                                              C

Point C sits on the point 0.28.

Which of the following sets of angle measures can be used to draw an acute isosceles triangle? Select all that apply. 75°, 30°, 75° 80°, 55°, 45° 80°, 80°, 40° 60°, 60°, 60° 50°, 50°, 80° 20°, 140°, 20°​

Answers

Answer:

1. 80°, 80°, 40°

2. 60°, 60°, 60°

3. 20°, 140°, 20°

4. 50°, 50°, 80°

5. 75°, 30°, 75°

6. 80°, 55°, 45°

6, 2, and 4

Answer:

I think its 6,2, and 4

Step-by-step explanation: hope that helps! °∪°


A rectangular swimming pool is 6 it deep. One side of the pool is 3.5 times longer than the other. The amount of water needed to fill the swimming pool is
1344 cubic feet. Find the dimensions of the pool.

Answers

Answer:

8 feet by 28 feet by 6 feet

Step-by-step explanation:

So volume is length times width times height

It tells us that the volume is 1344 cubic feet (the water used to fill it)

And it also tells us that the height/depth (which are the same thing in this case) is 6ft

All we need now are length and width

We know that one of the sides is 3.5 times the other one. So we can just say length is x and width is 3.5x

So plugging that in, the equation becomes

[tex]3.5x*x*6=1344[/tex]

3.5 x times x is just 3.5x squared so

[tex]3.5x^2*6=1344[/tex]

       divide both sides by 6

[tex]3.5x^2=244[/tex]

       divide by 3.5

[tex]x^2 =64[/tex]

        [tex]x=\sqrt{64}[/tex]

x = 8

So that means the one side is 8 feet long and the other side is 3.5 times that, which is 28 feet long.

So the dimensions of the pool are 8 feet by 28 feet by 6 feet

Consider a sequence of i.i.d random variables X₁, X2,..., each with a discrete uniform distribution on the set {0, 1,2}. In other words, P(X = 0) = 1/3 = P(X₁ = 1) = P(X = 2), for each k. (a) Compute P(X₁ + X₂ ≤ 1). (b) Determine the mgf of X₁ along with its domain. n (c) Consider a sequence of sample averages, {X}, where X₁ = EX for n € N. Find k=1 the mgf of X, by also stating its domain. Hint. First describe the mgf of X, in terms of the mgf of Xk, and then use the mgf of X.

Answers

(a) To compute P(X₁ + X₂ ≤ 1), we can list out all the possible values of X₁ and X₂ that satisfy the inequality: X₁ + X₂ ≤ 10 + 0 = 0, which is impossible, so P(X₁ + X₂ ≤ 1) = P(X₁ = 0, X₂ = 0) + P(X₁ = 1, X₂ = 0) + P(X₁ = 0, X₂ = 1) = (1/3)² + (1/3)² + (1/3)² = 1/3.

(b) The moment generating function (mgf) of X₁ is given by:

M(t) = E(etX₁) = (1/3) et0 + (1/3) et1 + (1/3) et2 = (1/3) + (1/3) et + (1/3) e2t

The domain of M(t) is the set of all values of t for which E(etX₁) exists.

(c) Let X be the sample average of {Xk}, where Xk are i.i.d random variables with the same distribution as X₁.

Then, by the linearity of expectation and the definition of X₁, we have:

E(X) = E( (X₁ + X₂ + ... + Xn)/n ) = (E(X₁) + E(X₂) + ... + E(Xn))/n = (EX₁ + EX₂ + ... + EXn)/n = X₁ = 1

From part (b), we have the mgf of X₁ as M₁(t) = (1/3) + (1/3)et + (1/3)e2t.

Then, the mgf of X is given by the formula: M(t) = E(etX) = et (X₁ + X₂ + ... + Xn)/n) = E(etX₁/n) × E(etX₂/n) × ... × E(etXn/n) = (M₁(t/n)) ⁿ = [(1/3) + (1/3) et/n + (1/3) e2t/n] ⁿ

The domain of M(t) is the set of all values of t for which E(etX) exists.

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find the shaded region of the figure below​

Answers

Answer:

-x³ + 3x² - 14x + 12

Step-by-step explanation:

Area of outer rectangle = (x² + 3x - 4) * (2x - 3)

      = (x² + 3x - 4) * 2x  + (x² + 3x - 4) * (-3)

     =x²*2x + 3x *2x - 4*2x  + x² *(-3) + 3x *(-3)  - 4*(-3)

     =2x³ + 6x² - 8x - 3x² - 9x + 12

    = 2x³ + 6x² - 3x²   - 8x - 9x + 12     {Combine like terms}

    = 2x³ + 3x² - 17x + 12

Area of inner rectangle = (x² - 1)* 3x

                                       = x² *3x - 1*3x

                                       = 3x³ - 3x

Area of shaded region = area of outer rectangle - area of inner rectangle

         = 2x³ + 3x² - 17x + 12 - (3x³ - 3x)

         = 2x³ + 3x² - 17x + 12 -3x³ + 3x

        = 2x³ - 3x³ + 3x² - 17x + 3x + 12

        = -x³ + 3x² - 14x + 12

Write a simplified polynomial expression that can be used to represent the perimeter of the rectangle. 3x-7 and x-7​

Answers

Answer:

P = 8x-28

Step-by-step explanation:

Given that,

Length = (3x-7)

Width = (x-7)

We need to find the perimeter of the rectangle. The formula for the perimeter of a rectangle is given by :

[tex]P=2 (l+b)\\\\P=2(3x-7+x-7)\\\\P=2(4x-14)\\\\P=8x-28[/tex]

So, the perimeter of the rectangle is equal to 8x-28.

increase 50$ by 15%

Can you say how to do it and answer?

Answers

15% = 0.15
0.15 • 50 = 7.5
50 + 7.5 = 57.5

Simple word problem. 40 POINTS!!!!Thank you.​

Answers

Answer:

$50

Step-by-step explanation:

Hello There!

We are given that for 1 hour of work 250 dollars is charged and for 3 hours of work 350 dollars is charged

This could also be represented in two points (1,250) and (3,350)

The question wants us to find the hourly charge rate (slope)

we can easily find the slope ( hourly charge rate ) by using the slope formula

[tex]slope=\frac{y_2-y_1}{x_2-x_1}[/tex]

we have our two points so all we need to do is plug in the values (remember y values go on top and x values go on the bottom.)

[tex]slope=\frac{350-250}{3-1} \\350-250=100\\3-1=2\\slope=\frac{100}{2} or50[/tex]

So we can conclude that the hourly charge rate is $50

HELP PLEASE I NEED HELP !

Answers

Answer:

G

Step-by-step explanation:

out of a total of 280 spinners as the overall.

3/40 were defective

280 * 3/40 = 21

Answer:

G

Step-by-step explanation:

For every 40 spinners 3 are defective

Divide amount made by 40 for numbers of groups of 40

280 ÷ 40 = 7 , then

7 × 3 = 21 ← likely defective spinners → G

2, 3, 1, 6, 4, 5, 3, 2, 3, 4 is the set

Answers

Answer:

mean: 3.3

median: 3

mode: 3

range: 5

Q1 = 2

Q3 = 4

IQR = 2

Step-by-step explanation:

Mean=3.3
Median=3
Mode=3
Range=5
Q1=2
Q3=4
Iqr =2

Please help me with my math( if you help i will give you brainliest)

Answers

Answer:

4. 50

5. 35

6. 45

7. 30

8. No mode

9. 42

10. 22, 25, 45, 73, 80

11. 15, 25, 30, 48, 50

12. 58

13. 35

14. 51

15. 24

16. 22.13

17. 10.22

18. Iffy's team had a lower performance than Kaiya's team. Iffy's team collected an average of 35 cans, whereas, Kaiya's team collected an average of 50 cans!! Kaiya's team also had very versatile and active players who were able to collect more, individually, unlike Iffy's team.

Step-by-step explanation:

y=5x
y=-3x+24
Solve by substitution

Answers

Answer:

x=12

Step-by-step explanation:

5x = -3x+24

2x = 24

x = 12

A number,
n
n, is multiplied by

0.7
−0.7. The product is

1
2

2
1

. What is the value of
n
n?

Answers

Answer:

0.8

Step-by-step explanation:

got it right on edg

Answer:

5/7

Step-by-step explanation:

Worth five points! it doesnt tell me if what answer is right but if i get 75% or up i will mark the first person who answered with an actual answer brainliest and i don't lie about brainliest!! Please no nonsense answers I just want help :(
Triangle DEF is an isosceles triangle with DE = EF, and mE =92°
What is mD?
A. 45
B. 44°
C. 88°
D. 90°

Answers

Answer:

Step-by-step explanation:

Answer:

44 is the awnser

Step-by-step explanation:

becuase if you were to look at the first persons work it is correct showing him solving the equasion and witch it is not 44

Can someone please help me with math.

Answers

the mapping doesn’t represent a function
and i think that’s a vertical angle?

the circumfrence is 72 cm what is the length of the minor arc

Answers

Answer:

Should be 9 centimeters.

Step-by-step explanation:

Seats in a theater are curved from the front row to the back. The front row has 10 chairs, the second has 16 and the third has 22, and so on.


A. Write a recursive rule for this series


B. Write an explicit rule for this series


C. Using the explicit formula, find the number of chairs in row 5


D. The auditorium can hold 17 rows of chairs. Write a sigma notation for this series, and then use either series formula to calculate how many chairs can fit in the auditorium

Answers

Answer:

The first term is 10.

The second term is 16

The third term is 22.

We can see that the first term plus 6, is:

10 + 6 = 16

Then the first term plus 6 is equal to the second term.

And the second term plus 6 is:

16 + 6 = 22

Then the second term plus 6 is equal to the third term.

A) As we already found, the recursive rule is:

Aₙ = Aₙ₋₁ + 6

B) The explicit rule is:

Aₙ = A₁ + (n - 1)*6

Such that A1 is the first term, in this case A₁ = 10

Then:

Aₙ = 10 + (n - 1)*6

C)

Now we want to find A₅, then:

A₅ = 10 + (5 - 1)*6 = 34

There are 34 chairs in row 5.

D)

Here we have 17 rows, then we can have 17 terms, this means that the total number of chairs will be:

C = A₀ + A₁ + ... + A₁₆

This summation can be written as:

∑ 10 + (n - 1)*6        such that n goes from 0 to 16.

The formula  for the sum of the first N terms of a sum like this is:

S(N) = (N)*(A₁ + Aₙ)/2

Then the sum of the 17 rows gives:

S(17) = 17*(10 + (10 + (17 - 1)*6)/2 = 986 chairs.

There are total 986 chairs in the considered auditorium and there are 34 chairs in the fifth row.

The recursive rule for this series is: [tex]T_n = T_{n-1} + 6[/tex]The explicit rule for this series is: [tex]T_n = 6n + 4[/tex]

What is recursive rule?

A rule defined such that its definition includes itself.

Example: [tex]F(x) = F(x-1) + c[/tex] is one such recursive rule.

For this case, we're provided that:

Seats in rows are 10 in front, 16 in second, 22 in third, and so on.

10 , 16 , 22 , .....

16 - 10 = 6

22 - 16 = 6

...

So consecutive difference is 6

If we take [tex]T_i[/tex] as ith term of the series then:

[tex]T_2 - T_1 = 6\\T_3 - T_2 = 6\\T_4 - T_3 = 6 \\T_5 - T_4 = 6\\\cdots\\T_{n} - T_{n-1} = 6[/tex]

Thus, the recursive rule for the given series is [tex]T_{n} - T_{n-1} = 6[/tex] or [tex]T_n = T_{n-1} + 6[/tex]

From this recursive rule, we can deduce the explicit formula as:
[tex]T_n = T_{n-1} + 6\\T_n = T_{n-2} + 6 + 6\\\cdots\\T_n = T_{n-k} + k \times 6\\T_n = T_1 + 6(n-1)\\T_n = 10 + 6(n-1) \: \rm (as \: T_1 = 10)\\[/tex]

Thus, the explicit rule for this series is [tex]T_n = 10 + 6(n-1)[/tex]

For 5th row, putting n = 5 gives us:

[tex]T_n = 10 + 6(n-1) = 6n + 4\\T_5 = 6(5) + 4 = 34[/tex]

If the auditorium has 17 rows, then total chairs are:

[tex]T = T_1 + T_2 + \cdots + T_{17} = \sum_{n=1}^{17} T_n\\\\T = \sum_{n=1}^{17} (10 + 6(n-1))\\\\T = \sum_{n=1}^{17} (6n + 4)\\\\T = 6\sum_{n=1}^{17} n + \sum_{n=1}^{17}4 = 6\sum_{n=1}^{17} n + 4 \times 17\\\\T = 6\left( \dfrac{17(18)}{2}\right) + 68 = 918 + 68\\\\T = 986[/tex]

(it is because [tex]\sum_{k=1}^n k = 1 + 2 + \cdots + n = \dfrac{n(n+1)}{2}[/tex] )

Thus, there are total 986 chairs in the considered auditorium. There are 34 chairs in the fifth row. The recursive rule for this series is: [tex]T_n = T_{n-1} + 6[/tex] The explicit rule for this series is: [tex]T_n = 6n + 4[/tex].

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EQUAÇO
1. x + 5 - 25=x + 3x - 4
2. 1 - 2x = 3 - 2(x + 1)

Answers

1. 5-25=3x-4 => -20=3x-4 => -16=3x => x= -16/3
2. 1-2x=3-2x-2 => 1=3-2 => 1=1 => x=R

the radius of a circle is 8 miles. what is the area of a sector bounded by a 144° arc

Answers

Answer:

Step-by-step explanation:

The area of a sector and the properties of circles bounded by a 144° arc in a circle with a radius of 8 miles can be calculated using the formula: Area of sector = (θ/360°) * π * r² where θ is the central angle of the sector and r is the radius of the circle.

In this case, the central angle is 144° and the radius is 8 miles. Plugging these values into the formula, we get: Area of sector = (144°/360°) * π * (8 miles)². Simplifying the equation, we have: Area of sector = (0.4) * π * (8 miles)².

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Someone please help!!! will give brainliest!!!
Round your answer to the nearest hundredths, if necessary.
Find the surface area of the figure

Answers

Answer:161.56

Step-by-step explanation:

8 x5=40

8 x 7.07=56.56

1/2 x 5 x 5 x 2= 25

8 x 5=40

Add that all together

A survey was conducted that asked 1014 people how many books they had read in the past year. Results indicated that x = 12.7 books and s= 16.6 books. Construct a 90% confidence interval for the mean number of books people read. Interpret the interval Click the icon to view the table of critical t-values. Construct a 90% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice (Use ascending order. Round to two decimal places as needed) OA. There is 90% confidence that the population mean number of books read is between __ and __. if repeated samples are taken, 90% of them will have a sample mean between __ and __. There is a 90% probability that the true mean number of books read is between __ and __ .

Answers

There is 90% confidence that the population mean number of books read is between 9.85 and 15.55. If repeated samples are taken, 90% of them will have a sample mean between 9.85 and 15.55. There is a 90% probability that the true mean number of books read is between 9.85 and 15.55.

What is the 90% confidence interval for the mean number of books read?

The survey results indicate that the mean number of books read in the past year is estimated to be 12.7, with a standard deviation of 16.6. To construct a 90% confidence interval, we can use the t-distribution and the sample size of 1014. Using the critical t-values from the table, we calculate the margin of error by multiplying the standard error (s / √n) with the t-value. Adding and subtracting the margin of error from the sample mean gives us the lower and upper bounds of the confidence interval.

The confidence interval for the mean number of books read is calculated as 12.7 ± (t-value * 16.6 / [tex]\sqrt{1014}[/tex]), which simplifies to 12.7 ± 2.58. Therefore, the confidence interval is (9.85, 15.55).

In interpretation, this means that we can be 90% confident that the true mean number of books read in the population falls between 9.85 and 15.55. If we were to repeat the survey and take different samples, 90% of those samples would produce a mean number of books read within the range of 9.85 to 15.55. The confidence interval provides a range of values within which we can reasonably estimate the true population mean.

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PLEASE HELP !!!! find the focus (parabolas)

(y-2)^2=4(x+3)

Answers

Answer:

C. ( -2 , 2 )

Step-by-step explanation:

Focus of parabola [tex](y-2)^2 = 4(x+3)[/tex] is (-2 , 2) .

Correct option is C .

Given, Equation of parabola  [tex](y-2)^2 = 4(x+3)[/tex]

Focus of parabola :

Standard equation of parabola : (y - k)² = 4a(x - h)

Axis of parabola : y = k

Vertex of parabola : (h, k)

Focus of parabola : (h + a, k)

Compare the equation of parabola with standard equation.

(y - k)² = 4a(x - h)

[tex](y-2)^2 = 4(x+3)[/tex]

k = 2

a = 1

h = -3

So focus of parabola:  (h + a, k).

-3 + 1 , 2

Focus of parabola = -2 , 2

Hence the correct option is C .

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For 25 pts
Pls Help this is hard as hell

Answers

Answer: For the first one Independent variable would be Cars age and the dependent would be cars price. For the second one, independent variable would be number of training miles and dependent would be Time to finish the race in minutes.

Step-by-step explanation:

Answer:

First one:

The independent variable is the car’s age

The dependent variable is the car’s price according tot he age

Second one:

The independent variable is the number of training miles

The dependent variable is the time it takes to finish

Step-by-step explanation:

Just think of the independent variable as the cause and the dependent variable as the effect.

Tell which value of the variable is the solution of the equation 30 = 6w W = 3, 5, 6, 8??

Answers

Answer: w=5

Step-by-step explanation: Hope this help

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